subject:"\[one\-users\] xmlrpc client"

Re: [one-users] xmlrpc client

2011-12-09 Thread Ksenija Poljak

Even when I use that API, I still get Unauthorized exception.
What is the proper way to form a session string that gets user (for start
oneadmin) authenticated and authorized in Java client so that I can test
other methods?
I use client function: Client client = new Client(session_string,
server_url);

public *Client*(java.lang.String secret,
  java.lang.String endpoint)
   throws ClientConfigurationException
http://opennebula.org/doc/3.0/oca/java/org/opennebula/client/ClientConfigurationException.html



On Thu, Dec 8, 2011 at 5:16 PM, Prakhar Srivastava prakhar@gmail.comwrote:

 Hi Ksenija,
 Why don't you simply use the Java OpenNebula Cloud 
 APIhttp://opennebula.org/documentation:rel3.0:java that
 is packaged with opennebula. If there is no specific scenario, its best to
 use them.

 Prakhar

 On Thu, Dec 8, 2011 at 3:23 PM, Ksenija Poljak ksenija.pol...@altus-it.hr
  wrote:

 Hi, I'm using opennebula 3 and I'm trying to write an xmlrpc Java client.
 I'm not able to connect my client to opennebula server.
 I keep getting unauthorized exception:

 org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
 returned unexpected status: Unauthorized

 My testing program:

 package open.nebula.client;


 import java.net.MalformedURLException;
 import java.net.URL;

 import org.apache.xmlrpc.XmlRpcException;
 import org.apache.xmlrpc.client.XmlRpcClient;
 import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;

 public class OpenNebulaClient{
  private XmlRpcClient client = new XmlRpcClient();;
 private XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
  private String session =
 oneadmin:ffd775fdb8e47ebf5b68513843f31742f74118e8;
  public OpenNebulaClient(String server_url)
 {
 try{
  this.config.setServerURL(new URL(server_url));
 this.client.setConfig(this.config);
  }catch(MalformedURLException e){
 System.err.println(e);
 }
  }
  public void getUserInfo(int id) throws XmlRpcException
  {
 Object[] params = {session,id};
 try {
 Object[] result = (Object[])this.client.execute(
 one.user.info,params);
 if(!result[0].equals(null)) {
 boolean success = (Boolean)result[0];
 String str_res = (String)result[1];
 System.out.println(success=+success);
 System.out.println(result=+str_res);
 }else{
 System.out.println(success=0);
 }
 }catch (XmlRpcException e) {
 System.err.println(e);
  //e.printStackTrace();
 }
 }
  public static void main(String[] args)
 {
 OpenNebulaClient on_client = new

  OpenNebulaClient(http://server_ip:port/RPC2;);
 try{
 on_client.getUserInfo(0);
  }catch(XmlRpcException xmlrpce){
 System.err.println(xmlrpce);
 }
  }
 }


 I'm confused becose when I look at examples on the web, there are methods
 used as one.userinfo, and on opennebula official site they are listed in
 form: one.user.info.
 Session string I used consists of username:password that I get listed
 with command: 'oneuser show 0' on opennebula server.
 Client and opennebula server are on different machines.
 I'm not sure what I do wrong. Any suggestions would be more than
 helpfull. Tnx in advance.

 the full stackTrace of error:

 org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
 returned unexpected status: Unauthorized
 at
 org.apache.xmlrpc.client.XmlRpcSunHttpTransport.getInputStream(XmlRpcSunHttpTransport.java:94)
  at
 org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:152)
 at
 org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143)
  at
 org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:69)
 at
 org.apache.xmlrpc.client.XmlRpcClientWorker.execute(XmlRpcClientWorker.java:56)
  at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:167)
 at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:137)
  at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:126)
 at
 open.nebula.client.OpenNebulaClient.getUserInfo(OpenNebulaClient.java:30)
  at open.nebula.client.OpenNebulaClient.main(OpenNebulaClient.java:49)

 ___
 Users mailing list
 Users@lists.opennebula.org
 http://lists.opennebula.org/listinfo.cgi/users-opennebula.org



 ___
 Users mailing list
 Users@lists.opennebula.org
 http://lists.opennebula.org/listinfo.cgi/users-opennebula.org


___
Users mailing list
Users@lists.opennebula.org
http://lists.opennebula.org/listinfo.cgi/users-opennebula.org

Re: [one-users] xmlrpc client

2011-12-09 Thread Prakhar Srivastava

Hi,
This is how I create a connection to the server
oneClient = new Client(oneadmin:onepass,http://192.168.1.5:2633/RPC2;);

Check that you are using the
import org.opennebula.client.Client;

to make user that you are using the correct client. Also send the
stacktrace if you are still facing problems.

