How to use row caching to enable faster retrieval of rows in Cassandra
Dear all, I am trying to understand whether I can fasten the retrieval process using cache. Please can you help me write the code for setting the cache properties in Cassandra. Please help Thanks and Regards Prakrati This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Hector code not running when replication factor set to 2
How do I verify that I am using a wrong consistency level? Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: aaron morton [mailto:aa...@thelastpickle.com] Sent: Wednesday, June 13, 2012 2:38 PM To: user@cassandra.apache.org Subject: Re: Hector code not running when replication factor set to 2 It looks like the request used a CL higher than ONE. Cheers - Aaron Morton Freelance Developer @aaronmorton http://www.thelastpickle.com On 13/06/2012, at 6:49 PM, Prakrati Agrawal wrote: The error stack is as follows: Exception in thread "main" java.lang.reflect.InvocationTargetException at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:616) at org.eclipse.jdt.internal.jarinjarloader.JarRsrcLoader.main(JarRsrcLoader.java:58) Caused by: me.prettyprint.hector.api.exceptions.HUnavailableException: : May not be enough replicas present to handle consistency level. at me.prettyprint.cassandra.service.ExceptionsTranslatorImpl.translate(ExceptionsTranslatorImpl.java:59) at me.prettyprint.cassandra.service.KeyspaceServiceImpl$7.execute(KeyspaceServiceImpl.java:285) at me.prettyprint.cassandra.service.KeyspaceServiceImpl$7.execute(KeyspaceServiceImpl.java:268) at me.prettyprint.cassandra.service.Operation.executeAndSetResult(Operation.java:103) at me.prettyprint.cassandra.connection.HConnectionManager.operateWithFailover(HConnectionManager.java:258) at me.prettyprint.cassandra.service.KeyspaceServiceImpl.operateWithFailover(KeyspaceServiceImpl.java:131) at me.prettyprint.cassandra.service.KeyspaceServiceImpl.getSlice(KeyspaceServiceImpl.java:289) at me.prettyprint.cassandra.model.thrift.ThriftSliceQuery$1.doInKeyspace(ThriftSliceQuery.java:53) at me.prettyprint.cassandra.model.thrift.ThriftSliceQuery$1.doInKeyspace(ThriftSliceQuery.java:49) at me.prettyprint.cassandra.model.KeyspaceOperationCallback.doInKeyspaceAndMeasure(KeyspaceOperationCallback.java:20) at me.prettyprint.cassandra.model.ExecutingKeyspace.doExecute(ExecutingKeyspace.java:85) at me.prettyprint.cassandra.model.thrift.ThriftSliceQuery.execute(ThriftSliceQuery.java:48) at me.prettyprint.cassandra.service.ColumnSliceIterator.hasNext(ColumnSliceIterator.java:88) at com.musigma.hectortest.HectorUtilTest.getAllColumns(HectorUtil.java:70) at com.musigma.hectortest.HectorUtil.main(HectorUtil.java:168) ... 5 more Caused by: UnavailableException() at org.apache.cassandra.thrift.Cassandra$get_slice_result.read(Cassandra.java:7204) at org.apache.thrift.TServiceClient.receiveBase(TServiceClient.java:78) at org.apache.cassandra.thrift.Cassandra$Client.recv_get_slice(Cassandra.java:543) at org.apache.cassandra.thrift.Cassandra$Client.get_slice(Cassandra.java:527) at me.prettyprint.cassandra.service.KeyspaceServiceImpl$7.execute(KeyspaceServiceImpl.java:273) ... 18 more The node tool ring from the node I connected to looks like : Address DC RackStatus State Load Effective-Owership Token 85070591730234615865843651857942052864 162.192.100.16 datacenter1 rack1 Up Normal 239.82 MB 100.00% 0 162.192.100.9 datacenter1 rack1 Down Normal 239.81 MB 100.00% 85070591730234615865843651857942052864 I did not find any error in the logs generated by Cassandra on the running machine. Please help me Thanks and Regards Prakrati From: aaron morton [mailto:aa...@thelastpickle.com] Sent: Tuesday, June 12, 2012 2:42 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: Re: Hector code not running when replication factor set to 2 What was the exact error stack you got ? What does node tool ring look look from the node you connected to? Did you notice any errors in the logs on the machine you connected to ? Cheers - Aaron Morton Freelance Developer @aaronmorton http://www.thelastpickle.com On 12/06/2012, at 8:41 PM, Prakrati Agrawal wrote: I am using the consistency level one and replication factor 2 Thanks Prakrati From: aaron morton [mailto:aa...@thelastpickle.com] Sent: Tuesday, June 12, 2012 2:12 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: Re: Hector code not running when replication factor set to 2 What consistency level and replication factor were you using ? UnavailableException is thrown when less the consistency level nodes are UP. Cheers
RE: Hector code not running when replication factor set to 2
The error stack is as follows: Exception in thread "main" java.lang.reflect.InvocationTargetException at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:616) at org.eclipse.jdt.internal.jarinjarloader.JarRsrcLoader.main(JarRsrcLoader.java:58) Caused by: me.prettyprint.hector.api.exceptions.HUnavailableException: : May not be enough replicas present to handle consistency level. at me.prettyprint.cassandra.service.ExceptionsTranslatorImpl.translate(ExceptionsTranslatorImpl.java:59) at me.prettyprint.cassandra.service.KeyspaceServiceImpl$7.execute(KeyspaceServiceImpl.java:285) at me.prettyprint.cassandra.service.KeyspaceServiceImpl$7.execute(KeyspaceServiceImpl.java:268) at me.prettyprint.cassandra.service.Operation.executeAndSetResult(Operation.java:103) at me.prettyprint.cassandra.connection.HConnectionManager.operateWithFailover(HConnectionManager.java:258) at me.prettyprint.cassandra.service.KeyspaceServiceImpl.operateWithFailover(KeyspaceServiceImpl.java:131) at me.prettyprint.cassandra.service.KeyspaceServiceImpl.getSlice(KeyspaceServiceImpl.java:289) at me.prettyprint.cassandra.model.thrift.ThriftSliceQuery$1.doInKeyspace(ThriftSliceQuery.java:53) at me.prettyprint.cassandra.model.thrift.ThriftSliceQuery$1.doInKeyspace(ThriftSliceQuery.java:49) at me.prettyprint.cassandra.model.KeyspaceOperationCallback.doInKeyspaceAndMeasure(KeyspaceOperationCallback.java:20) at me.prettyprint.cassandra.model.ExecutingKeyspace.doExecute(ExecutingKeyspace.java:85) at me.prettyprint.cassandra.model.thrift.ThriftSliceQuery.execute(ThriftSliceQuery.java:48) at me.prettyprint.cassandra.service.ColumnSliceIterator.hasNext(ColumnSliceIterator.java:88) at com.musigma.hectortest.HectorUtilTest.getAllColumns(HectorUtil.java:70) at com.musigma.hectortest.HectorUtil.main(HectorUtil.java:168) ... 5 more Caused by: UnavailableException() at org.apache.cassandra.thrift.Cassandra$get_slice_result.read(Cassandra.java:7204) at org.apache.thrift.TServiceClient.receiveBase(TServiceClient.java:78) at org.apache.cassandra.thrift.Cassandra$Client.recv_get_slice(Cassandra.java:543) at org.apache.cassandra.thrift.Cassandra$Client.get_slice(Cassandra.java:527) at me.prettyprint.cassandra.service.KeyspaceServiceImpl$7.execute(KeyspaceServiceImpl.java:273) ... 18 more The node tool ring from the node I connected to looks like : Address DC RackStatus State Load Effective-Owership Token 85070591730234615865843651857942052864 162.192.100.16 datacenter1 rack1 Up Normal 239.82 MB 100.00% 0 162.192.100.9 datacenter1 rack1 Down Normal 239.81 MB 100.00% 85070591730234615865843651857942052864 I did not find any error in the logs generated by Cassandra on the running machine. Please help me Thanks and Regards Prakrati From: aaron morton [mailto:aa...@thelastpickle.com] Sent: Tuesday, June 12, 2012 2:42 PM To: user@cassandra.apache.org Subject: Re: Hector code not running when replication factor set to 2 What was the exact error stack you got ? What does node tool ring look look from the node you connected to? Did you notice any errors in the logs on the machine you connected to ? Cheers - Aaron Morton Freelance Developer @aaronmorton http://www.thelastpickle.com On 12/06/2012, at 8:41 PM, Prakrati Agrawal wrote: I am using the consistency level one and replication factor 2 Thanks Prakrati From: aaron morton [mailto:aa...@thelastpickle.com] Sent: Tuesday, June 12, 2012 2:12 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: Re: Hector code not running when replication factor set to 2 What consistency level and replication factor were you using ? UnavailableException is thrown when less the consistency level nodes are UP. Cheers - Aaron Morton Freelance Developer @aaronmorton http://www.thelastpickle.com On 11/06/2012, at 10:19 PM, Prakrati Agrawal wrote: Dear all I had a 2 node cluster with replication factor set to 1. Then I changed the replication factor to 2 and brought down one node so that only 1 node was up and running. Then I ran my Hector code on the running node. But it gave me Unavailable Exception. I also had a Thrift code which ran successfully. I am confused as to why the Hector code did not run. Did I miss something? Please help me. Thanks and Regards Prakrati ___
