Re[2]: [twsocket] Receive result of the first ReceiveStr() call twice-not resolved
Hello Francois,
Thanks for the quick reply. You are right. I should check in
the code. But in this particular test environment, I am receiving
HTTP/1.x. This I checked from the log.
I looked at the httpcli code briefly yesterday but failed to
find the part that parses the http headers (I know it should be there.)
I have been displaying the logs in a TMemo and yes, I do receive
a part of the string twice as shown in the log. I didn't call any
of the functions you mentioned in your earlier emails about what
could mess up the message pump.
I have further stripped the test project - very simple now.
I will email it to you. Please take a look when you have time.
BTW, are attachments allowed here, or should I send you a private mail?
--
Best regards,
Jack
Thursday, June 2, 2005, 6:43:30 AM, you wrote:
To avoid difficulties, you should first correctly write your
GetHTTPReponseStatusCode function to
correctly parse the answer. You should not simply remove
HTTP/1.1 but actually check you really
have that string. I'm sure you think you receive data twice while
you aren't. You think you receive
it twice because you don't parse it correctly and you overlooked
the mechanism that makes TCP stream
split into several packets and OnDataAvailable events.
You can have look at the HTTP client component source code (if
you don't want to use it, look at the
code and copy what you need to reinvent your wheel).
Use OutputDebugString to display what you receive in your
OnDataAvailable event. You'll see that you
never receive data twice, unless you mess up with the message pump.
--
[EMAIL PROTECTED]
Auteur du freeware ICS - Internet Component Suite
Auteur du freeware MidWare - Multi-tiers framework
http://www.overbyte.be
- Original Message -
From: Jack [EMAIL PROTECTED]
To: ICS support mailing twsocket@elists.org
Sent: Thursday, June 02, 2005 12:39 AM
Subject: Re: [twsocket] Receive result of the first ReceiveStr() call
twice-not resolved
This problem is still bugging me. I did some further testing
and find some strange things. In the OnDataAvailable event
handler, I call the function below to get HTTP status code.
The HttpReply is the string variable I get from ReceiveStr() call.
I find that as long as I call this function, I get a part of
the HTTP reply twice from ReceiveStr() call. Further testing
shows that this line is teh culprit:
Result := StrToInt(s);
If I comment out this line, I don't have a problem (then I don't
get a result from the function either.)
Any ideas? (Below is the whole function.)
function GetHTTPReponseStatusCode(const HttpReply: String): Integer;
var i: Integer; s: String;
begin
Result := -1;
i := Pos(' ', HttpReply);
if i 0 then
begin
s := Copy(HttpReply, i + 1, Length(HttpReply)); // Remove HTTP/1.1 at
the beginning
i := Pos(' ', s); // Remove the trailing text
if i 0 then
begin
s := Copy(s, 1, i - 1);
Result := StrToInt(s);
end;
end;
end;
--
Best regards,
Jack
I celebrated a little too early. I am getting this problem again
in further testing after I changed Close() to CloseDelayed();
The difference is, I'm not getting result of the first ReceiveStr()
twice. Instead, I get the result of the second ReceiveStr() twice.
I think this is because CloseDelayed() delayed the Close().
What I don't understand is why the buffer isn't cleared after
ReceiveStr() in both scenarios of Close() and CloseDelayed().
I reason I thought it was fixed is because I tested from
an allowed IP earlier and got a very short response back from
the proxy server. The whole message was retrieved in the first
ReceiveStr() call so I didn't get a chance to call ReceiveStr()
twice. I then run the same app on a blocked IP. The proxy sends
a longer message (the error message) and it is retrieved in
two ReceiveStr() calls. Then I found that the second ReceiveStr()
result was duplicated.
--
Best regards,
Jack
Thursday, May 19, 2005, 10:53:49 AM, you wrote:
J Francois, thanks! This fixed the problem! It's actually in the FAQ:
J - CloseDelayed
J Is in most cases the preferred way. It will post a message to
J itself to close the TWSocket. This means that the socket closure
J is done outside the code that calls the CloseDelayed, meaning a
J while later. The message handler will call Close.
J - Close
J Attempt to gracefully close the socket. If there is still some
J data waiting in the buffers it will try to send it. ***Do not use
J Close from within any TWSocket events, instead use CloseDelayed.***
J Thursday, May 19, 2005, 2:46:47 AM, you wrote:
FP Use CloseDelayed instead of Close.