Prakhar

On Fri, Dec 9, 2011 at 5:03 PM, Ksenija Poljak
ksenija.pol...@altus-it.hrwrote:

 Even when I use that API, I still get Unauthorized exception.
 What is the proper way to form a session string that gets user (for start
 oneadmin) authenticated and authorized in Java client so that I can test
 other methods?
 I use client function: Client client = new Client(session_string,
 server_url);

 public *Client*(java.lang.String secret,
   java.lang.String endpoint)
throws ClientConfigurationException 
 http://opennebula.org/doc/3.0/oca/java/org/opennebula/client/ClientConfigurationException.html



 On Thu, Dec 8, 2011 at 5:16 PM, Prakhar Srivastava 
 prakhar@gmail.comwrote:

 Hi Ksenija,
 Why don't you simply use the Java OpenNebula Cloud 
 APIhttp://opennebula.org/documentation:rel3.0:java that
 is packaged with opennebula. If there is no specific scenario, its best to
 use them.

 Prakhar

 On Thu, Dec 8, 2011 at 3:23 PM, Ksenija Poljak 
 ksenija.pol...@altus-it.hr wrote:

 Hi, I'm using opennebula 3 and I'm trying to write an xmlrpc Java client.
 I'm not able to connect my client to opennebula server.
 I keep getting unauthorized exception:

 org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
 returned unexpected status: Unauthorized

 My testing program:

 package open.nebula.client;


 import java.net.MalformedURLException;
 import java.net.URL;

 import org.apache.xmlrpc.XmlRpcException;
 import org.apache.xmlrpc.client.XmlRpcClient;
 import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;

 public class OpenNebulaClient{
  private XmlRpcClient client = new XmlRpcClient();;
 private XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
  private String session =
 oneadmin:ffd775fdb8e47ebf5b68513843f31742f74118e8;
  public OpenNebulaClient(String server_url)
 {
 try{
  this.config.setServerURL(new URL(server_url));
 this.client.setConfig(this.config);
  }catch(MalformedURLException e){
 System.err.println(e);
 }
  }
  public void getUserInfo(int id) throws XmlRpcException
  {
 Object[] params = {session,id};
 try {
 Object[] result = (Object[])this.client.execute(
 one.user.info,params);
 if(!result[0].equals(null)) {
 boolean success = (Boolean)result[0];
 String str_res = (String)result[1];
 System.out.println(success=+success);
 System.out.println(result=+str_res);
 }else{
 System.out.println(success=0);
 }
 }catch (XmlRpcException e) {
 System.err.println(e);
  //e.printStackTrace();
 }
 }
  public static void main(String[] args)
 {
 OpenNebulaClient on_client = new

  OpenNebulaClient(http://server_ip:port/RPC2;);
 try{
 on_client.getUserInfo(0);
  }catch(XmlRpcException xmlrpce){
 System.err.println(xmlrpce);
 }
  }
 }


 I'm confused becose when I look at examples on the web, there are
 methods used as one.userinfo, and on opennebula official site they are
 listed in form: one.user.info.
 Session string I used consists of username:password that I get listed
 with command: 'oneuser show 0' on opennebula server.
 Client and opennebula server are on different machines.
 I'm not sure what I do wrong. Any suggestions would be more than
 helpfull. Tnx in advance.

 the full stackTrace of error:

 org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
 returned unexpected status: Unauthorized
 at
 org.apache.xmlrpc.client.XmlRpcSunHttpTransport.getInputStream(XmlRpcSunHttpTransport.java:94)
  at
 org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:152)
 at
 org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143)
  at
 org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:69)
 at
 org.apache.xmlrpc.client.XmlRpcClientWorker.execute(XmlRpcClientWorker.java:56)
  at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:167)
 at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:137)
  at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:126)
 at
 open.nebula.client.OpenNebulaClient.getUserInfo(OpenNebulaClient.java:30)
  at open.nebula.client.OpenNebulaClient.main(OpenNebulaClient.java:49)

 ___
 Users mailing list
 Users@lists.opennebula.org
 http://lists.opennebula.org/listinfo.cgi/users-opennebula.org



 ___
 Users mailing list
 Users@lists.opennebula.org
 http://lists.opennebula.org/listinfo.cgi/users-opennebula.org



 ___
 Users mailing list

Re: [one-users] xmlrpc client

2011-12-09 Thread Ksenija Poljak

I do the same thing and is not working. This line alone does not cause any
problems. But when I try to use UserPool.info(client); or any other method,
returned error string is: HTTP server returned unexpected status:
Unauthorized.

