Re: Resources can't object HTTP request body

[Илья Нарыжный]

Martin,

Ticket has been created: https://issues.apache.org/jira/browse/WICKET-6135
Will attach quick start today/tomorrow.

Thanks,

Ilia

2016-03-29 6:39 GMT-07:00 Martin Grigorov :
> Please create a ticket at JIRA.
> With a quickstart would be nice!
> Thank you!
>
> Martin Grigorov
> Wicket Training and Consulting
> https://twitter.com/mtgrigorov
>
> On Tue, Mar 29, 2016 at 3:30 PM, Илья Нарыжный  wrote:
>
>> Martin,
>>
>> There are 3 problems:
>>
>> 1) Map can not guarantee that order of keys remain the same. In my
>> case Jetty use HashMap as underling storage.
>> 2) Some part of content might be URL encoded. So after collecting all
>> back: it's hard to revert exectly to initial value due to fact that
>> some parts contained URL encoded stuff.
>> 3) POST can contain huge body. So it looks very strange.
>>
>> As a work-around I use Filter configured prior to wicket to intercept
>> body whenever it's needed:
>>
>> https://github.com/OrienteerDW/wicket-orientdb/commit/c9e706d9e84a828901a5ad97ed50aa46521f7bfb
>>
>> Is it really required for isAjax() method check POST parameters as
>> well? I mean, may be flag is in query string and there is even no goal
>> to check POST body.
>>
>> Thanks,
>>
>> Ilia
>>
>> 2016-03-27 4:07 GMT-07:00 Martin Grigorov :
>> > Hi,
>> >
>> > I remember dealing with this in the past but I cannot find the mail
>> thread
>> > now.
>> > I think the complete body should be available as a valueless key in the
>> > post parameters:
>> > getRequest().getPostParameters().getParameterNames().iterator().next().
>> > Please confirm whether this works!
>> > If it does then I think it would be good to add a helper method to
>> simplify
>> > this.
>> >
>> > Martin Grigorov
>> > Wicket Training and Consulting
>> > https://twitter.com/mtgrigorov
>> >
>> > On Sat, Mar 26, 2016 at 5:28 AM, Илья Нарыжный  wrote:
>> >
>> >> It seems that Wicket Resource can't obtain whole HTTP POST body.
>> >> The reason of that is the following:
>> >> Mappers invoke WebRequest.isAjax() and isAjax() is trying to
>> >> getRequestParameters() - so body of POST parsed prior to actual
>> >> getInputStream() in a Resource object.
>> >>
>> >> Is there any chances to allow Resources to get request body?
>> >>
>> >> Thanks,
>> >>
>> >> Ilia
>> >>
>> >> -
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>> >>
>> >>
>>
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>>

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Re: Getting the model

[Sven Meier]

Hi,

yeah, of course this is right:

protected void onComponentTag(final ComponentTag tag) {

if (getModelObject().doubleValue() < 0.0) {
tag.put("class", " negative");
}
}

Otherwise you'll end up with one additional behavior for each render - stupid 
copy-paste error :/.

BTW this might be an additional candidate for the new Wicket 8 lambdas:

label.add(onTag(tag -> if (getModelObject().doubleValue() < 0.0) tag.put("class", 
"negative") ));

Sven


On 31.03.2016 21:16, Martin Grigorov wrote:

Hi,

On Thu, Mar 31, 2016 at 4:29 PM, Sven Meier  wrote:


Hi,

you can access a component's model with #getDefaultModel() or - if it is a
generic component - with #getModel().

To properly 'bind' to a model you should delay invocation of #getObject()
as late as possible, so better overwrite #onComponentTag():

 protected void onComponentTag(final ComponentTag tag) {

 if (getModelObject().doubleValue() < 0.0) {
 add(new AttributeAppender("class", " negative"));


Since you are in #onComponentTag() there is no reason to add a Behavior.
Just use the tag: tag.append("class", "negative", " ");



 }
 }


Have fun
Sven




On 31.03.2016 16:06, Ron Smits wrote:


I have searched but I dont find a clear way of getting the model when one
is creating a custom component:


public MoneyLabel(String id) {
  super(id);
  add(new AttributeAppender("class", " number"));
}


It sounds like you always need the model.
If there is a CompoundPropertyModel in the parents' hierarchy then move
your logic to #onComponentTag(), as per Sven's suggestion.
If there is no CPM in the parents then just remove this constructor.



public MoneyLabel(String id, Model bigDecimalModel)
{
  super(id, bigDecimalModel);
  add(new AttributeAppender("class", " number"));
  if (bigDecimalModel.getObject().doubleValue() < 0.0) {
  add(new AttributeAppender("class", " negative"));
  }
}

In the second constructor I can use the supplied model to determine to add
the negative class. However in the first constructor I cannot find a way
to
access the model.

What am I missing?