RE: Hector code not running when replication factor set to 2
I am using the consistency level one and replication factor 2 Thanks Prakrati From: aaron morton [mailto:aa...@thelastpickle.com] Sent: Tuesday, June 12, 2012 2:12 PM To: user@cassandra.apache.org Subject: Re: Hector code not running when replication factor set to 2 What consistency level and replication factor were you using ? UnavailableException is thrown when less the consistency level nodes are UP. Cheers - Aaron Morton Freelance Developer @aaronmorton http://www.thelastpickle.com On 11/06/2012, at 10:19 PM, Prakrati Agrawal wrote: Dear all I had a 2 node cluster with replication factor set to 1. Then I changed the replication factor to 2 and brought down one node so that only 1 node was up and running. Then I ran my Hector code on the running node. But it gave me Unavailable Exception. I also had a Thrift code which ran successfully. I am confused as to why the Hector code did not run. Did I miss something? Please help me. Thanks and Regards Prakrati This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Hector code not running when replication factor set to 2
Dear all I had a 2 node cluster with replication factor set to 1. Then I changed the replication factor to 2 and brought down one node so that only 1 node was up and running. Then I ran my Hector code on the running node. But it gave me Unavailable Exception. I also had a Thrift code which ran successfully. I am confused as to why the Hector code did not run. Did I miss something? Please help me. Thanks and Regards Prakrati This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Why cassandra nodes ownership is 0.00%
Dear all I have a Cassandra cluster with 2 nodes. I am using NetworkTopologyStrategy. I was trying to increase the replication factor of keyspace in Cassandra to 2. I did the following steps: UPDATE KEYSPACE demo WITH strategy_options = {DC1:2,DC2:2}; on both the nodes Then I ran the nodetool repair on both the nodes Then I ran my Hector code to count the number of rows and columns in the database. I get the following error: Unavailable Exception Also when I run the command ./nodetool -h ip_address ring I found that both nodes ownership is 0 %. Please tell me how should I fix that. Thanks and Regards Prakrati This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Effective ownership on both nodes 0 %
Dear all I have a Cassandra cluster with 2 nodes. I was trying to increase the replication factor of keyspace in Cassandra to 2. I did the following steps: UPDATE KEYSPACE demo WITH strategy_options = {DC1:2,DC2:2}; on both the nodes Then I ran the nodetool repair on both the nodes Then I ran my Hector code to count the number of rows and columns in the database. I get the following error: Unavailable Exception Also when I run the command ./nodetool -h ip_address ring I found that both nodes ownership is 0 %. Please tell me how should I fix that. Thanks and Regards Prakrati This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Out of memory error
The version is 1.1.0 Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Dave Brosius [mailto:dbros...@mebigfatguy.com] Sent: Monday, June 11, 2012 10:07 AM To: user@cassandra.apache.org Subject: Re: Out of memory error What version of Cassandra? might be related to https://issues.apache.org/jira/browse/CASSANDRA-4098 On 06/11/2012 12:07 AM, Prakrati Agrawal wrote: Sorry I ran list columnFamilyName; and it threw this error. Thanks and Regards Prakrati From: aaron morton [mailto:aa...@thelastpickle.com] Sent: Saturday, June 09, 2012 12:18 AM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: Re: Out of memory error When you ask a question please include the query or function call you have made. An any other information that would help someone understand what you are trying to do. Also, please list things you have already tried to work around the problem. Cheers - Aaron Morton Freelance Developer @aaronmorton http://www.thelastpickle.com On 8/06/2012, at 9:04 PM, Prakrati Agrawal wrote: Dear all, When I try to list the entire data in my column family I get the following error: Using default limit of 100 Exception in thread "main" java.lang.OutOfMemoryError: Java heap space at org.apache.thrift.transport.TFramedTransport.readFrame(TFramedTransport.java:140) at org.apache.thrift.transport.TFramedTransport.read(TFramedTransport.java:101) at org.apache.thrift.transport.TTransport.readAll(TTransport.java:84) at org.apache.thrift.protocol.TBinaryProtocol.readAll(TBinaryProtocol.java:378) at org.apache.thrift.protocol.TBinaryProtocol.readI32(TBinaryProtocol.java:297) at org.apache.thrift.protocol.TBinaryProtocol.readMessageBegin(TBinaryProtocol.java:204) at org.apache.thrift.TServiceClient.receiveBase(TServiceClient.java:69) at org.apache.cassandra.thrift.Cassandra$Client.recv_get_range_slices(Cassandra.java:683) at org.apache.cassandra.thrift.Cassandra$Client.get_range_slices(Cassandra.java:667) at org.apache.cassandra.cli.CliClient.executeList(CliClient.java:1373) at org.apache.cassandra.cli.CliClient.executeCLIStatement(CliClient.java:264) at org.apache.cassandra.cli.CliMain.processStatementInteractive(CliMain.java:219) at org.apache.cassandra.cli.CliMain.main(CliMain.java:346) Please help me Thanks and Regards Prakrati This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by
RE: Out of memory error
Sorry I ran list columnFamilyName; and it threw this error. Thanks and Regards Prakrati From: aaron morton [mailto:aa...@thelastpickle.com] Sent: Saturday, June 09, 2012 12:18 AM To: user@cassandra.apache.org Subject: Re: Out of memory error When you ask a question please include the query or function call you have made. An any other information that would help someone understand what you are trying to do. Also, please list things you have already tried to work around the problem. Cheers - Aaron Morton Freelance Developer @aaronmorton http://www.thelastpickle.com On 8/06/2012, at 9:04 PM, Prakrati Agrawal wrote: Dear all, When I try to list the entire data in my column family I get the following error: Using default limit of 100 Exception in thread "main" java.lang.OutOfMemoryError: Java heap space at org.apache.thrift.transport.TFramedTransport.readFrame(TFramedTransport.java:140) at org.apache.thrift.transport.TFramedTransport.read(TFramedTransport.java:101) at org.apache.thrift.transport.TTransport.readAll(TTransport.java:84) at org.apache.thrift.protocol.TBinaryProtocol.readAll(TBinaryProtocol.java:378) at org.apache.thrift.protocol.TBinaryProtocol.readI32(TBinaryProtocol.java:297) at org.apache.thrift.protocol.TBinaryProtocol.readMessageBegin(TBinaryProtocol.java:204) at org.apache.thrift.TServiceClient.receiveBase(TServiceClient.java:69) at org.apache.cassandra.thrift.Cassandra$Client.recv_get_range_slices(Cassandra.java:683) at org.apache.cassandra.thrift.Cassandra$Client.get_range_slices(Cassandra.java:667) at org.apache.cassandra.cli.CliClient.executeList(CliClient.java:1373) at org.apache.cassandra.cli.CliClient.executeCLIStatement(CliClient.java:264) at org.apache.cassandra.cli.CliMain.processStatementInteractive(CliMain.java:219) at org.apache.cassandra.cli.CliMain.main(CliMain.java:346) Please help me Thanks and Regards Prakrati This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Time taken to retrieve data from a 2 node cluster is more than 1 node cluster
