Re: [Tutor] Creating a class and calling an exception
Thank you very much. I should have added that I did that and it ran. I had
one other error in the script thta I missed. I fixed that and it ran, then
I named them as recommended and it still works and fits better with
conventions, so I learned two things.
On Fri, Jun 3, 2011 at 1:05 AM, Alan Gauld wrote:
>
> "Becky Mcquilling" wrote
>
> The Second script written here, always raises the exception and I'm
>> missing
>> why, any advice?
>> class Log_Parser:
>> def __init__(self):
>> self.re_backup_status = re.compile(r'^\s+Files\s+:\s+\d',
>> re.IGNORECASE)
>>
>> def log_parse(self, log_file):
>>
>> try:
>>
>>
>> for line in log1:
>> if re_backup_status.search(line):
>>
>
> When accessing an attribute of a class you need to prefix with self.
> You are getting a name error here I suspect.
>
>
>log1.close()
>> except: print "%s" %('succeeded:0 failed:1')
>>
>
> But your cattchall exception is hiding the error. If you add
> a raise inside the exception handler while debugging it
> will print the full error text.
>
> If you did that you would have been pointed to the
> line with the error and told the name of the bad name.
> Using a catchall exceptioon is OK after the code is
> working if you want to shield your users from tracebacks,
> but during debugging catchall exceptions are evil,
> don't do it.
>
> HTH,
>
> --
> Alan Gauld
> Author of the Learn to Program web site
> http://www.alan-g.me.uk/
>
>
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Re: [Tutor] Creating a class and calling an exception
> class Log_Parser: It is highly recommended that you use new-style classes which would be class Log_Parser(object): Ramit Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology 712 Main Street | Houston, TX 77002 work phone: 713 - 216 - 5423 This communication is for informational purposes only. It is not intended as an offer or solicitation for the purchase or sale of any financial instrument or as an official confirmation of any transaction. All market prices, data and other information are not warranted as to completeness or accuracy and are subject to change without notice. Any comments or statements made herein do not necessarily reflect those of JPMorgan Chase & Co., its subsidiaries and affiliates. This transmission may contain information that is privileged, confidential, legally privileged, and/or exempt from disclosure under applicable law. If you are not the intended recipient, you are hereby notified that any disclosure, copying, distribution, or use of the information contained herein (including any reliance thereon) is STRICTLY PROHIBITED. Although this transmission and any attachments are believed to be free of any virus or other defect that might affect any computer system into which it is received and opened, it is the responsibility of the recipient to ensure that it is virus free and no responsibility is accepted by JPMorgan Chase & Co., its subsidiaries and affiliates, as applicable, for any loss or damage arising in any way from its use. If you received this transmission in error, please immediately contact the sender and destroy the material in its entirety, whether in electronic or hard copy format. Thank you. Please refer to http://www.jpmorgan.com/pages/disclosures for disclosures relating to European legal entities. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Creating a class and calling an exception
"Becky Mcquilling" wrote
The Second script written here, always raises the exception and I'm
missing
why, any advice?
class Log_Parser:
def __init__(self):
self.re_backup_status = re.compile(r'^\s+Files\s+:\s+\d',
re.IGNORECASE)
def log_parse(self, log_file):
try:
for line in log1:
if re_backup_status.search(line):
When accessing an attribute of a class you need to prefix with self.
You are getting a name error here I suspect.
log1.close()
except: print "%s" %('succeeded:0 failed:1')
But your cattchall exception is hiding the error. If you add
a raise inside the exception handler while debugging it
will print the full error text.
If you did that you would have been pointed to the
line with the error and told the name of the bad name.
Using a catchall exceptioon is OK after the code is
working if you want to shield your users from tracebacks,
but during debugging catchall exceptions are evil,
don't do it.
HTH,
--
Alan Gauld
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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[Tutor] Creating a class and calling an exception
So I'm new to doing creating classes in python and took a script I had
written to parse a log file and tried to create a class just to understand
it a little better. The first script below works fine.
It looks at the log, checks the date and if it's too old, raises the
exception and returns a set value or if the file doesn't exist it raises the
exception. If the file is there and is no more than a day old, it parses
the log and returns what was backed up by the utility I'm using.
The Second script written here, always raises the exception and I'm missing
why, any advice?
*FIRST SCRIPT*
import re, os
import stat
import sys
from datetime import date, timedelta
log_file = 'd:/backup_logs/backups.log'
re_backup_status = re.compile(r'^\s+Files\s+:\s+\d', re.IGNORECASE)
"""Example of return from regexFiles: Succeeded"168933 failed:0 """
def main():
try:
s = os.stat(log_file)
mtime = date.fromtimestamp(s[stat.ST_MTIME])
yesterday = date.today() - timedelta(days=1)
mode = s[stat.ST_MODE]
if stat.S_ISREG(mode):
if mtime < yesterday:
print "%s" % ('succeeded:0 failed:1')
else:
log1 = (open(log_file, 'r'))
for line in log1:
if re_backup_status.search(line):
status_out = line.split()
print '%s succeeded:%s failed:%s' % (
'map:files', status_out[2], status_out[6])
log1.close()
except: print "%s" %('succeeded:0 failed:1')
if __name__ == '__main__':
main()
*
*
*SECOND SCRIPT*
*
*
import re
import os
import stat
import sys
from datetime import date, timedelta
class Log_Parser:
def __init__(self):
self.re_backup_status = re.compile(r'^\s+Files\s+:\s+\d',
re.IGNORECASE)
"""Example of return from regexFiles: Succeeded"168933 failed:0 """
def log_parse(self, log_file):
try:
s = os.stat(log_file)
mtime = date.fromtimestamp(s[stat.ST_MTIME])
yesterday = date.today() - timedelta(days=1)
mode = s[stat.ST_MODE]
if stat.S_ISREG(mode):
print ('file is there')
if mtime < yesterday:
print('file is the wrong date')
print "%s" % ('succeeded:0 failed:1')
else:
log1 = (open(log_file, 'r'))
for line in log1:
if re_backup_status.search(line):
status_out = line.split()
print '%s succeeded:%s failed:%s' % (
'map:files', status_out[2], status_out[6])
log1.close()
except: print "%s" %('succeeded:0 failed:1')
backup_log_parser = Log_Parser()
backup_log_parser.log_parse('d:/backup_logs/backups.log')
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Re: [Tutor] creating a class
"T MURPHY" wrote how do i go about creating a class in python. class C: pass is the simplest way. But it's not very useful, being empty. But most tutorials discuss OOP, which one are you using? -- Alan Gauld Author of the Learn to Program web site http://www.alan-g.me.uk/ ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a class
On Wed, Oct 6, 2010 at 4:16 AM, T MURPHY wrote:
> how do i go about creating a class in python.
By using the "class" keyword.
Example:
class Fruit(object):
def __init__(self, name)
self.name = name
class Apple(Fruit):
def __init__(self):
super(Apple, self).__init__("apple")
apple = Apple()
print apple.name
For more information, I suggest you start reading
the python tutorial (1)
cheers
James
1. http://docs.python.org/tutorial/
--
-- James Mills
--
-- "Problems are solved by method"
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[Tutor] creating a class
how do i go about creating a class in python. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
