For testing purposes I would like to execute a function in scheduler.py
using command line (better ideas are welcome)
I tried:
web2py.exe -S myapp/scheduler/dummy_task -M
But got the following error
web2py Web Framework
Created by Massimo Di Pierro, Copyright 2007-2017
Version 2.14.6-stable+timestamp.2016.05.10.00.21.47
Database drivers available: psycopg2, pymysql, imaplib, MySQLdb, sqlite3,
pyodbc
Traceback (most recent call last):
File "<string>", line 6, in <module>
File "__main__.py", line 128, in <module>
File "__main__web2py__.py", line 33, in <module>
File "C:\Dev\web\web2py_win\web2py_2_14_06\gluon\widget.py", line 1146,
in start
cronjob=options.cronjob)
File "C:\Dev\web\web2py_win\web2py_2_14_06\gluon\shell.py", line 245, in
run
exec read_pyc(pycfile) in _env
File "C:\Dev\web\web2py_win\web2py_2_14_06\gluon\compileapp.py", line
461, in read_pyc
data = read_file(filename, 'rb')
File "C:\Dev\web\web2py_win\web2py_2_14_06\gluon\fileutils.py", line 103,
in read_file
f = open(filename, mode)
IOError: [Errno 2] No such file or directory:
'applications\\myapp\\compiled\\controllers_scheduler_dummy_task.pyc'
Thanks for any help
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