My consistency level is 1 and I did not set any replication factor. I am using Hector API for getting data and don't know whether they are asynchronous or not. Thanks and Regards Prakrati -Original Message- From: rohit bhatia [mailto:rohit2...@gmail.com] Sent: Friday, June 08, 2012 3:58 PM To: user@cassandra.apache.org Subject: Re: Time taken to retrieve data from a 2 node cluster is more than 1 node cluster Is ur client code calling with asyncrhynous requests?? and whats ur replication factor and read consistency level. In any case, 2 nodes might take as much time as one, but should not be slow (unless u also doubled the data)... On Fri, Jun 8, 2012 at 2:41 PM, Prakrati Agrawal wrote: > > > Dear all > > > > Initially I had a one node cluster and I flooded my data into it. I then ran > my Hector code to get some rows and columns. It took around 52.793 seconds. > > Then I added one more node to the cluster. I again ran the same code and it > took around 112.065 seconds. > > Cassandra should perform faster when there are more nodes was my belief.Is > my belief wrong or am I doing something wrong? Please help me > > > > Thanks and Regards > > Prakrati > > > > > > This email message may contain proprietary, private and confidential > information. The information transmitted is intended only for the person(s) > or entities to which it is addressed. Any review, retransmission, > dissemination or other use of, or taking of any action in reliance upon, > this information by persons or entities other than the intended recipient is > prohibited and may be illegal. If you received this in error, please contact > the sender and delete the message from your system. > > Mu Sigma takes all reasonable steps to ensure that its electronic > communications are free from viruses. However, given Internet accessibility, > the Company cannot accept liability for any virus introduced by this e-mail > or any attachment and you are advised to use up-to-date virus checking > software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Time taken to retrieve data from a 2 node cluster is more than 1 node cluster
Dear all Initially I had a one node cluster and I flooded my data into it. I then ran my Hector code to get some rows and columns. It took around 52.793 seconds. Then I added one more node to the cluster. I again ran the same code and it took around 112.065 seconds. Cassandra should perform faster when there are more nodes was my belief.Is my belief wrong or am I doing something wrong? Please help me Thanks and Regards Prakrati This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Out of memory error
Dear all, When I try to list the entire data in my column family I get the following error: Using default limit of 100 Exception in thread "main" java.lang.OutOfMemoryError: Java heap space at org.apache.thrift.transport.TFramedTransport.readFrame(TFramedTransport.java:140) at org.apache.thrift.transport.TFramedTransport.read(TFramedTransport.java:101) at org.apache.thrift.transport.TTransport.readAll(TTransport.java:84) at org.apache.thrift.protocol.TBinaryProtocol.readAll(TBinaryProtocol.java:378) at org.apache.thrift.protocol.TBinaryProtocol.readI32(TBinaryProtocol.java:297) at org.apache.thrift.protocol.TBinaryProtocol.readMessageBegin(TBinaryProtocol.java:204) at org.apache.thrift.TServiceClient.receiveBase(TServiceClient.java:69) at org.apache.cassandra.thrift.Cassandra$Client.recv_get_range_slices(Cassandra.java:683) at org.apache.cassandra.thrift.Cassandra$Client.get_range_slices(Cassandra.java:667) at org.apache.cassandra.cli.CliClient.executeList(CliClient.java:1373) at org.apache.cassandra.cli.CliClient.executeCLIStatement(CliClient.java:264) at org.apache.cassandra.cli.CliMain.processStatementInteractive(CliMain.java:219) at org.apache.cassandra.cli.CliMain.main(CliMain.java:346) Please help me Thanks and Regards Prakrati This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Problem in adding a new node
Yes I gave the ip address of the 1st node in the seeds option Thanks and Regards Prakrati From: MOHD ARSHAD SALEEM [mailto:marshadsal...@tataelxsi.co.in] Sent: Friday, June 08, 2012 12:51 PM To: user@cassandra.apache.org Subject: RE: Problem in adding a new node Hi, the node which you added in that (cassandra.yaml file)give the ip address of 1st node in seeds option. Regards Arshad From: Prakrati Agrawal [prakrati.agra...@mu-sigma.com] Sent: Friday, June 08, 2012 12:44 PM To: user@cassandra.apache.org Subject: Problem in adding a new node Dear all, I had a 1 node cluster of Cassandra. Then I added one more node to it and started Cassandra on it. I got the following error: INFO 12:44:49,588 Loading persisted ring state ERROR 12:44:49,613 Exception in thread Thread[COMMIT-LOG-ALLOCATOR,5,main] java.io.IOError: java.io.IOException: Map failed at org.apache.cassandra.db.commitlog.CommitLogSegment.(CommitLogSegment.java:127) at org.apache.cassandra.db.commitlog.CommitLogAllocator$3.run(CommitLogAllocator.java:191) at org.apache.cassandra.db.commitlog.CommitLogAllocator$1.runMayThrow(CommitLogAllocator.java:95) at org.apache.cassandra.utils.WrappedRunnable.run(WrappedRunnable.java:30) at java.lang.Thread.run(Thread.java:662) Caused by: java.io.IOException: Map failed at sun.nio.ch.FileChannelImpl.map(FileChannelImpl.java:748) at org.apache.cassandra.db.commitlog.CommitLogSegment.(CommitLogSegment.java:119) ... 4 more Caused by: java.lang.OutOfMemoryError: Map failed at sun.nio.ch.FileChannelImpl.map0(Native Method) at sun.nio.ch.FileChannelImpl.map(FileChannelImpl.java:745) Please tell me what is the reason for this error and how should I rectify it. Thanks and Regards Prakrati This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Problem in getting data from a 2 node cluster of Cassandra
Yes the code is the same for both 1 and 2 node cluster. It's a Hector code. How do I get the number of rows and columns from Cassandra CLI as the data is very large. Thanks and Regards Prakrati -Original Message- From: Roshni Rajagopal [mailto:roshni.rajago...@wal-mart.com] Sent: Friday, June 08, 2012 12:43 PM To: user@cassandra.apache.org Subject: Re: Problem in getting data from a 2 node cluster of Cassandra Hi Prakrati, In an ideal situation, no data should be lost when a node is added. How are you getting the statistics below. The output below looks like its from some code using Hector or Thrift..is the code to get statistics from a 1 node cluster or 2 exactly the same- with the only change being a node being added or removed? Could you verify the number of rows & cols in the column family using CLI or CQL.. Regards, Roshni From: Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> Reply-To: "user@cassandra.apache.org<mailto:user@cassandra.apache.org>" mailto:user@cassandra.apache.org>> Date: Friday 8 June 2012 11:50 AM To: "user@cassandra.apache.org<mailto:user@cassandra.apache.org>" mailto:user@cassandra.apache.org>> Subject: Problem in getting data from a 2 node cluster of Cassandra Dear all I was originally having a 1 node cluster. Then I added one more node to it with initial token configured appropriately. Now when I run my queries I am not getting all my data ie all columns. Output on 2 nodes Time taken to retrieve columns 43707 of key range is 1276 Time taken to retrieve columns 2084199 of all tickers is 54334 Time taken to count is 230776 Total number of rows in the database are 183 Total number of columns in the database are 7903753 Output on 1 node Time taken to retrieve columns 43707 of key range is 767 Time taken to retrieve columns 382 of all tickers is 52793 Time taken to count is 268135 Total number of rows in the database are 396 Total number of columns in the database are 16316426 Please help me. Where is my data going or how should I retrieve it. I have consistency level specified as ONE and I did not specify any replication factor. Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email and any files transmitted with it are confidential and intended solely for the individual or entity to whom they are addressed. If you have received this email in error destroy it immediately. *** Walmart Confidential *** This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Problem in adding a new node
Dear all, I had a 1 node cluster of Cassandra. Then I added one more node to it and started Cassandra on it. I got the following error: INFO 12:44:49,588 Loading persisted ring state ERROR 12:44:49,613 Exception in thread Thread[COMMIT-LOG-ALLOCATOR,5,main] java.io.IOError: java.io.IOException: Map failed at org.apache.cassandra.db.commitlog.CommitLogSegment.(CommitLogSegment.java:127) at org.apache.cassandra.db.commitlog.CommitLogAllocator$3.run(CommitLogAllocator.java:191) at org.apache.cassandra.db.commitlog.CommitLogAllocator$1.runMayThrow(CommitLogAllocator.java:95) at org.apache.cassandra.utils.WrappedRunnable.run(WrappedRunnable.java:30) at java.lang.Thread.run(Thread.java:662) Caused by: java.io.IOException: Map failed at sun.nio.ch.FileChannelImpl.map(FileChannelImpl.java:748) at org.apache.cassandra.db.commitlog.CommitLogSegment.(CommitLogSegment.java:119) ... 4 more Caused by: java.lang.OutOfMemoryError: Map failed at sun.nio.ch.FileChannelImpl.map0(Native Method) at sun.nio.ch.FileChannelImpl.map(FileChannelImpl.java:745) Please tell me what is the reason for this error and how should I rectify it. Thanks and Regards Prakrati This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Not getting all data from a 2 node cluster