Hello Wilfried,
Sure. Below is my event handler code. Hope I'm doing something
wrong, otherwise, it's really strange. TProxyChecker is the owner
object of the TProxySocket object array. TProxySocket is derived
from TWSocket
Re: [twsocket] Receive result of the first ReceiveStr() call twice -not resolved
This problem is still bugging me. I did some further testing
and find some strange things. In the OnDataAvailable event
handler, I call the function below to get HTTP status code.
The HttpReply is the string variable I get from ReceiveStr() call.
I find that as long as I call this function, I get a part of
the HTTP reply twice from ReceiveStr() call. Further testing
shows that this line is teh culprit:
Result := StrToInt(s);
If I comment out this line, I don't have a problem (then I don't
get a result from the function either.)
Any ideas? (Below is the whole function.)
function GetHTTPReponseStatusCode(const HttpReply: String): Integer;
var i: Integer; s: String;
begin
Result := -1;
i := Pos(' ', HttpReply);
if i 0 then
begin
s := Copy(HttpReply, i + 1, Length(HttpReply)); // Remove HTTP/1.1 at
the beginning
i := Pos(' ', s); // Remove the trailing text
if i 0 then
begin
s := Copy(s, 1, i - 1);
Result := StrToInt(s);
end;
end;
end;
--
Best regards,
Jack
I celebrated a little too early. I am getting this problem again
in further testing after I changed Close() to CloseDelayed();
The difference is, I'm not getting result of the first ReceiveStr()
twice. Instead, I get the result of the second ReceiveStr() twice.
I think this is because CloseDelayed() delayed the Close().
What I don't understand is why the buffer isn't cleared after
ReceiveStr() in both scenarios of Close() and CloseDelayed().
I reason I thought it was fixed is because I tested from
an allowed IP earlier and got a very short response back from
the proxy server. The whole message was retrieved in the first
ReceiveStr() call so I didn't get a chance to call ReceiveStr()
twice. I then run the same app on a blocked IP. The proxy sends
a longer message (the error message) and it is retrieved in
two ReceiveStr() calls. Then I found that the second ReceiveStr()
result was duplicated.
--
Best regards,
Jack
Thursday, May 19, 2005, 10:53:49 AM, you wrote:
J Francois, thanks! This fixed the problem! It's actually in the FAQ:
J - CloseDelayed
J Is in most cases the preferred way. It will post a message to
J itself to close the TWSocket. This means that the socket closure
J is done outside the code that calls the CloseDelayed, meaning a
J while later. The message handler will call Close.
J - Close
J Attempt to gracefully close the socket. If there is still some
J data waiting in the buffers it will try to send it. ***Do not use
J Close from within any TWSocket events, instead use CloseDelayed.***
J Thursday, May 19, 2005, 2:46:47 AM, you wrote:
FP Use CloseDelayed instead of Close.
Hello Wilfried,
Sure. Below is my event handler code. Hope I'm doing something
wrong, otherwise, it's really strange. TProxyChecker is the owner
object of the TProxySocket object array. TProxySocket is derived
from TWSocket.
procedure TProxyChecker.WSocketDataAvailable(Sender: TObject; ErrCode:
Word);
var s: String;
begin
if ErrCode = 0 then
with TProxySocket(Sender) do
begin
s := ReceiveStr();
Log(s);
Close();
end;
end;
The destination server is a commercial http proxy server.
I tried using #13#10 and #13#10#13#10, I different strings
read back from ReceiveStr. But the second string includes
the first string in both cases. So it shouldn't be the server
sending the string twice.
BTW, I'm using the latest ICS.
--
Best regards,
Jack
Wednesday, May 18, 2005, 3:31:32 PM, you wrote:
WM Hello Jack,
WM Can you show your OnDataAvailable handler ?
WM Eventually download SocketSpy from 'user made' page and 'hang' it
WM between client and server. Then you see exacly what is sent by
server.
WM ---
WM Rgds, Wilfried
WM http://www.mestdagh.biz
WM Wednesday, May 18, 2005, 20:48, Jack wrote:
Hello Francois and all,
I'm using a TWSocket client in LineMode with LineEnd set to #13#10.
