Re: [one-users] error deploying the guest on VMWARE Host
can Any body give an idea on this? thanks, Siva On 12/8/2011 3:00 PM, Siva Prasad wrote: Hi All, I am getting the following error when i deploy the vm (with onedeploy 1 2) in vm.log after the disk is transffered. Thu Dec 8 14:39:01 2011 [VMM][E]: Wrong target value in DISK. Thu Dec 8 14:39:01 2011 [VMM][E]: deploy_action, error generating deployment file: /one/var/2/deployment.0 my onehost shows the following: oneadmin@onserver:~/var/2$ onehost list ID NAME RVM TCPU FCPU ACPU TMEM FMEM AMEM STAT 1 10.2.1.2000200200200 2.9G 2.3G 2.9G on --- my private.net file. oneadmin@oneserver:~/var/2$ onevnet show 0 VIRTUAL NETWORK 0 INFORMATION ID : 0 USER : oneadmin GROUP : oneadmin PUBLIC : No USED LEASES: 2 VIRTUAL NETWORK TEMPLATE BRIDGE=eth0 NAME=Private NETWORK_ADDRESS=10.2.1.0 NETWORK_SIZE=250 TYPE=RANGED LEASES INFORMATION LEASE=[ IP=10.2.1.1, MAC=02:00:c0:a8:08:01, USED=1, VID=1 ] LEASE=[ IP=10.2.1.2, MAC=02:00:c0:a8:08:02, USED=1, VID=2 ] my onevm.template file ( this is the file i am using to create onevm ) oneadmin@onserver:~/var/2$ cat ../../config/onevm.template NAME=VMwareVM MEMORY=256 CPU=1 NIC=[NETWORK_ID = 0 ] DISK=[ source=/one/var/images/StaticbaseImg, clone=yes, save=no] oneadmin@leopard3:~/var/2$ file /one/var/2/images/disk.0 gets created, the vm.log show the following Thu Dec 8 14:57:05 2011 [LCM][I]: New VM state is BOOT Thu Dec 8 14:57:05 2011 [VMM][I]: Generating deployment file: /one/var/2/deployment.0 Thu Dec 8 14:57:05 2011 [VMM][E]: Wrong target value in DISK. Thu Dec 8 14:57:05 2011 [VMM][E]: deploy_action, error generating deployment file: /one/var/4/deployment.0 Thu Dec 8 14:57:05 2011 [DiM][I]: New VM state is FAILED. Please help me Thanks, siva ___ Users mailing list Users@lists.opennebula.org http://lists.opennebula.org/listinfo.cgi/users-opennebula.org
Re: [one-users] xmlrpc client
Even when I use that API, I still get Unauthorized exception.
What is the proper way to form a session string that gets user (for start
oneadmin) authenticated and authorized in Java client so that I can test
other methods?
I use client function: Client client = new Client(session_string,
server_url);
public *Client*(java.lang.String secret,
java.lang.String endpoint)
throws ClientConfigurationException
http://opennebula.org/doc/3.0/oca/java/org/opennebula/client/ClientConfigurationException.html
On Thu, Dec 8, 2011 at 5:16 PM, Prakhar Srivastava prakhar@gmail.comwrote:
Hi Ksenija,
Why don't you simply use the Java OpenNebula Cloud
APIhttp://opennebula.org/documentation:rel3.0:java that
is packaged with opennebula. If there is no specific scenario, its best to
use them.
Prakhar
On Thu, Dec 8, 2011 at 3:23 PM, Ksenija Poljak ksenija.pol...@altus-it.hr
wrote:
Hi, I'm using opennebula 3 and I'm trying to write an xmlrpc Java client.
I'm not able to connect my client to opennebula server.
