Re: [Tutor] Creating a list from other lists
It's an HTML post. Not according to the version of Thunderbird I am using, which shows it as a plain text email. I suspect that the HTML attachment may be invalid HTML, understandable by Gmail and possibly nothing else. Typical of Google :( Looking at the email source it clearly shows as being mimetype multipart with both a plaintext and HTML part. I don't think you can much criticise GMail for interpreting and attempting to render an HTML email as HTML. The biggest culprit here IMHO was the sending mail client that generated a broken text mode version of the email's intended formatting by dropping the indentation (and if the HTML is broken, generated broken HTML to boot as well.) Walter ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Creating a list from other lists
On 23/10/12 19:51, Walter Prins wrote: It's an HTML post. Not according to the version of Thunderbird I am using, which shows it as a plain text email. I suspect that the HTML attachment may be invalid HTML, understandable by Gmail and possibly nothing else. Typical of Google :( Looking at the email source it clearly shows as being mimetype multipart with both a plaintext and HTML part. I don't think you can much criticise GMail for interpreting and attempting to render an HTML email as HTML. Perhaps not, but I can criticize Gmail for offering such an anti-feature in the first place. The biggest culprit here IMHO was the sending mail client That would be Gmail, almost certainly. that generated a broken text mode version of the email's intended formatting by dropping the indentation (and if the HTML is broken, generated broken HTML to boot as well.) I don't actually know if the HTML part is broken or not. I saved it and opened it in Firefox, and Firefox rendered it as raw text showing the tags. Perhaps that just means my test was faulty. Either way though, I'm sick to the back teeth of Google-related technologies being user hostile. Whether it is the horror that Google Groups has become, Google's search engine tracking and bubbling you when you search, Google illegally installing tracking cookies AND THEN LYING ABOUT IT to the American FTC, the awfulness of their image search interface (which just about every search engine now apes), and their efforts to link everything you do on the Internet to a Google account which can be matched to your offline identity, I think their motto is now best described as Do be evil. -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Creating a list from other lists
On Tue, Oct 23, 2012 at 4:51 AM, Walter Prins wpr...@gmail.com wrote: Looking at the email source it clearly shows as being mimetype multipart with both a plaintext and HTML part. I don't think you can much criticise GMail for interpreting and attempting to render an HTML email as HTML. The biggest culprit here IMHO was the sending mail client that generated a broken text mode version of the email's intended formatting by dropping the indentation (and if the HTML is broken, generated broken HTML to boot as well.) The message looks to have been sent with Gmail's webmail client. The problem I think starts with Webkit. When the user presses tab in a rich text box, instead of tabbing between fields on the page, it inserts a span class=Apple-tab-span stylewhite-space:pre element. I tested how Gmail handles this by creating a simple HTML file containing the following: divfor x, y , z in zip(a, b, c):/divdivspan class=Apple-tab-span style=white-space:pre /spanL.extend([x, y, z])/divdivspan class=Apple-tab-span style=white-space:pre/spanprint L/div I rendered this in Firefox and copied it into a new rich text email. Gmail stripped out the tab characters before rendering the plain text section as follows: for x, y , z in zip(a, b, c): L.extend([x, y, z]) print L They certainly could be smarter when it comes to spans with whitespace:pre styling, but it's better if users would just think to use plain text when posting code. That said, plain text with Gmail has its own pitfalls. To render it correctly with a monospace font in the web client you need to use something like Stylish to hack Gmail's CSS. But, more importantly, you have to be wise to Google's line wrapping at 69 characters (no RFC requires this). It doesn't give you a live preview. Instead you have to manually wrap code at 69 columns in an IDE and paste it into the text box. Otherwise your code will probably get mangled. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Creating a list from other lists
