[web2py] Re: How to use button instead of input in SQLForm

[Andreas Kaiser]

Hi,

is there a way to simplify these expression:  form[0][-1][1] ? Ok, I can 
assign these expression to a var. For a lot of questions regarding forms, 
there is  form[0][-1][1] part of an answer.

Thanks
Andreas

Am Samstag, 7. Juli 2012 02:38:04 UTC+2 schrieb Massimo Di Pierro:

 try

 form[0][-1][1].components = [
   TAG.button('Upload', _id=px-submit,_type=submit),
   TAG.button('Clear',_id=px-clear,_type=reset),
 ]

 or you can use a custom form.

 On Friday, 6 July 2012 17:09:41 UTC-5, Andrew Evans wrote:

 Hello I am trying to figure out how to replace the submit button in 
 SQLFORM

 I would like to replace with 

 button id=px-submit type=submitUpload/button

 and add

 button id=px-clear type=resetClear/button

 My controller is

 def index():
 form = SQLFORM(db.music2)
 if form.accepts(request.vars, session):
 #db.music2.insert(song = 
 db.music2.song.store(request.vars.Filedata.file, 
 request.vars.Filedata.filename))
 response.flash = 'Your data has been submitted'
 elif form.errors:
 response.flash = 'Please correct the highlighted fields'
 return dict(form=form)
 else:
 return dict(form=form)

 return dict()

 Any ideas/advice is greatly appreciated :-)

[web2py] Re: How to use button instead of input in SQLForm

[Massimo Di Pierro]

You can try replace
form[0][-1][1]

with

form.element(_type='submit').parent

On Saturday, July 7, 2012 3:19:02 AM UTC-5, Andreas Kaiser wrote:

 Hi,

 is there a way to simplify these expression:  form[0][-1][1] ? Ok, I can 
 assign these expression to a var. For a lot of questions regarding forms, 
 there is  form[0][-1][1] part of an answer.

 Thanks
 Andreas

 Am Samstag, 7. Juli 2012 02:38:04 UTC+2 schrieb Massimo Di Pierro:

 try

 form[0][-1][1].components = [
   TAG.button('Upload', _id=px-submit,_type=submit),
   TAG.button('Clear',_id=px-clear,_type=reset),
 ]

 or you can use a custom form.

 On Friday, 6 July 2012 17:09:41 UTC-5, Andrew Evans wrote:

 Hello I am trying to figure out how to replace the submit button in 
 SQLFORM

 I would like to replace with 

 button id=px-submit type=submitUpload/button

 and add

 button id=px-clear type=resetClear/button

 My controller is

 def index():
 form = SQLFORM(db.music2)
 if form.accepts(request.vars, session):
 #db.music2.insert(song = 
 db.music2.song.store(request.vars.Filedata.file, 
 request.vars.Filedata.filename))
 response.flash = 'Your data has been submitted'
 elif form.errors:
 response.flash = 'Please correct the highlighted fields'
 return dict(form=form)
 else:
 return dict(form=form)

 return dict()

 Any ideas/advice is greatly appreciated :-)

[web2py] Re: How to use button instead of input in SQLForm

[Massimo Di Pierro]

try

form[0][-1][1].components = [
  TAG.button('Upload', _id=px-submit,_type=submit),
  TAG.button('Clear',_id=px-clear,_type=reset),
]

or you can use a custom form.

On Friday, 6 July 2012 17:09:41 UTC-5, Andrew Evans wrote:

 Hello I am trying to figure out how to replace the submit button in SQLFORM

 I would like to replace with 

 button id=px-submit type=submitUpload/button

 and add

 button id=px-clear type=resetClear/button

 My controller is

 def index():
 form = SQLFORM(db.music2)
 if form.accepts(request.vars, session):
 #db.music2.insert(song = 
 db.music2.song.store(request.vars.Filedata.file, 
 request.vars.Filedata.filename))
 response.flash = 'Your data has been submitted'
 elif form.errors:
 response.flash = 'Please correct the highlighted fields'
 return dict(form=form)
 else:
 return dict(form=form)

 return dict()

 Any ideas/advice is greatly appreciated :-)