http://www.wolframalpha.com/input/?i=energy+to+heat+1.2+kg+of+water+to+100+celsius
Wow, wolfram is amazing. Who needs to be a scientist! :D
On Sun, Dec 28, 2014 at 2:58 PM, Blaze Spinnaker blazespinna...@gmail.com
wrote:
errr, 4.8 joules in a calorie even. Yeah science ain't my strong suit!
I should just stick to the social proof thing..
On Sun, Dec 28, 2014 at 2:57 PM, Blaze Spinnaker blazespinna...@gmail.com
wrote:
sorry, 4.8 calories in a joule. Nvm
On Sun, Dec 28, 2014 at 2:51 PM, Blaze Spinnaker
blazespinna...@gmail.com wrote:
If it takes 540 calories are needed to turn 1 gram (at 100 degrees
Celsius) of water to steam, than that's 540 * 1200 * .23 = 149000 joules,
right?
On Sun, Dec 28, 2014 at 2:45 PM, Blaze Spinnaker
blazespinna...@gmail.com wrote:
Also... is 2712000 the right amount for vaporization of the water?
Doesn't it have to be dry steam to reach that energy amount? Looking at his
set up, it seems like it would be pretty wet.
On Sun, Dec 28, 2014 at 2:26 PM, Blaze Spinnaker
blazespinna...@gmail.com wrote:
https://docs.google.com/document/d/1Y3Bxr_aE2iosEKpGFUZiQgAcuT8AFN78RFCAlR-JqNw/edit
On Sun, Dec 28, 2014 at 2:26 PM, Blaze Spinnaker
blazespinna...@gmail.com wrote:
Note by translator Stoyan Sarg: The initial heating power and
temperature before reaching 1C is not shown in the plot of slide
#16 (does he mean 17?). Is it taken into account for the accumulated
energy? If not a much longer test is needed for estimation of the COP.