Dear all I am using Cassandra to retrieve a number of rows and columns stored in it. Initially I had a 1 node cluster and I flooded it with data. I ran a Hector code to retrieve data from it I got the following output: Total number of rows in the database are 396 Total number of columns in the database are 16316426 Now I added one more node to it by doing the following steps: 1. I added both the nodes ip addresses in the seeds property in Cassandra.yaml file. 2. I also changed the rpc_address to 0.0.0.0 in both the nodes config file. 3. I changed the listen_address to their respective ip addresses. 4. I specified the initial token in the new node config file 5. I did not specify auto_bootstrap option anywhere because there is no such option available in Cassandra 1.1.0 6. Then I restarted the first node and the new node Now after adding the second node when I run the same Hector code, I am getting the following result: Total number of rows in the database are 183 Total number of columns in the database are 7903753 I am using the consistency level 1 and I did not specify any replication factor while creating the keyspace. I used the following link for the reference: http://www.datastax.com/docs/0.7/getting_started/configuring Please tell me what step am I doing wrong to not get the entire data on a 2 node cluster ? Thanks and Regards Prakrati This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Problem in getting data from a 2 node cluster of Cassandra
Dear all I was originally having a 1 node cluster. Then I added one more node to it with initial token configured appropriately. Now when I run my queries I am not getting all my data ie all columns. Output on 2 nodes Time taken to retrieve columns 43707 of key range is 1276 Time taken to retrieve columns 2084199 of all tickers is 54334 Time taken to count is 230776 Total number of rows in the database are 183 Total number of columns in the database are 7903753 Output on 1 node Time taken to retrieve columns 43707 of key range is 767 Time taken to retrieve columns 382 of all tickers is 52793 Time taken to count is 268135 Total number of rows in the database are 396 Total number of columns in the database are 16316426 Please help me. Where is my data going or how should I retrieve it. I have consistency level specified as ONE and I did not specify any replication factor. Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Cassandra not retrieving the complete data on 2 nodes
I was told that the node bootstraps automatically in 1.1.0 version of Cassandra. Please help me how to rectify the mistake Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Tyler Hobbs [mailto:ty...@datastax.com] Sent: Wednesday, June 06, 2012 11:45 PM To: user@cassandra.apache.org Subject: Re: Cassandra not retrieving the complete data on 2 nodes In addition to using a low consistency level, it sounds like you didn't bootstrap the node or run a repair after it joined the ring. On Wed, Jun 6, 2012 at 12:41 PM, Poziombka, Wade L mailto:wade.l.poziom...@intel.com>> wrote: what is your consistency level? From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com<mailto:prakrati.agra...@mu-sigma.com>] Sent: Wednesday, June 06, 2012 4:58 AM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: RE: Cassandra not retrieving the complete data on 2 nodes Please anyone reply to my query Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com] Sent: Wednesday, June 06, 2012 2:34 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: Cassandra not retrieving the complete data on 2 nodes Dear all I was originally having a 1 node cluster. Then I added one more node to it with initial token configured appropriately. Now when I run my queries I am not getting all my data ie all columns. Output on 2 nodes Time taken to retrieve columns 43707 of key range is 1276 Time taken to retrieve columns 2084199 of all tickers is 54334 Time taken to count is 230776 Total number of rows in the database are 183 Total number of columns in the database are 7903753 Output on 1 node Time taken to retrieve columns 43707 of key range is 767 Time taken to retrieve columns 382 of all tickers is 52793 Time taken to count is 268135 Total number of rows in the database are 396 Total number of columns in the database are 16316426 Please help me. Where is my data going or how should I retrieve it. Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. -- Tyler Hobbs DataStax<http://datastax.com/> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Cassandra not retrieving the complete data on 2 nodes
I have specified the consistency level as 1 Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Poziombka, Wade L [mailto:wade.l.poziom...@intel.com] Sent: Wednesday, June 06, 2012 11:11 PM To: user@cassandra.apache.org Subject: RE: Cassandra not retrieving the complete data on 2 nodes what is your consistency level? From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com] Sent: Wednesday, June 06, 2012 4:58 AM To: user@cassandra.apache.org Subject: RE: Cassandra not retrieving the complete data on 2 nodes Please anyone reply to my query Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com] Sent: Wednesday, June 06, 2012 2:34 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: Cassandra not retrieving the complete data on 2 nodes Dear all I was originally having a 1 node cluster. Then I added one more node to it with initial token configured appropriately. Now when I run my queries I am not getting all my data ie all columns. Output on 2 nodes Time taken to retrieve columns 43707 of key range is 1276 Time taken to retrieve columns 2084199 of all tickers is 54334 Time taken to count is 230776 Total number of rows in the database are 183 Total number of columns in the database are 7903753 Output on 1 node Time taken to retrieve columns 43707 of key range is 767 Time taken to retrieve columns 382 of all tickers is 52793 Time taken to count is 268135 Total number of rows in the database are 396 Total number of columns in the database are 16316426 Please help me. Where is my data going or how should I retrieve it. Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Problem in getting data from a 2 node cluster
What is the default replication factor? I did not set any replication factor. Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com -Original Message- From: Tim Wintle [mailto:timwin...@gmail.com] Sent: Wednesday, June 06, 2012 5:42 PM To: user@cassandra.apache.org Subject: RE: Problem in getting data from a 2 node cluster On Wed, 2012-06-06 at 06:54 -0500, Prakrati Agrawal wrote: > This node will not auto bootstrap because it is configured to be a > seed node This means the cassandra.yaml on that node references itself as a seed node. After you decommission the second node, can you still access the entire dataset in the single node cluser, or has it been lost along the way? What is the replication factor for your data? Tim Wintle This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Problem in getting data from a 2 node cluster