Ron
​



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Re: Getting the model

[Martin Grigorov]

Hi,

On Thu, Mar 31, 2016 at 4:29 PM, Sven Meier  wrote:

> Hi,
>
> you can access a component's model with #getDefaultModel() or - if it is a
> generic component - with #getModel().
>
> To properly 'bind' to a model you should delay invocation of #getObject()
> as late as possible, so better overwrite #onComponentTag():
>
> protected void onComponentTag(final ComponentTag tag) {
>
> if (getModelObject().doubleValue() < 0.0) {
> add(new AttributeAppender("class", " negative"));
>

Since you are in #onComponentTag() there is no reason to add a Behavior.
Just use the tag: tag.append("class", "negative", " ");


> }
> }
>
>
> Have fun
> Sven
>
>
>
>
> On 31.03.2016 16:06, Ron Smits wrote:
>
>> I have searched but I dont find a clear way of getting the model when one
>> is creating a custom component:
>>
>>
>> public MoneyLabel(String id) {
>>  super(id);
>>  add(new AttributeAppender("class", " number"));
>> }
>>
>
It sounds like you always need the model.
If there is a CompoundPropertyModel in the parents' hierarchy then move
your logic to #onComponentTag(), as per Sven's suggestion.
If there is no CPM in the parents then just remove this constructor.


>
>> public MoneyLabel(String id, Model bigDecimalModel)
>> {
>>  super(id, bigDecimalModel);
>>  add(new AttributeAppender("class", " number"));
>>  if (bigDecimalModel.getObject().doubleValue() < 0.0) {
>>  add(new AttributeAppender("class", " negative"));
>>  }
>> }
>>
>> In the second constructor I can use the supplied model to determine to add
>> the negative class. However in the first constructor I cannot find a way
>> to
>> access the model.
>>
>> What am I missing?
>>
>> Ron
>> ​
>>
>>
>
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> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
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>
>

Re: Getting the model

[Martin Makundi]

2016-03-31 17:06 GMT+03:00 Ron Smits :

> I have searched but I dont find a clear way of getting the model when one
> is creating a custom component:
>
>
> public MoneyLabel(String id) {
> super(id);
> add(new AttributeAppender("class", " number"));
> }
>
> public MoneyLabel(String id, Model bigDecimalModel) {
> super(id, bigDecimalModel);
> add(new AttributeAppender("class", " number"));
> if (bigDecimalModel.getObject().doubleValue() < 0.0) {
> add(new AttributeAppender("class", " negative"));
> }
> }
>
> In the second constructor I can use the supplied model to determine to add
> the negative class. However in the first constructor I cannot find a way to
> access the model.
>
> What am I missing?
>

1. To answer your question: Is this MoneyLabel your own design? If it is
you are free to implement as you whish, or even drop the first constructor.

2. To give a recommendation on your design, I would attach the
AttributeAppender in any case and only check if the model is negative at
runtime (hollywood principle) like this:

add(new AttributeAppender("class", " negative") {

 @Override
  isEnabled(..) {
 bigDecimalModel.getObject().doubleValue() < 0.0
  }
});


**
Martin

>
> Ron
> ​
>

Re: Getting the model

[Sven Meier]

Hi,

you can access a component's model with #getDefaultModel() or - if it is 
a generic component - with #getModel().


To properly 'bind' to a model you should delay invocation of 
#getObject() as late as possible, so better overwrite #onComponentTag():


protected void onComponentTag(final ComponentTag tag) {

if (getModelObject().doubleValue() < 0.0) {
add(new AttributeAppender("class", " negative"));
}
}


Have fun
Sven



On 31.03.2016 16:06, Ron Smits wrote:

I have searched but I dont find a clear way of getting the model when one
is creating a custom component:


public MoneyLabel(String id) {
 super(id);
 add(new AttributeAppender("class", " number"));
}

public MoneyLabel(String id, Model bigDecimalModel) {
 super(id, bigDecimalModel);
 add(new AttributeAppender("class", " number"));
 if (bigDecimalModel.getObject().doubleValue() < 0.0) {
 add(new AttributeAppender("class", " negative"));
 }
}

In the second constructor I can use the supplied model to determine to add
the negative class. However in the first constructor I cannot find a way to
access the model.

What am I missing?

Ron
​




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Getting the model

[Ron Smits]

I have searched but I dont find a clear way of getting the model when one
is creating a custom component:


public MoneyLabel(String id) {
super(id);
add(new AttributeAppender("class", " number"));
}

public MoneyLabel(String id, Model bigDecimalModel) {
super(id, bigDecimalModel);
add(new AttributeAppender("class", " number"));
if (bigDecimalModel.getObject().doubleValue() < 0.0) {
add(new AttributeAppender("class", " negative"));
}
}

In the second constructor I can use the supplied model to determine to add
the negative class. However in the first constructor I cannot find a way to
access the model.

What am I missing?

Ron
​

Re: Failing test SpringBeanWithGenericsTest in 7.3.0.0 SNAPSHOT

[Thorsten Schöning]

Guten Tag Martin Grigorov,
am Mittwoch, 30. März 2016 um 15:54 schrieben Sie:

> Please create a patch / Pull Request and a ticket.

https://issues.apache.org/jira/browse/WICKET-6133

Mit freundlichen Grüßen,

Thorsten Schöning

-- 
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AM-SoFT IT-Systeme  http://www.AM-SoFT.de/

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