Re: [Tutor] creating a tab delimited filename
C Smith wrote: Here's an example that cycles through 3 number, 0, 1, and 2: ### >>> j=0 >>> for i in range(10): .. print j .. j = (j+1)%3 .. 0 1 2 0 1 2 0 1 2 0 ### A nice way to do this is with itertools.cycle(): >>> import itertools >>> cyc = itertools.cycle(range(3)) >>> for i in range(10): ... print cyc.next() ... 0 1 2 0 1 2 0 1 2 0 Kent ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
Hi Jacob,
Watch out with your code,
###
if i==1000:
i=0
else:
i=i+1
###
Since this test is done after you have stored your data you are
actually going to store 1001 pieces of data.
i starts at 0
you store 0
you do your test and i is incremented
{that's set 1}
i is 1
you store 1
you do your test and i is incremented
{that's set 2}
...
i is 1000
you store 1000
you do your test and i is set to 0
{that's set 10001}
Also, it looks like you have that i-incrementing happening at the same
level as the if-test. If so, it is possible that the i's that are used
to store the data will not increase by 1 each time since they are being
incremented for every k and not only when the data is being stored. If
you only want it incremented when something is stored, put it inside
the if-block. Also, consider using the modulo operator to keep track
of i: replace your test with
###
i = (i+1)%1000
###
i starts and 0 and will be incremented until it is 999 and then when
this calculation is then performed you will calculate (999+1)%1000
which is 1000%1000 which is 0--just what you wanted. Here's an example
that cycles through 3 number, 0, 1, and 2:
###
>>> j=0
>>> for i in range(10):
.. print j
.. j = (j+1)%3
..
0
1
2
0
1
2
0
1
2
0
###
/c
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Re: Fwd: [Tutor] creating a tab delimited filename
Max Noel wrote:
Forwarding to the list -- please use Reply to All.
Begin forwarded message:
From: jrlen balane <[EMAIL PROTECTED]>
Date: March 16, 2005 04:13:40 GMT
To: Max Noel <[EMAIL PROTECTED]>
Subject: Re: [Tutor] creating a tab delimited filename
Reply-To: jrlen balane <[EMAIL PROTECTED]>
why is this not working, what i am trying to do is create a table like
file based on 6 arrays. i 've used the forward slashes so i assume
that the text file was created, but to no avail, there were no text
file.:
for k in range (rx_len-9):
if byte[k] == 70 and byte [k+2] == 6 and sum(byte[k:k+10]) &
0xff == 0:
temp1.append(byte[k+3])
temp2.append(byte[k+4])
pyra1.append(byte[k+5])
pyra2.append(byte[k+6])
voltage.append(byte[k+7])
current.append(byte[k+8])
print temp1[i], temp2[i], pyra1[i], pyra2[i], voltage[i],
current[i]
if i==1000:
i = 0
else:
i = i+1
ser.flushInput()
filename = "%s%s.txt" %('C:/Documents and Settings/nyer/My
Documents/Info',time.strftime("%Y%m%d%H%M"))
print filename
might be helpful here
table_file = open(filename,"a")
lendata = len(temp1)
for ii in xrange(lendata):
table_file.write('%i\t'%temp1[ii])
table_file.write('%i\t'%temp2[ii])
table_file.write('%i\t'%pyra1[ii])
table_file.write('%i\t'%pyra2[ii])
table_file.write('%i\t'%voltage[ii])
table_file.write('%i\t'%current[ii])
table_file.write('\n')
table_file.close() might help...do you get any error messages or just no
file written?
Kent
===
it is printing the array so i assume that that the problem is in this
table_file...
please, i need help
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Fwd: [Tutor] creating a tab delimited filename
Forwarding to the list -- please use Reply to All.