I will repeat my query once again: I had a 1 node cluster. Then I added 1 more node to it. When I ran my query on 1 node cluster I got all my data but when I ran my query on the 2 node cluster (Hector code) I am not getting the same data. How do I ensure that my Hector code retrieves data from all the nodes. Also when I decommission my node and then add it again I get the following message. This node will not auto bootstrap because it is configured to be a seed node Please tell me the meaning of it also The things I already tried are: 1. Used CassandraHostConfigurator - Still same issue 2. Used nodetool repair on both the nodes - Still same issue Please help me out. I am badly stuck Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com] Sent: Wednesday, June 06, 2012 4:41 PM To: user@cassandra.apache.org Subject: RE: Problem in getting data from a 2 node cluster I even used CassandraHostConfigurator and added a string of hosts but still the same issue. Please someone help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com] Sent: Wednesday, June 06, 2012 4:04 PM To: user@cassandra.apache.org Subject: RE: Problem in getting data from a 2 node cluster Yes I ran nodetool repair also. Still the same problem I am getting lesser data when using my code on a 2 node cluster. Please help me Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: R. Verlangen [mailto:ro...@us2.nl] Sent: Wednesday, June 06, 2012 4:01 PM To: user@cassandra.apache.org Subject: Re: Problem in getting data from a 2 node cluster Repair ensures that all data is consistent and available on the node. 2012/6/6 Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> When I run the nodetool command I get the following information ./nodetool -h localhost ring Address DC RackStatus State Load Effective-Owership Token 85070591730234615865843651857942052864 162.192.100.16 datacenter1 rack1 Up Normal 238.22 MB 50.00% 0 162.192.100.48 datacenter1 rack1 Up Normal 115.6 MB50.00% 85070591730234615865843651857942052864 Please help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com<mailto:prakrati.agra...@mu-sigma.com>] Sent: Wednesday, June 06, 2012 3:55 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: RE: Problem in getting data from a 2 node cluster What does repair do? Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> From: R. Verlangen [mailto:ro...@us2.nl<mailto:ro...@us2.nl>] Sent: Wednesday, June 06, 2012 3:56 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: Re: Problem in getting data from a 2 node cluster Did you run repair on the new node? 2012/6/6 Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> Dear all, I had a 1 node cluster. Then I added 1 more node to it. When I ran my query on 1 node cluster I got all my data but when I ran my query on the 2 node cluster (Hector code) I am not getting the same data. How do I ensure that my Hector code retrieves data from all the nodes. Also when I decommission my node and then add it again I get the following message. This node will not auto bootstrap because it is configured to be a seed node Please tell me the meaning of it also Thanks and Regards Prakrati Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. -- With kind regards, Robin Verlangen Software engineer W http://www.robinverlangen.nl E ro...@us2.nl<mailto:ro...@us2.nl>
RE: Problem in getting data from a 2 node cluster
I even used CassandraHostConfigurator and added a string of hosts but still the same issue. Please someone help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com] Sent: Wednesday, June 06, 2012 4:04 PM To: user@cassandra.apache.org Subject: RE: Problem in getting data from a 2 node cluster Yes I ran nodetool repair also. Still the same problem I am getting lesser data when using my code on a 2 node cluster. Please help me Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: R. Verlangen [mailto:ro...@us2.nl] Sent: Wednesday, June 06, 2012 4:01 PM To: user@cassandra.apache.org Subject: Re: Problem in getting data from a 2 node cluster Repair ensures that all data is consistent and available on the node. 2012/6/6 Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> When I run the nodetool command I get the following information ./nodetool -h localhost ring Address DC RackStatus State Load Effective-Owership Token 85070591730234615865843651857942052864 162.192.100.16 datacenter1 rack1 Up Normal 238.22 MB 50.00% 0 162.192.100.48 datacenter1 rack1 Up Normal 115.6 MB50.00% 85070591730234615865843651857942052864 Please help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com<mailto:prakrati.agra...@mu-sigma.com>] Sent: Wednesday, June 06, 2012 3:55 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: RE: Problem in getting data from a 2 node cluster What does repair do? Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> From: R. Verlangen [mailto:ro...@us2.nl<mailto:ro...@us2.nl>] Sent: Wednesday, June 06, 2012 3:56 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: Re: Problem in getting data from a 2 node cluster Did you run repair on the new node? 2012/6/6 Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> Dear all, I had a 1 node cluster. Then I added 1 more node to it. When I ran my query on 1 node cluster I got all my data but when I ran my query on the 2 node cluster (Hector code) I am not getting the same data. How do I ensure that my Hector code retrieves data from all the nodes. Also when I decommission my node and then add it again I get the following message. This node will not auto bootstrap because it is configured to be a seed node Please tell me the meaning of it also Thanks and Regards Prakrati Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. -- With kind regards, Robin Verlangen Software engineer W http://www.robinverlangen.nl E ro...@us2.nl<mailto:ro...@us2.nl> Disclaimer: The information contained in this message and attachments is intended solely for the attention and use of the named addressee and may be confidential. If you are not the intended recipient, you are reminded that the information remains the property of the sender. You must not use, disclose, distribute, copy, print or rely on this e-mail. If you have received this message in error, please contact the sender immediately and irrevocably delete this message and any copies. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the m
RE: Problem in getting data from a 2 node cluster
Yes I ran nodetool repair also. Still the same problem I am getting lesser data when using my code on a 2 node cluster. Please help me Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: R. Verlangen [mailto:ro...@us2.nl] Sent: Wednesday, June 06, 2012 4:01 PM To: user@cassandra.apache.org Subject: Re: Problem in getting data from a 2 node cluster Repair ensures that all data is consistent and available on the node. 2012/6/6 Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> When I run the nodetool command I get the following information ./nodetool -h localhost ring Address DC RackStatus State Load Effective-Owership Token 85070591730234615865843651857942052864 162.192.100.16 datacenter1 rack1 Up Normal 238.22 MB 50.00% 0 162.192.100.48 datacenter1 rack1 Up Normal 115.6 MB50.00% 85070591730234615865843651857942052864 Please help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com<mailto:prakrati.agra...@mu-sigma.com>] Sent: Wednesday, June 06, 2012 3:55 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: RE: Problem in getting data from a 2 node cluster What does repair do? Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> From: R. Verlangen [mailto:ro...@us2.nl<mailto:ro...@us2.nl>] Sent: Wednesday, June 06, 2012 3:56 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: Re: Problem in getting data from a 2 node cluster Did you run repair on the new node? 2012/6/6 Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> Dear all, I had a 1 node cluster. Then I added 1 more node to it. When I ran my query on 1 node cluster I got all my data but when I ran my query on the 2 node cluster (Hector code) I am not getting the same data. How do I ensure that my Hector code retrieves data from all the nodes. Also when I decommission my node and then add it again I get the following message. This node will not auto bootstrap because it is configured to be a seed node Please tell me the meaning of it also Thanks and Regards Prakrati Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. -- With kind regards, Robin Verlangen Software engineer W http://www.robinverlangen.nl E ro...@us2.nl<mailto:ro...@us2.nl> Disclaimer: The information contained in this message and attachments is intended solely for the attention and use of the named addressee and may be confidential. If you are not the intended recipient, you are reminded that the information remains the property of the sender. You must not use, disclose, distribute, copy, print or rely on this e-mail. If you have received this message in error, please contact the sender immediately and irrevocably delete this message and any copies. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private
RE: Problem in getting data from a 2 node cluster
