lmac wrote:
Hi there,
i want to use an long int from an list which i got from my function
find_lineno().
But i got this error and i don't understand why i can not use this long
as an argument.
You have the arguments to file.seek() reversed.
Where do i find a good documentation on errors so that i complete
understand what
the heck is going on.
From http://docs.python.org/lib/bltin-file-objects.html
seek( offset[, whence])
Set the file's current position, like stdio's fseek(). The whence argument
is optional and defaults to 0 (absolute file positioning); other values are 1
(seek relative to the current position) and 2 (seek relative to the file's
end).
Kent
Many thanks.
ERROR:
---
Traceback (most recent call last):
File ./extrmails.py, line 42, in ?
inputfile.seek(0,li)
IOError: [Errno 22] Invalid argument
---
CODE-START:
-
inputfile=open(mails,rt)
# --
def reset_inputfile():
inputfile.seek(0,0)
# --
def find_lineno(string):
f = -1
a = start
found_lines = []
reset_inputfile()
while len(a) != 0:
a = inputfile.readline()
f = a.find(string)
if f != -1:
found_lines.append(inputfile.tell())
return found_lines
# --
from_lineno=find_lineno(From:)
subj_lineno=find_lineno(Subject:)
print len(subj_lineno)
print len(from_lineno)
reset_inputfile()
for li in subj_lineno:
inputfile.seek(0,li)-- ???
...
..
--
CODE-END
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