Re: How to explode array columns of a dataframe having the same length

2023-02-19 Thread 404




sql:   select inline(arrays_zip(col1, col2, col3)) as (c1, c2, c3) from t1


 Replied Message 
| From | Enrico Minack |
| Date | 02/16/2023 16:06 |
| To |  ,
sam smith |
| Subject | Re: How to explode array columns of a dataframe having the same 
length |
You have to take each row and zip the lists, each element of the result becomes 
one new row.


So turn write a method that turns

  Row(List("A","B","null"), List("C","D","null"), List("E","null","null"))

into
  List(List("A","C","E"), List("B","D","null"), List("null","null","null"))

and use flatmap with that method.



In Scala, this would read:


df.flatMap { row => (row.getSeq[String](0), row.getSeq[String](1), 
row.getSeq[String](2)).zipped.toIterable }.show()


Enrico




Am 14.02.23 um 22:54 schrieb sam smith:

Hello guys,


I have the following dataframe:


|
|

col1

|

col2

|

col3

|
|

["A","B","null"]

|

["C","D","null"]

|

["E","null","null"]

|
|
|
|
I want to explode it to the following dataframe:


|

col1

|

col2

|

col3

|
|

"A"

|

"C"

|

"E"

|
|

"B"

|

"D"

|

"null"

|
|

"null"

|

"null"

|

"null"

|


How to do that (preferably in Java) using the explode() method ? knowing that 
something like the following won't yield correct output:


for (String colName: dataset.columns())
dataset=dataset.withColumn(colName,explode(dataset.col(colName)));








Re: How to explode array columns of a dataframe having the same length

2023-02-16 Thread Vikas Kumar
I think these 4 steps should help:

Use zip
Explode
Withcolumn (getelement of array)
Drop the array column

Thanks



On Thu, Feb 16, 2023, 2:18 PM sam smith  wrote:

> @Enrico Minack  I used arrays_zip to merge values
> into one row, and then used toJSON() to export the data.
> @Bjørn explode_outer didn't yield the expected results.
>
> Thanks anyway.
>
> Le jeu. 16 févr. 2023 à 09:06, Enrico Minack  a
> écrit :
>
>> You have to take each row and zip the lists, each element of the result
>> becomes one new row.
>>
>> So turn write a method that turns
>>   Row(List("A","B","null"), List("C","D","null"), List("E","null","null"))
>> into
>>   List(List("A","C","E"), List("B","D","null"),
>> List("null","null","null"))
>> and use flatmap with that method.
>>
>> In Scala, this would read:
>>
>> df.flatMap { row => (row.getSeq[String](0), row.getSeq[String](1),
>> row.getSeq[String](2)).zipped.toIterable }.show()
>>
>> Enrico
>>
>>
>> Am 14.02.23 um 22:54 schrieb sam smith:
>>
>> Hello guys,
>>
>> I have the following dataframe:
>>
>> *col1*
>>
>> *col2*
>>
>> *col3*
>>
>> ["A","B","null"]
>>
>> ["C","D","null"]
>>
>> ["E","null","null"]
>>
>>
>> I want to explode it to the following dataframe:
>>
>> *col1*
>>
>> *col2*
>>
>> *col3*
>>
>> "A"
>>
>> "C"
>>
>> "E"
>>
>> "B"
>>
>> "D"
>>
>> "null"
>>
>> "null"
>>
>> "null"
>>
>> "null"
>>
>> How to do that (preferably in Java) using the explode() method ? knowing
>> that something like the following won't yield correct output:
>>
>> for (String colName: dataset.columns())
>> dataset=dataset.withColumn(colName,explode(dataset.col(colName)));
>>
>>
>>
>>


Re: How to explode array columns of a dataframe having the same length

2023-02-16 Thread sam smith
@Enrico Minack  I used arrays_zip to merge values
into one row, and then used toJSON() to export the data.
@Bjørn explode_outer didn't yield the expected results.

Thanks anyway.

Le jeu. 16 févr. 2023 à 09:06, Enrico Minack  a
écrit :

> You have to take each row and zip the lists, each element of the result
> becomes one new row.
>
> So turn write a method that turns
>   Row(List("A","B","null"), List("C","D","null"), List("E","null","null"))
> into
>   List(List("A","C","E"), List("B","D","null"), List("null","null","null"))
> and use flatmap with that method.
>
> In Scala, this would read:
>
> df.flatMap { row => (row.getSeq[String](0), row.getSeq[String](1),
> row.getSeq[String](2)).zipped.toIterable }.show()
>
> Enrico
>
>
> Am 14.02.23 um 22:54 schrieb sam smith:
>
> Hello guys,
>
> I have the following dataframe:
>
> *col1*
>
> *col2*
>
> *col3*
>
> ["A","B","null"]
>
> ["C","D","null"]
>
> ["E","null","null"]
>
>
> I want to explode it to the following dataframe:
>
> *col1*
>
> *col2*
>
> *col3*
>
> "A"
>
> "C"
>
> "E"
>
> "B"
>
> "D"
>
> "null"
>
> "null"
>
> "null"
>
> "null"
>
> How to do that (preferably in Java) using the explode() method ? knowing
> that something like the following won't yield correct output:
>
> for (String colName: dataset.columns())
> dataset=dataset.withColumn(colName,explode(dataset.col(colName)));
>
>
>
>