When I run the nodetool command I get the following information ./nodetool -h localhost ring Address DC RackStatus State Load Effective-Owership Token 85070591730234615865843651857942052864 162.192.100.16 datacenter1 rack1 Up Normal 238.22 MB 50.00% 0 162.192.100.48 datacenter1 rack1 Up Normal 115.6 MB50.00% 85070591730234615865843651857942052864 Please help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com] Sent: Wednesday, June 06, 2012 3:55 PM To: user@cassandra.apache.org Subject: RE: Problem in getting data from a 2 node cluster What does repair do? Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: R. Verlangen [mailto:ro...@us2.nl] Sent: Wednesday, June 06, 2012 3:56 PM To: user@cassandra.apache.org Subject: Re: Problem in getting data from a 2 node cluster Did you run repair on the new node? 2012/6/6 Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> Dear all, I had a 1 node cluster. Then I added 1 more node to it. When I ran my query on 1 node cluster I got all my data but when I ran my query on the 2 node cluster (Hector code) I am not getting the same data. How do I ensure that my Hector code retrieves data from all the nodes. Also when I decommission my node and then add it again I get the following message. This node will not auto bootstrap because it is configured to be a seed node Please tell me the meaning of it also Thanks and Regards Prakrati Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. -- With kind regards, Robin Verlangen Software engineer W http://www.robinverlangen.nl E ro...@us2.nl<mailto:ro...@us2.nl> Disclaimer: The information contained in this message and attachments is intended solely for the attention and use of the named addressee and may be confidential. If you are not the intended recipient, you are reminded that the information remains the property of the sender. You must not use, disclose, distribute, copy, print or rely on this e-mail. If you have received this message in error, please contact the sender immediately and irrevocably delete this message and any copies. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Problem in getting data from a 2 node cluster
What does repair do? Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: R. Verlangen [mailto:ro...@us2.nl] Sent: Wednesday, June 06, 2012 3:56 PM To: user@cassandra.apache.org Subject: Re: Problem in getting data from a 2 node cluster Did you run repair on the new node? 2012/6/6 Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> Dear all, I had a 1 node cluster. Then I added 1 more node to it. When I ran my query on 1 node cluster I got all my data but when I ran my query on the 2 node cluster (Hector code) I am not getting the same data. How do I ensure that my Hector code retrieves data from all the nodes. Also when I decommission my node and then add it again I get the following message. This node will not auto bootstrap because it is configured to be a seed node Please tell me the meaning of it also Thanks and Regards Prakrati Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. -- With kind regards, Robin Verlangen Software engineer W http://www.robinverlangen.nl E ro...@us2.nl<mailto:ro...@us2.nl> Disclaimer: The information contained in this message and attachments is intended solely for the attention and use of the named addressee and may be confidential. If you are not the intended recipient, you are reminded that the information remains the property of the sender. You must not use, disclose, distribute, copy, print or rely on this e-mail. If you have received this message in error, please contact the sender immediately and irrevocably delete this message and any copies. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Problem in getting data from a 2 node cluster
Dear all, I had a 1 node cluster. Then I added 1 more node to it. When I ran my query on 1 node cluster I got all my data but when I ran my query on the 2 node cluster (Hector code) I am not getting the same data. How do I ensure that my Hector code retrieves data from all the nodes. Also when I decommission my node and then add it again I get the following message. This node will not auto bootstrap because it is configured to be a seed node Please tell me the meaning of it also Thanks and Regards Prakrati Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Cassandra not retrieving the complete data on 2 nodes
Please anyone reply to my query Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com] Sent: Wednesday, June 06, 2012 2:34 PM To: user@cassandra.apache.org Subject: Cassandra not retrieving the complete data on 2 nodes Dear all I was originally having a 1 node cluster. Then I added one more node to it with initial token configured appropriately. Now when I run my queries I am not getting all my data ie all columns. Output on 2 nodes Time taken to retrieve columns 43707 of key range is 1276 Time taken to retrieve columns 2084199 of all tickers is 54334 Time taken to count is 230776 Total number of rows in the database are 183 Total number of columns in the database are 7903753 Output on 1 node Time taken to retrieve columns 43707 of key range is 767 Time taken to retrieve columns 382 of all tickers is 52793 Time taken to count is 268135 Total number of rows in the database are 396 Total number of columns in the database are 16316426 Please help me. Where is my data going or how should I retrieve it. Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Why Hector is taking more time than Thrift
Dear all I am trying to evaluate the performance of Cassandra and wrote a code to retrieve a complete row ( having 43707 columns) using Thrift and Hector. The thrift client code took 0.767 seconds while Hector code took 0.883 seconds . Is it expected that Hector will be slower than Thrift? If yes, then why are we using Hector and not Thrift? Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Cassandra not retrieving the complete data on 2 nodes
Dear all I was originally having a 1 node cluster. Then I added one more node to it with initial token configured appropriately. Now when I run my queries I am not getting all my data ie all columns. Output on 2 nodes Time taken to retrieve columns 43707 of key range is 1276 Time taken to retrieve columns 2084199 of all tickers is 54334 Time taken to count is 230776 Total number of rows in the database are 183 Total number of columns in the database are 7903753 Output on 1 node Time taken to retrieve columns 43707 of key range is 767 Time taken to retrieve columns 382 of all tickers is 52793 Time taken to count is 268135 Total number of rows in the database are 396 Total number of columns in the database are 16316426 Please help me. Where is my data going or how should I retrieve it. Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: how to create keyspace using cassandra API's
You have to create the keyspace manually first using Cassandra cli Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: MOHD ARSHAD SALEEM [mailto:marshadsal...@tataelxsi.co.in] Sent: Wednesday, June 06, 2012 2:27 PM To: user@cassandra.apache.org Subject: how to create keyspace using cassandra API's Hi All, I am using Hector as a client in cassandra.And iam trying to create Keyspace using the following API's Keyspace keyspace = HFactory.createKeyspace("test", cluster); but it showing the following error: caused by: InvalidRequestException(why:Keyspace test does not exist) can any body help me how to create keyspace in cassandra. Regards Arshad This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
How to make a decommissioned node join the ring again
Dear all I decommissioned a node. Now I want to make that node a part of the ring again. How do I do it? Please help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: How to include two nodes in Java code using Hector