I connect to a HTTP proxy server using CONNECT command. I then get
a reply back from the HTTP proxy from ReceiveStr()
Things look OK except that I am receiving the data from the first
ReceiveStr() call twice. I get two WSocketDataAvailable messages for
3 lines in the HTTP response:
Line 1: HTTP/1.0 200 Connection established
Line 2: Proxy-agent: Proxy+ 3.00
Line 3: (Blank line)
However, I'm getting the first ReceiveStr() result twice, see below:
I'm getting HTTP/1.0 200 Connection established twice:
5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480
ErrCode=0
5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established
5/18/2005 2:36:43 PM
5/18/2005 2:36:43 PM
5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480
ErrCode=0
5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established
Proxy-agent: Proxy+ 3.00
I then changed LineEnd to #13#10#13#10, I still get the result of
the
Re: [twsocket] Receive result of the first ReceiveStr() call twice -not resolved
I still persist saying the you probably call the message pump directly or indirectly (for example your Log() function, or any component you use for display). I suggest you make a stripped down version of your program, just he bare minimum in a small project. If the problem persist with this small project, make it available for download somewhere. If I have time, I'll look at it. -- Contribute to the SSL Effort. Visit http://www.overbyte.be/eng/ssl.html -- [EMAIL PROTECTED] Author of ICS (Internet Component Suite, freeware) Author of MidWare (Multi-tier framework, freeware) http://www.overbyte.be - Original Message - From: Jack [EMAIL PROTECTED] To: ICS support mailing twsocket@elists.org Sent: Thursday, May 19, 2005 9:31 PM Subject: [twsocket] Receive result of the first ReceiveStr() call twice -not resolved I celebrated a little too early. I am getting this problem again in further testing after I changed Close() to CloseDelayed(); The difference is, I'm not getting result of the first ReceiveStr() twice. Instead, I get the result of the second ReceiveStr() twice. I think this is because CloseDelayed() delayed the Close(). What I don't understand is why the buffer isn't cleared after ReceiveStr() in both scenarios of Close() and CloseDelayed(). I reason I thought it was fixed is because I tested from an allowed IP earlier and got a very short response back from the proxy server. The whole message was retrieved in the first ReceiveStr() call so I didn't get a chance to call ReceiveStr() twice. I then run the same app on a blocked IP. The proxy sends a longer message (the error message) and it is retrieved in two ReceiveStr() calls. Then I found that the second ReceiveStr() result was duplicated. -- Best regards, Jack Thursday, May 19, 2005, 10:53:49 AM, you wrote: J Francois, thanks! This fixed the problem! It's actually in the FAQ: J - CloseDelayed J Is in most cases the preferred way. It will post a message to J itself to close the TWSocket. This means that the socket closure J is done outside the code that calls the CloseDelayed, meaning a J while later. The message handler will call Close. J - Close J Attempt to gracefully close the socket. If there is still some J data waiting in the buffers it will try to send it. ***Do not use J Close from within any TWSocket events, instead use CloseDelayed.*** J Thursday, May 19, 2005, 2:46:47 AM, you wrote: FP Use CloseDelayed instead of Close. Hello Wilfried, Sure. Below is my event handler code. Hope I'm doing something wrong, otherwise, it's really strange. TProxyChecker is the owner object of the TProxySocket object array. TProxySocket is derived from TWSocket. procedure TProxyChecker.WSocketDataAvailable(Sender: TObject; ErrCode: Word); var s: String; begin if ErrCode = 0 then with TProxySocket(Sender) do begin s := ReceiveStr(); Log(s); Close(); end; end; The destination server is a commercial http proxy server. I tried using #13#10 and #13#10#13#10, I different strings read back from ReceiveStr. But the second string includes the first string in both cases. So it shouldn't be the server sending the string twice. BTW, I'm using the latest ICS. -- Best regards, Jack Wednesday, May 18, 2005, 3:31:32 PM, you wrote: WM Hello Jack, WM Can you show your OnDataAvailable handler ? WM Eventually download SocketSpy from 'user made' page and 'hang' it WM between client and server. Then you see exacly what is sent by server. WM --- WM Rgds, Wilfried WM http://www.mestdagh.biz WM Wednesday, May 18, 2005, 20:48, Jack wrote: Hello Francois and all, I'm using a TWSocket client in LineMode with LineEnd