RE: Internationalized titles

2009-05-04 Thread Shelah Horvitz
Many thanks!


From: Jeremy Thomerson [jer...@wickettraining.com]
Sent: Monday, May 04, 2009 2:08 PM
To: users@wicket.apache.org
Subject: Re: Internationalized titles

add(new Label("appTitle", new ResourceModel("your.title.key"));

also, change your html:
this will be replaced

Of course, if you don't use markup inheritance, you'll need to repeat
this throughout each page.

--
Jeremy Thomerson
http://www.wickettraining.com




On Mon, May 4, 2009 at 1:02 PM, Shelah Horvitz
 wrote:
> I want to internationalize the title of my application, so that I would get 
> its value from a properties file, and the HTML would look something like:
>
> 
>  
> 
>
> It doesn't look like I can use a header contributor to do this sort of thing, 
> so how is it done?
>
> Thanks for your help.
>
> Shelah
>

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Internationalized titles

2009-05-04 Thread Shelah Horvitz
I want to internationalize the title of my application, so that I would get its 
value from a properties file, and the HTML would look something like:


  


It doesn't look like I can use a header contributor to do this sort of thing, 
so how is it done?

Thanks for your help.

Shelah


RE: How to expose regular exception message in FeedbackPanel?

2008-10-06 Thread Shelah Horvitz
Thank you.  I can't believe you got back to me so fast!

This is a slick solution.  I appreciate it.



From: Serkan Camurcuoglu [EMAIL PROTECTED]
Sent: Monday, October 06, 2008 2:36 PM
To: users@wicket.apache.org
Subject: Re: How to expose regular exception message in FeedbackPanel?

you can use the info, warn, error or fatal methods of component to
generate feedback messages.. usually you can just write:

catch (Exception e) {
  error(e.getMessage());
}



Seven Corners wrote:
> I have a form whose submission can possibly generate exceptions.  I would
> like to expose the exception text in the FeedbackPanel.  How can I do this?
>
> I've tried getting the FeedbackMessagesModel and doing a setObject() on that
> but it's not accepting a String, a FeedbackMessages List, or a new
> FeedbackMessage.  Obviously I'm going about this the wrong way.
>
> Ideas?
>
> Thanking you in advance for your time and trouble.
>


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RE: How to update ListChoice after form submission?

2008-10-03 Thread Shelah Horvitz
Thank you, Igor, for getting back to me so quickly.  Actually, thank you for 
answering at all.

I thought of the onclick handler, but the AjaxFallbackButton doesn't have an 
onClick() function.  It does have a getOnClickScript() which I can override, 
but I believe the timing will be off.  I think it will fire before the form is 
submitted.  Hold on, I think I get what you're saying: write some JavaScript 
AJAX for the onclick script that will call whatever routines I need to create 
the user and then update the ListChoice's model.  I don't need to do anything 
with the onSubmit() overload.  Is that what you're saying?  I will try it.  I 
think it's a good idea.

An interesting aspect of this solution is that I don't think I even need a 
form.  I think the validation of control inputs would happen after the onclick 
handler returns.  I think this is a strictly roll-your-own solution.

Have I got it right?


From: Igor Vaynberg [EMAIL PROTECTED]
Sent: Thursday, October 02, 2008 4:42 PM
To: users@wicket.apache.org
Subject: Re: How to update ListChoice after form submission?

inside the onclick of your ajaxfallbackbutton you have to add the
listchoice to the target so wicket rerenders it

-igor

On Thu, Oct 2, 2008 at 12:49 PM, Seven Corners <[EMAIL PROTECTED]> wrote:
>
> I have a page with a ListChoice of user names that is populated with a call
> to our server (loadUserNames()).  The page also contains a number of
> TextFields corresponding to the user's other attributes.  When you modify
> those text fields so the user name doesn't correspond to anything in the
> list, the Add AjaxFallbackButton enables.  Click this, and you make a call
> to the server which creates the new user.
>
> The new user does not show up in the ListChoice.  If you refresh the page,
> it does, so we know it's created, and we know that loadUserNames() will
> return the correct list if it were called and its values were used..  I want
> the new user name to show up in the ListChoice after submission, and I'd
> like to be able to set the selection in the ListChoice to the new user.
> I've tried giving the ListChoice a LoadableDetachableModel, I've tried
> giving it an ArrayList model with a call to loadUserNames() and setChoices()
> on the ListChoice after submission, I've tried a
> AjaxFormComponentUpdatingBehavior( "onsubmit" ), hoping this might fire
> after submission, I've tried using a call to
> getRequestCycleSettings().setRenderStrategy(IRequestCycleSettings.ONE_PASS_RENDER)
> in my application class's init() method, I've tried a ton of things and I
> can't figure this out.
>
> Any ideas?
> --
> View this message in context: 
> http://www.nabble.com/How-to-update-ListChoice-after-form-submission--tp19786374p19786374.html
> Sent from the Wicket - User mailing list archive at Nabble.com.
>
>
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