Ian Witham wrote:
This looks like a job for List Comprehensions!
list = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
new_list = [item[1] for item in list]
new_list
[2, 5, 8]
Alternately, if you want *all* columns, you can use zip() to transpose
the lists:
In [1]: lst = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
In [2]: zip(*lst)
Out[2]: [(1, 4, 7), (2, 5, 8), (3, 6, 9)]
PS. Don't use 'list' as the name of a list, it shadows the builtin
'list' which is the type of list. Similarly, avoid str, dict, set and
file as names.
Kent
looks good?
Ian
On 8/21/07, *Orest Kozyar* [EMAIL PROTECTED]
mailto:[EMAIL PROTECTED] wrote:
I've got a 2D list (essentially a list of lists where all sublists
are of
the same length). The sublists are polymorphic. One 2D list I
commonly
work with is:
[ [datetime object, float, int, float],
[datetime object, float, int, float],
[datetime object, float, int, float] ]
I'd like to be able to quickly accumulate the datetime column into a
list.
Is there a simple/straightforward syntax (such as list[:][0]) to do
this, or
do we need to use a for loop? I expect what I have in mind is
similar to
the Python array type, except it would be polymorphic.
Thanks,
Orest
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