Begin forwarded message:
From: jrlen balane <[EMAIL PROTECTED]>
Date: March 16, 2005 04:13:40 GMT
To: Max Noel <[EMAIL PROTECTED]>
Subject: Re: [Tutor] creating a tab delimited filename
Reply-To: jrlen balane <[EMAIL PROTECTED]>
why is this not working, what i am trying to do is create a table like
file based on 6 arrays. i 've used the forward slashes so i assume
that the text file was created, but to no avail, there were no text
file.:
for k in range (rx_len-9):
if byte[k] == 70 and byte [k+2] == 6 and sum(byte[k:k+10]) &
0xff == 0:
temp1.append(byte[k+3])
temp2.append(byte[k+4])
pyra1.append(byte[k+5])
pyra2.append(byte[k+6])
voltage.append(byte[k+7])
current.append(byte[k+8])
print temp1[i], temp2[i], pyra1[i], pyra2[i], voltage[i],
current[i]
if i==1000:
i = 0
else:
i = i+1
ser.flushInput()
filename = "%s%s.txt" %('C:/Documents and Settings/nyer/My
Documents/Info',time.strftime("%Y%m%d%H%M"))
table_file = open(filename,"a")
lendata = len(temp1)
for ii in xrange(lendata):
table_file.write('%i\t'%temp1[ii])
table_file.write('%i\t'%temp2[ii])
table_file.write('%i\t'%pyra1[ii])
table_file.write('%i\t'%pyra2[ii])
table_file.write('%i\t'%voltage[ii])
table_file.write('%i\t'%current[ii])
table_file.write('\n')
===
it is printing the array so i assume that that the problem is in this
table_file...
please, i need help
--
maxnoel_fr at yahoo dot fr -- ICQ #85274019
"Look at you hacker... A pathetic creature of meat and bone, panting
and sweating as you run through my corridors... How can you challenge a
perfect, immortal machine?"
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
On Mar 16, 2005, at 03:54, jrlen balane wrote:
how would i make this the correct path:
filename = "%s%s.txt" %('C:\Documents and Settings\nyer\My
Documents\Info',time.strftime("%Y%m%d%H%M"))
table_file = open(os.path.normpath(filename),"a")
running on IDLE, i get the following error:
Traceback (most recent call last):
File "C:/Python23/practices/serialnewesttes3.py", line 65, in
-toplevel-
table_file = open(os.path.normpath(filename),"a")
IOError: [Errno 2] No such file or directory: 'C:\\Documents and
Settings\nyer\\My Documents\\Info200503161153.txt'
it seems that it adds "\".
The "\n" of "\nyer" is escaped as a new line. That's a Bad Thing. In
fact, relying on backslashes being automatically escaped thanks to the
following character not having a special meaning in escape context is a
Bad Thing.
Either way, it's better to use forward slashes (or os.sep if you're
going for overkill and/or obscure, non-POSIX platforms), with which
such problems just don't happen.
-- Max
maxnoel_fr at yahoo dot fr -- ICQ #85274019
"Look at you hacker... A pathetic creature of meat and bone, panting
and sweating as you run through my corridors... How can you challenge a
perfect, immortal machine?"
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
how would i make this the correct path:
filename = "%s%s.txt" %('C:\Documents and Settings\nyer\My
Documents\Info',time.strftime("%Y%m%d%H%M"))
table_file = open(os.path.normpath(filename),"a")
running on IDLE, i get the following error:
Traceback (most recent call last):
File "C:/Python23/practices/serialnewesttes3.py", line 65, in -toplevel-
table_file = open(os.path.normpath(filename),"a")
IOError: [Errno 2] No such file or directory: 'C:\\Documents and
Settings\nyer\\My Documents\\Info200503161153.txt'
it seems that it adds "\".
On Tue, 15 Mar 2005 19:45:31 -0500, Jacob S. <[EMAIL PROTECTED]> wrote:
>
>
> > that is exactly what i am looking for, but how would i add this to my
> > filename???
> > should i use this:
> >
> > output_file = open(os.path.join(self.Save_Session.GetValue(),
> > time.strftime('%Y%m%d%H%M')), 'w')
> >
> > the self.Save_Session.GetValue() is generated by a dirdialog
> >
>
> Uck,uck, uck, no...
>
> That's what Kent's post was for...
> This will do the trick.
>
> filename = "%s%s.txt" %
> (self.Save_Session.GetValue(),time.strftime("%Y%m%d%H%M"))
> output_file = open(filename,"a")
>
> This uses string formatting, are you familiar with that?
>
> If not -- see here http://docs.python.org/lib/typesseq-strings.html#l2h-211
> remember, if you don't understand--not that you wouldn't--you can always ask
> here.
