[ovirt-users] Re: latest pycurl 7.43 brokes ovirtsdk4

2019-01-24 Thread Ondra Machacek

Can you please open issue on AWX: https://github.com/ansible/awx/issues ?

On 1/23/19 5:18 PM, Nathanaël Blanchet wrote:
And the AWX embedded pycurl 7.43 also brakes the ovirt4.py dynamic 
inventory!


  [WARNING]: Unable to parse /opt/awx/embedded/lib/python2.7/site-
packages/awx/plugins/inventory/ovirt4.py as an inventory source

Le 23/01/2019 à 11:55, Nathanaël Blanchet a écrit :



Le 23/01/2019 à 09:27, Ondra Machacek a écrit :

On 1/22/19 5:54 PM, Nathanaël Blanchet wrote:

Hi all,

If anyone uses latest pycurl 7.43 provided by pip or ansible 
tower/awx, any ovirtsdk4 calling will issue with the log:


The full traceback is:
WARNING: The below traceback may *not* be related to the actual 
failure.
   File "/tmp/ansible_ovirt_auth_payload_L1HK9E/__main__.py", line 
202, in 

 import ovirtsdk4 as sdk
   File 
"/opt/awx/embedded/lib64/python2.7/site-packages/ovirtsdk4/__init__.py", 
line 22, in 

 import pycurl

fatal: [localhost]: FAILED! => {
 "changed": false,
 "invocation": {
 "module_args": {
 "ca_file": null,
 "compress": true,
 "headers": null,
 "hostname": null,
 "insecure": true,
 "kerberos": false,
 "ovirt_auth": null,
 "password": "VALUE_SPECIFIED_IN_NO_LOG_PARAMETER",
 "state": "present",
 "timeout": 0,
 "token": null,
 "url": "https://acore.v100.abes.fr/ovirt-engine/api";,
 "username": "admin@internal"
 }
 },
 "msg": "ovirtsdk4 version 4.2.4 or higher is required for this 
module"

}

The only way is to set the version of pycurl with

pip install -U "pycurl == 7.19.0"

(Before this, in tower/awx, you should  create venv)


What's the version of AWX, where pycurl 7.43 is provided? I use latest
and I have 7.19. But anyway, I've tried to update to 7.43, and this 
worked for me with nss:


AWX 2.1.2
/opt/awx/embedded/lib64/python2.7/site-packages/pycurl-7.43.0.1.dist-info



$ source venv/awx/bin/activate
$ export PYCURL_SSL_LIBRARY=nss; pip install pycurl --compile 
--no-cache-dir

$ python -c 'import pycurl; print pycurl.version'
PycURL/7.43.0.2 libcurl/7.29.0 NSS/3.36 zlib/1.2.7 libidn/1.28 
libssh2/1.4.3


Yes, I've tried your trick and 7.43 works with the nss support like 
you say, but...


  * how can anyone guess he needs the nss library
  * it doesn't work out the box with the awx embedded  pycurl, so we
    must use venv

So it should be good to compile the embedded awx pycurl to natively 
support nss, out of venv.






--
Nathanaël Blanchet

Supervision réseau
Pôle Infrastrutures Informatiques
227 avenue Professeur-Jean-Louis-Viala
34193 MONTPELLIER CEDEX 5
Tél. 33 (0)4 67 54 84 55
Fax  33 (0)4 67 54 84 14
blanc...@abes.fr
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[ovirt-users] Re: latest pycurl 7.43 brokes ovirtsdk4

2019-01-23 Thread Nathanaël Blanchet
And the AWX embedded pycurl 7.43 also brakes the ovirt4.py dynamic 
inventory!


 [WARNING]: Unable to parse /opt/awx/embedded/lib/python2.7/site-
packages/awx/plugins/inventory/ovirt4.py as an inventory source

Le 23/01/2019 à 11:55, Nathanaël Blanchet a écrit :



Le 23/01/2019 à 09:27, Ondra Machacek a écrit :

On 1/22/19 5:54 PM, Nathanaël Blanchet wrote:

Hi all,

If anyone uses latest pycurl 7.43 provided by pip or ansible 
tower/awx, any ovirtsdk4 calling will issue with the log:


The full traceback is:
WARNING: The below traceback may *not* be related to the actual 
failure.
   File "/tmp/ansible_ovirt_auth_payload_L1HK9E/__main__.py", line 
202, in 

 import ovirtsdk4 as sdk
   File 
"/opt/awx/embedded/lib64/python2.7/site-packages/ovirtsdk4/__init__.py", 
line 22, in 

 import pycurl

fatal: [localhost]: FAILED! => {
 "changed": false,
 "invocation": {
 "module_args": {
 "ca_file": null,
 "compress": true,
 "headers": null,
 "hostname": null,
 "insecure": true,
 "kerberos": false,
 "ovirt_auth": null,
 "password": "VALUE_SPECIFIED_IN_NO_LOG_PARAMETER",
 "state": "present",
 "timeout": 0,
 "token": null,
 "url": "https://acore.v100.abes.fr/ovirt-engine/api";,
 "username": "admin@internal"
 }
 },
 "msg": "ovirtsdk4 version 4.2.4 or higher is required for this 
module"

}

The only way is to set the version of pycurl with

pip install -U "pycurl == 7.19.0"

(Before this, in tower/awx, you should  create venv)


What's the version of AWX, where pycurl 7.43 is provided? I use latest
and I have 7.19. But anyway, I've tried to update to 7.43, and this 
worked for me with nss:


AWX 2.1.2
/opt/awx/embedded/lib64/python2.7/site-packages/pycurl-7.43.0.1.dist-info



$ source venv/awx/bin/activate
$ export PYCURL_SSL_LIBRARY=nss; pip install pycurl --compile 
--no-cache-dir

$ python -c 'import pycurl; print pycurl.version'
PycURL/7.43.0.2 libcurl/7.29.0 NSS/3.36 zlib/1.2.7 libidn/1.28 
libssh2/1.4.3


Yes, I've tried your trick and 7.43 works with the nss support like 
you say, but...


  * how can anyone guess he needs the nss library
  * it doesn't work out the box with the awx embedded  pycurl, so we
must use venv

So it should be good to compile the embedded awx pycurl to natively 
support nss, out of venv.






--
Nathanaël Blanchet

Supervision réseau
Pôle Infrastrutures Informatiques
227 avenue Professeur-Jean-Louis-Viala
34193 MONTPELLIER CEDEX 5   
Tél. 33 (0)4 67 54 84 55
Fax  33 (0)4 67 54 84 14
blanc...@abes.fr  


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--
Nathanaël Blanchet

Supervision réseau
Pôle Infrastrutures Informatiques
227 avenue Professeur-Jean-Louis-Viala
34193 MONTPELLIER CEDEX 5   
Tél. 33 (0)4 67 54 84 55
Fax  33 (0)4 67 54 84 14
blanc...@abes.fr

___
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To unsubscribe send an email to users-le...@ovirt.org
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[ovirt-users] Re: latest pycurl 7.43 brokes ovirtsdk4

2019-01-23 Thread Nathanaël Blanchet


Le 23/01/2019 à 09:27, Ondra Machacek a écrit :

On 1/22/19 5:54 PM, Nathanaël Blanchet wrote:

Hi all,

If anyone uses latest pycurl 7.43 provided by pip or ansible 
tower/awx, any ovirtsdk4 calling will issue with the log:


The full traceback is:
WARNING: The below traceback may *not* be related to the actual failure.
   File "/tmp/ansible_ovirt_auth_payload_L1HK9E/__main__.py", line 
202, in 

 import ovirtsdk4 as sdk
   File 
"/opt/awx/embedded/lib64/python2.7/site-packages/ovirtsdk4/__init__.py", 
line 22, in 

 import pycurl

fatal: [localhost]: FAILED! => {
 "changed": false,
 "invocation": {
 "module_args": {
 "ca_file": null,
 "compress": true,
 "headers": null,
 "hostname": null,
 "insecure": true,
 "kerberos": false,
 "ovirt_auth": null,
 "password": "VALUE_SPECIFIED_IN_NO_LOG_PARAMETER",
 "state": "present",
 "timeout": 0,
 "token": null,
 "url": "https://acore.v100.abes.fr/ovirt-engine/api";,
 "username": "admin@internal"
 }
 },
 "msg": "ovirtsdk4 version 4.2.4 or higher is required for this 
module"

}

The only way is to set the version of pycurl with

pip install -U "pycurl == 7.19.0"

(Before this, in tower/awx, you should  create venv)


What's the version of AWX, where pycurl 7.43 is provided? I use latest
and I have 7.19. But anyway, I've tried to update to 7.43, and this 
worked for me with nss:


AWX 2.1.2
/opt/awx/embedded/lib64/python2.7/site-packages/pycurl-7.43.0.1.dist-info



$ source venv/awx/bin/activate
$ export PYCURL_SSL_LIBRARY=nss; pip install pycurl --compile 
--no-cache-dir

$ python -c 'import pycurl; print pycurl.version'
PycURL/7.43.0.2 libcurl/7.29.0 NSS/3.36 zlib/1.2.7 libidn/1.28 
libssh2/1.4.3


Yes, I've tried your trick and 7.43 works with the nss support like you 
say, but...


 * how can anyone guess he needs the nss library
 * it doesn't work out the box with the awx embedded  pycurl, so we
   must use venv

So it should be good to compile the embedded awx pycurl to natively 
support nss, out of venv.






--
Nathanaël Blanchet

Supervision réseau
Pôle Infrastrutures Informatiques
227 avenue Professeur-Jean-Louis-Viala
34193 MONTPELLIER CEDEX 5   
Tél. 33 (0)4 67 54 84 55
Fax  33 (0)4 67 54 84 14
blanc...@abes.fr

___
Users mailing list -- users@ovirt.org
To unsubscribe send an email to users-le...@ovirt.org
Privacy Statement: https://www.ovirt.org/site/privacy-policy/
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https://www.ovirt.org/community/about/community-guidelines/
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https://lists.ovirt.org/archives/list/users@ovirt.org/message/PMOHDZADCP3R6GKYFUHSDH5NRAZJGNOM/


[ovirt-users] Re: latest pycurl 7.43 brokes ovirtsdk4

2019-01-23 Thread Ondra Machacek

On 1/22/19 5:54 PM, Nathanaël Blanchet wrote:

Hi all,

If anyone uses latest pycurl 7.43 provided by pip or ansible tower/awx, 
any ovirtsdk4 calling will issue with the log:


The full traceback is:
WARNING: The below traceback may *not* be related to the actual failure.
   File "/tmp/ansible_ovirt_auth_payload_L1HK9E/__main__.py", line 202, 
in 

     import ovirtsdk4 as sdk
   File 
"/opt/awx/embedded/lib64/python2.7/site-packages/ovirtsdk4/__init__.py", 
line 22, in 

     import pycurl

fatal: [localhost]: FAILED! => {
     "changed": false,
     "invocation": {
     "module_args": {
     "ca_file": null,
     "compress": true,
     "headers": null,
     "hostname": null,
     "insecure": true,
     "kerberos": false,
     "ovirt_auth": null,
     "password": "VALUE_SPECIFIED_IN_NO_LOG_PARAMETER",
     "state": "present",
     "timeout": 0,
     "token": null,
     "url": "https://acore.v100.abes.fr/ovirt-engine/api";,
     "username": "admin@internal"
     }
     },
     "msg": "ovirtsdk4 version 4.2.4 or higher is required for this module"
}

The only way is to set the version of pycurl with

pip install -U "pycurl == 7.19.0"

(Before this, in tower/awx, you should  create venv)


What's the version of AWX, where pycurl 7.43 is provided? I use latest
and I have 7.19. But anyway, I've tried to update to 7.43, and this 
worked for me with nss:


$ source venv/awx/bin/activate
$ export PYCURL_SSL_LIBRARY=nss; pip install pycurl --compile --no-cache-dir
$ python -c 'import pycurl; print pycurl.version'
PycURL/7.43.0.2 libcurl/7.29.0 NSS/3.36 zlib/1.2.7 libidn/1.28 libssh2/1.4.3





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