On Fri, Dec 9, 2011 at 12:52 PM, Prakhar Srivastava
prakhar@gmail.comwrote:

 Hi,
 This is how I create a connection to the server
 oneClient = new Client(oneadmin:onepass,http://192.168.1.5:2633/RPC2;);

 Check that you are using the
 import org.opennebula.client.Client;

 to make user that you are using the correct client. Also send the
 stacktrace if you are still facing problems.

 Prakhar


 On Fri, Dec 9, 2011 at 5:03 PM, Ksenija Poljak ksenija.pol...@altus-it.hr
  wrote:

 Even when I use that API, I still get Unauthorized exception.
 What is the proper way to form a session string that gets user (for start
 oneadmin) authenticated and authorized in Java client so that I can test
 other methods?
 I use client function: Client client = new Client(session_string,
 server_url);

 public *Client*(java.lang.String secret,
   java.lang.String endpoint)
throws ClientConfigurationException 
 http://opennebula.org/doc/3.0/oca/java/org/opennebula/client/ClientConfigurationException.html



 On Thu, Dec 8, 2011 at 5:16 PM, Prakhar Srivastava prakhar@gmail.com
  wrote:

 Hi Ksenija,
 Why don't you simply use the Java OpenNebula Cloud 
 APIhttp://opennebula.org/documentation:rel3.0:java that
 is packaged with opennebula. If there is no specific scenario, its best to
 use them.

 Prakhar

 On Thu, Dec 8, 2011 at 3:23 PM, Ksenija Poljak 
 ksenija.pol...@altus-it.hr wrote:

 Hi, I'm using opennebula 3 and I'm trying to write an xmlrpc Java
 client.
 I'm not able to connect my client to opennebula server.
 I keep getting unauthorized exception:

 org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
 returned unexpected status: Unauthorized

 My testing program:

 package open.nebula.client;


 import java.net.MalformedURLException;
 import java.net.URL;

 import org.apache.xmlrpc.XmlRpcException;
 import org.apache.xmlrpc.client.XmlRpcClient;
 import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;

 public class OpenNebulaClient{
  private XmlRpcClient client = new XmlRpcClient();;
 private XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
  private String session =
 oneadmin:ffd775fdb8e47ebf5b68513843f31742f74118e8;
  public OpenNebulaClient(String server_url)
 {
 try{
  this.config.setServerURL(new URL(server_url));
 this.client.setConfig(this.config);
  }catch(MalformedURLException e){
 System.err.println(e);
 }
  }
  public void getUserInfo(int id) throws XmlRpcException
  {
 Object[] params = {session,id};
 try {
 Object[] result = (Object[])this.client.execute(
 one.user.info,params);
 if(!result[0].equals(null)) {
 boolean success = (Boolean)result[0];
 String str_res = (String)result[1];
 System.out.println(success=+success);
 System.out.println(result=+str_res);
 }else{
 System.out.println(success=0);
 }
 }catch (XmlRpcException e) {
 System.err.println(e);
  //e.printStackTrace();
 }
 }
  public static void main(String[] args)
 {
 OpenNebulaClient on_client = new

  OpenNebulaClient(http://server_ip:port/RPC2;);
 try{
 on_client.getUserInfo(0);
  }catch(XmlRpcException xmlrpce){
 System.err.println(xmlrpce);
 }
  }
 }


 I'm confused becose when I look at examples on the web, there are
 methods used as one.userinfo, and on opennebula official site they are
 listed in form: one.user.info.
 Session string I used consists of username:password that I get listed
 with command: 'oneuser show 0' on opennebula server.
 Client and opennebula server are on different machines.
 I'm not sure what I do wrong. Any suggestions would be more than
 helpfull. Tnx in advance.

