Re: free-energy mechanism with H2O
In a message dated 7/26/04 5:38:10 PM Pacific Daylight Time, [EMAIL PROTECTED] writes: Ironically, the reason that any of this can happen at all, as Fred has been suggesting, is that a high voltage gradient serves to oscillate the ever-present neutrino flux to the degree that they will interact with neutrons. This has been demonstrated. The neutrinos, however, cannot accomplish this accelerated decay thing within the D nucleus, so there has to be QM "partial" tunneling involved first. This is the determining factor on the rate of the reaction. That is why the Fusor is likely a dead-end street as far as viable LENR device is concerned, unless a larger amount of neutrinos can be focused into the device using much larger HV coils, space around the device. Fred threw this out to Earth-Tech, but they didn't bite. Nikola Tesla used flat spiral coils in reverse, and capacitors in resonance, with the condition of synchronisation to capture neutrinos and materialize them into useable energy: " As quoted from Konstantine Meyl, Scalar Waves, Pg. 207: The answer of the potential vortex theory could turn out as follows: If at the transition of the one wire to the wireless transmission the ring-like vortices is purloined the guiding wire the vortices immediately begin to turn around each other, as is observable for flow-technical ring-like vortices. In this way the ring-like vortex the next moment shows it inside. If it before as an electron vortex (fig. 4.3), then it now shows as positron, if it was negatively charged, then it now is positively charged. Following it oscillates back again, etc. Wit that the ring-like vortex on the average has no measurable charge and no mass, because it alternately forms matter and antimatter. Without interaction it has an enormous ability of penetration. In physics such particles are called neutrinos. Tesla thus had, apart from his transmitted energy wave, which turned out to be neutrino radiation, by chance also caught neutrinos which oscillated synchronously. According to the actual level of knowledge do neutrinos penetrate the earth and appear also on the night side. The order of magnitude in every second amounts to approx. 66 billion neutrinos per square centimeter. It is a true bombardment. If we could be able to collect and convert all neutrinos, the won energy would be entirely sufficient to cover the need for energy of the world population (approx. 27 W/m^2). We merely have to materialize them, thus give them mass, charge, and the necessary localization. Tesla was able to do that experimentally! Let's record: The ring like vortices, which Telsa with his transmitter has sent on a journey as electrons with an open vortex center, are neutrinos (fig 7.12). Telsa requests that transmitter and reciever operate in resonance, thus with the same frequency. Under this condition the receiver collects in all oscillating vortices, so that non one is lost. If the neutrinos for instance are just positively charged, when leaving the transmitter electrode, then an electromagnetic force of attraction takes place, if the receiver electrode at the same time is negatively charged. The required operation with the same frequency and opposite phase guarantees that also the next moment, if both, the neutrino and the receiver have changed their polarity, the electromagnetic attraction is preserved. It is obvious that strange neutrinos which fly past and by chance oscillate synchronously are as well attracted. In that way the power collected in the receiver capacitor will increase further and degrees of effectiveness of over 100% are obtainable. Telsa discharges the receiver capacitor timed with the frequency of resonance (fig. 9.9) and points to the difficultly of an exact keeping of the condition of synchronization. .." Baron Von Volsung, www.rhfweb.com\baron, Email: www.rhfweb.com\emailform.html President Thomas D. Clark, Email: www.rhfweb.com\emailform.html, Personal Web Page: www.rhfweb.com\personal New Age Production's Inc., www.rhfweb.com\newage Star Haven Community Services, at www.rhfweb.com\sh. Radiation Health Foundation Trust at www.rhfweb.com Making a difference one person at a time Get informed. Inform others.
Re: free-energy mechanism with H2O
In reply to Jones Beene's message of Sat, 17 Jul 2004 12:48:30 -0700: Hi, [snip] That is to say, in stripping, the energy deficit that appears to prohibit the reaction from happening in the first place comes from the energy that should have been left over once it happened. Of course it does, except it's not a case of before or after, but rather both at the same time. Imagine two deuterons aligned NP NP. As they approach, the first bond grows weaker as the second bond grows stronger:- N P NP followed by N PNP, and 2 D has become N + He3. The force required to tear the D apart is supplied by the growing force between the P and the other D. The net reaction is exothermic, and the other reaction resulting in P + T works about as well. Regards, Robin van Spaandonk Hot fusion is sort of like Heaven, It's the reward you get long after everyone's dead
Re: free-energy mechanism with H2O
Robin, As they approach, the first bond grows weaker as the second bond grows stronger:- N P NP followed by N PNP, and 2 D has become N + He3. The force required to tear the D apart is supplied by the growing force between the P and the other D. The net reaction is exothermic, and the other reaction resulting in P + T works about as well. I can't disagree except to say that the reason the two got that close may involve an 'extra' energy component which can be supplied by the stripping reaction. Now can you figure out how do we get helium4 in a three body reaction? Jones
Re: free-energy mechanism with H2O
So there are lots of 700 keV electrons detected? How would you detect these in a Fusor? If the question is, are secondary gammas detected the answer is yes.
