Re: [Tutor] Help required
On 03/20/2013 02:12 AM, Arijit Ukil wrote: I am new to python. My intention is to read the file digi.txt and store in separate arrays all the values of each columns. However, the following program prints only the last value, i.e. 1350696500.0. Please help to rectify this. f = open (/digi.txt/, /r+/) datafile = f.readlines() list_of_lists = datafile fordata inlist_of_lists: lstval = data.split (/','/) timest = float(lstval[0]) energy = float(lstval[1]) f.close() printtimest Regards, Arijit Ukil You would want to create an empty list and then append values to it inside the loop. E.g. lst=[]; lst.append(val) -m -- Lark's Tongue Guide to Python: http://lightbird.net/larks/ ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Help required
On 20 March 2013 06:12, Arijit Ukil arijit.u...@tcs.com wrote:
I am new to python. My intention is to read the file digi.txt and store in
separate arrays all the values of each columns. However, the following
program prints only the last value, i.e. 1350696500.0.
Please help to rectify this.
f = open (digi.txt, r+)
datafile = f.readlines()
list_of_lists = datafile
for data in list_of_lists:
lstval = data.split (',')
timest = float(lstval[0])
energy = float(lstval[1])
f.close()
print timest
A few questions to ask yourself.
Is 'f' a descriptive name, equivalent to your other variable names?
What does your third line do, and do you think it's actually required?
What implications would it cause if you removed it?
How do you overcome those issues?
What value is stored in 'timest' the first iteration of the loop, the
second, the third? (Put a print statement in the loop to find out)
Are you actually doing anything with 'energy'?
Do you need to wait until after the loop to close your file?
HTH,
Bodsda
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Re: [Tutor] Help required
First up please give a sensible subject, say problem parsing csv file.
I'm assuming the crud shown below is due to you posting in html, please
use plain text instead.
On 20/03/2013 06:12, Arijit Ukil wrote:
I am new to python. My intention is to read the file digi.txt and store
in separate arrays all the values of each columns. However, the
following program prints only the last value, i.e. 1350696500.0.
Please help to rectify this.
f = open (/digi.txt/, /r+/)
You might like to use the with statement as it saves the explicit close
later. Do you really need update mode? I'll assume not.
with open('digi.txt', 'r') as f:
datafile = f.readlines()
datafile is a poor name, it's the contents of the file here not the file
itself.
list_of_lists = datafile
This gives another name for datafile which you only use in the for loop,
you can use datafile directly.
fordata inlist_of_lists:
lstval = data.split (/','/)
The csv module from the standard library can look after this for you.
timest = float(lstval[0])
energy = float(lstval[1])
You do nothing with timest and energy within the for loop.
f.close()
printtimest
You're printing the last value for timest here.
So you need something like the following, I'll leave you to look up the
csv module if you're interested.
with open('digi.txt', 'r') as f:
lines = f.readlines()
timestamps = []
energies = []
for line in lines:
splits = line.split(',') # I'll admit not the best name
timestamps.append(float(splits[0]))
energies.append(float(splits[1]))
# process timestamps and energies to your heart's content
Regards,
Arijit Ukil
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Re: [Tutor] Help required to count no of lines that are until 1000 characters
Dave Angel da...@ieee.org wrote But you have a serious bug in your code, that nobody in the first five responses has addressed. That while loop will loop over the first line repeatedly, till it reaches or exceeds 1000, regardless of the length of subsequent lines. Oooh, good catch, I completely missed that one! :-) Alan G ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Help required to count no of lines that are until 1000 characters
On Tue, May 11, 2010 at 1:00 PM, ramya natarajan nramy...@gmail.com wrote:
Hello, I have to read lines from
files exactly upto 1000 characters.
But the problem is its reading entire line and not stopping
excatly in 1000 characters. Can some one help what mistake i am doing here?.
log = open('/tmp/new.txt','r')
lines,char = 0,0
for line in log.readlines():
while char 1000 :
for ch in line :
char += len(ch)
lines += 1
print char , lines
here's the pseudocode of what you're doing, it might help you
understand what the problem is:
for every line in the file:
if the character count is less than 1000, add the length of the
current line.
You are missing a condition.
Here is another version of your code that has the same problem, see if
this helps make it clearer:
lines, chars = 0,0
with open('/temp/new.txt') as f:
for line in f:
if chars 1000: break
chars += len(line)
This sounds a lot like a homework problem so I won't give you the
answer, but I hope that helps.
Also do you realize you are counting newlines as well? You may not
want to do this, depending on your intended application.
Hope that helps,
-Luke
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Re: [Tutor] Help required to count no of lines that are until 1000 characters
On Tue, 11 May 2010 11:00:20 -0700
ramya natarajan nramy...@gmail.com wrote:
Hello,
I am very beginner to programming, I got task to Write a loop that reads
each line of a file and counts the number of lines that are read until the
total length of the lines is 1,000 characters. I have to read lines from
files exactly upto 1000 characters.
