Re: [Tutor] nonlocal variables

[Vladislav Vorobyov]

2010/2/23 Hugo Arts 

> On Tue, Feb 23, 2010 at 1:38 PM, Vladislav Vorobyov
>  wrote:
> > #!/usr/bin/python
> > def func_outer():
> > x = 2
> > print('x is', x)
> > def func_inner():
> > nonlocal x
> > x = 5
> > func_inner()
> > print('Changed local x to', x)
> >
> > func_outer()
> >
> > Output:
> > File "nonlocal_var.py", line 6
> > nonlocal x
> >  ^
> > SyntaxError: invalid syntax
> > Why? Cannon find in google it.
> >
>
> check your python version. The nonlocal keyword is only supported in python
> 3.x
>
> Hugo
>
O! Thank. I'm reading "Byte of Python". Didn't look about what version of
python is it.
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Re: [Tutor] nonlocal variables

[Hugo Arts]

On Tue, Feb 23, 2010 at 1:38 PM, Vladislav Vorobyov
 wrote:
> #!/usr/bin/python
> def func_outer():
>     x = 2
>     print('x is', x)
>     def func_inner():
>     nonlocal x
>     x = 5
>     func_inner()
>     print('Changed local x to', x)
>
> func_outer()
>
> Output:
> File "nonlocal_var.py", line 6
>     nonlocal x
>  ^
> SyntaxError: invalid syntax
> Why? Cannon find in google it.
>

check your python version. The nonlocal keyword is only supported in python 3.x

Hugo
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[Tutor] nonlocal variables

[Vladislav Vorobyov]

#!/usr/bin/python
def func_outer():
x = 2
print('x is', x)
def func_inner():
nonlocal x
x = 5
func_inner()
print('Changed local x to', x)

func_outer()

Output:
File "nonlocal_var.py", line 6
nonlocal x
 ^
SyntaxError: invalid syntax
Why? Cannon find in google it.
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