set to #13#10. I connect to a HTTP proxy server using CONNECT command. I then get a reply back from the HTTP proxy from ReceiveStr() Things look OK except that I am receiving the data from the first ReceiveStr() call twice. I get two WSocketDataAvailable messages for 3 lines in the HTTP response: Line 1: HTTP/1.0 200 Connection established Line 2: Proxy-agent: Proxy+ 3.00 Line 3: (Blank line) However, I'm getting the first ReceiveStr() result twice, see below: I'm getting HTTP/1.0 200 Connection established twice: 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 I then changed LineEnd to #13#10#13#10, I still get the result of the first ReceiveStr() twice, this time the result is two lines: HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 (Blank line) 5/18/2005 2:40:11 PM
Re[2]: [twsocket] Receive result of the first ReceiveStr() call twice -not resolved
Thanks Francois. I double-checked and didn't see any calls to ProcessMessages or ShowMessage, etc. I'll make a simplified version and send the code in private email. Jack Friday, May 20, 2005, 3:50:18 AM, you wrote: FP I still persist saying the you probably call the message pump FP directly or indirectly (for example FP your Log() function, or any component you use for display). FP I suggest you make a stripped down version of your program, FP just he bare minimum in a small project. FP If the problem persist with this small project, make it FP available for download somewhere. If I have FP time, I'll look at it. FP -- FP Contribute to the SSL Effort. Visit FP http://www.overbyte.be/eng/ssl.html FP -- FP [EMAIL PROTECTED] FP Author of ICS (Internet Component Suite, freeware) FP Author of MidWare (Multi-tier framework, freeware) FP http://www.overbyte.be FP - Original Message - FP From: Jack [EMAIL PROTECTED] FP To: ICS support mailing twsocket@elists.org FP Sent: Thursday, May 19, 2005 9:31 PM FP Subject: [twsocket] Receive result of the first ReceiveStr() call twice -not resolved I celebrated a little too early. I am getting this problem again in further testing after I changed Close() to CloseDelayed(); The difference is, I'm not getting result of the first ReceiveStr() twice. Instead, I get the result of the second ReceiveStr() twice. I think this is because CloseDelayed() delayed the Close(). What I don't understand is why the buffer isn't cleared after ReceiveStr() in both scenarios of Close() and CloseDelayed(). I reason I thought it was fixed is because I tested from an allowed IP earlier and got a very short response back from the proxy server. The whole message was retrieved in the first ReceiveStr() call so I didn't get a chance to call ReceiveStr() twice. I then run the same app on a blocked IP. The proxy sends a longer message (the error message) and it is retrieved in two ReceiveStr() calls. Then I found that the second ReceiveStr() result was duplicated. -- Best regards, Jack Thursday, May 19, 2005, 10:53:49 AM, you wrote: J Francois, thanks! This fixed the problem! It's actually in the FAQ: J - CloseDelayed J Is in most cases the preferred way. It will post a message to J itself to close the TWSocket. This means that the socket closure J is done outside the code that calls the CloseDelayed, meaning a J while later. The message handler will call Close. J - Close J Attempt to gracefully close the socket. If there is still some J data waiting in the buffers it will try to send it. ***Do not use J Close from within any TWSocket events, instead use CloseDelayed.*** J Thursday, May 19, 2005, 2:46:47 AM, you wrote: FP Use CloseDelayed instead of Close. Hello Wilfried, Sure. Below is my event handler code. Hope I'm doing something wrong, otherwise, it's really strange. TProxyChecker is the owner object of the TProxySocket object array. TProxySocket is derived from TWSocket. procedure TProxyChecker.WSocketDataAvailable(Sender: TObject; ErrCode: Word); var s: String; begin if ErrCode = 0 then with TProxySocket(Sender) do begin s := ReceiveStr(); Log(s); Close(); end; end; The destination server is a commercial http proxy server. I tried using #13#10 and #13#10#13#10, I different strings read back from ReceiveStr. But the second string includes the first string in both cases. So it shouldn't be the server sending the string twice. BTW, I'm using the latest ICS. -- Best regards, Jack Wednesday, May 18, 2005, 3:31:32 PM, you wrote: WM Hello Jack, WM Can you show your OnDataAvailable handler ? WM Eventually download SocketSpy from 'user made' page and 'hang' it WM between client and server. Then you see exacly what is sent by server. WM --- WM