Hi Anthony,
Thanks for your continuous help. I tried like below, i had to specify
uploadfolder in SQLFORM.factory(), otherwise web2py raised error saying
user must specify uploadfolder. Then I thought i could override it after
form.accepted, but it didn't. The uploaded file ended up storing under the
top-level folder (auth.user.id) instead of (company_id). One thing I don't
want is to ask the user to fill in company details in 1 form, submit it,
then redirect to another form and upload the logo image. I wonder if you
actually meant what I did below. Thanks!
form=SQLFORM.factory(
Field('company_name', requires=[IS_NOT_EMPTY(),
IS_NOT_IN_DB(db, 'company.company_name')]),
Field('logo', 'upload',
uploadfolder=os.path.join(request.folder, 'uploads', str(auth.user.id)),
uploadseparate=True, autodelete=True), # 23x23mm, 300K recommended
table_name='company',
formstyle='table3cols').process()
if form.accepted:
company_id= db.company.insert(company_name=form.vars.company_name)
db.company.logo.uploadfolder=os.path.join(request.folder,
'uploads', str(company_id)) # 23x23mm, 300K recommended
db.company.chop.uploadseparate=True
db.company.logo.autodelete=True
company_row = db.company(company_id)
company_row.update_record(logo=form.vars.logo)
elif form.errors: ...
else: ...
On Friday, October 13, 2017 at 9:59:34 AM UTC+8, Anthony wrote:
>
> Instead of having SQLFORM automatically insert the new record, you can
> create custom logic to first insert everything but the file, and then after
> getting the new record ID, use that to set the uploadfolder and update the
> record with the file.
>
> Anthony
>
> On Thursday, October 12, 2017 at 8:26:16 PM UTC-4, Rudy wrote:
>>
>> Hi Antony,
>>
>> Thanks so much again for sharing your insights. I have been playing with
>> uploadfolder, your suggestion below and from another thread
>> (uploadfolder=os.path.join(request.folder, 'uploads', str(auth.user.id)
>> if auth.user else '') work. However what I really want to do is to separate
>> the files being uploaded based on a company_id. Say an user comes to my
>> site, register as admin user for his company based on group assignment,
>> then he / she will be instructed to register his/her company details
>> including the logo image (being uploaded). Now I want to set this top-level
>> upload folder to be company_id, however I will only get the company_id
>> after i submit the form, I don't want to set the top-level upload folder
>> based on auth.user.id because this admin user can create more users for
>> this company for day-to-day tasks, I want to group all the file system
>> consumption based on company.
>>
>> I think about computing the next_company_id by doing below, but if i have
>> 2 users trying to do the same thing, i will have a race condition and get
>> error. I search in this forum to see how people deal with auto increment
>> field, Mathieu suggested Field('ref_number', compute=lambda r: r['id'] +
>> 100), but i don't seem to be able to apply it in uploadfolder attribute,
>> any suggestion will be much appreciated.
>>
>> company_rows=db().select(db.company.ALL)
>> if company_rows:
>> last_company_row=company_rows.last()
>> next_company_id=last_company_row.id + 1
>> else:
>> next_company_id=1
>>
>>
>> On Thursday, September 28, 2017 at 12:32:46 AM UTC+8, Anthony wrote:
>>>
>>> On Wednesday, September 27, 2017 at 5:04:27 AM UTC-4, Rudy wrote:
Dave / Anthony,
Thanks for your input and confirmation. I will look into the code to
see how i can use the uuid to separate files for multi-tenant purpose.
>>>
>>> If you're going to be accessing the uploaded files based on the
>>> filenames stored in the database, you don't necessarily need to do anything
>>> with the filesystem to enable multi-tenant functionality. The database
>>> records will identify the tenants and therefore enable you to identify
>>> which files belong to which tenants.
>>>
>>> However, if you need to easily be able to identify files associated with
>>> a given tenant from the filesystem only (i.e., without reference to the
>>> database records), then you could create separate top-level upload folders
>>> for each client. In your code, you would do that by dynamically specifying
>>> the "uploadfolder" argument of the Field() constructor to set a unique
>>> folder for each client. For example:
>>>
>>> uploadfolder=os.path.join(request.folder, 'uploads', tenant_id)
>>>
>>> You could still leave uploadseparate=True, and then you'll get folders
>>> like:
>>>
>>> /uploads/1/company.logo/ab/
>>> /uploads/2/company.logo/dy/
>>>
>>> where 1 and 2 are the id's of different tenants.
>>>
>>> Anthony
>>>
>>
--
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