We are building a wrapper that makes it possible to use reactive streams
(i.e. Observable, see reactivex.io) as input to Spark Streaming. We
therefore tried to create a custom receiver for Spark. However, the
Observable lives at the driver program and is generally not serializable.

Is it possible to create a receiver that runs next to the driver program and
therefore does not need to be serialized?

We tried the following, which gives a NotSerializableException:

object Main {
  def main(args: Array[String]): Unit = {
    val conf = new SparkConf().setMaster("local[2]").setAppName("Clock")
    val ssc = new StreamingContext(conf, Seconds(1))

    val data = // A non-serializable stream of data
    val stream = RxcreateStream(ssc, data)

    // Mapping, filtering, etc

    ssc.start()
    ssc.awaitTermination()
  }
}

with the createStream method something like the following:

object RxUtils {
  def createStream[T: ClassTag](scc_ : StreamingContext, observable:
Observable[T]): ReceiverInputDStream[T] = {
    new RxInputDStream[T](scc_, observable,
StorageLevel.MEMORY_AND_DISK_SER_2)
  }
}

class RxInputDStream[T: ClassTag](ssc_ : StreamingContext, observable:
Observable[T], storageLevel: StorageLevel) extends
ReceiverInputDStream[T](ssc_)  {
  override def getReceiver(): Receiver[T] = {
    new RxReceiver(observable, storageLevel)
  }
}

class RxReceiver[T](observable: Observable[T], storageLevel: StorageLevel)
extends Receiver[T](storageLevel) with Logging {
  var subscription: Option[Subscription] = None

  override def onStart(): Unit = {
    // NOTE: 'observable' is a reference to a variable in the driver program
    subscription = Some(
      observable
        .asInstanceOf[Observable[T]]
        .subscribe(x => store(x))
    )
  }
}

the comment indicates what causes the NotSerializableException.



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