Re: [xwiki-users] Solved

2010-02-16 Thread Vincent Massol
Hi Stefan,

On Feb 16, 2010, at 9:43 AM, stefan bachert wrote:

 1. How the change a color on a ColorTheme (stefan bachert)
 2. Readable only (stefan bachert)
 3. How to put a user into a certain group (stefan bachert)
 
 1. and 3. is resolved. My confussion was not to call inline form which 
 means execute this 'document'.
 It is confussion to the beginners only to talk about view and edit mode.
 There is at least an execute mode, too.
 
 2. is considered to be a bug.
 
 Thank you answering.
 
 How can I reply answers from the digest list without ask a new question?

I can see only 2 solutions:
1) you subscribe to receive all mails (and not only a daily digest)
2) you use Nabble/Gmane to answer, see for example: 
http://dev.xwiki.org/xwiki/bin/view/Community/Forum
(you can see more info on 
http://dev.xwiki.org/xwiki/bin/view/Community/MailingLists)

Thanks
-Vincent

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Re: [xwiki-users] Display a well rendered field

2010-02-16 Thread PERINAUD Christophe
I checked my code and my problem now is that all is displayed well except 
carriage returns
So if i have some text in bold it's well displayed but all lines are displayed 
in only one string. Do i have to add/remove an option somewhere to not removed 
them ?

Also when i click on the Edit menu in the top bar, it opens the WYSIWYG editor. 
Is it possible with velocity to force the inline form editor ? (iT worked 
before but i guess i changed something somewhere ...)

Thanks 

 -Message d'origine-
 De : users-boun...@xwiki.org [mailto:users-boun...@xwiki.org] 
 De la part de Valdis Vitolinš
 Envoyé : lundi 15 février 2010 14:32
 À : XWiki Users
 Objet : Re: [xwiki-users] Display a well rendered field
 
 Standard ClassSheet template has simpler syntax:
 $doc.display(propertyname)
 
 e.g.
 {{velocity}}
 ## You can modify this page to customize the presentation of your
 object.
 ## At first you should keep the default presentation and just save the
 document.
 = Īsziņa $doc.name =
 
 #set($class = $doc.getObject('Custom.IszinaClass').xWikiClass)
 #foreach($prop in $class.properties)
 |$prop.prettyName| $doc.display($prop.getName())
 #end
 {{/velocity}}
 
 and it works seamlessly.
 Valdis 
 
  Thanks Valdis. 
  
   
   I check the class in the class editor and for this 
 textarea, i don't see how to change the rendering. Is it in 
 the class or in the call to display the field ? (i use 
 $doc.display($fieldName, view) )
   
   I use Xwiki 2.0.3
   
-Message d'origine-
De : users-boun...@xwiki.org [mailto:users-boun...@xwiki.org] 
De la part de Valdis Vitolinš
Envoyé : lundi 15 février 2010 13:03
À : XWiki Users
Objet : Re: [xwiki-users] Display a well rendered field

It seems your default editor is WYSIWYG, but text field is 
simple text.
You need to set textarea field to FullyRenderedText (Xwiki 
1.x version)
or WYSIWYG (2.x version) mode.

Valdis


 Hello all,
 
 I have a class with text fields. When i want to display the 
value of one of them, i only have a very long string.
 How can i display it with nice rendering (bold, colors, 
etc) ? (In edit mode i have the WYSIWYG editor)
 
 Thank you 
 
 Christophe Périnaud
 Windows Server 2003 SP2 in a VMWare instance
 Oracle 10g
 Java 1.6.0_12
 Xwiki 2.0.3 from the pack Jetty/HSQL
 
 ...
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[xwiki-users] How to get the creation date of a document

2010-02-16 Thread Hernández Cuchí , Francisco Ricardo
Hello,

 

I am rewriting the todo example list to be suitable for my company. I would 
like to show in the list the date of creation of the documents. How can i get 
it?

 

The code is something like:

 

table id=todoTable class=grid sortable filterable doOddEven 
cellpadding=0 cellspacing=0 border=0

  tr class=sortHeader

th class=unsortable selectFilterFecha/th

thResumen/th

thStatus/th

thPersona/th

thPestaña/th

th class=unsortable selectFilterDescripcion/th

/tr

#foreach ($todo in $todos)

  tr

#set ($todoDoc = $xwiki.getDocument($todo))

#set ($todoObj = $todoDoc.getObject(XWiki.TodoClass))

td[$todoObj.TargetDate$todo]/td

td[$todoObj.Resumen$todo]/td

td[$todoObj.Status$todo]/td

td[$todoObj.Persona$todo]/td

td[$todoObj.Pestana$todo]/td

td$todoObj.Descripcion/td

 

  /tr

#end

/table

 

So get from the todoobj the creation date.

