One way you could do this is to call /users/show. If the user exists
their details will be returned, if not, you will get a 404 or 403
error (Suspended users are returned as a 403 error). You can find out
more about /users/show on our developer resources site:
http://dev.twitter.com/doc/get/users/show
The /users/show request is rate limited so you will want to be careful
about the number of requests you make.
Hope that helps,
Matt
On Sat, Aug 28, 2010 at 5:46 PM, Sujit Kumar Garikipati
garikipati.sujitku...@gmail.com wrote:
You can refer to this library, written by @abraham to learn using OAuth
authorization in PHP.
http://twitteroauth.labs.poseurtech.com/connect.php
On Sat, Aug 28, 2010 at 7:15 AM, computerzworld meat2...@gmail.com wrote:
Hi, I have created application that fetches users' tweets from his/her
user account. I want to validate the username using php ajax when he/
she is entering in the textbox. Is there any way using which I can get
response whether user have entered valid username or not? Please help
me. Thanks in advance.
--
Twitter developer documentation and resources: http://dev.twitter.com/doc
API updates via Twitter: http://twitter.com/twitterapi
Issues/Enhancements Tracker:
http://code.google.com/p/twitter-api/issues/list
Change your membership to this group:
http://groups.google.com/group/twitter-development-talk?hl=en
--
Twitter developer documentation and resources: http://dev.twitter.com/doc
API updates via Twitter: http://twitter.com/twitterapi
Issues/Enhancements Tracker:
http://code.google.com/p/twitter-api/issues/list
Change your membership to this group:
http://groups.google.com/group/twitter-development-talk?hl=en
--
Matt Harris
Developer Advocate, Twitter
http://twitter.com/themattharris
--
Twitter developer documentation and resources: http://dev.twitter.com/doc
API updates via Twitter: http://twitter.com/twitterapi
Issues/Enhancements Tracker: http://code.google.com/p/twitter-api/issues/list
Change your membership to this group:
http://groups.google.com/group/twitter-development-talk?hl=en