Here is my code:
I created file under /tmp/new.txt which has 100 lines and 2700 characters
, I wrote code will read exactly 1000 characters and count lines upto those
characters.But the problem is its reading entire line and not stopping
excatly in 1000 characters. Can some one help what mistake i am doing here?.
log = open('/tmp/new.txt','r')
lines,char = 0,0
for line in log.readlines():
while char 1000 :
for ch in line :
char += len(ch)
lines += 1
print char , lines
1026 , 38 Its counting entire line instead of character upto 1000
-- can some one point out what mistake am i doing here , where its not
stopping at 1000 . I am reading only char by car
My new.txt -- cotains content like
this is my new number\n
Can some one please help. I spent hours and hours to find issue but i am not
able to figure out, Any help would be greatly appreciated.
Thank you
Ramya
Either you read line per line, but then you cannot stop exactly at the 1000th
character; or you traverse the text char per char, but this is a bit picky.
I would read line per line, and when count = 1000, read chars inside current
line to get to the 1000th, if needed.
(Your specification does not state this, but your disappointment seems to be
about that issue ;-)
Denis
vit esse estrany ☣
spir.wikidot.com
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Re: [Tutor] Help required to count no of lines that are until 1000 characters
On 12-May-2010, at 12:32 AM, spir ☣ wrote:
On Tue, 11 May 2010 11:00:20 -0700
ramya natarajan nramy...@gmail.com wrote:
Hello,
I am very beginner to programming, I got task to Write a loop that reads
each line of a file and counts the number of lines that are read until the
total length of the lines is 1,000 characters. I have to read lines from
files exactly upto 1000 characters.
Here is my code:
I created file under /tmp/new.txt which has 100 lines and 2700 characters
, I wrote code will read exactly 1000 characters and count lines upto those
characters.But the problem is its reading entire line and not stopping
excatly in 1000 characters. Can some one help what mistake i am doing here?.
log = open('/tmp/new.txt','r')
lines,char = 0,0
for line in log.readlines():
while char 1000 :
for ch in line :
char += len(ch)
lines += 1
print char , lines
1026 , 38 Its counting entire line instead of character upto 1000
-- can some one point out what mistake am i doing here , where its not
stopping at 1000 . I am reading only char by car
My new.txt -- cotains content like
this is my new number\n
Can some one please help. I spent hours and hours to find issue but i am not
able to figure out, Any help would be greatly appreciated.
Thank you
Ramya
Either you read line per line, but then you cannot stop exactly at the 1000th
character; or you traverse the text char per char, but this is a bit picky.
I would read line per line, and when count = 1000, read chars inside current
line to get to the 1000th, if needed.
(Your specification does not state this, but your disappointment seems to be
about that issue ;-)
Denis
You can try read instead of readlines.
Something like...
print 'Number of lines till 1000th character:',
len(open('/tmp/new.txt','r').read(1000).split('\n'))
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Re: [Tutor] Help required to count no of lines that are until 1000characters
ramya natarajan nramy...@gmail.com wrote
characters.But the problem is its reading entire line and not stopping
excatly in 1000 characters.
Do you really need to stop reading the file at 1000 characters rather
than the line containing the 1000th character? That seems a very
arbitrary sort of thing to do.
Can some one help what mistake i am doing here?.
log = open('/tmp/new.txt','r')
lines,char = 0,0
for line in log.readlines():
while char 1000 :
for ch in line :
char += len(ch)
lines += 1
The problem is that the inner for loop will always process every
character in the line. You want to stop (or break) from the for loop
when char gets to 1000. So you need to insert a test inside the for
loop. Or don't use the for loop and use an index to get the characters
within your while loop.
BTW You don't want to add the length of the characters you just
want to add 1...
stopping at 1000 . I am reading only char by car
No you are not, you are reading all the chars in every line
that you read from the file. In fact even if you fix this loop
error you will still be reading the full line from the file.
Thats why I asked if you really had to stop reading the
file at 1000 chars, because if so this design is fundamentally
wrong.
But I suspect you only need to stop reading at the line
containing the 1000th char... If that is so there is an easier
way to do it:
# pseudo code
chars = 0
for count, line in enumerate(file)
if chars + len(line) 1000
chars += len(line)
else: break
print 1000 chars read in, count, lines
HTH,
--
Alan Gauld
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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Re: [Tutor] Help required to count no of lines that are until 1000 characters
spir ☣ denis.s...@gmail.com wrote Either you read line per line, but then you cannot stop exactly at the 1000th character; or you traverse the text char per char, but this is a bit picky. Or you could just read 1000 chars from the file then pick out the lines from that. But that requires you to count newlines as characters! :-) HTH, Alan G. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Help required to count no of lines that are until 1000 characters
ramya natarajan wrote:
Hello,
I am very beginner to programming, I got task to Write a loop that
reads
each line of a file and counts the number of lines that are read until
the
total length of the lines is 1,000 characters. I have to read lines from
files exactly upto 1000 characters.