Thank you for the reply. Now I have decommissioned a node but now I don't know how to recommission it .Please help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com -Original Message- From: Roshni Rajagopal [mailto:roshni.rajago...@wal-mart.com] Sent: Wednesday, June 06, 2012 11:42 AM To: user@cassandra.apache.org Subject: Re: How to include two nodes in Java code using Hector In Hector when you create a cluster using the API, you specify an IP address & cluster name. Thereafter internally which node serves the request or how many nodes need to be contacted to read/write data depends on the cluster configuration i.e. Whats your replication strategy, factor, consistency levels for the col family , how many nodes are there in the ring etc. So you don't individually need to connect to each node via Hector client. Once you connect to the cluster & keyspace, via any IP add of any node in the cluster, when you make Hector calls to read/write data, it would automatically figure out the node level details and carry out the task. You won't get 50% of the data, you will get all data. Also when you remove a node, your data will be unavailable ONLY if you don't have it available in some other node as a replica.. Regards, From: Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> Reply-To: "user@cassandra.apache.org<mailto:user@cassandra.apache.org>" mailto:user@cassandra.apache.org>> Date: Tue, 5 Jun 2012 20:05:21 -0700 To: "user@cassandra.apache.org<mailto:user@cassandra.apache.org>" mailto:user@cassandra.apache.org>> Subject: RE: How to include two nodes in Java code using Hector But the data is distributed on the nodes ( meaning 50% of data is on one node and 50% of data is on another node) so I need to specify the node ip address somewhere in the code. But where do I specify that is what I am clueless about. Please help me Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Harshvardhan Ojha [mailto:harshvardhan.o...@makemytrip.com] Sent: Tuesday, June 05, 2012 5:51 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: RE: How to include two nodes in Java code using Hector Use Consistency Level =2. Regards Harsh From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com] Sent: Tuesday, June 05, 2012 4:08 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: How to include two nodes in Java code using Hector Dear all I am using a two node Cassandra cluster. How do I code in Java using Hector to get data from both the nodes. Please help Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email and any files transmitted with it are confidential and intended solely for the individual or entity to whom they are addressed. If you have received this email in error destroy it immediately. *** Walmart Confidential *** This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmissio
Removing a node in cluster
Dear all I am trying to check the performance of Cassandra on adding or removing nodes. I want to know what happens to my existing data if I remove a node ? Please help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: How to include two nodes in Java code using Hector
But the data is distributed on the nodes ( meaning 50% of data is on one node and 50% of data is on another node) so I need to specify the node ip address somewhere in the code. But where do I specify that is what I am clueless about. Please help me Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Harshvardhan Ojha [mailto:harshvardhan.o...@makemytrip.com] Sent: Tuesday, June 05, 2012 5:51 PM To: user@cassandra.apache.org Subject: RE: How to include two nodes in Java code using Hector Use Consistency Level =2. Regards Harsh From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com] Sent: Tuesday, June 05, 2012 4:08 PM To: user@cassandra.apache.org Subject: How to include two nodes in Java code using Hector Dear all I am using a two node Cassandra cluster. How do I code in Java using Hector to get data from both the nodes. Please help Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
How to include two nodes in Java code using Hector
Dear all I am using a two node Cassandra cluster. How do I code in Java using Hector to get data from both the nodes. Please help Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: How to configure the Cassandra connection using Hector
Thank you all for the quick response :) Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: MOHD ARSHAD SALEEM [mailto:marshadsal...@tataelxsi.co.in] Sent: Tuesday, June 05, 2012 3:07 PM To: user@cassandra.apache.org Subject: RE: How to configure the Cassandra connection using Hector In the following line give cluster = HFactory.getCluster("Test Cluster",ip:9160); ip =ip address of your machine and respective port no. Regards Arshad ____ From: Prakrati Agrawal [prakrati.agra...@mu-sigma.com] Sent: Tuesday, June 05, 2012 3:00 PM To: user@cassandra.apache.org Subject: RE: How to configure the Cassandra connection using Hector cluster = HFactory.getCluster("Test Cluster"); keySpace = HFactory.createKeyspace("mstream", cluster); These are the lines that I am executing and getting an error Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Harshvardhan Ojha [mailto:harshvardhan.o...@makemytrip.com] Sent: Tuesday, June 05, 2012 2:59 PM To: user@cassandra.apache.org Subject: RE: How to configure the Cassandra connection using Hector Check if you have rightly provided your cluster name. Regards Harsh From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com] Sent: Tuesday, June 05, 2012 2:55 PM To: user@cassandra.apache.org Subject: How to configure the Cassandra connection using Hector Dear all, I am writing a java code using Hector but when I am configuring the already created key space using HFactory.createKeySpace its giving me the error Null Point Exception. What am I doing wrong. Please help me. Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: How to configure the Cassandra connection using Hector
cluster = HFactory.getCluster("Test Cluster"); keySpace = HFactory.createKeyspace("mstream", cluster); These are the lines that I am executing and getting an error Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Harshvardhan Ojha [mailto:harshvardhan.o...@makemytrip.com] Sent: Tuesday, June 05, 2012 2:59 PM To: user@cassandra.apache.org Subject: RE: How to configure the Cassandra connection using Hector Check if you have rightly provided your cluster name. Regards Harsh From: Prakrati Agrawal [mailto:prakrati.agra...@mu-sigma.com] Sent: Tuesday, June 05, 2012 2:55 PM To: user@cassandra.apache.org Subject: How to configure the Cassandra connection using Hector Dear all, I am writing a java code using Hector but when I am configuring the already created key space using HFactory.createKeySpace its giving me the error Null Point Exception. What am I doing wrong. Please help me. Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
How to configure the Cassandra connection using Hector
Dear all, I am writing a java code using Hector but when I am configuring the already created key space using HFactory.createKeySpace its giving me the error Null Point Exception. What am I doing wrong. Please help me. Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
How to use Hector to retrieve data from Cassandra
Dear all, I am unable to find a good elaborate example on how to use Hector to get data stored in Cassandra. Please help me. Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Which client to use for Cassandra real time insertion and retrieval
Dear all, I am trying to explore Cassandra for real time applications. Can you please suggest me which client is the best to use ? Is the client choice based on the user 's comfort level or on use cases. Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Adding a new node to Cassandra cluster
Ye I know I am trying to reinvent the wheel but I have to. The requirement is such that I have to use Java Thrift API without any client like Hector. Can you please tell me how do I do it. Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: samal [mailto:samalgo...@gmail.com] Sent: Monday, June 04, 2012 3:12 PM To: user@cassandra.apache.org Subject: Re: Adding a new node to Cassandra cluster If you use thrift API, you have to maintain lot of low level code by yourself which is already being polished by HLC hector, pycassa also with HLC your can easily switch between thrift and growing CQL. On Mon, Jun 4, 2012 at 3:00 PM, R. Verlangen mailto:ro...@us2.nl>> wrote: You might consider using a higher level client (like Hector indeed). If you don't want this you will have to write your own connection pool. For start take a look at Hector. But keep in mind that you might be reinventing the wheel. 2012/6/4 Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> Hi, I am using Thrift API and I am not able to find anything on the internet about how to configure it for multiple nodes. I am not using any proper client like Hector. Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> From: R. Verlangen [mailto:ro...@us2.nl<mailto:ro...