Re: Navigation bar links

2012-08-22 Thread Martin Grigorov 
See org.apache.wicket.markup.html.link.BookmarkablePageLink#linksTo(Page).

if (link.linksTo(getPage()) {
  link.setEnable(false);
}

On Tue, Aug 21, 2012 at 7:54 PM, Mansour Al Akeel
mansour.alak...@gmail.com wrote:
 Thank you a lot.
 Both methods did the trick. One last question in the same context. This is
 the code I am working with:

 list.add(new BookmarkablePageLinkWebPage(link, HomePage.class));
 list.add(new BookmarkablePageLinkWebPage(link, About.class));
 list.add(new BookmarkablePageLinkWebPage(link,
 ContactUs.class));

 @SuppressWarnings(unchecked)
 ListView listview = new ListView(listview, list) {
 protected void populateItem(ListItem item) {

 BookmarkablePageLinkWebPage lnk =
 (BookmarkablePageLinkWebPage) item
 .getModelObject();
 String requestedUrl = getRequest().getUrl().getPath();

 String linkUrl = getRequestCycle().urlFor(
 lnk.getPageClass() , new PageParameters()).toString().substring(2);

 logger.debug(requested :  + requestedUrl);
 logger.debug(current link :  + linkUrl);

 Label label = new Label(lbl, lnk.getId());

 lnk.add(label);
 item.add(lnk);

 if (linkUrl.equals(requestedUrl)) {
 logger.debug(matched link with requested url);
 // lnk.setRenderBodyOnly(true);
 lnk.setEnabled(false);
 }
 }
 };
 add(listview);

 I am trying to compare the requested URL to the link url. I need to obtain
 the link url. It's no clear to me how to do it in clean way.
 I am using:
 String linkUrl = getRequestCycle().urlFor(
 lnk.getPageClass() , new PageParameters()).toString().substring(2);
 This introduced a problem. It works fine if the page is mounted on some
 path. But if the link url is something like:

 wicket/bookmarkable/com.example.MyPage

 Then it breaks. Is there a better way to obtain the url for each link ??

 Thank you.



 On Tue, Aug 21, 2012 at 2:55 AM, Martin Grigorov mgrigo...@apache.orgwrote:

 Or you can do link.setRenderBodyOnly(true);

 On Tue, Aug 21, 2012 at 9:30 AM, Sven Meier s...@meiers.net wrote:
  You can use a disabled link, which will render as a span.
 
  Sven
 
 
  On 08/21/2012 08:10 AM, Mansour Al Akeel wrote:
 
  I am looking to produce the following mark up:
  ul
  lia href=/Home/a/li
  li class=current About/li
  lia href=contactContact us/a/li
  ul
 
  the problem is I can not add a conditionally to li. I am using
  ListView
  to populate the Items.
  Can someone give me a hint about how to achieve this ??
 
  Thank you in advance.
 
 
 
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Navigation bar links

2012-08-21 Thread Mansour Al Akeel 
I am looking to produce the following mark up:
ul
lia href=/Home/a/li
li class=current About/li
lia href=contactContact us/a/li
ul

the problem is I can not add a conditionally to li. I am using ListView
to populate the Items.
Can someone give me a hint about how to achieve this ??

Thank you in advance.

Re: Navigation bar links

2012-08-21 Thread Sven Meier 

You can use a disabled link, which will render as a span.

Sven

On 08/21/2012 08:10 AM, Mansour Al Akeel wrote:

I am looking to produce the following mark up:
ul
lia href=/Home/a/li
li class=current About/li
lia href=contactContact us/a/li
ul

the problem is I can not add a conditionally to li. I am using ListView
to populate the Items.
Can someone give me a hint about how to achieve this ??

Thank you in advance.




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Re: Navigation bar links

2012-08-21 Thread Mansour Al Akeel 
Thank you a lot.
Both methods did the trick. One last question in the same context. This is
the code I am working with:

list.add(new BookmarkablePageLinkWebPage(link, HomePage.class));
list.add(new BookmarkablePageLinkWebPage(link, About.class));
list.add(new BookmarkablePageLinkWebPage(link,
ContactUs.class));

@SuppressWarnings(unchecked)
ListView listview = new ListView(listview, list) {
protected void populateItem(ListItem item) {

BookmarkablePageLinkWebPage lnk =
(BookmarkablePageLinkWebPage) item
.getModelObject();
String requestedUrl = getRequest().getUrl().getPath();

String linkUrl = getRequestCycle().urlFor(
lnk.getPageClass() , new PageParameters()).toString().substring(2);

logger.debug(requested :  + requestedUrl);
logger.debug(current link :  + linkUrl);

Label label = new Label(lbl, lnk.getId());

lnk.add(label);
item.add(lnk);

if (linkUrl.equals(requestedUrl)) {
logger.debug(matched link with requested url);
// lnk.setRenderBodyOnly(true);
lnk.setEnabled(false);
}
}
};
add(listview);

I am trying to compare the requested URL to the link url. I need to obtain
the link url. It's no clear to me how to do it in clean way.
I am using:
String linkUrl = getRequestCycle().urlFor(
lnk.getPageClass() , new PageParameters()).toString().substring(2);
This introduced a problem. It works fine if the page is mounted on some
path. But if the link url is something like:

wicket/bookmarkable/com.example.MyPage

Then it breaks. Is there a better way to obtain the url for each link ??

Thank you.



On Tue, Aug 21, 2012 at 2:55 AM, Martin Grigorov mgrigo...@apache.orgwrote:

 Or you can do link.setRenderBodyOnly(true);

 On Tue, Aug 21, 2012 at 9:30 AM, Sven Meier s...@meiers.net wrote:
  You can use a disabled link, which will render as a span.
 
  Sven
 
 
  On 08/21/2012 08:10 AM, Mansour Al Akeel wrote:
 
  I am looking to produce the following mark up:
  ul
  lia href=/Home/a/li
  li class=current About/li
  lia href=contactContact us/a/li
  ul
 
  the problem is I can not add a conditionally to li. I am using
  ListView
  to populate the Items.
  Can someone give me a hint about how to achieve this ??
 
  Thank you in advance.
 
 
 
  -
  To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
  For additional commands, e-mail: users-h...@wicket.apache.org
 



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How to build a dynamic navigation bar

2008-07-22 Thread Edbay 

Hello, 
  
I want to be able to build a left-side dynamic navigation bar based on user
permissions. For example, if the user does not have access to the Prices
page, I do not want to show the Prices link on the navigation bar. Also,
since the link will point to a Wicket page, it has to be a Wicket link. 

This is how I would like the NavBar to appear: 

div id=mainNav
ul
li Home /li
li Prices /li
li Contracts /li
li Products /li
li Transactions /li
/ul
/div

I tried using ListView, but I could not get it to work, as it forces the
wicket id of the line items to be all the same. 


Thanks in advance.
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RE: How to build a dynamic navigation bar

2008-07-22 Thread Alexander Landsnes Keül 
I'd use a ListView :)

Assuming this lil code

add( new ListView(list, linkList )
{
public void populateItem(ListItem item)
{
item.add( (Link)linkList );
}
});

You'd have the html look something like this

ul wicket:id=list
lia href=# wicket:id=linkIdLink text here/a/li
/ul

Just remember to add whatever you want to the item, and not just use add(...). 

http://wicket.apache.org/docs/wicket-1.3.2/wicket/apidocs/org/apache/wicket/markup/html/list/ListView.html

Alex

-Opprinnelig melding-
Fra: Edbay [mailto:[EMAIL PROTECTED] 
Sendt: 22. juli 2008 18:08
Til: users@wicket.apache.org
Emne: How to build a dynamic navigation bar


Hello, 
  
I want to be able to build a left-side dynamic navigation bar based on user
permissions. For example, if the user does not have access to the Prices
page, I do not want to show the Prices link on the navigation bar. Also,
since the link will point to a Wicket page, it has to be a Wicket link. 

This is how I would like the NavBar to appear: 

div id=mainNav
ul
li Home /li
li Prices /li
li Contracts /li
li Products /li
li Transactions /li
/ul
/div

I tried using ListView, but I could not get it to work, as it forces the
wicket id of the line items to be all the same. 


Thanks in advance.
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RE: How to build a dynamic navigation bar

2008-07-22 Thread Edbay 

Thanks for the quick reply.

