[web2py] web2py UnicodeDecodeError: 'utf8' codec can't decode byte 0xc7 in position 15: invalid continuation
I'm using a firebird legacy database and when I make this query: dbFb.INVENTORY.CODE==3 i got this output error: UnicodeDecodeError: 'utf8' codec can't decode byte 0xc7 in position 15: invalid continuation *there is a field called 'name', and when dbFb.INVENTORY.CODE==3,* *the field name has a word 'ç' in its value * Anyone can help me? -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] web2py fails to read words in utf8 format with db.executesql()
I'm having a problem with my web2py website When I execute a sql command, for all fields that has "ç", I got this message: 'utf8' codec can't decode byte 0xc7 in position 15: invalid continuation byteError This is my method: def get_something(): mRow=dbFb.executesql("select first 1 CODIGO, NOME, PRECO_CONS, QTD from ESTOQUE where CODIGO='"request.vars.mCode+"'", as_dict = True) How can i fix this? -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Interact Web2Py App with Android App Security
i thought i can use this session in my schema... but really, i have no idea what i need to do ... i read something about base authentication in Web2Py, is this helpful? Em sexta-feira, 2 de outubro de 2015 19:47:09 UTC-3, Niphlod escreveu: > > what authentication do you want to support ? web2py's default use session > cookies, but you need to get to the login page and obtain one before > hitting a protected page > > On Friday, October 2, 2015 at 11:06:25 PM UTC+2, Fábio Filho wrote: >> >> I'm sorry by my english >> >> How can i connect my android application in my web2py site using auth >> authentication (@auth.requires_login)? >> >> I need make a secure connection between them >> >> for example: >> >> >> Web2Py Side : >> >> @auth.requires_login() >> def get_examplet(): >> return "{'code':'0'}" >> >> >> >> >> Android Java side: >> >> new Thread(){ >> >> @Override >> public void run(){ >> >> Http.request("localhost:8080/mysite/controller/get_example") >> ; // < i got a refused connection because that python line code >> ("@auth.requires_login()"), >> >> //so of course that is expected >> because i need to be logged in to make this request >> >> // when a remove that python line code >> above ("@auth.requires_login()"), i take it perfectly >> >>} >> >> }.start(); >> >> >> >> How can i do this above? >> >> >> -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Interact Web2Py App with Android App Security
I'm sorry by my english How can i connect my android application in my web2py site using auth authentication (@auth.requires_login)? I need make a secure connection between them for example: Web2Py Side : @auth.requires_login() def get_examplet(): return "{'code':'0'}" Android Java side: new Thread(){ @Override public void run(){ Http.request("localhost:8080/mysite/controller/get_example") ; // < i got a refused connection because that python line code ("@auth.requires_login()"), //so of course that is expected because i need to be logged in to make this request // when a remove that python line code above ("@auth.requires_login()"), i take it perfectly } }.start(); How can i do this above? -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Importing Data / Force Record ID #s To Remain As Specified in the CSV
Massimo, It's doesn't works for me. I have two columns: tbState.id and tbState.Name . I need to keep this id because i am using it in another table. i'm using the following code in shell tool: db.tbState.import_from_csv_file(open('db_tbState.csv'), map = {}) Thaks On Thursday, January 23, 2014 at 2:39:51 PM UTC-3, Mark Billion wrote: > > I know that this is a dumb question, but I have a database with static > data entry ids 17 to 100. When I download the CSV, it has the x.id field > and the corresponding number. However, when I create a new database and > upload the data using the db admin, it automatically renumbers these > entries. Because its static, I have been referencing it by id -- so > renumbering throws this off. > > Anything I can do? > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.