Re: How to explode array columns of a dataframe having the same length

2023-02-16 Thread Bjørn Jørgensen
Use explode_outer() when rows have null values.

tor. 16. feb. 2023 kl. 16:48 skrev Navneet :

> I am not expert, may be try if this works:
> In order to achieve the desired output using the explode() method in
> Java, you can create a User-Defined Function (UDF) that zips the lists
> in each row and returns the resulting list. Here's an example
> implementation:
>
> typescript
> Copy code
> import org.apache.spark.sql.Row;
> import org.apache.spark.sql.api.java.UDF1;
> import org.apache.spark.sql.types.DataTypes;
>
> public class ZipRows implements UDF1 {
> @Override
> public Row call(Row row) {
> List list1 = row.getList(0);
> List list2 = row.getList(1);
> List list3 = row.getList(2);
> List> zipped = new ArrayList<>();
> for (int i = 0; i < list1.size(); i++) {
> List sublist = new ArrayList<>();
> sublist.add(list1.get(i));
> sublist.add(list2.get(i));
> sublist.add(list3.get(i));
> zipped.add(sublist);
> }
> return RowFactory.create(zipped);
> }
> }
> This UDF takes a Row as input, which contains the three lists in each
> row of the original DataFrame. It then zips these lists using a loop
> that creates a new sublist for each element in the lists. Finally, it
> returns a new Row that contains the zipped list.
>
> You can then use this UDF in combination with explode() to achieve the
> desired output:
>
> javascript
> Copy code
> import org.apache.spark.sql.Dataset;
> import org.apache.spark.sql.Row;
> import static org.apache.spark.sql.functions.*;
>
> // assuming you have a Dataset called "df"
> df.withColumn("zipped", callUDF(new ZipRows(),
>
> DataTypes.createArrayType(DataTypes.createArrayType(DataTypes.StringType))),
> "col1", "col2", "col3")
> .selectExpr("explode(zipped) as zipped")
> .selectExpr("zipped[0] as col1", "zipped[1] as col2", "zipped[2] as col3")
> .show();
> This code first adds a new column called "zipped" to the DataFrame
> using the callUDF() function, which applies the ZipRows UDF to the
> "col1", "col2", and "col3" columns. It then uses explode() to explode
> the "zipped" column, and finally selects the three sub-elements of the
> zipped list as separate columns using selectExpr(). The output should
> be the desired DataFrame.
>
>
>
> Regards,
> Navneet Kr
>
>
> On Thu, 16 Feb 2023 at 00:07, Enrico Minack 
> wrote:
> >
> > You have to take each row and zip the lists, each element of the result
> becomes one new row.
> >
> > So turn write a method that turns
> >   Row(List("A","B","null"), List("C","D","null"),
> List("E","null","null"))
> > into
> >   List(List("A","C","E"), List("B","D","null"),
> List("null","null","null"))
> > and use flatmap with that method.
> >
> > In Scala, this would read:
> >
> > df.flatMap { row => (row.getSeq[String](0), row.getSeq[String](1),
> row.getSeq[String](2)).zipped.toIterable }.show()
> >
> > Enrico
> >
> >
> > Am 14.02.23 um 22:54 schrieb sam smith:
> >
> > Hello guys,
> >
> > I have the following dataframe:
> >
> > col1
> >
> > col2
> >
> > col3
> >
> > ["A","B","null"]
> >
> > ["C","D","null"]
> >
> > ["E","null","null"]
> >
> >
> >
> > I want to explode it to the following dataframe:
> >
> > col1
> >
> > col2
> >
> > col3
> >
> > "A"
> >
> > "C"
> >
> > "E"
> >
> > "B"
> >
> > "D"
> >
> > "null"
> >
> > "null"
> >
> > "null"
> >
> > "null"
> >
> >
> > How to do that (preferably in Java) using the explode() method ? knowing
> that something like the following won't yield correct output:
> >
> > for (String colName: dataset.columns())
> > dataset=dataset.withColumn(colName,explode(dataset.col(colName)));
> >
> >
> >
>
> -
> To unsubscribe e-mail: user-unsubscr...@spark.apache.org
>
>