>
> HTH,
> Jacob
>
>
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
that is exactly what i am looking for, but how would i add this to my
filename???
should i use this:
output_file = open(os.path.join(self.Save_Session.GetValue(),
time.strftime('%Y%m%d%H%M')), 'w')
the self.Save_Session.GetValue() is generated by a dirdialog
Uck,uck, uck, no...
That's what Kent's post was for...
This will do the trick.
filename = "%s%s.txt" %
(self.Save_Session.GetValue(),time.strftime("%Y%m%d%H%M"))
output_file = open(filename,"a")
This uses string formatting, are you familiar with that?
If not -- see here http://docs.python.org/lib/typesseq-strings.html#l2h-211
remember, if you don't understand--not that you wouldn't--you can always ask
here.
HTH,
Jacob
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
that is exactly what i am looking for, but how would i add this to my
filename???
should i use this:
output_file = open(os.path.join(self.Save_Session.GetValue(),
time.strftime('%Y%m%d%H%M')), 'w')
the self.Save_Session.GetValue() is generated by a dirdialog
On Tue, 15 Mar 2005 09:41:35 -0600, C Smith <[EMAIL PROTECTED]> wrote:
>
> On Tuesday, Mar 15, 2005, at 05:01 America/Chicago,
> [EMAIL PROTECTED] wrote:
>
> > how am i going to change the filename automaticaly?
> > for example:
> > #every 5 minutes, i am going to create a file based on the
> > data above
> > for i in range(100)
> > output_file = file('c:/output' +.join(i) +'.txt', 'w')
> > #guess this won't work
> > output_file.writelines(lines)
> > output_file.close()
> >
>
> When faced with this problem, one of the tings that I liked to do was
> use a date stamp for the files. The time module has a function called
> strftime which allows you to use a template to create a string from the
> current time. (See the documentation of python module 'time' for more
> details.) e.g.
>
> ###
> >>> import time
> >>> time.strftime('%Y%m%d%H%M')
> '200503150934'
> ###
>
> This string can be added to your 'c:/output' rather than a generic
> number like i. Just to be safe you might want to check that the file
> doesn't already exist. The nice thing is that there should be few files
> that have this number added to them so the loop to get a valid name is
> going to succeed quickly.
>
> /c
>
>
> ___
> Tutor maillist - Tutor@python.org
> http://mail.python.org/mailman/listinfo/tutor
>
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
On Tuesday, Mar 15, 2005, at 05:01 America/Chicago,
[EMAIL PROTECTED] wrote:
how am i going to change the filename automaticaly?
for example:
#every 5 minutes, i am going to create a file based on the
data above
for i in range(100)
output_file = file('c:/output' +.join(i) +'.txt', 'w')
#guess this won't work
output_file.writelines(lines)
output_file.close()
When faced with this problem, one of the tings that I liked to do was
use a date stamp for the files. The time module has a function called
strftime which allows you to use a template to create a string from the
current time. (See the documentation of python module 'time' for more
details.) e.g.
###
>>> import time
>>> time.strftime('%Y%m%d%H%M')
'200503150934'
###
This string can be added to your 'c:/output' rather than a generic
number like i. Just to be safe you might want to check that the file
doesn't already exist. The nice thing is that there should be few files
that have this number added to them so the loop to get a valid name is
going to succeed quickly.
/c
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
jrlen balane wrote:
so for example, i have 5 arrays, i can do this (is this correct):
data1[1,2,3,4,5 (and so on)]
data2[1,2,3,4,5 (and so on)]
data3[1,2,3,4,5 (and so on)]
data4[1,2,3,4,5 (and so on)]
data5[1,2,3,4,5 (and so on)]
datas = [data1, data2, data3, data4, data5]
for data in datas:
lines.append('\t'.join(data) + '\n')
=
(supposed to be output)
1 234 5 ...
1 234 5 ...
1 234 5 ...
...
(but i want this output)
111 11
222 22
333 33
... ... ... ......