I keep getting unauthorized exception:
org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
returned unexpected status: Unauthorized
My testing program:
package open.nebula.client;
import java.net.MalformedURLException;
import java.net.URL;
import org.apache.xmlrpc.XmlRpcException;
import org.apache.xmlrpc.client.XmlRpcClient;
import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;
public class OpenNebulaClient{
private XmlRpcClient client = new XmlRpcClient();;
private XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
private String session =
oneadmin:ffd775fdb8e47ebf5b68513843f31742f74118e8;
public OpenNebulaClient(String server_url)
{
try{
this.config.setServerURL(new URL(server_url));
this.client.setConfig(this.config);
}catch(MalformedURLException e){
System.err.println(e);
}
}
public void getUserInfo(int id) throws XmlRpcException
{
Object[] params = {session,id};
try {
Object[] result = (Object[])this.client.execute(
one.user.info,params);
if(!result[0].equals(null)) {
boolean success = (Boolean)result[0];
String str_res = (String)result[1];
System.out.println(success=+success);
System.out.println(result=+str_res);
}else{
System.out.println(success=0);
}
}catch (XmlRpcException e) {
System.err.println(e);
//e.printStackTrace();
}
}
public static void main(String[] args)
{
OpenNebulaClient on_client = new
OpenNebulaClient(http://server_ip:port/RPC2;);
try{
on_client.getUserInfo(0);
}catch(XmlRpcException xmlrpce){
System.err.println(xmlrpce);
}
}
}
I'm confused becose when I look at examples on the web, there are methods
used as one.userinfo, and on opennebula official site they are listed in
form: one.user.info.
Session string I used consists of username:password that I get listed
with command: 'oneuser show 0' on opennebula server.
Client and opennebula server are on different machines.
I'm not sure what I do wrong. Any suggestions would be more than
helpfull. Tnx in advance.
the full stackTrace of error:
org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
returned unexpected status: Unauthorized
at
org.apache.xmlrpc.client.XmlRpcSunHttpTransport.getInputStream(XmlRpcSunHttpTransport.java:94)
at
org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:152)
at
org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143)
at
org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:69)
at
org.apache.xmlrpc.client.XmlRpcClientWorker.execute(XmlRpcClientWorker.java:56)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:167)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:137)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:126)
at
open.nebula.client.OpenNebulaClient.getUserInfo(OpenNebulaClient.java:30)
at open.nebula.client.OpenNebulaClient.main(OpenNebulaClient.java:49)
___
Users mailing list
Users@lists.opennebula.org
http://lists.opennebula.org/listinfo.cgi/users-opennebula.org
___
Users mailing list
Users@lists.opennebula.org
http://lists.opennebula.org/listinfo.cgi/users-opennebula.org
___
Users mailing list
Users@lists.opennebula.org
http://lists.opennebula.org/listinfo.cgi/users-opennebula.org
Re: [one-users] xmlrpc client
Hi,
This is how I create a connection to the server
oneClient = new Client(oneadmin:onepass,http://192.168.1.5:2633/RPC2;);
Check that you are using the
import org.opennebula.client.Client;
to make user that you are using the correct client. Also send the
stacktrace if you are still facing problems.
Prakhar
On Fri, Dec 9, 2011 at 5:03 PM, Ksenija Poljak
ksenija.pol...@altus-it.hrwrote:
Even when I use that API, I still get Unauthorized exception.
What is the proper way to form a session string that gets user (for start
oneadmin) authenticated and authorized in Java client so that I can test
other methods?
I use client function: Client client = new Client(session_string,
server_url);
public *Client*(java.lang.String secret,
java.lang.String endpoint)
throws ClientConfigurationException
http://opennebula.org/doc/3.0/oca/java/org/opennebula/client/ClientConfigurationException.html
On Thu, Dec 8, 2011 at 5:16 PM, Prakhar Srivastava
prakhar@gmail.comwrote:
Hi Ksenija,
Why don't you simply use the Java OpenNebula Cloud
APIhttp://opennebula.org/documentation:rel3.0:java that
is packaged with opennebula. If there is no specific scenario, its best to
use them.
Prakhar
On Thu, Dec 8, 2011 at 3:23 PM, Ksenija Poljak
ksenija.pol...@altus-it.hr wrote:
Hi, I'm using opennebula 3 and I'm trying to write an xmlrpc Java client.
