Re: container authentication and form action url
Igor Vaynberg wrote: dont use a wicket form if you dont want it processed by wicket. -igor Hi Igor, I want to use wicket to manage that page, I want to process user data to fetch user profiles by username/password than I will post all user data (name/password/profile) to j_security_check using an hidden plain html form and some javascript code. Thank you for your suggestions... alf - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
container authentication and form action url
Hi all, I've setup my container-authentication (form based) using a simple SigninPage (mounted on /login) and a dummy protected url "/protected", here is the web.xml relevant code: w myapp /protected GET POST FORM /login /error I've extended AbstractPageAuthorizationStrategy to redirect all protected pages access to the container-protected url (/protected) and activate the container authentication. When the user request a protected page, for example "GET /app/protected HTTP/1.1" all works good: the configured is returned as response and the requested url will not change as expected. The login page contains a form with two input (username/password) and a combo for user profiles, so I need to post to the sign in page to load available user profiles. The problem is that the form action attribute created by wicket is something like "?wicket:interface=:0:privateLogin::IFormSubmitListener::" that produce a POST to "/app/protected?wicket:interface=:0:privateLogin:ajaxButton::" INSTEAD OF "/app/login". This cause a new sign in page instantiation discarding user input. How can I obtain to POST to the sign in page instead of the requested url (/app/protected) ? I don't want to do a redirect to login page (that trick works) because I would like to avoid the user bookmark the login page that prevent to activate the container-based authentication. Thank you alf - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
user input lost on first form submission
Hi all,
I have a simple sign-in page with a form and two fields (username and
password)
public LoginPage() {
super();
add(new SignInForm("signInForm"));
}
private class SignInForm extends Form {
private String username, password;
public SignInForm(String id) {
super(id);
add(new TextField("username", new
PropertyModel(this, "username")));
add(new PasswordTextField("password", new
PropertyModel(this, "password")));
}
@Override
protected void onSubmit() {
// TODO Auto-generated method stub
super.onSubmit();
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
}
if the user get the page directly, using the mounted url, all work as
expected.
When the user get this page after a container redirection (I'm using
form based servlet container authentication), on first form submission,
the user entered data are not available (the sets are never called) but
on the next submit all work as normal and models are updated.
The page is mounted using
mountBookmarkablePage("/login", LoginPage.class);
and the relevant part of the web.xml is
/login
Thank you
alf
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Application scope vs Singleton
Hi, I have a doubt about application-scoped objects. What's the pro and cons of setting an object instance into my WebApplication class or define that class as singleton (using a static method to access it) ? Thank you alf - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Datatable columns converter
Hi, I can't figure out the best way to define something like a object-to-string converter to add to a DataTable's column (PropertyColumn). I have an Integer in my model and I want to display a proper String to the user by a defined mapping. Thank you alf - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
AjaxTabbedPanel custom validation behaviour
I'm using an AjaxTabbedPanel and I would like to obtain the following
behaviours:
1) user input must be retained when switching tabs
2) tabs link should skip only the "requireness" validation but not all
other validators so the user can switch from tab to tab if he doesn't
insert bad input
3) a submit button present in all tabs should execute a full validation
of the TabbedPanel (all tabs) before execute some logic on the user input
Actually I've solved the point 1 overriding the AjaxTabbedPanel#newLink
returning an AjaxSubmitLink instead the AjaxFallbackLink.
What is the best way to solve the other two open points?
Thank you
The relevant code of my WebPage follow:
||
public TabbedPanelPage() {
final Form form = new Form("formy", new CompoundPropertyModel(this));
form.setOutputMarkupId(true);
add(form);
final FeedbackPanel fp = new FeedbackPanel("feedback");
fp.setOutputMarkupId(true);
add(fp);
List tabs = new ArrayList();
tabs.add(new AbstractTab(new Model("first tab")) {
public Panel getPanel(String panelId) {
Panel p = new TabPanel1(panelId, form.getModel());
firstNameText = new TextField("text1");
firstNameText.setOutputMarkupId(true);
firstNameText.add(new
StringValidator.MinimumLengthValidator(2));
p.add(firstNameText);
return p;
}
});
tabs.add(new AbstractTab(new Model("second tab")) {
public Panel getPanel(String panelId) {
Panel p = new TabPanel2(panelId, form.getModel());
lastNameText = new TextField("text2");
lastNameText.add(new StringValidator.MinimumLengthValidator(2));
p.add(lastNameText);
return p;
}
});
tabPanel = new AjaxTabbedPanel("tabs", tabs) {
@Override
protected WebMarkupContainer newLink(String linkId, final int
index) {
return new AjaxSubmitLink(linkId, form) {
private static final long serialVersionUID = 1L;
@Override
protected void onSubmit(AjaxRequestTarget target, Form
form) {
setSelectedTab(index);
if (target != null) {
target.addComponent(form);
}
onAjaxUpdate(target);
}
@Override
protected void onError(AjaxRequestTarget target, Form form){
target.addComponent(fp);
}
}.setDefaultFormProcessing(true);
}
};
form.add(tabPanel);
Button submit = new Button("submit_button") {
@Override
public void onSubmit() {
// TODO - validate entire form and process data
}
};
form.add(submit);
}
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datatable columns shuffle
Hi,
I'm a wicket beginner.
I'm trying to shuffle the columns of a datatable using an
AjaxFallbackLink, this is my code (only relevant part):
my WebPage content:
private AjaxFallbackDefaultDataTable usersTable;
private List> userColumns = new ArrayList>();
private UserProvider userProvider = new UserProvider();
public QueryPage() {
userColumns.add(new PropertyColumn(new Model("First
Name"), "FIRSTNAME", "firstName"));
userColumns.add(new PropertyColumn(new Model("Last
Name"), "LASTNAME", "lastName"));
usersTable = new AjaxFallbackDefaultDataTable("users_table",
userColumns, userProvider, 20);
usersTable.setOutputMarkupId(true);
add(usersTable);
add(new AjaxFallbackLink("users_shuffle") {
@Override
public void onClick(AjaxRequestTarget target) {
Collections.shuffle(userColumns);
usersTable = new
AjaxFallbackDefaultDataTable("users_table", userColumns, userProvider, 20);
if (target != null) {
target.addComponent(usersTable);
}
}
});
}
my html page content:
Shuffle!
[table]
When I click the ajax link the "onClick" is executed, the userColumns
list is shuffled but the page rendering is always the same as defined in
the constructor of the WebPage.
I've tryied also using a standard Link (no ajax) getting the same result.
I'm using Wicket 1.4rc2.
Thank you
Alfredo
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