Re: java file path in exec:java
I see your problem now.
Would it be a problem for you to use ant to run the program instead of
the exec-plugin? Then you could have Ant convert the path:
pathconvert targetos=unix property=unix-path
path location=${project.build.outputDirectory} /
/pathconvert
Now if there was a way to have this property available in Maven, you
could use the exec-plugin, but I believe you can't access this property
(${unix-path}) in Maven...
Roland
On 21.04.2011 1:17, Zilvinas Vilutis wrote:
yes, I can do that, however ${project.build.outputDirectory} still
generates C:\folder1\folder2\... etc :)
Žilvinas Vilutis
Mobile: (+370) 652 38353
E-mail: cika...@gmail.com
On Wed, Apr 20, 2011 at 2:57 PM, Asmann, Roland
roland.asm...@adesso.at wrote:
What I meant was: don't use ${file.separator} and write '/' in your POM.
Or do you have a reason you need the variable?
On 20-04-11 23:51, Zilvinas Vilutis wrote:
Exactly, but I need *maven* to generate those / :)
I need the
${project.build.outputDirectory}${file.separator}orm.properties
to contain / in the output, but it generates the path with \
slashes, e.g. C:\path to myproject\target\classes\orm.properties
Regards
Žilvinas Vilutis
Mobile: (+370) 652 38353
E-mail: cika...@gmail.com
On Wed, Apr 20, 2011 at 12:57 PM, Asmann, Roland
roland.asm...@adesso.at wrote:
Just use the character '/', it works on Windows!
On 20-04-11 21:45, Zilvinas Vilutis wrote:
Hi maven users!
I'm trying to execute a java command and pass a path to a file as
an argument:
plugin
groupIdorg.codehaus.mojo/groupId
artifactIdexec-maven-plugin/artifactId
configuration
executablejava/executable
workingDirectory${project.build.outputDirectory}/workingDirectory
classpathScoperuntime/classpathScope
arguments
argument-c
${project.build.outputDirectory}${file.separator}orm.properties/argument
/arguments
mainClasscom.company.deploy.product.AutomatedProductDeploy/mainClass
/configuration
/plugin
And I'm using maven properties to construct the filename:
${project.build.outputDirectory}${file.separator}orm.properties
Unfortunately, I'm getting an exception from the java class I'm
running:
Caused by: java.io.FileNotFoundException: C:\path to my
project\target\classes\orm.properties (The filename, directory name,
or volume label syntax is incorrect)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.init(FileInputStream.java:106)
Most likely the it is using the argument and does not escape slashes
to new java.io.File( filePath )
As I don't have access to source code of the class - is there any way
to enforce maven use unix style path generation on windows? ( change
slashes to / )
I tried to override the ${file.separator} property - but it seems to
be read-only and doesn't help.
Any ideas?
Thank you!
Žilvinas Vilutis
E-mail: cika...@gmail.com
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
--
Roland Asmann
Senior Software Engineer
adesso Austria GmbH
Floridotower 26. Stock T +43 1 2198790-27
Floridsdorfer Hauptstr. 1 F +43 1 2198790-927
A-1210 Wien M +43 664 88657566
E roland.asm...@adesso.at
W www.adesso.at
-
business. people. technology.
-
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To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
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--
Roland Asmann
Senior Software Engineer
adesso Austria GmbH
Floridotower 26. Stock T +43 1 2198790-27
Floridsdorfer Hauptstr. 1 F +43 1 2198790-927
A-1210 Wien M +43 664 88657566
E roland.asm...@adesso.at
W www.adesso.at
-
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--
Roland Asmann
Senior Software Engineer
adesso Austria GmbH
Floridotower 26. Stock T +43 1 2198790-27
Floridsdorfer Hauptstr. 1 F +43 1 2198790-927
A-1210 Wien M +43 664 88657566
Re: java file path in exec:java
It seems gmaven might be able to help you out here:
http://maven.40175.n5.nabble.com/Exporting-Ant-properties-to-Maven-td510023.html#a510117
http://pastebin.com/XsAdbbcY
Roland
On 21.04.2011 12:14, Asmann, Roland wrote:
I see your problem now.
Would it be a problem for you to use ant to run the program instead of
the exec-plugin? Then you could have Ant convert the path:
pathconvert targetos=unix property=unix-path
path location=${project.build.outputDirectory} /
/pathconvert
Now if there was a way to have this property available in Maven, you
could use the exec-plugin, but I believe you can't access this property
(${unix-path}) in Maven...
Roland
On 21.04.2011 1:17, Zilvinas Vilutis wrote:
yes, I can do that, however ${project.build.outputDirectory} still
generates C:\folder1\folder2\... etc :)
Žilvinas Vilutis
Mobile: (+370) 652 38353
E-mail: cika...@gmail.com
On Wed, Apr 20, 2011 at 2:57 PM, Asmann, Roland
roland.asm...@adesso.at wrote:
What I meant was: don't use ${file.separator} and write '/' in your
POM.
