Re: [Tutor] Iterating over letters or arbitrary symbols like they were numbers...
On Wed, Mar 18, 2009 at 5:26 PM, Alexander Daychilde (Gmail) wrote: > exp_list = [] > > exp_range = exp.split(":") > > min_padding = len(exp_range[0]) > > for i in range(int(exp_range[0]),(int(exp_range[1])+1)): > > exp_list.append('%0*d' % (min_padding, i)) This could be a little cleaner using tuple assignment to get rid of the subscripting and list comprehension to get rid of the loop: lower, upper = exp.split(':') min_padding = len(lower) exp_list = [ '%0*d' % (min_padding, i) for in in range(int(lower), int(upper)+1) ] Kent ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Iterating over letters or arbitrary symbols like they were numbers...
2009/3/19 Alexander Daychilde (Gmail) : > That creates a list of numbers. I also need to do letters. That is, treat > a-z as base 26, and do the same thing. The three examples I gave from before > would be: > 1:9 --> a:z > 1:99 --> a:zz > 01:99 -- no "zero" in alpha to worry about, so no padding > necessary... > > So my first question is: Can I somehow treat letters like base 26? > > If I can, what about alphanumeric, i.e. 0-9+a-z would be like base 36... The int() function takes a second parameter, which is the base. This is so that it can deal with hex strings -- for example, int('7a', 16) == 122. But the base can actually be anything up to 36. For converting a base n string to an integer, the digits are the first n elements of '0123456789abcdefghijklmnopqrstuvwxyz'. To go the other way, I had a quick poke around in the python cookbook and found this one-liner: def baseN(num,b,numerals="0123456789abcdefghijklmnopqrstuvwxyz"): return ((num == 0) and "0" ) or ( baseN(num // b, b).lstrip("0") + numerals[num % b]) You may be able to find better ones. If you want to convert 'a'..'z' to integers by treating them as base-26 numbers.. it could be tricky because you (I think) have no 0. Multiplication without a 0 is really quite tricky :-) You might be better off writing a function to take one "integer" (e.g. 'ghzz') and produce the next one ('giaa'). Or you could cheat :-) >>> import string >>> letters = string.lowercase >>> pairs = [''.join([a,b]) for a in letters for b in letters] >>> threes = [''.join([a,b,c]) for a in letters for b in letters for c in >>> letters] >>> fours = [''.join([a,b,c,d]) for a in letters for b in letters for c in >>> letters for d in letters] >>> words = list(letters) + pairs + threes + fours >>> def wcmp(x,y): ... if len(x) < len(y): ... return -1 ... elif len(x) > len(y): ... return 1 ... else: ... return cmp(x,y) ... >>> words.sort(cmp=wcmp) >>> words[words.index('a'):words.index('bb')+1] ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'aa', 'ab', 'ac', 'ad', 'ae', 'af', 'ag', 'ah', 'ai', 'aj', 'ak', 'al', 'am', 'an', 'ao', 'ap', 'aq', 'ar', 'as', 'at', 'au', 'av', 'aw', 'ax', 'ay', 'az', 'ba', 'bb'] Note that this is not very practical if your words can get out to five characters.. -- John. ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Iterating over letters or arbitrary symbols like they were numbers...
Title: Signature.html It looks like you used the wrong thread to post this. It's connected to questions about linux and Win, and not iterations. Alexander Daychilde (Gmail) wrote: If there's an easy way to do this, I'd like to have a pointer to it (i.e. what functions would deal with this - not wanting my code written for me...) Right now, I have written code to generate a list of strings that happen to be a range of numbers. (The fact that they're strings is actually desirable to me). My code looks at the range given to the function and zero-pads based on the length of the start of the range. Ranges are indicated by number-colon-number, e.g. 1:9 or 01:99 or 1:99. (for reasons outside this snippet of code, I refer to these as "expressions" or "exp" for short...) Here's the code in question: __ exp_list = [] exp_range = exp.split(":") min_padding = len(exp_range[0]) for i in range(int(exp_range[0]),(int(exp_range[1])+1)): exp_list.append('%0*d' % (min_padding, i)) __ (in fact, I'm *actually* parsing something like n(1:9;13;15;17:25) - so I have multiple ranges and individual numbers to add to exp_list[], so in my actual code, the list exists elsewhere, and this code is executed if I find a colon in an element in the list created from splitting the original line on commas (and removing the n and parentheses) - hope that makes sense) I'm quite proud of that - for the level of programming I feel I'm at, I thought it was somewhat clever. ;-) But I'm open to feedback on that... BUT, here's what I need to do: That creates a list of numbers. I also need to do letters. That is, treat a-z as base 26, and do the same thing. The three examples I gave from before would be: 1:9 --> a:z 1:99 --> a:zz 01:99 -- no "zero" in alpha to worry about, so no padding necessary... So my first question is: Can I somehow treat letters like base 26? If I can, what about alphanumeric, i.e. 0-9+a-z would be like base 36... Am I stuck rolling my own arithmetic-type function? (i.e. z+a=aa and z+b=ab, etc) Thank you very much for any advice (and again, in addition to my actual question, I wouldn't mind hearing if my solution for the numbers is less clever than I thought-- i.e. not looking for praise; rather, looking for improvement if it's glaringly dumb) ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor -- Wayne Watson (Watson Adventures, Prop., Nevada City, CA) (121.01 Deg. W, 39.26 Deg. N) GMT-8 hr std. time) “Life is one damn thing after another." -- Mark Twain ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor