Re: Tomcat 6 Windows Service

2008-08-05 Thread Skondras Panos
Setting the catalina_base solves the problem but you have to create a
new dir for the conf files.
Is there a way to just pass as a parameter the server.xml in the startUp class 
as StartParams or something else.
Thanks a lot


--- Στις Δευτ., 04/08/08, ο/η Mark Thomas [EMAIL PROTECTED] έγραψε:

 Από: Mark Thomas [EMAIL PROTECTED]
 Θέμα: Re: Tomcat 6 Windows Service
 Προς: Tomcat Users List users@tomcat.apache.org
 Ημερομηνία: Δευτέρα, 4 Αύγουστος 2008, 17:21
 Skondras Panos wrote:
  Hi all,
  I install Tomcat 6 as a services in windows 2000.
  I follow the how-to and all went ok.
  Now i want to install another service of tomcat 6 BUT
 for this service
  i want to get a different server.xml file than the
 other service.
  I want to do this without having to copy the dir of
 tomcat and install
  the service from there.I want to have one installation
 of tomcat.
  I tried all the StartParams option with no luck.
  Also i tries the tomcat6w config tool to add the
 parameter no luck.
  When i run catalina.bat start -config /con/server2.xml
 all works ok.
  Any suggestions.
 
 Read RUNNING.txt
 Use service.bat to create multiple instances with different
 service names.
 
 Mark
 
 
 
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Tomcat 6 Windows Service

2008-08-04 Thread Skondras Panos
Hi all,
I install Tomcat 6 as a services in windows 2000.
I follow the how-to and all went ok.
Now i want to install another service of tomcat 6 BUT for this service
i want to get a different server.xml file than the other service.
I want to do this without having to copy the dir of tomcat and install
the service from there.I want to have one installation of tomcat.
I tried all the StartParams option with no luck.
Also i tries the tomcat6w config tool to add the parameter no luck.
When i run catalina.bat start -config /con/server2.xml all works ok.
Any suggestions.
Thanks in advance


  
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