Re: one form - two submit buttons with different behavior
An idea: in Form#onSubmit() check whether the current request is Ajax: if (AjaxRequestTarget.get() != null) return; // i.e. do not execute the method' body You can even check whether the submittingComponent is the AjaxButton and do nothing in that case only On Wed, Jan 5, 2011 at 1:19 PM, Marek Pribyl mr.pri...@gmail.com wrote: hi all, I have form with two submit buttons want different behavior for each button. submitButton: - standard submit button - expected onClick behavior: validate form save the form's model (implemented in form's onSubmit() method) redirect to another page ajaxButton: - AjaxButton - expected onClick behavior: validate form, if valid get form's model display it as XML in modal window for preview the problem is that form's onSubmit() is called when I click on ajaxButton - I need to keep validation but do not call form's onSubmit() method, i.e. stay on the current form page do not save the model. Is there any chance to do this wicket way? thanks, marek - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: one form - two submit buttons with different behavior
You can also move all your code from form.onSubmit to the standartButton.onSubmit On Wed, Jan 5, 2011 at 10:19 AM, Marek Pribyl mr.pri...@gmail.com wrote: hi all, I have form with two submit buttons want different behavior for each button. submitButton: - standard submit button - expected onClick behavior: validate form save the form's model (implemented in form's onSubmit() method) redirect to another page ajaxButton: - AjaxButton - expected onClick behavior: validate form, if valid get form's model display it as XML in modal window for preview the problem is that form's onSubmit() is called when I click on ajaxButton - I need to keep validation but do not call form's onSubmit() method, i.e. stay on the current form page do not save the model. Is there any chance to do this wicket way? thanks, marek - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org -- Pedro Henrique Oliveira dos Santos
Re: one form - two submit buttons with different behavior
Hi Marek, you could override form method 'process(IFormSubmittingComponent submittingComponent) ' checking whether submittingComponent is submitButton or ajaxButton. submitButton follows standard behavior calling super.process(...), whereas ajaxButton just call validate(). But remember that form's onSubmit() must be called anyway, so as Pedro suggested you should move onSubmit code to submitButton. hi all, I have form with two submit buttons want different behavior for each button. submitButton: - standard submit button - expected onClick behavior: validate form save the form's model (implemented in form's onSubmit() method) redirect to another page ajaxButton: - AjaxButton - expected onClick behavior: validate form, if valid get form's model display it as XML in modal window for preview the problem is that form's onSubmit() is called when I click on ajaxButton - I need to keep validation but do not call form's onSubmit() method, i.e. stay on the current form page do not save the model. Is there any chance to do this wicket way? thanks, marek - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: one form - two submit buttons with different behavior
thanks all for reply, I chose martin's solution which works for me in this particular case marek On Wed, 2011-01-05 at 13:19 +0100, Marek Pribyl wrote: hi all, I have form with two submit buttons want different behavior for each button. submitButton: - standard submit button - expected onClick behavior: validate form save the form's model (implemented in form's onSubmit() method) redirect to another page ajaxButton: - AjaxButton - expected onClick behavior: validate form, if valid get form's model display it as XML in modal window for preview the problem is that form's onSubmit() is called when I click on ajaxButton - I need to keep validation but do not call form's onSubmit() method, i.e. stay on the current form page do not save the model. Is there any chance to do this wicket way? thanks, marek - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