Hi Saad, On 22 October 2012 11:21, Saad Javed sbja...@gmail.com wrote: Hi, I'm trying to create a list (L) from items of different lists (a, b, c) but in a specific order (L = [[a1, b1, c1], [a2, b2, c2]...etc]) L = [] a = [1, 2, 3, 4] b = ['a', 'b', 'c', 'd'] c = [2009, 2010, 2011, 2012] for x, y , z in zip(a, b, c): L.extend([x, y, z]) print L But this outputs: [[1, 'a', 2009]] [[1, 'a', 2009], [2, 'b', 2010]] [[1, 'a', 2009], [2, 'b', 2010], [3, 'c', 2011]] [[1, 'a', 2009], [2, 'b', 2010], [3, 'c', 2011], [4, 'd', 2012]] I just want L = [[1, 'a', 2009], [2, 'b', 2010], [3, 'c', 2011], [4, 'd', 2012]] You've already asked essentially this question on another thread -- in general please don't start new threads for the same question but continue the discussion on the original question for the sake of continuity and avoiding wasting people's time. (New readers of the new question may not be aware of the previous discussion, and may expend time and energy addressing issues which have already been discussed in the previous question.) As for your problem: You're printing the list every iteration of the loop which is why your output looks the way it does. Instead put your print statement after the loop and you'll see the list you get after the loop is in fact what you say you want. However, that doesn't actually solve your problem, because you're putting the input data into the lists in sorted order already. You should jumble up your input data to ensure you also solve the sorting aspect of this problem (or use the input data from your original problem which was jumbled up enough already.) Hint, to deal with sorting your output list, refer to the list.sort() method and the key parameter. See also the Sorting HowTo on the PythonInfo wiki by Raymond Hettinger: http://wiki.python.org/moin/HowTo/Sorting/ Hope is enough to get you going, Walter ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Creating a list from other lists
On 22/10/12 21:21, Saad Javed wrote: Hi, I'm trying to create a list (L) from items of different lists (a, b, c) but in a specific order (L = [[a1, b1, c1], [a2, b2, c2]...etc]) L = [] a = [1, 2, 3, 4] b = ['a', 'b', 'c', 'd'] c = [2009, 2010, 2011, 2012] for x, y , z in zip(a, b, c): L.extend([x, y, z]) print L This is not your code, because that gives a SyntaxError. Where is the indentation? Indentation is required in Python, if you leave it out, your code will not work correctly. You should have either: # Option 1 for x, y , z in zip(a, b, c): L.extend([x, y, z]) print L which will extend the list four times, and print the list four times, once each time through the loop. Or: # Option 2 for x, y , z in zip(a, b, c): L.extend([x, y, z]) print L # this is not indented, so it is outside the loop Now the list only gets printed once, after the for loop has completely finished, and you don't see the intermediate results. But this outputs: [[1, 'a', 2009]] [[1, 'a', 2009], [2, 'b', 2010]] [[1, 'a', 2009], [2, 'b', 2010], [3, 'c', 2011]] [[1, 'a', 2009], [2, 'b', 2010], [3, 'c', 2011], [4, 'd', 2012]] I just want L = [[1, 'a', 2009], [2, 'b', 2010], [3, 'c', 2011], [4, 'd', 2012]] Then don't print the list four times, only print it once. -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Creating a list from other lists
On Mon, Oct 22, 2012 at 6:37 AM, Steven D'Aprano st...@pearwood.info wrote: On 22/10/12 21:21, Saad Javed wrote: for x, y , z in zip(a, b, c): L.extend([x, y, z]) print L This is not your code, because that gives a SyntaxError. Where is the indentation? Indentation is required in Python, if you leave it out, your code will not work correctly. It's an HTML post. Using these styled span tags never translates well to the text/plain section. div for x, y , z in zip(a, b, c): /div div span class=Apple-tab-span style=white-space:pre /span L.extend([x, y, z]) /div div span class=3DApple-tab-span style=3Dwhite-space:pre /span print L /div ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Creating a list from other lists
Hi Saad, On 22 October 2012 11:37, Steven D'Aprano st...@pearwood.info wrote: On 22/10/12 21:21, Saad Javed wrote: I'm trying to create a list (L) from items of different lists (a, b, c) but in a specific order (L = [[a1, b1, c1], [a2, b2, c2]...etc]) L = [] a = [1, 2, 3, 4] b = ['a', 'b', 'c', 'd'] c = [2009, 2010, 2011, 2012] for x, y , z in zip(a, b, c): L.extend([x, y, z]) print L This is not your code, because that gives a SyntaxError. Where is the indentation? Indentation is required in Python, if you leave it out, your code will not work correctly. You should have either: Just to note: For me your (Saad's) indentation showed perfectly fine on GMail. I'm note sure why Steven didn't see it (I think he reads only plaintext email), so I'd guess perhaps your email included both HTML and plain text parts and the plain text part perhaps had the indentation stripped out and the HTML did not. Anyway point being, it's best to post plain text if you're emailing unless you absolutely must use HTML, certainly this is the best way for this mailing list. Regards, Walter ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Creating a list from other lists
On 22/10/12 21:52, eryksun wrote: On Mon, Oct 22, 2012 at 6:37 AM, Steven D'Apranost...@pearwood.info wrote: On 22/10/12 21:21, Saad Javed wrote: for x, y , z in zip(a, b, c): L.extend([x, y, z]) print L This is not your code, because that gives a SyntaxError. Where is the indentation? Indentation is required in Python, if you leave it out, your code will not work correctly. It's an HTML post. Not according to the version of Thunderbird I am using, which shows it as a plain text email. I suspect that the HTML attachment may be invalid HTML, understandable by Gmail and possibly nothing else. Typical of Google :( -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