Wouldn't this force all links to have the same wicket ids (linkid)?
I'd like to be able to have the line items look like this:

ul wicket:id=list
li # Link01 text here /li
li # Link02 text here /li
li # Link03 text here /li
/ul





Alexander Landsnes Keül wrote:
 
 I'd use a ListView :)
 
 Assuming this lil code
 
 add( new ListView(list, linkList )
 {
   public void populateItem(ListItem item)
   {
   item.add( (Link)linkList );
   }
 });
 
 You'd have the html look something like this
 
 ul wicket:id=list
   li # Link text here /li
 /ul
 
 Just remember to add whatever you want to the item, and not just use
 add(...). 
 
 http://wicket.apache.org/docs/wicket-1.3.2/wicket/apidocs/org/apache/wicket/markup/html/list/ListView.html
 
 Alex
 
 -Opprinnelig melding-
 Fra: Edbay [mailto:[EMAIL PROTECTED] 
 Sendt: 22. juli 2008 18:08
 Til: users@wicket.apache.org
 Emne: How to build a dynamic navigation bar
 
 
 Hello, 
   
 I want to be able to build a left-side dynamic navigation bar based on
 user
 permissions. For example, if the user does not have access to the Prices
 page, I do not want to show the Prices link on the navigation bar. Also,
 since the link will point to a Wicket page, it has to be a Wicket link. 
 
 This is how I would like the NavBar to appear: 
 
   div id=mainNav
   ul
   li Home /li
   li Prices /li
   li Contracts /li
   li Products /li
   li Transactions /li
   /ul
   /div
 
 I tried using ListView, but I could not get it to work, as it forces the
 wicket id of the line items to be all the same. 
 
 
 Thanks in advance.
 -- 
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RE: How to build a dynamic navigation bar

2008-07-22 Thread Alexander Landsnes Keül 
They need the same wicket:id yes, but that doesn't mean that they need the same 
text or targets. Just create as many links as you want/need, with whatever 
behaviour they need. Just make sure they all have the same id :)

Alex

-Opprinnelig melding-
Fra: Edbay [mailto:[EMAIL PROTECTED] 
Sendt: 22. juli 2008 19:00
Til: users@wicket.apache.org
Emne: RE: How to build a dynamic navigation bar


Thanks for the quick reply.

Wouldn't this force all links to have the same wicket ids (linkid)?
I'd like to be able to have the line items look like this:

ul wicket:id=list
li # Link01 text here /li
li # Link02 text here /li
li # Link03 text here /li
/ul





Alexander Landsnes Keül wrote:
 
 I'd use a ListView :)
 
 Assuming this lil code
 
 add( new ListView(list, linkList )
 {
   public void populateItem(ListItem item)
   {
   item.add( (Link)linkList );
   }
 });
 
 You'd have the html look something like this
 
 ul wicket:id=list
   li # Link text here /li
 /ul
 
 Just remember to add whatever you want to the item, and not just use
 add(...). 
 
 http://wicket.apache.org/docs/wicket-1.3.2/wicket/apidocs/org/apache/wicket/markup/html/list/ListView.html
 
 Alex
 
 -Opprinnelig melding-
 Fra: Edbay [mailto:[EMAIL PROTECTED] 
 Sendt: 22. juli 2008 18:08
 Til: users@wicket.apache.org
 Emne: How to build a dynamic navigation bar
 
 
 Hello, 
   
 I want to be able to build a left-side dynamic navigation bar based on
 user
 permissions. For example, if the user does not have access to the Prices
 page, I do not want to show the Prices link on the navigation bar. Also,
 since the link will point to a Wicket page, it has to be a Wicket link. 
 
 This is how I would like the NavBar to appear: 
 
   div id=mainNav
   ul
   li Home /li
   li Prices /li
   li Contracts /li
   li Products /li
   li Transactions /li
   /ul
   /div
 
 I tried using ListView, but I could not get it to work, as it forces the
 wicket id of the line items to be all the same. 
 
 
 Thanks in advance.
 -- 
 View this message in context:
 http://www.nabble.com/How-to-build-a-dynamic-navigation-bar-tp18592899p18592899.html
 Sent from the Wicket - User mailing list archive at Nabble.com.
 
 
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Re: How to build a dynamic navigation bar

2008-07-22 Thread John Krasnay 
On Tue, Jul 22, 2008 at 09:59:48AM -0700, Edbay wrote:
 
 Thanks for the quick reply.
 
 Wouldn't this force all links to have the same wicket ids (linkid)?
 I'd like to be able to have the line items look like this:
 
 ul wicket:id=list
   li # Link01 text here /li
   li # Link02 text here /li
   li # Link03 text here /li
 /ul

Well, you would only put in one link line. The ListView repeats the
markup for each item in the list. Note that Alexander's example is a
little broken, since it would repeat the entire ul for each item,
where I think you want to repeat the li.