 the full stackTrace of error:

 org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
 returned unexpected status: Unauthorized
 at
 org.apache.xmlrpc.client.XmlRpcSunHttpTransport.getInputStream(XmlRpcSunHttpTransport.java:94)
  at
 org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:152)
 at
 org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143)
  at
 org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:69)
 at
 org.apache.xmlrpc.client.XmlRpcClientWorker.execute(XmlRpcClientWorker.java:56)
  at
 org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:167)
 at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:137)
  at
 org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:126)
 at
 open.nebula.client.OpenNebulaClient.getUserInfo(OpenNebulaClient.java:30)
  at open.nebula.client.OpenNebulaClient.main(OpenNebulaClient.java:49)

 ___
 Users mailing list

Re: [one-users] xmlrpc client

2011-12-09 Thread Prakhar Srivastava

You appear to use the hashed password and not the password itself. Use the
real password to construct the session string.


On Fri, Dec 9, 2011 at 5:38 PM, Ksenija Poljak
ksenija.pol...@altus-it.hrwrote:

 I do the same thing and is not working. This line alone does not cause any
 problems. But when I try to use UserPool.info(client); or any other method,
 returned error string is: HTTP server returned unexpected status:
 Unauthorized.

 On Fri, Dec 9, 2011 at 12:52 PM, Prakhar Srivastava prakhar@gmail.com
  wrote:

 Hi,
 This is how I create a connection to the server
 oneClient = new Client(oneadmin:onepass,http://192.168.1.5:2633/RPC2
 );

 Check that you are using the
 import org.opennebula.client.Client;

 to make user that you are using the correct client. Also send the
 stacktrace if you are still facing problems.

 Prakhar


 On Fri, Dec 9, 2011 at 5:03 PM, Ksenija Poljak 
 ksenija.pol...@altus-it.hr wrote:

 Even when I use that API, I still get Unauthorized exception.
 What is the proper way to form a session string that gets user (for
 start oneadmin) authenticated and authorized in Java client so that I can
 test other methods?
 I use client function: Client client = new Client(session_string,
 server_url);

 public *Client*(java.lang.String secret,
   java.lang.String endpoint)
throws ClientConfigurationException 
 http://opennebula.org/doc/3.0/oca/java/org/opennebula/client/ClientConfigurationException.html



 On Thu, Dec 8, 2011 at 5:16 PM, Prakhar Srivastava 
 prakhar@gmail.com wrote:

 Hi Ksenija,
 Why don't you simply use the Java OpenNebula Cloud 
 APIhttp://opennebula.org/documentation:rel3.0:java that
 is packaged with opennebula. If there is no specific scenario, its best to
 use them.

 Prakhar

 On Thu, Dec 8, 2011 at 3:23 PM, Ksenija Poljak 
 ksenija.pol...@altus-it.hr wrote:

 Hi, I'm using opennebula 3 and I'm trying to write an xmlrpc Java
 client.
 I'm not able to connect my client to opennebula server.
 I keep getting unauthorized exception:

 org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
 returned unexpected status: Unauthorized

 My testing program:

 package open.nebula.client;


 import java.net.MalformedURLException;
 import java.net.URL;

 import org.apache.xmlrpc.XmlRpcException;
 import org.apache.xmlrpc.client.XmlRpcClient;
 import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;

 public class OpenNebulaClient{
  private XmlRpcClient client = new XmlRpcClient();;
 private XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
  private String session =
 oneadmin:ffd775fdb8e47ebf5b68513843f31742f74118e8;
  public OpenNebulaClient(String server_url)
 {
 try{
  this.config.setServerURL(new URL(server_url));
 this.client.setConfig(this.config);
  }catch(MalformedURLException e){
 System.err.println(e);
 }
  }
  public void getUserInfo(int id) throws XmlRpcException
  {
 Object[] params = {session,id};
 try {
 Object[] result = (Object[])this.client.execute(
 one.user.info,params);
 if(!result[0].equals(null)) {
 boolean success = (Boolean)result[0];
 String str_res = (String)result[1];
 System.out.println(success=+success);
 System.out.println(result=+str_res);
 }else{
 System.out.println(success=0);
 }
 }catch (XmlRpcException e) {
 System.err.println(e);
  //e.printStackTrace();
 }
 }
  public static void main(String[] args)
 {
 OpenNebulaClient on_client = new

