Yes, Great. I thought it was math.max instead of math.min on that line. Thank
you!
From: Ye Xianjin [mailto:advance...@gmail.com]
Sent: Tuesday, July 22, 2014 11:37 AM
To: user@spark.apache.org
Subject: Re: defaultMinPartitions in textFile
well, I think you miss this line of code in SparkContext.scala
line 1242-1243(master):
/** Default min number of partitions for Hadoop RDDs when not given by user */
def defaultMinPartitions: Int = math.min(defaultParallelism, 2)
so the defaultMinPartitions will be 2 unless the defaultParallelism is less
than 2...
--
Ye Xianjin
Sent with Sparrowhttp://www.sparrowmailapp.com/?sig
On Tuesday, July 22, 2014 at 10:18 AM, Wang, Jensen wrote:
Hi,
I started to use spark on yarn recently and found a problem while
tuning my program.
When SparkContext is initialized as sc and ready to read text file from hdfs,
the textFile(path, defaultMinPartitions) method is called.
I traced down the second parameter in the spark source code and finally found
this:
conf.getInt(spark.default.parallelism, math.max(totalCoreCount.get(), 2))
in CoarseGrainedSchedulerBackend.scala
I do not specify the property “spark.default.parallelism” anywhere so the
getInt will return value from the larger one between totalCoreCount and 2.
When I submit the application using spark-submit and specify the parameter:
--num-executors 2 --executor-cores 6, I suppose the totalCoreCount will be
2*6 = 12, so defaultMinPartitions will be 12.
But when I print the value of defaultMinPartitions in my program, I still get 2
in return, How does this happen, or where do I make a mistake?