Logesh Pillay said unto the world upon 10/01/06 11:28 PM:
Hello list
I want to declare a list of a specific size as global to some nested
function like so
Hi Logesh,
what problem are you trying to solve by doing this? Knowing that will
help generate more useful answers, I suspect.
def foo (n):
A[] (of size n)
def foo1
...
The only way I can think to declare the list is to use dummy values:
A = [0] * n
A = [] * n doesn't work. [] * n = []
A = [None] * n
would be a better way to created an n-placed list of dummy values in
Python, I think.
I'd prefer not to use dummy values I have no use for. Is there any
way?
This is why knowing your problem would be helpful. Built-in Python
data structures don't have size limitations that are declared when an
instance of the data structure is created. (Python's not C.) There is
no way (that I know of) to create an n-placed list save creating a
list with n objects.
So, I think you will have to either give up on not employing dummy
values or give up on creating a list of a fixed length.
You could subclass list to create a class with a max. and/or min.
length, but I think knowing more about what you want to do would be
helpful before getting into that :-)
Best,
Brian vdB
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