I'm not able to connect my client to opennebula server.
I keep getting unauthorized exception:
org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
returned unexpected status: Unauthorized
My testing program:
package open.nebula.client;
import java.net.MalformedURLException;
import java.net.URL;
import org.apache.xmlrpc.XmlRpcException;
import org.apache.xmlrpc.client.XmlRpcClient;
import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;
public class OpenNebulaClient{
private XmlRpcClient client = new XmlRpcClient();;
private XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
private String session =
oneadmin:ffd775fdb8e47ebf5b68513843f31742f74118e8;
public OpenNebulaClient(String server_url)
{
try{
this.config.setServerURL(new URL(server_url));
this.client.setConfig(this.config);
}catch(MalformedURLException e){
System.err.println(e);
}
}
public void getUserInfo(int id) throws XmlRpcException
{
Object[] params = {session,id};
try {
Object[] result = (Object[])this.client.execute(
one.user.info,params);
if(!result[0].equals(null)) {
boolean success = (Boolean)result[0];
String str_res = (String)result[1];
System.out.println(success=+success);
System.out.println(result=+str_res);
}else{
System.out.println(success=0);
}
}catch (XmlRpcException e) {
System.err.println(e);
//e.printStackTrace();
}
}
public static void main(String[] args)
{
OpenNebulaClient on_client = new
OpenNebulaClient(http://server_ip:port/RPC2;);
try{
on_client.getUserInfo(0);
}catch(XmlRpcException xmlrpce){
System.err.println(xmlrpce);
}
}
}
I'm confused becose when I look at examples on the web, there are
methods used as one.userinfo, and on opennebula official site they are
listed in form: one.user.info.
Session string I used consists of username:password that I get listed
with command: 'oneuser show 0' on opennebula server.
Client and opennebula server are on different machines.
I'm not sure what I do wrong. Any suggestions would be more than
helpfull. Tnx in advance.
the full stackTrace of error:
org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
returned unexpected status: Unauthorized
at
org.apache.xmlrpc.client.XmlRpcSunHttpTransport.getInputStream(XmlRpcSunHttpTransport.java:94)
at
org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:152)
at
org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143)
at
org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:69)
at
org.apache.xmlrpc.client.XmlRpcClientWorker.execute(XmlRpcClientWorker.java:56)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:167)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:137)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:126)
at
open.nebula.client.OpenNebulaClient.getUserInfo(OpenNebulaClient.java:30)
at open.nebula.client.OpenNebulaClient.main(OpenNebulaClient.java:49)
___
Users mailing list
Users@lists.opennebula.org
http://lists.opennebula.org/listinfo.cgi/users-opennebula.org
___
Users mailing list
Users@lists.opennebula.org
http://lists.opennebula.org/listinfo.cgi/users-opennebula.org
___
Users mailing list
Re: [one-users] xmlrpc client
I do the same thing and is not working. This line alone does not cause any
problems. But when I try to use UserPool.info(client); or any other method,
returned error string is: HTTP server returned unexpected status:
Unauthorized.
On Fri, Dec 9, 2011 at 12:52 PM, Prakhar Srivastava
prakhar@gmail.comwrote:
Hi,
This is how I create a connection to the server
oneClient = new Client(oneadmin:onepass,http://192.168.1.5:2633/RPC2;);
Check that you are using the
import org.opennebula.client.Client;
to make user that you are using the correct client. Also send the
stacktrace if you are still facing problems.
Prakhar
On Fri, Dec 9, 2011 at 5:03 PM, Ksenija Poljak ksenija.pol...@altus-it.hr
wrote:
Even when I use that API, I still get Unauthorized exception.
What is the proper way to form a session string that gets user (for start
oneadmin) authenticated and authorized in Java client so that I can test
other methods?