  OpenNebulaClient(http://server_ip:port/RPC2;);
 try{
 on_client.getUserInfo(0);
  }catch(XmlRpcException xmlrpce){
 System.err.println(xmlrpce);
 }
  }
 }


 I'm confused becose when I look at examples on the web, there are
 methods used as one.userinfo, and on opennebula official site they are
 listed in form: one.user.info.
 Session string I used consists of username:password that I get listed
 with command: 'oneuser show 0' on opennebula server.
 Client and opennebula server are on different machines.
 I'm not sure what I do wrong. Any suggestions would be more than
 helpfull. Tnx in advance.

 the full stackTrace of error:

 org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
 returned unexpected status: Unauthorized
 at
 org.apache.xmlrpc.client.XmlRpcSunHttpTransport.getInputStream(XmlRpcSunHttpTransport.java:94)
  at
 org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:152)
 at
 org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143)
  at
 org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:69)
 at
 org.apache.xmlrpc.client.XmlRpcClientWorker.execute(XmlRpcClientWorker.java:56)
  at
 org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:167)
 at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:137)
  at
 org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:126)
 at

Re: [one-users] xmlrpc client

2011-12-09 Thread Ksenija Poljak

Thank you very much for your help.
The problem was actually in xmlrpc port. :)

On Fri, Dec 9, 2011 at 1:36 PM, Ksenija Poljak
ksenija.pol...@altus-it.hrwrote:

 I use the real password.


 On Fri, Dec 9, 2011 at 1:32 PM, Prakhar Srivastava 
 prakhar@gmail.comwrote:

 You appear to use the hashed password and not the password itself. Use
 the real password to construct the session string.


 On Fri, Dec 9, 2011 at 5:38 PM, Ksenija Poljak 
 ksenija.pol...@altus-it.hr wrote:

 I do the same thing and is not working. This line alone does not cause
 any problems. But when I try to use UserPool.info(client); or any other
 method, returned error string is: HTTP server returned unexpected status:
 Unauthorized.

 On Fri, Dec 9, 2011 at 12:52 PM, Prakhar Srivastava 
 prakhar@gmail.com wrote:

 Hi,
 This is how I create a connection to the server
 oneClient = new Client(oneadmin:onepass,http://192.168.1.5:2633/RPC2
 );

 Check that you are using the
 import org.opennebula.client.Client;

 to make user that you are using the correct client. Also send the
 stacktrace if you are still facing problems.

 Prakhar


 On Fri, Dec 9, 2011 at 5:03 PM, Ksenija Poljak 
 ksenija.pol...@altus-it.hr wrote:

 Even when I use that API, I still get Unauthorized exception.
 What is the proper way to form a session string that gets user (for
 start oneadmin) authenticated and authorized in Java client so that I can
 test other methods?
 I use client function: Client client = new Client(session_string,
 server_url);

 public *Client*(java.lang.String secret,
   java.lang.String endpoint)
throws ClientConfigurationException 
 http://opennebula.org/doc/3.0/oca/java/org/opennebula/client/ClientConfigurationException.html



 On Thu, Dec 8, 2011 at 5:16 PM, Prakhar Srivastava 
 prakhar@gmail.com wrote:

 Hi Ksenija,
 Why don't you simply use the Java OpenNebula Cloud 
 APIhttp://opennebula.org/documentation:rel3.0:java that
 is packaged with opennebula. If there is no specific scenario, its best 
 to
 use them.

 Prakhar

 On Thu, Dec 8, 2011 at 3:23 PM, Ksenija Poljak 
 ksenija.pol...@altus-it.hr wrote:

 Hi, I'm using opennebula 3 and I'm trying to write an xmlrpc Java
 client.
 I'm not able to connect my client to opennebula server.
 I keep getting unauthorized exception:

 org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
 returned unexpected status: Unauthorized