Rgds, Wilfried WM http://www.mestdagh.biz WM Wednesday, May 18, 2005, 20:48, Jack wrote: Hello Francois and all, I'm using a TWSocket client in LineMode with LineEnd set to #13#10. I connect to a HTTP proxy server using CONNECT command. I then get a reply back from the HTTP proxy from ReceiveStr() Things look OK except that I am receiving the data from the first ReceiveStr() call twice. I get two WSocketDataAvailable messages for 3 lines in the HTTP response: Line 1: HTTP/1.0 200 Connection established Line 2: Proxy-agent: Proxy+ 3.00 Line 3: (Blank line) However, I'm getting the first ReceiveStr() result twice, see below: I'm getting HTTP/1.0 200 Connection established twice: 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established Proxy-agent
Re: Re[4]: [twsocket] Receive result of the first ReceiveStr() call twice
Attempt to gracefully close the socket. If there is still some data waiting in the buffers it will try to send it. ***Do not use Close from within any TWSocket events, instead use CloseDelayed.*** You even have to call Shutdown(1) to really gracefully close the socket. Calling Shutdown will send the close request to the other side which in turn will close his side and then you receive the OnSessionClosed event. Be aware that if the remote side is hung, you may never receive the real close. You then must call Abort after a timeout of your choice. Contribute to the SSL Effort. Visit http://www.overbyte.be/eng/ssl.html -- [EMAIL PROTECTED] The author for the freeware multi-tier middleware MidWare The author of the freeware Internet Component Suite (ICS) http://www.overbyte.be - Original Message - From: Jack [EMAIL PROTECTED] To: ICS support mailing twsocket@elists.org Sent: Thursday, May 19, 2005 4:53 PM Subject: Re[4]: [twsocket] Receive result of the first ReceiveStr() call twice Francois, thanks! This fixed the problem! It's actually in the FAQ: - CloseDelayed Is in most cases the preferred way. It will post a message to itself to close the TWSocket. This means that the socket closure is done outside the code that calls the CloseDelayed, meaning a while later. The message handler will call Close. - Close Attempt to gracefully close the socket. If there is still some data waiting in the buffers it will try to send it. ***Do not use Close from within any TWSocket events, instead use CloseDelayed.*** Thursday, May 19, 2005, 2:46:47 AM, you wrote: FP Use CloseDelayed instead of Close. Hello Wilfried, Sure. Below is my event handler code. Hope I'm doing something wrong, otherwise, it's really strange. TProxyChecker is the owner object of the TProxySocket object array. TProxySocket is derived from TWSocket. procedure TProxyChecker.WSocketDataAvailable(Sender: TObject; ErrCode: Word); var s: String; begin if ErrCode = 0 then with TProxySocket(Sender) do begin s := ReceiveStr(); Log(s); Close(); end; end; The destination server is a commercial http proxy server. I tried using #13#10 and #13#10#13#10, I different strings read back from ReceiveStr. But the second string includes the first string in both cases. So it shouldn't be the server sending the string twice. BTW, I'm using the latest ICS. -- Best regards, Jack Wednesday, May 18, 2005, 3:31:32 PM, you wrote: WM Hello Jack, WM Can you show your OnDataAvailable handler ? WM Eventually download SocketSpy from 'user made' page and 'hang' it WM between client and server. Then you see exacly what is sent by server. WM --- WM Rgds, Wilfried WM http://www.mestdagh.biz WM Wednesday, May 18, 2005, 20:48, Jack wrote: Hello Francois and all, I'm using a TWSocket client in LineMode with LineEnd set to #13#10. I connect to a HTTP proxy server using CONNECT command. I then get a reply back from the HTTP proxy from ReceiveStr() Things look OK except that I am receiving the data from the first ReceiveStr() call twice. I get two WSocketDataAvailable messages for 3 lines in the HTTP response: Line 1: HTTP/1.0 200 Connection established Line 2: Proxy-agent: Proxy+ 3.00 Line 3: (Blank line) However, I'm getting the first ReceiveStr() result twice, see below: I'm getting HTTP/1.0 200 Connection established twice: 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 I then changed LineEnd to #13#10#13#10, I still get the result of the first ReceiveStr() twice, this time the result is two lines: HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 (Blank line) 5/18/2005 2:40:11 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:40:11 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 5/18/2005 2:40:11 PM 5/18/2005 2:40:11 PM 5/18/2005 2:40:11 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:40:11 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 It seems that, somehow the first ReceiveStr() didn't remove the data from the buffer. Or am I missing anything? -- Best regards, Jack -- To unsubscribe or change your settings for TWSocket mailing list please goto http://www.elists.org/mailman/listinfo/twsocket Visit our website at http://www.overbyte.be -- To unsubscribe or change your settings for TWSocket mailing list please goto http://www.elists.org/mailman/listinfo/twsocket Visit our website
