This python program shows the problem
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#!/usr/bin/python3
# -*- coding: utf-8 -*-
#
from pydbus import SessionBus
from time import sleep
# Global constants
#
item= "org.freedesktop.Notifications"
path= "/org/freedesktop/Notifications"
interface = "org.freedesktop.Notifications"
app_name= "NotifyTest"
icon= "/usr/share/icons/breeze/devices/64/camera-web.svg"
actions_list= []
hint= {}
bus = SessionBus()
notifications = bus.get('.Notifications')
# Global variables
#
our_notify_id = 0
timeout = 3000 # ms
wait4 = 0 # s
body = "from NotifyTest.py"
while wait4 < 6:
wait4 += 1
message = "The next wait will be %ss" % wait4
# This should replace any previous notification still there...
# (can do this with notify-send command, but doing it in python allows
# us to use a fixed id for replacement).
#
our_notify_id = notifications.Notify(app_name, our_notify_id, icon,
message, body, actions_list, hint, timeout)
print("our_notify_id:", our_notify_id)
# At Ubuntu 21.10 we have to change this to get the new message seen...
#
#our_notify_id += 1
print(message)
sleep(wait4)
print("Done")
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On 21.04 after the sleep exceeds the 3s timeout a new info message box
is displayed.
On 21.10 after the sleep exceeds the 3s timeout nothing is shown.
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https://bugs.launchpad.net/bugs/1949615
Title:
Notify method not working correctly in 21.10 (impish)
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https://bugs.launchpad.net/ubuntu/+source/dbus/+bug/1949615/+subscriptions
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