 My testing program:

 package open.nebula.client;


 import java.net.MalformedURLException;
 import java.net.URL;

 import org.apache.xmlrpc.XmlRpcException;
 import org.apache.xmlrpc.client.XmlRpcClient;
 import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;

 public class OpenNebulaClient{
  private XmlRpcClient client = new XmlRpcClient();;
 private XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
  private String session =
 oneadmin:ffd775fdb8e47ebf5b68513843f31742f74118e8;
  public OpenNebulaClient(String server_url)
 {
 try{
  this.config.setServerURL(new URL(server_url));
 this.client.setConfig(this.config);
  }catch(MalformedURLException e){
 System.err.println(e);
 }
  }
  public void getUserInfo(int id) throws XmlRpcException
  {
 Object[] params = {session,id};
 try {
 Object[] result = (Object[])this.client.execute(
 one.user.info,params);
 if(!result[0].equals(null)) {
 boolean success = (Boolean)result[0];
 String str_res = (String)result[1];
 System.out.println(success=+success);
 System.out.println(result=+str_res);
 }else{
 System.out.println(success=0);
 }
 }catch (XmlRpcException e) {
 System.err.println(e);
  //e.printStackTrace();
 }
 }
  public static void main(String[] args)
 {
 OpenNebulaClient on_client = new

  OpenNebulaClient(http://server_ip:port/RPC2;);
 try{
 on_client.getUserInfo(0);
  }catch(XmlRpcException xmlrpce){
 System.err.println(xmlrpce);
 }
  }
 }


 I'm confused becose when I look at examples on the web, there are
 methods used as one.userinfo, and on opennebula official site they are
 listed in form: one.user.info.
 Session string I used consists of username:password that I get
 listed with command: 'oneuser show 0' on opennebula server.
 Client and opennebula server are on different machines.
 I'm not sure what I do wrong. Any suggestions would be more than
 helpfull. Tnx in advance.

 the full stackTrace of error:

 org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server
 returned unexpected status: Unauthorized
 at
 org.apache.xmlrpc.client.XmlRpcSunHttpTransport.getInputStream(XmlRpcSunHttpTransport.java:94)
  at
 org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:152)
 at
 org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143)
  at
 org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:69)
 at

[one-users] xmlrpc client

2011-12-08 Thread Ksenija Poljak

Hi, I'm using opennebula 3 and I'm trying to write an xmlrpc Java client.
I'm not able to connect my client to opennebula server.
I keep getting unauthorized exception:

org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server returned
unexpected status: Unauthorized

My testing program:

package open.nebula.client;


import java.net.MalformedURLException;
import java.net.URL;

import org.apache.xmlrpc.XmlRpcException;
import org.apache.xmlrpc.client.XmlRpcClient;
import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;

public class OpenNebulaClient{
private XmlRpcClient client = new XmlRpcClient();;
private XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
private String session =
oneadmin:ffd775fdb8e47ebf5b68513843f31742f74118e8;
 public OpenNebulaClient(String server_url)
{
try{
this.config.setServerURL(new URL(server_url));
this.client.setConfig(this.config);
}catch(MalformedURLException e){
System.err.println(e);
}
}
 public void getUserInfo(int id) throws XmlRpcException
{
Object[] params = {session,id};
try {
Object[] result = (Object[])this.client.execute(one.user.info
,params);
if(!result[0].equals(null)) {
boolean success = (Boolean)result[0];
String str_res = (String)result[1];
System.out.println(success=+success);
System.out.println(result=+str_res);
}else{
System.out.println(success=0);
}
}catch (XmlRpcException e) {
System.err.println(e);
//e.printStackTrace();
}
}
 public static void main(String[] args)
{
OpenNebulaClient on_client = new

 OpenNebulaClient(http://server_ip:port/RPC2;);
try{
on_client.getUserInfo(0);
}catch(XmlRpcException xmlrpce){
System.err.println(xmlrpce);
}
}
}


I'm confused becose when I look at examples on the web, there are methods
used as one.userinfo, and on opennebula official site they are listed in
form: one.user.info.
Session string I used consists of username:password that I get listed with
command: 'oneuser show 0' on opennebula server.
Client and opennebula server are on different machines.
I'm not sure what I do wrong. Any suggestions would be more than helpfull.
Tnx in advance.

the full stackTrace of error:

org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server returned
unexpected status: Unauthorized
at
org.apache.xmlrpc.client.XmlRpcSunHttpTransport.getInputStream(XmlRpcSunHttpTransport.java:94)
at
org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:152)
at
org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143)
at
org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:69)
at
org.apache.xmlrpc.client.XmlRpcClientWorker.execute(XmlRpcClientWorker.java:56)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:167)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:137)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:126)
at open.nebula.client.OpenNebulaClient.getUserInfo(OpenNebulaClient.java:30)
at open.nebula.client.OpenNebulaClient.main(OpenNebulaClient.java:49)
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