[twsocket] Receive result of the first ReceiveStr() call twice - not resolved
I celebrated a little too early. I am getting this problem again in further testing after I changed Close() to CloseDelayed(); The difference is, I'm not getting result of the first ReceiveStr() twice. Instead, I get the result of the second ReceiveStr() twice. I think this is because CloseDelayed() delayed the Close(). What I don't understand is why the buffer isn't cleared after ReceiveStr() in both scenarios of Close() and CloseDelayed(). I reason I thought it was fixed is because I tested from an allowed IP earlier and got a very short response back from the proxy server. The whole message was retrieved in the first ReceiveStr() call so I didn't get a chance to call ReceiveStr() twice. I then run the same app on a blocked IP. The proxy sends a longer message (the error message) and it is retrieved in two ReceiveStr() calls. Then I found that the second ReceiveStr() result was duplicated. -- Best regards, Jack Thursday, May 19, 2005, 10:53:49 AM, you wrote: J Francois, thanks! This fixed the problem! It's actually in the FAQ: J - CloseDelayed J Is in most cases the preferred way. It will post a message to J itself to close the TWSocket. This means that the socket closure J is done outside the code that calls the CloseDelayed, meaning a J while later. The message handler will call Close. J - Close J Attempt to gracefully close the socket. If there is still some J data waiting in the buffers it will try to send it. ***Do not use J Close from within any TWSocket events, instead use CloseDelayed.*** J Thursday, May 19, 2005, 2:46:47 AM, you wrote: FP Use CloseDelayed instead of Close. Hello Wilfried, Sure. Below is my event handler code. Hope I'm doing something wrong, otherwise, it's really strange. TProxyChecker is the owner object of the TProxySocket object array. TProxySocket is derived from TWSocket. procedure TProxyChecker.WSocketDataAvailable(Sender: TObject; ErrCode: Word); var s: String; begin if ErrCode = 0 then with TProxySocket(Sender) do begin s := ReceiveStr(); Log(s); Close(); end; end; The destination server is a commercial http proxy server. I tried using #13#10 and #13#10#13#10, I different strings read back from ReceiveStr. But the second string includes the first string in both cases. So it shouldn't be the server sending the string twice. BTW, I'm using the latest ICS. -- Best regards, Jack Wednesday, May 18, 2005, 3:31:32 PM, you wrote: WM Hello Jack, WM Can you show your OnDataAvailable handler ? WM Eventually download SocketSpy from 'user made' page and 'hang' it WM between client and server. Then you see exacly what is sent by server. WM --- WM Rgds, Wilfried WM http://www.mestdagh.biz WM Wednesday, May 18, 2005, 20:48, Jack wrote: Hello Francois and all, I'm using a TWSocket client in LineMode with LineEnd set to #13#10. I connect to a HTTP proxy server using CONNECT command. I then get a reply back from the HTTP proxy from ReceiveStr() Things look OK except that I am receiving the data from the first ReceiveStr() call twice. I get two WSocketDataAvailable messages for 3 lines in the HTTP response: Line 1: HTTP/1.0 200 Connection established Line 2: Proxy-agent: Proxy+ 3.00 Line 3: (Blank line) However, I'm getting the first ReceiveStr() result twice, see below: I'm getting HTTP/1.0 200 Connection established twice: 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 I then changed LineEnd to #13#10#13#10, I still get the result of the first ReceiveStr() twice, this time the result is two lines: HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 (Blank line) 5/18/2005 2:40:11 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:40:11 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 5/18/2005 2:40:11 PM 5/18/2005 2:40:11 PM 5/18/2005 2:40:11 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:40:11 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 It seems that, somehow the first ReceiveStr() didn't remove the data from the buffer. Or am I missing anything? -- Best regards, Jack -- To unsubscribe or change your settings for TWSocket mailing list please goto http://www.elists.org/mailman/listinfo/twsocket Visit our website at http://www.overbyte.be -- To unsubscribe or change your settings for TWSocket mailing list please goto http://www.elists.org/mailman/listinfo/twsocket Visit our website at http://www.overbyte.be