I use client function: Client client = new Client(session_string,
server_url);
public *Client*(java.lang.String secret,
java.lang.String endpoint)
throws ClientConfigurationException
http://opennebula.org/doc/3.0/oca/java/org/opennebula/client/ClientConfigurationException.html
On Thu, Dec 8, 2011 at 5:16 PM, Prakhar Srivastava prakhar@gmail.com
wrote:
Hi Ksenija,
Why don't you simply use the Java OpenNebula Cloud
APIhttp://opennebula.org/documentation:rel3.0:java that
is packaged with opennebula. If there is no specific scenario, its best to
use them.
Prakhar
On Thu, Dec 8, 2011 at 3:23 PM, Ksenija Poljak
ksenija.pol...@altus-it.hr wrote:
Hi, I'm using opennebula 3 and I'm trying to write an xmlrpc Java
client.
I'm not able to connect my client to opennebula server.
I keep getting unauthorized exception:
org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
returned unexpected status: Unauthorized
My testing program:
package open.nebula.client;
import java.net.MalformedURLException;
import java.net.URL;
import org.apache.xmlrpc.XmlRpcException;
import org.apache.xmlrpc.client.XmlRpcClient;
import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;
public class OpenNebulaClient{
private XmlRpcClient client = new XmlRpcClient();;
private XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
private String session =
oneadmin:ffd775fdb8e47ebf5b68513843f31742f74118e8;
public OpenNebulaClient(String server_url)
{
try{
this.config.setServerURL(new URL(server_url));
this.client.setConfig(this.config);
}catch(MalformedURLException e){
System.err.println(e);
}
}
public void getUserInfo(int id) throws XmlRpcException
{
Object[] params = {session,id};
try {
Object[] result = (Object[])this.client.execute(
one.user.info,params);
if(!result[0].equals(null)) {
boolean success = (Boolean)result[0];
String str_res = (String)result[1];
System.out.println(success=+success);
System.out.println(result=+str_res);
}else{
System.out.println(success=0);
}
}catch (XmlRpcException e) {
System.err.println(e);
//e.printStackTrace();
}
}
public static void main(String[] args)
{
OpenNebulaClient on_client = new
OpenNebulaClient(http://server_ip:port/RPC2;);
try{
on_client.getUserInfo(0);
}catch(XmlRpcException xmlrpce){
System.err.println(xmlrpce);
}
}
}
I'm confused becose when I look at examples on the web, there are
methods used as one.userinfo, and on opennebula official site they are
listed in form: one.user.info.
Session string I used consists of username:password that I get listed
with command: 'oneuser show 0' on opennebula server.
Client and opennebula server are on different machines.
I'm not sure what I do wrong. Any suggestions would be more than
helpfull. Tnx in advance.
the full stackTrace of error:
org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
returned unexpected status: Unauthorized
at
org.apache.xmlrpc.client.XmlRpcSunHttpTransport.getInputStream(XmlRpcSunHttpTransport.java:94)
at
org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:152)
at
org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143)
at
org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:69)
at
org.apache.xmlrpc.client.XmlRpcClientWorker.execute(XmlRpcClientWorker.java:56)
at
org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:167)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:137)
at
org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:126)
at
open.nebula.client.OpenNebulaClient.getUserInfo(OpenNebulaClient.java:30)
at open.nebula.client.OpenNebulaClient.main(OpenNebulaClient.java:49)
___
Users mailing list
Re: [one-users] xmlrpc client
You appear to use the hashed password and not the password itself. Use the
real password to construct the session string.
On Fri, Dec 9, 2011 at 5:38 PM, Ksenija Poljak
ksenija.pol...@altus-it.hrwrote:
I do the same thing and is not working. This line alone does not cause any
problems. But when I try to use UserPool.info(client); or any other method,
returned error string is: HTTP server returned unexpected status:
Unauthorized.
On Fri, Dec 9, 2011 at 12:52 PM, Prakhar Srivastava prakhar@gmail.com
wrote:
Hi,
This is how I create a connection to the server
oneClient = new Client(oneadmin:onepass,http://192.168.1.5:2633/RPC2
);
Check that you are using the
import org.opennebula.client.Client;
to make user that you are using the correct client. Also send the
stacktrace if you are still facing problems.