Re: free-energy mechanism with H2O
In reply to Jones Beene's message of Mon, 26 Jul 2004 07:22:10 -0700: Hi, [snip] But fusors don't depend on Maxwellian tails. All the deuterons get accelerated to thousands of eV, which equates to a temperature of approx. 1E8 K. NO!! You are confusing kv with KeV. All Fusore depend on Maxwellian tails. The actual average plasma temperature of the Fusor is less than 2 eV Then they are operating with way too high plasma densities. The original intent was that bare nuclei be accelerated by the full voltage of the device, shoot right through the centre, and come out the other side, from where they would be reversed and sent back again. All of which would result in the occasional head on collision, and hopefully, a fusion reaction. If the average temperature in practice is only 2 eV or less, then this has to be because most fast moving ions are being scattered before they can pass through the core, which in turn implies that the density is way too high. Regards, Robin van Spaandonk Hot fusion is sort of like Heaven, It's the reward you get long after everyone's dead
Re: free-energy mechanism with H2O
In reply to Jones Beene's message of Mon, 26 Jul 2004 07:26:26 -0700: Hi, [snip] So there are lots of 700 keV electrons detected? How would you detect these in a Fusor? By putting a small instrument portal in the wall? If the question is, are secondary gammas detected the answer is yes. Actually I was trying to come up with a way of measuring the ratio of stripping reactions to fusion reactions, but upon further consideration I realise that since both would produce lone neutrons, this isn't a good measure anyway. A better alternative might be to measure the ratio of neutron production to that of He3 production. Since, if I'm not mistaken, the reaction you propose would result in D splitting into N + P, while a fusion reaction would result in N + He3. If the ratio of He3 to N is small, then we can assume that the D - N + P reaction predominates. Regards, Robin van Spaandonk Hot fusion is sort of like Heaven, It's the reward you get long after everyone's dead
Re: free-energy mechanism with H2O
Hi Robin, Actually I was trying to come up with a way of measuring the ratio of stripping reactions to fusion reactions, but upon further consideration I realize that since both would produce lone neutrons, this isn't a good measure anyway. That measurement can be done with a neutron spectrometer. In fact this has been done and most neutrons appear to be 2.5 MeV, which is as expected for D+D fusion. This is the main reason that Fusorites don't buy the (formerly flawed) hypothesis for stripping. I think that the earlier hypothesis which neglected the immediate n decay is also what you have been referring to in these posts. But that is not the way this *present version* of stripping should be understood. This is a new twist. I shouldn't even call it a hypothesis yet - as it must be tested, which can be done. Consequently, if what I am proposing happens in fact, the split-neutron will decay too fast to be noticed as a free neutron, and it should not have ever been picked up by any neutron spectrometer anyway, which it wasn't. So far, so good. The most noticeable thing, and the test that would prove my hypothesis, is a magnetic plasma divertor which samples a small portion of the bulk plasma spectrographically. This is probably way too expensive for most small inventors to manage - plus - none of the ones I know are convinced of this hypothesis anyway. Side note: the not-invented-here mentality extends even to the garage inventor group... IF protons are seen near 500 KeV and beyond - then yes, I think my suggestion is the only reasonable explanation. These would NOT be the proton which is left over from stripping - that would be much lower energy. Let me make that clear - we are not talking about the proton left over when a deuteron is split into a proton and a neutron. That proton is cold - the putative hot proton needed to drive the secondary reaction (D+D) is the new twist on stripping. Instead, these hot protons would be the decay protons from accelerated neutron decay. These are the very particles (along with the betas) that provide the missing energy necessary to cause real D+D fusion and real 2.5 MeV neutrons. Make no mistake - real D+D fusion occurs, it just cannot be caused by 20 kv of input, unless there is an intermediary reaction which has heretofore gone unnoticed. That reaction is not stripping, per se, it is accelerated neutron decay. It is even possible that stripping will NOT occur frequently in circumstances where immediate decay is not favored by other circumstances. As stated earlier, for every 2.5 MeV neutron seen, I expect that you will find a multiple of hot protons - maybe in a ratio of from 2-1 up to 10-1. These would be your real power source, and would be the reason that it doesn't help to raise the voltage of the Fusor, nor to increase the plasma density. In the end, this is a QM reaction and it has nearly maxed-out at ~10^10 decays per second per 10^20 deuterons present (very rough approx). Another way to prove/disprove this hypothesis is to run the Fusor for a few hours, shut it down and run everything through a high precision mass-spec. I believe that the ratio of hydrogen to tritium, or hydrogen to 3He, will be on the order of 20-1 up to 50-1. If you started the run with 100% D2 as fuel, how would you explain this otherwise? Side Note: if the protons which I am suggesting are present were a bit hotter, one might find that boron atoms in a Fusor would fuse. Some might anyway. It should be tried. Proton-Boron fusion (fission) p + 11 B -- 3 alphas + 8.7 MeV is the reaction which probably offers the ultimate energy resource on the earth, because, the fuels are ubiquitous on the earth, cheap and fast neutrons are not generated. It has been shown, however, that bremsstrahlung power losses are too large to satisfy the ignition condition in a solenoid because the atomic number of boron is so large but as to a Fusor, well, let's say it should be tried. The real power source of the Fusor is IMHO not the 20 kilovolt input, nor a recycling of the D+D energy (as the neutron carries most of that off anyway) NOR is the real power source stripping per se. IMHO, the real power source is the nearly instantaneous beta decay of the neutron which has been slightly freed from the proton (QM tunneling effect) and is then subject to accelerated decay. As stated, it is even possible that stripping will NOT occur frequently in circumstances where immediate decay is not favored by other circumstances. Ironically, the reason that any of this can happen at all, as Fred has been suggesting, is that a high voltage gradient serves to oscillate the ever-present neutrino flux to the degree that they will interact with neutrons. This has been demonstrated. The neutrinos, however, cannot accomplish this accelerated decay thing within the D nucleus, so there has to be QM partial tunneling involved first. This is the determining factor on the