Personally, I would create a Panel class that encapsulates the link, the
link text, and perhaps any required images, behaviours, etc. Then I
would use a RepeatingView and add as many of these panels as I need:

ul
  !-- note: the a tag here is only for preview,
   it will be replaced by the link panel contents --
  li wicket:id=menuItema href=#Foo/a/li
/ul

RepeatingView menu = new RepeatingView(menuItem);

menu.add(new MyMenuPanel(menu.newChildId(), Home, HomePage.class));

if (userIsDarthVader) {
menu.add(new MyMenuPanel(menu.newChildId(), Enslave Universe,
EnslaveUniversePage.class));
}

jk

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Re: How to build a dynamic navigation bar

2008-07-22 Thread sstendal 


Edbay wrote:
 
 
 I tried using ListView, but I could not get it to work, as it forces the
 wicket id of the line items to be all the same. 
 
 

Why is that a problem? Using ListView should be a good solution. Could you
elaborate?

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Re: How to build a dynamic navigation bar

2008-07-22 Thread puschteblume 

Here is my code that works for me. I put the navigation bar in a panel.

wicket:panel
   span wicket:id=mainNavList
 span wicket:id=navigationItem 
   a href=#
 span wicket:id=navigationLabel/span
   /a
 /span
   /span

/wicket:panel

And the java class looks like this:

public class MainMenuListView extends ListViewINavigationItem {

   private static final long serialVersionUID = 1L;
   protected static Logger logger = 
Logger.getLogger(MainMenuListView.class);
  
   public MainMenuListView(String id, ListINavigationItem dataList) {

   super(id, dataList);
   }
  
  
   @Override

   protected void populateItem(ListItem item) {
   INavigationItem navItem = (INavigationItem) item.getModelObject();
   ResourceModel rModel = new ResourceModel(navItem.getResourceKey());
   BookmarkablePageLink pageLink = new 
BookmarkablePageLink(navigationItem, navItem.getNavTargetClass());
   item.add(new BookmarkablePageLink(navigationItem, 
navItem.getNavTargetClass()).add(new Label(navigationLabel, rModel)));

   }

}


Alexander Landsnes Keül wrote:

They need the same wicket:id yes, but that doesn't mean that they need the same 
text or targets. Just create as many links as you want/need, with whatever 
behaviour they need. Just make sure they all have the same id :)

Alex

-Opprinnelig melding-
Fra: Edbay [mailto:[EMAIL PROTECTED] 
Sendt: 22. juli 2008 19:00

Til: users@wicket.apache.org
Emne: RE: How to build a dynamic navigation bar


Thanks for the quick reply.

Wouldn't this force all links to have the same wicket ids (linkid)?
I'd like to be able to have the line items look like this:

ul wicket:id=list
li # Link01 text here /li
li # Link02 text here /li
li # Link03 text here /li
/ul





Alexander Landsnes Keül wrote:
  

I'd use a ListView :)

Assuming this lil code

add( new ListView(list, linkList )
{
public void populateItem(ListItem item)
{
item.add( (Link)linkList );
}
});

You'd have the html look something like this

ul wicket:id=list
li # Link text here /li
/ul

Just remember to add whatever you want to the item, and not just use
add(...). 


http://wicket.apache.org/docs/wicket-1.3.2/wicket/apidocs/org/apache/wicket/markup/html/list/ListView.html

Alex

-Opprinnelig melding-
Fra: Edbay [mailto:[EMAIL PROTECTED] 
Sendt: 22. juli 2008 18:08

Til: users@wicket.apache.org
Emne: How to build a dynamic navigation bar


Hello, 
  
I want to be able to build a left-side dynamic navigation bar based on

user
permissions. For example, if the user does not have access to the Prices
page, I do not want to show the Prices link on the navigation bar. Also,
since the link will point to a Wicket page, it has to be a Wicket link. 

This is how I would like the NavBar to appear: 


div id=mainNav
ul
li Home /li
li Prices /li
li Contracts /li
li Products /li
li Transactions /li
/ul
/div

I tried using ListView, but I could not get it to work, as it forces the
wicket id of the line items to be all the same. 