[twsocket] Receive result of the first ReceiveStr() call twice
Hello Francois and all, I'm using a TWSocket client in LineMode with LineEnd set to #13#10. I connect to a HTTP proxy server using CONNECT command. I then get a reply back from the HTTP proxy from ReceiveStr() Things look OK except that I am receiving the data from the first ReceiveStr() call twice. I get two WSocketDataAvailable messages for 3 lines in the HTTP response: Line 1: HTTP/1.0 200 Connection established Line 2: Proxy-agent: Proxy+ 3.00 Line 3: (Blank line) However, I'm getting the first ReceiveStr() result twice, see below: I'm getting HTTP/1.0 200 Connection established twice: 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 I then changed LineEnd to #13#10#13#10, I still get the result of the first ReceiveStr() twice, this time the result is two lines: HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 (Blank line) 5/18/2005 2:40:11 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:40:11 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 5/18/2005 2:40:11 PM 5/18/2005 2:40:11 PM 5/18/2005 2:40:11 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:40:11 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 It seems that, somehow the first ReceiveStr() didn't remove the data from the buffer. Or am I missing anything? -- Best regards, Jack -- To unsubscribe or change your settings for TWSocket mailing list please goto http://www.elists.org/mailman/listinfo/twsocket Visit our website at http://www.overbyte.be
Re: [twsocket] Receive result of the first ReceiveStr() call twice
Hello Jack, Can you show your OnDataAvailable handler ? Eventually download SocketSpy from 'user made' page and 'hang' it between client and server. Then you see exacly what is sent by server. --- Rgds, Wilfried http://www.mestdagh.biz Wednesday, May 18, 2005, 20:48, Jack wrote: Hello Francois and all, I'm using a TWSocket client in LineMode with LineEnd set to #13#10. I connect to a HTTP proxy server using CONNECT command. I then get a reply back from the HTTP proxy from ReceiveStr() Things look OK except that I am receiving the data from the first ReceiveStr() call twice. I get two WSocketDataAvailable messages for 3 lines in the HTTP response: Line 1: HTTP/1.0 200 Connection established Line 2: Proxy-agent: Proxy+ 3.00 Line 3: (Blank line) However, I'm getting the first ReceiveStr() result twice, see below: I'm getting HTTP/1.0 200 Connection established twice: 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 I then changed LineEnd to #13#10#13#10, I still get the result of the first ReceiveStr() twice, this time the result is two lines: HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 (Blank line) 5/18/2005 2:40:11 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:40:11 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 5/18/2005 2:40:11 PM 5/18/2005 2:40:11 PM 5/18/2005 2:40:11 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:40:11 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 It seems that, somehow the first ReceiveStr() didn't remove the data from the buffer. Or am I missing anything? -- Best regards, Jack -- To unsubscribe or change your settings for TWSocket mailing list please goto http://www.elists.org/mailman/listinfo/twsocket Visit our website at http://www.overbyte.be
Re[2]: [twsocket] Receive result of the first ReceiveStr() call twice
Hello Francois, Thanks for the quick reply. No, I don't have any message handler of my own in my code. I create an object as the owner of an array of TWSocket objects. I assign the even handler of the TWSocket objects to a member function of that owner object and call ReceiveStr() in the OnDataAvailable handler. Any other reasons that you can think of that could cause this problem? My component verifies if a HTTP proxies supports CONNECT on port 443. I don't think HTTPCli component does what I want to do ... -- Best regards, Jack Wednesday, May 18, 2005, 3:59:06 PM, you wrote: FP Usually, when you receive the same data twice, it is because you called the FP message pump from one the ICS component event handler. Never call directly FP or indirectly ( ShowMessage, MessageBox,...) from an event handler