@us2.nl>] Sent: Monday, June 04, 2012 2:44 PM To: user@cassandra.apache.org<mailto:user@cassandra.apache.org> Subject: Re: Adding a new node to Cassandra cluster Hi there, When you speak to one node it will internally redirect the request to the proper node (local / external): but you won't be able to failover on a crash of the localhost. For adding another node to the connection pool you should take a look at the documentation of your java client. Good luck! 2012/6/4 Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> Dear all I successfully added a new node to my cluster so now it’s a 2 node cluster. But how do I mention it in my Java code as when I am retrieving data its retrieving only for one node that I am specifying in the localhost. How do I specify more than one node in the localhost. Please help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. -- With kind regards, Robin Verlangen Software engineer W www.robinverlangen.nl<http://www.robinverlangen.nl> E ro...@us2.nl<mailto:ro...@us2.nl> Disclaimer: The information contained in this message and attachments is intended solely for the attention and use of the named addressee and may be confidential. If you are not the intended recipient, you are reminded that the information remains the property of the sender. You must not use, disclose, distribute, copy, print or rely on this e-mail. If you have received this message in error, please contact the sender immediately and irrevocably delete this message and any copies. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. -- With kind regards, Robin Verlangen Software engineer W www.robinverlangen.nl<http://www.robinverlangen.nl> E ro...@us2.nl<mailto:ro...@us2.nl> Disclaimer: The information contained in this message and attachments is intended solely for the attention and use of the named addressee an
RE: Adding a new node to Cassandra cluster
Hi, I am using Thrift API and I am not able to find anything on the internet about how to configure it for multiple nodes. I am not using any proper client like Hector. Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: R. Verlangen [mailto:ro...@us2.nl] Sent: Monday, June 04, 2012 2:44 PM To: user@cassandra.apache.org Subject: Re: Adding a new node to Cassandra cluster Hi there, When you speak to one node it will internally redirect the request to the proper node (local / external): but you won't be able to failover on a crash of the localhost. For adding another node to the connection pool you should take a look at the documentation of your java client. Good luck! 2012/6/4 Prakrati Agrawal mailto:prakrati.agra...@mu-sigma.com>> Dear all I successfully added a new node to my cluster so now it's a 2 node cluster. But how do I mention it in my Java code as when I am retrieving data its retrieving only for one node that I am specifying in the localhost. How do I specify more than one node in the localhost. Please help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com<http://www.mu-sigma.com> This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. -- With kind regards, Robin Verlangen Software engineer W www.robinverlangen.nl<http://www.robinverlangen.nl> E ro...@us2.nl<mailto:ro...@us2.nl> Disclaimer: The information contained in this message and attachments is intended solely for the attention and use of the named addressee and may be confidential. If you are not the intended recipient, you are reminded that the information remains the property of the sender. You must not use, disclose, distribute, copy, print or rely on this e-mail. If you have received this message in error, please contact the sender immediately and irrevocably delete this message and any copies. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Adding a new node to Cassandra cluster
Dear all I successfully added a new node to my cluster so now it's a 2 node cluster. But how do I mention it in my Java code as when I am retrieving data its retrieving only for one node that I am specifying in the localhost. How do I specify more than one node in the localhost. Please help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Finding whether a new node is successfully added or not
Dear all, I added a new node to my 1 node Cassandra cluster. Now I want to find out whether it is added successfully or not. Also do I need to restart the already running node after entering the seed value. Please help me. Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Getting error on adding seed to add a new node
Dear all, I am trying to add a new node to my existing one node Cassandra. So I edited the seeds value in the cassandra.yaml and added the ip addresses of both the nodes. But its giving me the following error: ERROR 13:16:48,342 Fatal configuration error error while parsing a block mapping in "", line 164, column 13: - seeds: "162.192.100.16","162.192 ... ^ expected , but found FlowEntry in "", line 164, column 36: - seeds: "162.192.100.16","162.192.100.48" ^ Please help me. Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Can not find auto bootstrap property in cassandra.yaml for Cassandra 1.1.0
Dear all I am trying to add a new node to the Cassandra cluster. In all the documentations available on net it says to set the auto bootstrap property in cassandra.yaml to true but I am not finding the property in the file. Please help me Thanks and Regards Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
RE: Doubt in Row key range scan
Please could you tell me how to tweak my data model to rely on 2nd index ? Thank you Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com From: Pierre Chalamet [mailto:pie...@chalamet.net] Sent: Monday, May 28, 2012 3:31 PM To: user@cassandra.apache.org Subject: Re: Doubt in Row key range scan Hi, It's normal. Keys to replicas are determined with a hash (md5) when using the random partitionner (which you are using I guess). You probably want to switch to the order preserving partionner or tweak your data model in order to rely on 2nd index for such filtering. - Pierre ____ From: Prakrati Agrawal Date: Mon, 28 May 2012 04:39:46 -0500 To: user@cassandra.apache.org ReplyTo: user@cassandra.apache.org Subject: Doubt in Row key range scan Dear all I have stored my data into Cassandra database in the format "tickerID_date". Now when I specify the row key range like 1_2012/05/24(start) to 1_2012/05/27(end) it says that the end key md5 value is lesser than start key md5 value. So I changed my start key to 1_2012/05/27 and end key to 1_2012/05/24, then I got all the keys even which are not in my range like 67_2012/05/23 and 54_2012/05/28. I am using Thrift API. Please help me as I want only the columns of 1_2012/05/24, 1_2012/05/25 , 1_2012/05/26 and 1_2012/05/27. Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software. This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Doubt in Row key range scan
Dear all I have stored my data into Cassandra database in the format "tickerID_date". Now when I specify the row key range like 1_2012/05/24(start) to 1_2012/05/27(end) it says that the end key md5 value is lesser than start key md5 value. So I changed my start key to 1_2012/05/27 and end key to 1_2012/05/24, then I got all the keys even which are not in my range like 67_2012/05/23 and 54_2012/05/28. I am using Thrift API. Please help me as I want only the columns of 1_2012/05/24, 1_2012/05/25 , 1_2012/05/26 and 1_2012/05/27. Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.
Query on how to count the total number of rowkeys and columns in them
Hi I am trying to learn Cassandra and I have one doubt. I am using the Thrift API, to count the number of row keys I am using KeyRange to specify the row keys. To count all of them, I specify the start and end as "new byte[0]". But the count is set to 100 by default. How do I use this method to count the keys if I don't know the actual number of keys in my Cassandra database? Please help me Prakrati Agrawal | Developer - Big Data(I&D)| 9731648376 | www.mu-sigma.com This email message may contain proprietary, private and confidential information. The information transmitted is intended only for the person(s) or entities to which it is addressed. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by persons or entities other than the intended recipient is prohibited and may be illegal. If you received this in error, please contact the sender and delete the message from your system. Mu Sigma takes all reasonable steps to ensure that its electronic communications are free from viruses. However, given Internet accessibility, the Company cannot accept liability for any virus introduced by this e-mail or any attachment and you are advised to use up-to-date virus checking software.