Or do you have a reason you need the variable?
On 20-04-11 23:51, Zilvinas Vilutis wrote:
Exactly, but I need *maven* to generate those / :)
I need the
${project.build.outputDirectory}${file.separator}orm.properties
to contain / in the output, but it generates the path with \
slashes, e.g. C:\path to myproject\target\classes\orm.properties
Regards
Žilvinas Vilutis
Mobile: (+370) 652 38353
E-mail: cika...@gmail.com
On Wed, Apr 20, 2011 at 12:57 PM, Asmann, Roland
roland.asm...@adesso.at wrote:
Just use the character '/', it works on Windows!
On 20-04-11 21:45, Zilvinas Vilutis wrote:
Hi maven users!
I'm trying to execute a java command and pass a path to a file as
an argument:
plugin
groupIdorg.codehaus.mojo/groupId
artifactIdexec-maven-plugin/artifactId
configuration
executablejava/executable
workingDirectory${project.build.outputDirectory}/workingDirectory
classpathScoperuntime/classpathScope
arguments
argument-c
${project.build.outputDirectory}${file.separator}orm.properties/argument
/arguments
mainClasscom.company.deploy.product.AutomatedProductDeploy/mainClass
/configuration
/plugin
And I'm using maven properties to construct the filename:
${project.build.outputDirectory}${file.separator}orm.properties
Unfortunately, I'm getting an exception from the java class I'm
running:
Caused by: java.io.FileNotFoundException: C:\path to my
project\target\classes\orm.properties (The filename, directory
name,
or volume label syntax is incorrect)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.init(FileInputStream.java:106)
Most likely the it is using the argument and does not escape slashes
to new java.io.File( filePath )
As I don't have access to source code of the class - is there
any way
to enforce maven use unix style path generation on windows? ( change
slashes to / )
I tried to override the ${file.separator} property - but it seems to
be read-only and doesn't help.
Any ideas?
Thank you!
Žilvinas Vilutis
E-mail: cika...@gmail.com
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
--
Roland Asmann
Senior Software Engineer
adesso Austria GmbH
Floridotower 26. Stock T +43 1 2198790-27
Floridsdorfer Hauptstr. 1 F +43 1 2198790-927
A-1210 Wien M +43 664 88657566
E roland.asm...@adesso.at
W www.adesso.at
-
business. people. technology.
-
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
--
Roland Asmann
Senior Software Engineer
adesso Austria GmbH
Floridotower 26. Stock T +43 1 2198790-27
Floridsdorfer Hauptstr. 1 F +43 1 2198790-927
A-1210 Wien M +43 664 88657566
E roland.asm...@adesso.at
W www.adesso.at
-
business. people. technology.
-
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
--
Roland Asmann
Senior Software Engineer
adesso Austria GmbH
Floridotower 26. Stock T +43 1
java file path in exec:java
Hi maven users!
I'm trying to execute a java command and pass a path to a file as an argument:
plugin
groupIdorg.codehaus.mojo/groupId
artifactIdexec-maven-plugin/artifactId
configuration
executablejava/executable
workingDirectory${project.build.outputDirectory}/workingDirectory
classpathScoperuntime/classpathScope
arguments
argument-c
${project.build.outputDirectory}${file.separator}orm.properties/argument
/arguments
mainClasscom.company.deploy.product.AutomatedProductDeploy/mainClass
/configuration
/plugin
And I'm using maven properties to construct the filename:
${project.build.outputDirectory}${file.separator}orm.properties
Unfortunately, I'm getting an exception from the java class I'm running:
Caused by: java.io.FileNotFoundException: C:\path to my
project\target\classes\orm.properties (The filename, directory name,
or volume label syntax is incorrect)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.init(FileInputStream.java:106)
Most likely the it is using the argument and does not escape slashes
to new java.io.File( filePath )
As I don't have access to source code of the class - is there any way
to enforce maven use unix style path generation on windows? ( change
slashes to / )
I tried to override the ${file.separator} property - but it seems to
be read-only and doesn't help.
Any ideas?
Thank you!
Žilvinas Vilutis
E-mail: cika...@gmail.com
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
Re: java file path in exec:java
Just use the character '/', it works on Windows!
On 20-04-11 21:45, Zilvinas Vilutis wrote:
Hi maven users!