 

Regards,

 

Francisco

 

--

Francisco Hernández Cuchí

Jefe de Servicios Sistemas de Información 

OFICINA ESPAÑOLA DE PATENTES Y MARCAS

C\ Paseo de la Castella 75

tlf: 913496844

mail: francisco.hernan...@oepm.es mailto:francisco.hernan...@oepm.es 

 

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[xwiki-users] Method that returns list of groups for a page

2010-02-16 Thread Meng Wu
Hey all,

I am trying to find a method that can return a list of groups that have a given 
access right to a given page. Is there a method(s) that allow me to do that? 
I'm aware that you can create an object of AccessRights onto a given page and 
filter in groups and users that have access rights to a given page, but only 
admins can see that. I need to generate a list of groups that have granted 
access so that when an unregistered user tries to log onto a page that he 
doesn't have access to, a list will be generated so that he can ask for 
membership to those groups. 

Thank you,

Felix Wu



  

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Re: [xwiki-users] How to get the creation date of a document

2010-02-16 Thread Marius Dumitru Florea
Hi Hernández,

Hernández Cuchí wrote:
 Hello,
 
  
 

 I am rewriting the todo example list to be suitable for my company. I would 
 like to show in the list the date of creation of the documents. How can i get 
 it?

See 
http://platform.xwiki.org/xwiki/bin/download/DevGuide/API/xwiki-core-2.2-javadoc.jar/com/xpn/xwiki/api/Document.html#getCreationDate%28%29

 
  
 
 The code is something like:
 
  
 
 table id=todoTable class=grid sortable filterable doOddEven 
 cellpadding=0 cellspacing=0 border=0
 
   tr class=sortHeader
 
 th class=unsortable selectFilterFecha/th
 
 thResumen/th
 
 thStatus/th
 
 thPersona/th
 
 thPestaña/th
 
 th class=unsortable selectFilterDescripcion/th
 
 /tr
 
 #foreach ($todo in $todos)
 
   tr
 
 #set ($todoDoc = $xwiki.getDocument($todo))
 
 #set ($todoObj = $todoDoc.getObject(XWiki.TodoClass))
 
 td[$todoObj.TargetDate$todo]/td
 
 td[$todoObj.Resumen$todo]/td
 
 td[$todoObj.Status$todo]/td
 
 td[$todoObj.Persona$todo]/td
 
 td[$todoObj.Pestana$todo]/td
 
 td$todoObj.Descripcion/td
 
  
 
   /tr
 
 #end
 
 /table
 
  
 

 So get from the todoobj the creation date.

You can't get it from the object, afaik, but from the document:

$todoDoc.creationDate

Hope this helps,
Marius

 
  
 
 Regards,
 
  
 
 Francisco
 
  
 
 --
 
 Francisco Hernández Cuchí
 
 Jefe de Servicios Sistemas de Información 
 
 OFICINA ESPAÑOLA DE PATENTES Y MARCAS
 
 C\ Paseo de la Castella 75
 
 tlf: 913496844
 
 mail: francisco.hernan...@oepm.es mailto:francisco.hernan...@oepm.es 
 
  
 
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 IMPORTANTE: El contenido de este correo y ficheros adjuntos es confidencial y 
 está dirigido únicamente 
 para el destinatario/s.
 Si Ud recibe este correo por error, por favor póngase en contacto con su 
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 emisor immediatamente y no difunda su contenido a nadie ni haga copias.
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Re: [xwiki-users] Method that returns list of groups for a page

2010-02-16 Thread Caleb James DeLisle
Hello Felix,

I think you're looking for:
$xwiki.hasAccessLevel(edit, XWiki.SomeUser, Main.DocumentInQuestion))

see: 
http://maven.xwiki.org/site/xwiki-core-parent/xwiki-core/apidocs/com/xpn/xwiki/api/XWiki.html#hasAccessLevel(java.lang.String,%20java.lang.String,%20java.lang.String)

It says users, but I think you can use a group name instead.

Caleb


Meng Wu wrote:
 Hey all,
 
 I am trying to find a method that can return a list of groups that have a 
 given access right to a given page. Is there a method(s) that allow me to do 
 that? I'm aware that you can create an object of AccessRights onto a given 
 page and filter in groups and users that have access rights to a given page, 
 but only admins can see that. I need to generate a list of groups that have 
 granted access so that when an unregistered user tries to log onto a page 
 that he doesn't have access to, a list will be generated so that he can ask 
 for membership to those groups. 
 
 Thank you,
 
 Felix Wu
 
 
 
   
 
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