Prakhar
On Fri, Dec 9, 2011 at 5:03 PM, Ksenija Poljak
ksenija.pol...@altus-it.hr wrote:
Even when I use that API, I still get Unauthorized exception.
What is the proper way to form a session string that gets user (for
start oneadmin) authenticated and authorized in Java client so that I can
test other methods?
I use client function: Client client = new Client(session_string,
server_url);
public *Client*(java.lang.String secret,
java.lang.String endpoint)
throws ClientConfigurationException
http://opennebula.org/doc/3.0/oca/java/org/opennebula/client/ClientConfigurationException.html
On Thu, Dec 8, 2011 at 5:16 PM, Prakhar Srivastava
prakhar@gmail.com wrote:
Hi Ksenija,
Why don't you simply use the Java OpenNebula Cloud
APIhttp://opennebula.org/documentation:rel3.0:java that
is packaged with opennebula. If there is no specific scenario, its best to
use them.
Prakhar
On Thu, Dec 8, 2011 at 3:23 PM, Ksenija Poljak
ksenija.pol...@altus-it.hr wrote:
Hi, I'm using opennebula 3 and I'm trying to write an xmlrpc Java
client.
I'm not able to connect my client to opennebula server.
I keep getting unauthorized exception:
org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
returned unexpected status: Unauthorized
My testing program:
package open.nebula.client;
import java.net.MalformedURLException;
import java.net.URL;
import org.apache.xmlrpc.XmlRpcException;
import org.apache.xmlrpc.client.XmlRpcClient;
import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;
public class OpenNebulaClient{
private XmlRpcClient client = new XmlRpcClient();;
private XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
private String session =
oneadmin:ffd775fdb8e47ebf5b68513843f31742f74118e8;
public OpenNebulaClient(String server_url)
{
try{
this.config.setServerURL(new URL(server_url));
this.client.setConfig(this.config);
}catch(MalformedURLException e){
System.err.println(e);
}
}
public void getUserInfo(int id) throws XmlRpcException
{
Object[] params = {session,id};
try {
Object[] result = (Object[])this.client.execute(
one.user.info,params);
if(!result[0].equals(null)) {
boolean success = (Boolean)result[0];
String str_res = (String)result[1];
System.out.println(success=+success);
System.out.println(result=+str_res);
}else{
System.out.println(success=0);
}
}catch (XmlRpcException e) {
System.err.println(e);
//e.printStackTrace();
}
}
public static void main(String[] args)
{
OpenNebulaClient on_client = new
OpenNebulaClient(http://server_ip:port/RPC2;);
try{
on_client.getUserInfo(0);
}catch(XmlRpcException xmlrpce){
System.err.println(xmlrpce);
}
}
}
I'm confused becose when I look at examples on the web, there are
methods used as one.userinfo, and on opennebula official site they are
listed in form: one.user.info.
Session string I used consists of username:password that I get listed
with command: 'oneuser show 0' on opennebula server.
Client and opennebula server are on different machines.
I'm not sure what I do wrong. Any suggestions would be more than
helpfull. Tnx in advance.
the full stackTrace of error:
org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
returned unexpected status: Unauthorized
at
org.apache.xmlrpc.client.XmlRpcSunHttpTransport.getInputStream(XmlRpcSunHttpTransport.java:94)
at
org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:152)
at
org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143)
at
org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:69)
at
org.apache.xmlrpc.client.XmlRpcClientWorker.execute(XmlRpcClientWorker.java:56)
at
org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:167)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:137)
at
org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:126)
at
Re: [one-users] xmlrpc client
Thank you very much for your help.
The problem was actually in xmlrpc port. :)
On Fri, Dec 9, 2011 at 1:36 PM, Ksenija Poljak
ksenija.pol...@altus-it.hrwrote:
I use the real password.