I'm trying to execute a java command and pass a path to a file as an argument:
plugin
groupIdorg.codehaus.mojo/groupId
artifactIdexec-maven-plugin/artifactId
configuration
executablejava/executable
workingDirectory${project.build.outputDirectory}/workingDirectory
classpathScoperuntime/classpathScope
arguments
argument-c
${project.build.outputDirectory}${file.separator}orm.properties/argument
/arguments
mainClasscom.company.deploy.product.AutomatedProductDeploy/mainClass
/configuration
/plugin
And I'm using maven properties to construct the filename:
${project.build.outputDirectory}${file.separator}orm.properties
Unfortunately, I'm getting an exception from the java class I'm running:
Caused by: java.io.FileNotFoundException: C:\path to my
project\target\classes\orm.properties (The filename, directory name,
or volume label syntax is incorrect)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.init(FileInputStream.java:106)
Most likely the it is using the argument and does not escape slashes
to new java.io.File( filePath )
As I don't have access to source code of the class - is there any way
to enforce maven use unix style path generation on windows? ( change
slashes to / )
I tried to override the ${file.separator} property - but it seems to
be read-only and doesn't help.
Any ideas?
Thank you!
Žilvinas Vilutis
E-mail: cika...@gmail.com
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
--
Roland Asmann
Senior Software Engineer
adesso Austria GmbH
Floridotower 26. Stock T +43 1 2198790-27
Floridsdorfer Hauptstr. 1 F +43 1 2198790-927
A-1210 Wien M +43 664 88657566
E roland.asm...@adesso.at
W www.adesso.at
-
business. people. technology.
-
Re: java file path in exec:java
Exactly, but I need *maven* to generate those / :)
I need the ${project.build.outputDirectory}${file.separator}orm.properties
to contain / in the output, but it generates the path with \
slashes, e.g. C:\path to myproject\target\classes\orm.properties
Regards
Žilvinas Vilutis
Mobile: (+370) 652 38353
E-mail: cika...@gmail.com
On Wed, Apr 20, 2011 at 12:57 PM, Asmann, Roland
roland.asm...@adesso.at wrote:
Just use the character '/', it works on Windows!
On 20-04-11 21:45, Zilvinas Vilutis wrote:
Hi maven users!
I'm trying to execute a java command and pass a path to a file as an
argument:
plugin
groupIdorg.codehaus.mojo/groupId
artifactIdexec-maven-plugin/artifactId
configuration
executablejava/executable
workingDirectory${project.build.outputDirectory}/workingDirectory
classpathScoperuntime/classpathScope
arguments
argument-c
${project.build.outputDirectory}${file.separator}orm.properties/argument
/arguments
mainClasscom.company.deploy.product.AutomatedProductDeploy/mainClass
/configuration
/plugin
And I'm using maven properties to construct the filename:
${project.build.outputDirectory}${file.separator}orm.properties
Unfortunately, I'm getting an exception from the java class I'm running:
Caused by: java.io.FileNotFoundException: C:\path to my
project\target\classes\orm.properties (The filename, directory name,
or volume label syntax is incorrect)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.init(FileInputStream.java:106)
Most likely the it is using the argument and does not escape slashes
to new java.io.File( filePath )
As I don't have access to source code of the class - is there any way
to enforce maven use unix style path generation on windows? ( change
slashes to / )
I tried to override the ${file.separator} property - but it seems to
be read-only and doesn't help.
Any ideas?
Thank you!
Žilvinas Vilutis
E-mail: cika...@gmail.com
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
--
Roland Asmann
Senior Software Engineer
adesso Austria GmbH
Floridotower 26. Stock T +43 1 2198790-27
Floridsdorfer Hauptstr. 1 F +43 1 2198790-927
A-1210 Wien M +43 664 88657566
E roland.asm...@adesso.at
W www.adesso.at
-
business. people. technology.
-
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
Re: java file path in exec:java
What I meant was: don't use ${file.separator} and write '/' in your POM.
Or do you have a reason you need the variable?
On 20-04-11 23:51, Zilvinas Vilutis wrote:
Exactly, but I need *maven* to generate those / :)
I need the ${project.build.outputDirectory}${file.separator}orm.properties
to contain / in the output, but it generates the path with \
slashes, e.g. C:\path to myproject\target\classes\orm.properties
Regards
Žilvinas Vilutis
Mobile: (+370) 652 38353
E-mail: cika...@gmail.com
On Wed, Apr 20, 2011 at 12:57 PM, Asmann, Roland
roland.asm...@adesso.at wrote:
Just use the character '/', it works on Windows!
On 20-04-11 21:45, Zilvinas Vilutis wrote:
Hi maven users!