=
You need to reformat your data. zip() is handy for this. Given multiple lists as arguments, zip()
creates tuples from the first element of each list, the second element of each list, etc:
>>> a=[1,2,3]
>>> b=[11,22,33]
>>> zip(a, b)
[(1, 11), (2, 22), (3, 33)]
When all the source lists are themselves in a list, you can use the *args form
of argument passing:
>>> c=[a, b]
>>> c
[[1, 2, 3], [11, 22, 33]]
>>> zip(*c)
[(1, 11), (2, 22), (3, 33)]
So in your case this will do what you want:
for data in zip(*datas):
lines.append('\t'.join(data) + '\n')
If datas is large you might want to use itertools.izip() instead. zip() creates an intermediate list
while izip() creates an iterator over the new tuples, so it is more memory-efficient.
output_file = file('c:/output.txt', 'w')
output_file.writelines(lines)
output_file.close()
=
how am i going to change the filename automaticaly?
for example:
#every 5 minutes, i am going to create a file based on the data above
for i in range(100)
output_file = file('c:/output' +.join(i) +'.txt', 'w')
#guess this won't work
output_file.writelines(lines)
output_file.close()
Two ways to do this:
>>> for i in range(5):
... print 'c:/output' + str(i) + '.txt'
... print 'c:/output%d.txt' % i
...
c:/output0.txt
c:/output0.txt
c:/output1.txt
c:/output1.txt
...
Kent
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
On Mar 15, 2005, at 03:35, jrlen balane wrote:
how am i going to change the filename automaticaly?
for example:
#every 5 minutes, i am going to create a file based on the
data above
for i in range(100)
output_file = file('c:/output' +.join(i) +'.txt', 'w')
#guess this won't work
output_file.writelines(lines)
output_file.close()
I'm not going to give you a complete solution because that'd spoil the
fun, but you need to use the os.path.exists function (in the os
module), which tells you if a file exists or not (no need to open it --
actually, your loop is dangerous: opening a file with "w" as the mode
erases it).
As for generating the file name, you've almost got it. Just remove
that bizarre call to "join", cause that won't work, and replace your
for loop with a while loop, so that you can break out of it when you've
found the correct file name, not before or after.
-- Max
maxnoel_fr at yahoo dot fr -- ICQ #85274019
"Look at you hacker... A pathetic creature of meat and bone, panting
and sweating as you run through my corridors... How can you challenge a
perfect, immortal machine?"
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
so for example, i have 5 arrays, i can do this (is this correct):
data1[1,2,3,4,5 (and so on)]
data2[1,2,3,4,5 (and so on)]
data3[1,2,3,4,5 (and so on)]
data4[1,2,3,4,5 (and so on)]
data5[1,2,3,4,5 (and so on)]
datas = [data1, data2, data3, data4, data5]
for data in datas:
lines.append('\t'.join(data) + '\n')
=
(supposed to be output)
1 234 5 ...
1 234 5 ...
1 234 5 ...
...
(but i want this output)
111 11
222 22
333 33
... ... ... ......
=
output_file = file('c:/output.txt', 'w')
output_file.writelines(lines)
output_file.close()
=
how am i going to change the filename automaticaly?
for example:
#every 5 minutes, i am going to create a file based on the data above
for i in range(100)
output_file = file('c:/output' +.join(i) +'.txt', 'w')
#guess this won't work
output_file.writelines(lines)
output_file.close()
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
On Sun, 13 Mar 2005, Brian van den Broek wrote:
> jrlen balane said unto the world upon 2005-03-13 19:37:
> > so for example, i am creating a text file with file.write()
> >
> > how am i going to make the file a tab-delimited file??? any
> > parameters needed???
> >
>
> >>> record1 = ['Foo', 'Bar', 'Baz']
> >>> record2 = ['Ham', 'Spam', 'Eggs']
> >>> records = [record1, record2]
> >>> lines = []
> >>> for record in records:
> ... lines.append('\t'.join(record) + '\n')
> ...
The 'csv' module might also be really handy here. For example, we can
adapt the code from:
http://www.python.org/doc/lib/node617.html
Let me write Brian's example with 'csv', just to show how it works.
##
>>> record1 = ['Foo', 'Bar', 'Baz']
>>> record2 = ['Ham', 'Spam', 'Eggs']
>>> import sys
>>> writer = csv.writer(sys.stdout)
>>> for row in [record1, record2]:
... writer.writerow(row)
...
Foo,Bar,Baz
Ham,Spam,Eggs
##
By default, the 'csv' writer uses commas as separators, but we can set the
'dialect' of a csv writer to the 'excel-tab' dialect, which uses tabs as
delimiters:
##
>>> writer = csv.writer(sys.stdout, dialect='excel-tab')
>>> for row in [record1, record2]:
... writer.writerow(row)
...