On Fri, Dec 9, 2011 at 1:32 PM, Prakhar Srivastava
prakhar@gmail.comwrote:
You appear to use the hashed password and not the password itself. Use
the real password to construct the session string.
On Fri, Dec 9, 2011 at 5:38 PM, Ksenija Poljak
ksenija.pol...@altus-it.hr wrote:
I do the same thing and is not working. This line alone does not cause
any problems. But when I try to use UserPool.info(client); or any other
method, returned error string is: HTTP server returned unexpected status:
Unauthorized.
On Fri, Dec 9, 2011 at 12:52 PM, Prakhar Srivastava
prakhar@gmail.com wrote:
Hi,
This is how I create a connection to the server
oneClient = new Client(oneadmin:onepass,http://192.168.1.5:2633/RPC2
);
Check that you are using the
import org.opennebula.client.Client;
to make user that you are using the correct client. Also send the
stacktrace if you are still facing problems.
Prakhar
On Fri, Dec 9, 2011 at 5:03 PM, Ksenija Poljak
ksenija.pol...@altus-it.hr wrote:
Even when I use that API, I still get Unauthorized exception.
What is the proper way to form a session string that gets user (for
start oneadmin) authenticated and authorized in Java client so that I can
test other methods?
I use client function: Client client = new Client(session_string,
server_url);
public *Client*(java.lang.String secret,
java.lang.String endpoint)
throws ClientConfigurationException
http://opennebula.org/doc/3.0/oca/java/org/opennebula/client/ClientConfigurationException.html
On Thu, Dec 8, 2011 at 5:16 PM, Prakhar Srivastava
prakhar@gmail.com wrote:
Hi Ksenija,
Why don't you simply use the Java OpenNebula Cloud
APIhttp://opennebula.org/documentation:rel3.0:java that
is packaged with opennebula. If there is no specific scenario, its best
to
use them.
Prakhar
On Thu, Dec 8, 2011 at 3:23 PM, Ksenija Poljak
ksenija.pol...@altus-it.hr wrote:
Hi, I'm using opennebula 3 and I'm trying to write an xmlrpc Java
client.
I'm not able to connect my client to opennebula server.
I keep getting unauthorized exception:
org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
returned unexpected status: Unauthorized
My testing program:
package open.nebula.client;
import java.net.MalformedURLException;
import java.net.URL;
import org.apache.xmlrpc.XmlRpcException;
import org.apache.xmlrpc.client.XmlRpcClient;
import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;
public class OpenNebulaClient{
private XmlRpcClient client = new XmlRpcClient();;
private XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
private String session =
oneadmin:ffd775fdb8e47ebf5b68513843f31742f74118e8;
public OpenNebulaClient(String server_url)
{
try{
this.config.setServerURL(new URL(server_url));
this.client.setConfig(this.config);
}catch(MalformedURLException e){
System.err.println(e);
}
}
public void getUserInfo(int id) throws XmlRpcException
{
Object[] params = {session,id};
try {
Object[] result = (Object[])this.client.execute(
one.user.info,params);
if(!result[0].equals(null)) {
boolean success = (Boolean)result[0];
String str_res = (String)result[1];
System.out.println(success=+success);
System.out.println(result=+str_res);
}else{
System.out.println(success=0);
}
}catch (XmlRpcException e) {
System.err.println(e);
//e.printStackTrace();
}
}
public static void main(String[] args)
{
OpenNebulaClient on_client = new
OpenNebulaClient(http://server_ip:port/RPC2;);
try{
on_client.getUserInfo(0);
}catch(XmlRpcException xmlrpce){
System.err.println(xmlrpce);
}
}
}
I'm confused becose when I look at examples on the web, there are
methods used as one.userinfo, and on opennebula official site they are
listed in form: one.user.info.
Session string I used consists of username:password that I get
listed with command: 'oneuser show 0' on opennebula server.
Client and opennebula server are on different machines.