I'm trying to execute a java command and pass a path to a file as an
argument:
plugin
groupIdorg.codehaus.mojo/groupId
artifactIdexec-maven-plugin/artifactId
configuration
executablejava/executable
workingDirectory${project.build.outputDirectory}/workingDirectory
classpathScoperuntime/classpathScope
arguments
argument-c
${project.build.outputDirectory}${file.separator}orm.properties/argument
/arguments
mainClasscom.company.deploy.product.AutomatedProductDeploy/mainClass
/configuration
/plugin
And I'm using maven properties to construct the filename:
${project.build.outputDirectory}${file.separator}orm.properties
Unfortunately, I'm getting an exception from the java class I'm running:
Caused by: java.io.FileNotFoundException: C:\path to my
project\target\classes\orm.properties (The filename, directory name,
or volume label syntax is incorrect)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.init(FileInputStream.java:106)
Most likely the it is using the argument and does not escape slashes
to new java.io.File( filePath )
As I don't have access to source code of the class - is there any way
to enforce maven use unix style path generation on windows? ( change
slashes to / )
I tried to override the ${file.separator} property - but it seems to
be read-only and doesn't help.
Any ideas?
Thank you!
Žilvinas Vilutis
E-mail: cika...@gmail.com
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
--
Roland Asmann
Senior Software Engineer
adesso Austria GmbH
Floridotower 26. Stock T +43 1 2198790-27
Floridsdorfer Hauptstr. 1 F +43 1 2198790-927
A-1210 Wien M +43 664 88657566
E roland.asm...@adesso.at
W www.adesso.at
-
business. people. technology.
-
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
--
Roland Asmann
Senior Software Engineer
adesso Austria GmbH
Floridotower 26. Stock T +43 1 2198790-27
Floridsdorfer Hauptstr. 1 F +43 1 2198790-927
A-1210 Wien M +43 664 88657566
E roland.asm...@adesso.at
W www.adesso.at
-
business. people. technology.
-
Re: java file path in exec:java
yes, I can do that, however ${project.build.outputDirectory} still
generates C:\folder1\folder2\... etc :)
Žilvinas Vilutis
Mobile: (+370) 652 38353
E-mail: cika...@gmail.com
On Wed, Apr 20, 2011 at 2:57 PM, Asmann, Roland roland.asm...@adesso.at wrote:
What I meant was: don't use ${file.separator} and write '/' in your POM.
Or do you have a reason you need the variable?
On 20-04-11 23:51, Zilvinas Vilutis wrote:
Exactly, but I need *maven* to generate those / :)
I need the ${project.build.outputDirectory}${file.separator}orm.properties
to contain / in the output, but it generates the path with \
slashes, e.g. C:\path to myproject\target\classes\orm.properties
Regards
Žilvinas Vilutis
Mobile: (+370) 652 38353
E-mail: cika...@gmail.com
On Wed, Apr 20, 2011 at 12:57 PM, Asmann, Roland
roland.asm...@adesso.at wrote:
Just use the character '/', it works on Windows!
On 20-04-11 21:45, Zilvinas Vilutis wrote:
Hi maven users!
I'm trying to execute a java command and pass a path to a file as an
argument:
plugin
groupIdorg.codehaus.mojo/groupId
artifactIdexec-maven-plugin/artifactId
configuration
executablejava/executable
workingDirectory${project.build.outputDirectory}/workingDirectory
classpathScoperuntime/classpathScope
arguments
argument-c
${project.build.outputDirectory}${file.separator}orm.properties/argument
/arguments
mainClasscom.company.deploy.product.AutomatedProductDeploy/mainClass
/configuration
/plugin
And I'm using maven properties to construct the filename:
${project.build.outputDirectory}${file.separator}orm.properties
Unfortunately, I'm getting an exception from the java class I'm running:
Caused by: java.io.FileNotFoundException: C:\path to my
project\target\classes\orm.properties (The filename, directory name,
or volume label syntax is incorrect)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.init(FileInputStream.java:106)
Most likely the it is using the argument and does not escape slashes
to new java.io.File( filePath )
As I don't have access to source code of the class - is there any way
to enforce maven use unix style path generation on windows? ( change
slashes to / )
I tried to override the ${file.separator} property - but it seems to
be read-only and doesn't help.
Any ideas?
Thank you!
Žilvinas Vilutis
E-mail: cika...@gmail.com
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
--
Roland Asmann
Senior Software Engineer
adesso Austria GmbH
Floridotower 26. Stock T +43 1 2198790-27
Floridsdorfer Hauptstr. 1 F +43 1 2198790-927
A-1210 Wien M +43 664 88657566
E roland.asm...@adesso.at
W www.adesso.at
-
business. people. technology.
-
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
--
Roland Asmann
Senior Software Engineer
adesso Austria GmbH
Floridotower 26. Stock T +43 1 2198790-27
Floridsdorfer Hauptstr. 1 F +43 1 2198790-927
A-1210 Wien M +43 664 88657566
E roland.asm...@adesso.at
W www.adesso.at
-
business. people. technology.
-
-
To unsubscribe, e-mail: users-unsubscr...@maven.apache.org
For additional commands, e-mail: users-h...@maven.apache.org