Here is my code:
I created file under /tmp/new.txt which has 100 lines and 2700
characters
, I wrote code will read exactly 1000 characters and count lines upto
those
characters.But the problem is its reading entire line and not stopping
excatly in 1000 characters. Can some one help what mistake i am doing
here?.
log = open('/tmp/new.txt','r')
lines,char = 0,0
for line in log.readlines():
while char 1000 :
for ch in line :
char += len(ch)
lines += 1
print char , lines
1026 , 38 Its counting entire line instead of character upto
1000
-- can some one point out what mistake am i doing here , where its not
stopping at 1000 . I am reading only char by car
My new.txt -- cotains content like
this is my new number\n
Can some one please help. I spent hours and hours to find issue but i
am not
able to figure out, Any help would be greatly appreciated.
Thank you
Ramya
The problem is ill-specified (contradictory). It'd probably be better
to give the exact wording of the assignment.
If you read each line of the file, then it would only be a coincidence
if you read exactly 1000 characters, as most likely one of those lines
will overlap the 1000 byte boundary.
But you have a serious bug in your code, that nobody in the first five
responses has addressed. That while loop will loop over the first line
repeatedly, till it reaches or exceeds 1000, regardless of the length of
subsequent lines. So it really just divides 1000 by the length of that
first line. Notice that the lines += 1 will execute multiple times for
a single iteration of the for loop.
Second, once 1000 is reached, the for loop does not quit. So it will
read the rest of the file, regardless of how big the file is. It just
stops adding to lines or char, since char reached 1000 on the first line.
The simplest change to your code which might accomplish what you want is
to put the whole thing inside a function, and return from the function
when the goal is reached. So instead of a while loop, you need some
form of if test. See if you can run with that. Remember that return
can return a tuple (pair of numbers).
There are plenty of other optimizations and approaches, but you'll learn
best by incrementally fixing what you already have.
DaveA
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Re: [Tutor] Help required
Hi,
First of all thanks a lot for your reply. search.findall is not working. here
is my complete small program.
def getAcl(request, pg):
pged = PageEditor(request, pg)
pagetext = pged.get_raw_body()
search=re.compile(^#acl InternationalGroup.*\n, re.M).search(pagetext)
if search:
ret=search.group()
else:
ret='not defined'
return ret
def execute(macro, args):
html=pbACL List For International Group:/bbr
all={}
pages = macro.request.rootpage.getPageList()
for pagename in pages:
if Page(macro.request,pagename).isStandardPage():
all[Page(macro.request,
pagename).link_to(macro.request)]=getAcl(macro.request, pagename)
html+=table
all1=sorted(all.items())
for pg, ac in all1:
if ac != not defined:
html+=trtd%s/td % pg
html+=td%s/td/tr % ac
html+=/table
return macro.formatter.rawHTML(html)
Now i explain this.
I have some wiki pages(or you can say documents).
This python program is giving me list of all those pages, where i have written
#acl InternationalGroup:read line in the pages and these pages may have also
CatInternational line in the page.
Now i want to search all those pages, where i have NOT written #acl
InternationalGroup:read But i have written only CatInternational in the
page text.
I dont know how can i find only those pages where i have written only
CatInternational line in the page.
I shall be veryy thankful to you really for help.
Best Regards,
Waqas
Date: Fri, 25 Sep 2009 15:39:27 -0600
Subject: Re: [Tutor] Help required
From: vinces1...@gmail.com
To: waqas...@hotmail.com
CC: python-l...@python.org; tutor@python.org
On Fri, Sep 25, 2009 at 1:56 PM, waqas ahmad waqas...@hotmail.com wrote:
Hi,
I dont know it is the right place to post this question. I need help to change
one search code line . can you help me please.
here is my search method code:
search=re.compile(^#acl InternationalGroup.*\n, re.M).search(pagetext)
if search:
ret=search.group()
else:
ret='not defined'
return ret
here i am searching for #acl InternationalGroup in the pageText and when it
true is then give me search group.
I want to change this for following requirement:
I want to search for #acl InternationalGroup and CatInternational for
both in the pageText.
when #acl InternationalGroup is not there but only CatInternational is
there. then return me search group.
I shall be thankful to you for any help.
Best Regards,
Waqas
What can you do with the new Windows Live? Find out
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i think this is what you are looking for:
search=re.compile((#acl\sInternationalGroup|CatInternational).*\n,
re.M).search(pagetext)
if search:
ret=search.findall()
else:
ret='not defined'
return ret
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Re: [Tutor] Help required
On Fri, Sep 25, 2009 at 1:56 PM, waqas ahmad waqas...@hotmail.com wrote: Hi, I dont know it is the right place to post this question. I need help to change one search code line . can you help me please. here is my search method code: search=re.compile(^#acl InternationalGroup.*\n, re.M).search(pagetext) if search: ret=search.group() else: ret='not defined' return ret here i am searching for #acl InternationalGroup in the pageText and when it true is then give me search group. I want to change this for following requirement: I want to search for #acl InternationalGroup and CatInternational for both in the pageText. when #acl InternationalGroup is not there but only CatInternational is there. then return me search group. I shall be thankful to you for any help. Best Regards, Waqas -- What can you do with the new Windows Live? Find outhttp://www.microsoft.com/windows/windowslive/default.aspx ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor i think this is what you are looking for: search=re.compile((#acl\sInternationalGroup|CatInternational).*\n, re.M).search(pagetext) if search: ret=search.findall() else: ret='not defined' return ret ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
