Re: The check in a menu item

2002-01-26 Thread Terry Vogelaar

>> In a menu I have 3 items that can be checked. When the check appears in the
>> 1st item, it should be removed from the 2nd and the 3rd item, and so on.
>> 
>> But there is something about checking I don't understand. When I want a
>> menu-item to be checked, I put "!c" before the line of that item. But when I
>> want to move the check from that item to another, I get (or RR gets)
>> confused. If I just remove the "!c" from the first line and then add "!c" to
>> the second, I have 2 items checked instead of one. But when I remove replace
>> the "!c" with a "!n", the check is gone. Then I check a third item. Then
>> chaos begins. "!n" is visible in the 1st item. And the more I swap the
>> menus, the more "!n!n!n"s I see.
>> 
>> With a lot of extra scripting, I managed to let it work reasonably reliable.
>> But I've got a feeling it should be less complex.

> What is the script you're using?

Never mind. I kinda figured out myself how to skip that useless "!n". For
all others who struggled with this problem, the final script is:

on menuPick pWhich
  put whichNumbers() into lNumber
  repeat with e = 1 to 3
if char 1 of line e of me = "!" then delete char 1 to 2 of line e of me
  end repeat
  switch pWhich
  case "Hebrew numbers"
put 1 into lNumber
break
  case "Traditional numbers"
put 2 into lNumber
break
  case "English numbers"
put 3 into lNumber
break
  end switch
  put "!c" before line lNumber of me
end menuPick

function whichNumbers
  repeat with e = 1 to 3
if char 1 to 2 of line e of btn id 1008 = "!c" then return e
  end repeat
end whichNumbers

Groetjes,
Terry



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Re: The check in a menu item

2002-01-26 Thread Sjoerd Op 't Land

Terry Vogelaar wrote/ schreef:

> In a menu I have 3 items that can be checked. When the check appears in the
> 1st item, it should be removed from the 2nd and the 3rd item, and so on.
> 
> But there is something about checking I don't understand. When I want a
> menu-item to be checked, I put "!c" before the line of that item. But when I
> want to move the check from that item to another, I get (or RR gets)
> confused. If I just remove the "!c" from the first line and then add "!c" to
> the second, I have 2 items checked instead of one. But when I remove replace
> the "!c" with a "!n", the check is gone. Then I check a third item. Then
> chaos begins. "!n" is visible in the 1st item. And the more I swap the
> menus, the more "!n!n!n"s I see.
> 
> With a lot of extra scripting, I managed to let it work reasonably reliable.
> But I've got a feeling it should be less complex.
What is the script you're using?

> BTW, why is there a "!n" or a "!u" anyway? I think the check/diamond should
> be gone as soon as the "!c"/"!r" is gone.
> 
> Terry
Regards, / Groeten,
Sjoerd

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The check in a menu item

2002-01-25 Thread Terry Vogelaar

In a menu I have 3 items that can be checked. When the check appears in the
1st item, it should be removed from the 2nd and the 3rd item, and so on.

But there is something about checking I don't understand. When I want a
menu-item to be checked, I put "!c" before the line of that item. But when I
want to move the check from that item to another, I get (or RR gets)
confused. If I just remove the "!c" from the first line and then add "!c" to
the second, I have 2 items checked instead of one. But when I remove replace
the "!c" with a "!n", the check is gone. Then I check a third item. Then
chaos begins. "!n" is visible in the 1st item. And the more I swap the
menus, the more "!n!n!n"s I see.

With a lot of extra scripting, I managed to let it work reasonably reliable.
But I've got a feeling it should be less complex.

BTW, why is there a "!n" or a "!u" anyway? I think the check/diamond should
be gone as soon as the "!c"/"!r" is gone.

Terry


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