that is FP called by hardware (a data packet comes from the network) unless you really FP know what you are doing. FP btw: Do not reinvent the wheel, use the HTTP component ! FP - Original Message - Hello Francois and all, I'm using a TWSocket client in LineMode with LineEnd set to #13#10. I connect to a HTTP proxy server using CONNECT command. I then get a reply back from the HTTP proxy from ReceiveStr() Things look OK except that I am receiving the data from the first ReceiveStr() call twice. I get two WSocketDataAvailable messages for 3 lines in the HTTP response: Line 1: HTTP/1.0 200 Connection established Line 2: Proxy-agent: Proxy+ 3.00 Line 3: (Blank line) However, I'm getting the first ReceiveStr() result twice, see below: I'm getting HTTP/1.0 200 Connection established twice: 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 FP ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 FP ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 I then changed LineEnd to #13#10#13#10, I still get the result of the first ReceiveStr() twice, this time the result is two lines: HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 (Blank line) 5/18/2005 2:40:11 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 FP ErrCode=0 5/18/2005 2:40:11 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 5/18/2005 2:40:11 PM 5/18/2005 2:40:11 PM 5/18/2005 2:40:11 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 FP ErrCode=0 5/18/2005 2:40:11 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 It seems that, somehow the first ReceiveStr() didn't remove the data from the buffer. Or am I missing anything? -- To unsubscribe or change your settings for TWSocket mailing list please goto http://www.elists.org/mailman/listinfo/twsocket Visit our website at http://www.overbyte.be
Re[2]: [twsocket] Receive result of the first ReceiveStr() call twice
Hello Wilfried, Sure. Below is my event handler code. Hope I'm doing something wrong, otherwise, it's really strange. TProxyChecker is the owner object of the TProxySocket object array. TProxySocket is derived from TWSocket. procedure TProxyChecker.WSocketDataAvailable(Sender: TObject; ErrCode: Word); var s: String; begin if ErrCode = 0 then with TProxySocket(Sender) do begin s := ReceiveStr(); Log(s); Close(); end; end; The destination server is a commercial http proxy server. I tried using #13#10 and #13#10#13#10, I different strings read back from ReceiveStr. But the second string includes the first string in both cases. So it shouldn't be the server sending the string twice. BTW, I'm using the latest ICS. -- Best regards, Jack Wednesday, May 18, 2005, 3:31:32 PM, you wrote: WM Hello Jack, WM Can you show your OnDataAvailable handler ? WM Eventually download SocketSpy from 'user made' page and 'hang' it WM between client and server. Then you see exacly what is sent by server. WM --- WM Rgds, Wilfried WM http://www.mestdagh.biz WM Wednesday, May 18, 2005, 20:48, Jack wrote: Hello Francois and all, I'm using a TWSocket client in LineMode with LineEnd set to #13#10. I connect to a HTTP proxy server using CONNECT command. I then get a reply back from the HTTP proxy from ReceiveStr() Things look OK except that I am receiving the data from the first ReceiveStr() call twice. I get two WSocketDataAvailable messages for 3 lines in the HTTP response: Line 1: HTTP/1.0 200 Connection established Line 2: Proxy-agent: Proxy+ 3.00 Line 3: (Blank line) However, I'm getting the first ReceiveStr() result twice, see below: I'm getting HTTP/1.0 200 Connection established twice: 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM 5/18/2005 2:36:43 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:36:43 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 I then changed LineEnd to #13#10#13#10, I still get the result of the first ReceiveStr() twice, this time the result is two lines: HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 (Blank line) 5/18/2005 2:40:11 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:40:11 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 5/18/2005 2:40:11 PM 5/18/2005 2:40:11 PM 5/18/2005 2:40:11 PM WSocketDataAvailable idx=0 addr=127.0.0.1:4480 ErrCode=0 5/18/2005 2:40:11 PM HTTP/1.0 200 Connection established Proxy-agent: Proxy+ 3.00 It seems that, somehow the first ReceiveStr() didn't remove the data from the buffer. Or am I missing anything? -- Best regards, Jack -- To unsubscribe or change your settings for TWSocket mailing list please goto http://www.elists.org/mailman/listinfo/twsocket Visit our website at http://www.overbyte.be