I'm not sure what I do wrong. Any suggestions would be more than
helpfull. Tnx in advance.
the full stackTrace of error:
org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
returned unexpected status: Unauthorized
at
org.apache.xmlrpc.client.XmlRpcSunHttpTransport.getInputStream(XmlRpcSunHttpTransport.java:94)
at
org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:152)
at
org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143)
at
org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:69)
at
Re: [one-users] Creating virtual machines from scratch
Hello Richard On 08.12.2011 17:45, richard -rw- weinberger wrote: I'm a bit confused how to create a vm from scratch. Assume I want a vm running with CentOS6 and a new virtual hard disk of 500GiB. How can I create a new disk using OpenNebula (especially with Sunstone)? I do not know how to do this steps in Sunstone, I did it with the command line tools. Create the image manually (outside of OpenNebula) with this steps (for KVM): On a system which has KVM available: qemu-img create -f raw servername.img 10G qemu-system-x86_64 -hda servername.img -cdrom /path/to/install.iso -boot d -m 512 Connect through VNC for installation, the above command will report you the used port (default 5900), see blow as qemu-system-x86_64 listen only on localhost for VNC qemu-system-x86_64 servername.img -m 512 # to test after install Connect through VNC login and run 'poweroff' as root or with sudo Now on the front-end: Create an image template (servername-image.one) oneimage register servername-image.one Create an VM template for the host (servername.one) onevm create servername.one Connect to VNC on the cluster node: I do not know about your workstation, but from my Mac client I use Chicken [1], which supports connection through ssh. I guess there is a VNC client for the OS of your workstation available which also can do this. Else you could run it with manual ssh forwarding like this: ssh -L localhost:5900:localhost:5907 server-with-KVM replace 5907 with the port which qemu-system-x86_64 as reported and then use the local VNC client to connect to localhost port 5900. [1] http://sourceforge.net/projects/chicken/ In my setup each vm will have it's own disk image, thus no disk image needs to be copied. Is there a way to enforce this? The best is to register each image in the Image Repository with 'oneimage register ...' A final question, is it possible to change the boot order of a vm? Do I really have to delete and recreate it? You need to shutdown and recreate the VM. Best done with the command line tool 'onevm create template' and the template you can modify. bye Fabian ___ Users mailing list Users@lists.opennebula.org http://lists.opennebula.org/listinfo.cgi/users-opennebula.org
Re: [one-users] Access network by name (custom attributes)
Hello Tomáš On 09.12.2011 10:42, Tomáš Nechutný wrote: possible to define network by name (instead of id)? I tried NETWORK=local, NETWORK=\local\ and same with NAME instead of NETWORK_ID=1, but it doesn't work. As far as I know with OpenNebula 3.0 only IDs can be uses. bye Fabian ___ Users mailing list Users@lists.opennebula.org http://lists.opennebula.org/listinfo.cgi/users-opennebula.org
Re: [one-users] [help]Could not create domain
I modified the user and group in /etc/libvirt/qemu.conf , is that correct? 2011/12/10 Fabian Wenk fab...@wenks.ch Hello Cat On 09.12.2011 14:35, cat fa wrote: Fri Dec 9 04:31:57 2011 [VMM][I]: Command execution fail: 'if [ -x /var/tmp/one/vmm/kvm/deploy ]; then /var/tmp/one/vmm/kvm/deploy /var/lib/one//10/images/**deployment.0 1.185.4.109 10 1.185.4.109; else exit 42; fi' Fri Dec 9 04:31:57 2011 [VMM][I]: error: Failed to create domain from /var/lib/one//10/images/**deployment.0 Is the configuration for libvirtd correct does is allow to be usesed by the oneadmin user or one of his groups it is member of? bye Fabian __**_ Users mailing list Users@lists.opennebula.org http://lists.opennebula.org/**listinfo.cgi/users-opennebula.**orghttp://lists.opennebula.org/listinfo.cgi/users-opennebula.org ___ Users mailing list Users@lists.opennebula.org http://lists.opennebula.org/listinfo.cgi/users-opennebula.org