-- 
Bjørn Jørgensen
Vestre Aspehaug 4, 6010 Ålesund
Norge

+47 480 94 297


Re: How to explode array columns of a dataframe having the same length

2023-02-16 Thread Navneet
I am not expert, may be try if this works:
In order to achieve the desired output using the explode() method in
Java, you can create a User-Defined Function (UDF) that zips the lists
in each row and returns the resulting list. Here's an example
implementation:

typescript
Copy code
import org.apache.spark.sql.Row;
import org.apache.spark.sql.api.java.UDF1;
import org.apache.spark.sql.types.DataTypes;

public class ZipRows implements UDF1 {
@Override
public Row call(Row row) {
List list1 = row.getList(0);
List list2 = row.getList(1);
List list3 = row.getList(2);
List> zipped = new ArrayList<>();
for (int i = 0; i < list1.size(); i++) {
List sublist = new ArrayList<>();
sublist.add(list1.get(i));
sublist.add(list2.get(i));
sublist.add(list3.get(i));
zipped.add(sublist);
}
return RowFactory.create(zipped);
}
}
This UDF takes a Row as input, which contains the three lists in each
row of the original DataFrame. It then zips these lists using a loop
that creates a new sublist for each element in the lists. Finally, it
returns a new Row that contains the zipped list.

You can then use this UDF in combination with explode() to achieve the
desired output:

javascript
Copy code
import org.apache.spark.sql.Dataset;
import org.apache.spark.sql.Row;
import static org.apache.spark.sql.functions.*;

// assuming you have a Dataset called "df"
df.withColumn("zipped", callUDF(new ZipRows(),
DataTypes.createArrayType(DataTypes.createArrayType(DataTypes.StringType))),
"col1", "col2", "col3")
.selectExpr("explode(zipped) as zipped")
.selectExpr("zipped[0] as col1", "zipped[1] as col2", "zipped[2] as col3")
.show();
This code first adds a new column called "zipped" to the DataFrame
using the callUDF() function, which applies the ZipRows UDF to the
"col1", "col2", and "col3" columns. It then uses explode() to explode
the "zipped" column, and finally selects the three sub-elements of the
zipped list as separate columns using selectExpr(). The output should
be the desired DataFrame.



Regards,
Navneet Kr


On Thu, 16 Feb 2023 at 00:07, Enrico Minack  wrote:
>
> You have to take each row and zip the lists, each element of the result 
> becomes one new row.
>
> So turn write a method that turns
>   Row(List("A","B","null"), List("C","D","null"), List("E","null","null"))
> into
>   List(List("A","C","E"), List("B","D","null"), List("null","null","null"))
> and use flatmap with that method.
>
> In Scala, this would read:
>
> df.flatMap { row => (row.getSeq[String](0), row.getSeq[String](1), 
> row.getSeq[String](2)).zipped.toIterable }.show()
>
> Enrico
>
>
> Am 14.02.23 um 22:54 schrieb sam smith:
>
> Hello guys,
>
> I have the following dataframe:
>
> col1
>
> col2
>
> col3
>
> ["A","B","null"]
>
> ["C","D","null"]
>
> ["E","null","null"]
>
>
>
> I want to explode it to the following dataframe:
>
> col1
>
> col2
>
> col3
>
> "A"
>
> "C"
>
> "E"
>
> "B"
>
> "D"
>
> "null"
>
> "null"
>
> "null"
>
> "null"
>
>
> How to do that (preferably in Java) using the explode() method ? knowing that 
> something like the following won't yield correct output:
>
> for (String colName: dataset.columns())
> dataset=dataset.withColumn(colName,explode(dataset.col(colName)));
>
>
>

-
To unsubscribe e-mail: user-unsubscr...@spark.apache.org



Re: How to explode array columns of a dataframe having the same length

2023-02-16 Thread Enrico Minack
You have to take each row and zip the lists, each element of the result 
becomes one new row.


So turn write a method that turns
  Row(List("A","B","null"), List("C","D","null"), List("E","null","null"))
into
  List(List("A","C","E"), List("B","D","null"), List("null","null","null"))
and use flatmap with that method.

In Scala, this would read:

df.flatMap { row => (row.getSeq[String](0), row.getSeq[String](1), 
row.getSeq[String](2)).zipped.toIterable }.show()


Enrico


Am 14.02.23 um 22:54 schrieb sam smith:

Hello guys,

I have the following dataframe:

*col1*



*col2*



*col3*

["A","B","null"]



["C","D","null"]



["E","null","null"]




I want to explode it to the following dataframe:

*col1*



*col2*



*col3*

"A"



"C"



"E"

"B"



"D"



"null"

"null"



"null"



"null"


How to do that (preferably in Java) using the explode() method ? 
knowing that something like the following won't yield correct output:


for (String colName: dataset.columns())
dataset=dataset.withColumn(colName,explode(dataset.col(colName)));




How to explode array columns of a dataframe having the same length

2023-02-14 Thread sam smith
Hello guys,

I have the following dataframe:

*col1*

*col2*

*col3*

["A","B","null"]

["C","D","null"]

["E","null","null"]
I want to explode it to the following dataframe:

*col1*

*col2*

*col3*

"A"

"C"

"E"

"B"

"D"

"null"

"null"

"null"

"null"

How to do that (preferably in Java) using the explode() method ? knowing
that something like the following won't yield correct output:

for (String colName: dataset.columns())
dataset=dataset.withColumn(colName,explode(dataset.col(colName)));