Foo Bar Baz
Ham SpamEggs
##
I hope this helps!
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
jrlen balane said unto the world upon 2005-03-13 19:37:
so for example, i am creating a text file with file.write()
how am i going to make the file a tab-delimited file??? any
parameters needed???
>>> record1 = ['Foo', 'Bar', 'Baz']
>>> record2 = ['Ham', 'Spam', 'Eggs']
>>> records = [record1, record2]
>>> lines = []
>>> for record in records:
... lines.append('\t'.join(record) + '\n')
...
>>> lines
['Foo\tBar\tBaz\n', 'Ham\tSpam\tEggs\n']
>>> output_file = file('c:/output.txt', 'w')
>>> output_file.writelines(lines)
>>> output_file.close()
>>>
HTH,
Brian vdB
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
specifically, I want to write an array in to a text file, how am i going to make the file a tab-delimited file??? On Mon, 14 Mar 2005 08:37:35 +0800, jrlen balane <[EMAIL PROTECTED]> wrote: > so for example, i am creating a text file with > file.write() > > how am i going to make the file a tab-delimited file??? any parameters > needed??? > > > On Sun, 13 Mar 2005 15:59:46 -0800 (PST), Danny Yoo > <[EMAIL PROTECTED]> wrote: > > > > > > On Sun, 13 Mar 2005, jrlen balane wrote: > > > > > what does a tab delimited filename mean? how am i going to make this? > > > also how does it differs from space delimited, csv, and others? > > > > Hello, > > > > As Kent mentioned, you probably mean "tab delimited file", which means a > > file whose lines are split up into columns. Each column is separated by a > > tab, which, in theory, should make it easy to parse. > > > > The main difference between a tab-delimited file and the others you > > mention is the "delimiter", the separator that's chosen to break columns > > apart. > > > > By the way, you might be interested in: > > > > http://www.faqs.org/docs/artu/ch05s02.html#id2901882 > > > > which talks a lot more about file formats in Unix and their relative > > strengths and weaknesses. > > > > Best of wishes to you! > > > > > ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
so for example, i am creating a text file with file.write() how am i going to make the file a tab-delimited file??? any parameters needed??? On Sun, 13 Mar 2005 15:59:46 -0800 (PST), Danny Yoo <[EMAIL PROTECTED]> wrote: > > > On Sun, 13 Mar 2005, jrlen balane wrote: > > > what does a tab delimited filename mean? how am i going to make this? > > also how does it differs from space delimited, csv, and others? > > Hello, > > As Kent mentioned, you probably mean "tab delimited file", which means a > file whose lines are split up into columns. Each column is separated by a > tab, which, in theory, should make it easy to parse. > > The main difference between a tab-delimited file and the others you > mention is the "delimiter", the separator that's chosen to break columns > apart. > > By the way, you might be interested in: > > http://www.faqs.org/docs/artu/ch05s02.html#id2901882 > > which talks a lot more about file formats in Unix and their relative > strengths and weaknesses. > > Best of wishes to you! > > ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
On Sun, 13 Mar 2005, jrlen balane wrote: > what does a tab delimited filename mean? how am i going to make this? > also how does it differs from space delimited, csv, and others? Hello, As Kent mentioned, you probably mean "tab delimited file", which means a file whose lines are split up into columns. Each column is separated by a tab, which, in theory, should make it easy to parse. The main difference between a tab-delimited file and the others you mention is the "delimiter", the separator that's chosen to break columns apart. By the way, you might be interested in: http://www.faqs.org/docs/artu/ch05s02.html#id2901882 which talks a lot more about file formats in Unix and their relative strengths and weaknesses. Best of wishes to you! ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] creating a tab delimited filename
jrlen balane wrote: what does a tab delimited filename mean? how am i going to make this? also how does it differs from space delimited, csv, and others? I think you probably mean "tab-delimited file", not "filename". A tab-delimited file is similar to a space-delimited file. It is typically a record-oriented text file with one record per line, with fields of a record separated by tabs. Like space-delimited files, this is a very easy format to read and write. Kent can't really find an article that could put me in the right direction so i posted here. thanks in advance. ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] creating a tab delimited filename
what does a tab delimited filename mean? how am i going to make this? also how does it differs from space delimited, csv, and others? can't really find an article that could put me in the right direction so i posted here. thanks in advance. ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