Thanks in advance.
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Re: How to build a dynamic navigation bar

2008-07-22 Thread Edbay 

I get this approach. Can you provide the code for the panel?

ul
  !-- note: the   tag here is only for preview,
   it will be replaced by the link panel contents --
  li wicket:id=menuItem # Foo /li
/ul

RepeatingView menu = new RepeatingView(menuItem);

menu.add(new MyMenuPanel(menu.newChildId(), Home, HomePage.class));

if (userIsDarthVader) {
menu.add(new MyMenuPanel(menu.newChildId(), Enslave Universe,
EnslaveUniversePage.class));
}

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Re: How to build a dynamic navigation bar

2008-07-22 Thread John Krasnay 
Something like this...

wicket:panel
  a wicket:id=linkspan wicket:id=labelFoo/span/a
/wicket:panel

public class MyMenuPanel extends Panel {
  public MyMenuPanel(String id, String label, Class pageClass) {
super(id);
Link link = new BookmarkablePageLink(link, pageClass);
add(link);
link.add(new Label(label, label));
  }
}

jk

On Tue, Jul 22, 2008 at 01:32:55PM -0700, Edbay wrote:
 
 I get this approach. Can you provide the code for the panel?
 
 ul
   !-- note: the   tag here is only for preview,
it will be replaced by the link panel contents --
   li wicket:id=menuItem # Foo /li
 /ul
 
 RepeatingView menu = new RepeatingView(menuItem);
 
 menu.add(new MyMenuPanel(menu.newChildId(), Home, HomePage.class));
 
 if (userIsDarthVader) {
 menu.add(new MyMenuPanel(menu.newChildId(), Enslave Universe,
 EnslaveUniversePage.class));
 }
 
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Re: How to build a dynamic navigation bar

2008-07-22 Thread Edbay 

Works! 
:clap:
wicket:panel
   Foo 
/wicket:panel


public class MyMenuPanel extends Panel {
  public MyMenuPanel(String id, String label, Class pageClass) {
super(id);
Link link = new BookmarkablePageLink(link, pageClass);
add(link);
link.add(new Label(label, label));
  }
}

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Navigation bar

2008-04-07 Thread Milan Křápek 
Hi, 
  I need your help. After few days I am out of ideas and still have no solution.

What I have:
  I have stored users in databes and each user has some List od favourite pages 
URLs. This URLs links external pages.

What I need:
  I need to do some sort of TabbedPanel or one row table without headers, which 
will contains links to the stored URLs.

Where is the problem:
  First I try to use TabbedPanel but this is impossible due to the TabbedPanel 
returns just wicket Panel and not any URL. Then I try to use DataTable but 
these tables have header line. So I try to give my links to the headers. It 
looks like it is working. But it did not render to the page. I think it was due 
to empty data rows so wicket does not render the empty table. At last I try to 
use GridView but I was not able to determine the names of url links. 

Please have you met this problem before? Is it possible to upgrade the 
TabbedPanel to return the url instead of Panel??

Thanks for any advice. 

Milan  

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Re: Navigation bar

2008-04-07 Thread Igor Vaynberg 
add(new listview(links, linksmodel) {
 onpopulateitem(item item) {
   e=new externallink(link, item.getmodel().getlink(),
item.getmodel().getlabel());
  }
}

tabletrtd wicket:id=linksa wicket:id=linklink/a/td/tr/table

-igor

On Mon, Apr 7, 2008 at 3:44 AM, Milan Křápek [EMAIL PROTECTED] wrote:
 Hi,
   I need your help. After few days I am out of ideas and still have no 
 solution.

  What I have:
   I have stored users in databes and each user has some List od favourite 
 pages URLs. This URLs links external pages.

  What I need:
   I need to do some sort of TabbedPanel or one row table without headers, 
 which will contains links to the stored URLs.

  Where is the problem:
   First I try to use TabbedPanel but this is impossible due to the 
 TabbedPanel returns just wicket Panel and not any URL. Then I try to use 
 DataTable but these tables have header line. So I try to give my links to the 
 headers. It looks like it is working. But it did not render to the page. I 
 think it was due to empty data rows so wicket does not render the empty 
 table. At last I try to use GridView but I was not able to determine the 
 names of url links.

  Please have you met this problem before? Is it possible to upgrade the 
 TabbedPanel to return the url instead of Panel??

  Thanks for any advice.

  Milan

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Re: Navigation bar

2008-04-07 Thread Milan Křápek 
Thanks a lot, this was the thing I was looking for.

Milan

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