Re: [web2py] Re: SEO Friendly URLs and Page Titles
Okay, but do I leave everything else alone? All I want to do is make it
www.mysite.com/equipment/id/title
currently, title is set up as slug in the DB. What am I doing wrong.
In my view:
equipment_id = request.args(0)
equipment_slug = request.args(1)
query = (db.equipment.id == item_id) (db.equipment.slug == item_slug)
item = db(query).select().first()
try:
equipment = db.equipment[int(request.args(0))]
except:
equipment = db.equipment(request.args(0)) or db(db.equipment.slug
== request.args(0)).select().first()
and then my link in sqlform:
links = [lambda row: A('Details',_href=URL('default','equipment',
args=[row.slug]))]
On Sunday, August 26, 2012 5:52:52 PM UTC-6, rochacbruno wrote:
def show():
item_id = request.args(0)
item_slug = request.args(1)
query = (db.items.id == item_id) (db.items.slug == item_slug)
item = db(query).select().first()
return dict(item=item)
http://myapp/items/show/1/awesome-product
http://myapp/items/show/2/awesome-product
On Sun, Aug 26, 2012 at 4:01 AM, SeamusSeamus
morrisjam...@gmail.comjavascript:
wrote:
I would like to make it part of the URLbut am unsure how to do
it...any tutorials or a quick way?
On Saturday, August 25, 2012 6:59:29 PM UTC-6, Anthony wrote:
Oh, yeah, I guess you probably can't use the id in a compute because
there is no id until the record has been inserted. You could instead make
the id part of the URL (like Stack Overflow), or maybe make it a virtual
field, or generate your own unique id (separate from the record id).
Anthony
On Saturday, August 25, 2012 8:34:22 PM UTC-4, SeamusSeamus wrote:
Thanks for the info Anthony...
When I do this:
Field('slug', compute=lambda row: IS_SLUG()(row.title + - + str(
row.id))[0])
I get none as a slug...
On Saturday, August 25, 2012 5:53:49 PM UTC-6, Anthony wrote:
Sure, something like that seems fine. Look at what SO does -- for
example: http://stackoverflow.**com/questions/12050934/web2py-**
build-forms-in-controller-or-**viewhttp://stackoverflow.com/questions/12050934/web2py-build-forms-in-controller-or-view.
I think they use the number as the unique record identifier, but also
include a slug (which doesn't necessarily have to be unique).
Anthony
On Saturday, August 25, 2012 7:16:50 PM UTC-4, SeamusSeamus wrote:
This runs into a problem where if I have two items of the same
'title', the user will only be linked to the first one that was created.
Can I make it so the slug is a field that I designate? Or make it so the
slug adds a incrementing number such as:
Field('slug', compute=lambda row: IS_SLUG()(row.title *+ row.id*
)[0])
I know thats not how you do it, but do you get what I mean? Is there
a better way?
On Thursday, August 23, 2012 1:18:16 AM UTC-6, Anthony wrote:
links = [lambda ro
w: A('Details',_href=URL('**default','show', args=[row.slug]))]
fields = [db.equipment.category, db.equipment.title,
db.equipment.price]
You have not included slug in your list of fields, so I believe it
will not be included in the data query. Instead of specifying the list
of
fields, you can set the readable attribute to False for fields you
don't
want displayed (including slug). In that case, all fields will be
included in the query (including slug), but only the fields you want
to
show will be visible in the grid.
Anthony
--
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
I don't know if you picked this up, but you don't seem to have row.id as
part of the sqlfrom url.
Perhaps try:
links = [lambda row: A('Details',_href=URL('default','equipment',
args=[row.id, row.slug]))]
On Tuesday, August 28, 2012 10:28:39 AM UTC+12, SeamusSeamus wrote:
Okay, but do I leave everything else alone? All I want to do is make it
www.mysite.com/equipment/id/title
currently, title is set up as slug in the DB. What am I doing wrong.
In my view:
equipment_id = request.args(0)
equipment_slug = request.args(1)
query = (db.equipment.id == item_id) (db.equipment.slug ==
item_slug)
item = db(query).select().first()
try:
equipment = db.equipment[int(request.args(0))]
except:
equipment = db.equipment(request.args(0)) or db(db.equipment.slug
== request.args(0)).select().first()
and then my link in sqlform:
links = [lambda row: A('Details',_href=URL('default','equipment',
args=[row.slug]))]
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
ah, yes, all is well now...however, this is strange.
Now, when I click the link on the table to take me to the
'equipment.html' page (I renamed it from details.html), it shows the
controller in the URL:
www.mysite.com/default/equipment/id/title
how do I make it so the 'default' does not show up? It didnt show up
before it looked like this:
links = [lambda row: A('Details',_href=URL('default', 'details',
args=[row.id, row.slug]))]
I changed to
links = [lambda row: A('Details',_href=URL('default', 'equipment',
args=[row.id, row.slug]))]
I also changed the controller from def default to def equipment, and also
changed default.html to equipment.html in views...
now it shows the controller in the URL...
my routes looks like this
routers = dict(
BASE = dict(default_application='equipment',
default_controller = 'default',),
)
On Monday, August 27, 2012 4:38:41 PM UTC-6, Limedrop wrote:
I don't know if you picked this up, but you don't seem to have row.id as
part of the sqlfrom url.
Perhaps try:
links = [lambda row: A('Details',_href=URL('default','equipment',
args=[row.id, row.slug]))]
On Tuesday, August 28, 2012 10:28:39 AM UTC+12, SeamusSeamus wrote:
Okay, but do I leave everything else alone? All I want to do is make it
www.mysite.com/equipment/id/title
currently, title is set up as slug in the DB. What am I doing wrong.
In my view:
equipment_id = request.args(0)
equipment_slug = request.args(1)
query = (db.equipment.id == item_id) (db.equipment.slug ==
item_slug)
item = db(query).select().first()
try:
equipment = db.equipment[int(request.args(0))]
except:
equipment = db.equipment(request.args(0)) or db(db.equipment.slug
== request.args(0)).select().first()
and then my link in sqlform:
links = [lambda row: A('Details',_href=URL('default','equipment',
args=[row.slug]))]
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
nevermind I fixed it. Not sure why, but if it was named 'equipment' the
controller showed up...any other name it doesnt. I just renamed
On Monday, August 27, 2012 5:05:44 PM UTC-6, SeamusSeamus wrote:
ah, yes, all is well now...however, this is strange.
Now, when I click the link on the table to take me to the
'equipment.html' page (I renamed it from details.html), it shows the
controller in the URL:
www.mysite.com/default/equipment/id/title
how do I make it so the 'default' does not show up? It didnt show up
before it looked like this:
links = [lambda row: A('Details',_href=URL('default', 'details', args=[
row.id, row.slug]))]
I changed to
links = [lambda row: A('Details',_href=URL('default', 'equipment',
args=[row.id, row.slug]))]
I also changed the controller from def default to def equipment, and also
changed default.html to equipment.html in views...
now it shows the controller in the URL...
my routes looks like this
routers = dict(
BASE = dict(default_application='equipment',
default_controller = 'default',),
)
On Monday, August 27, 2012 4:38:41 PM UTC-6, Limedrop wrote:
I don't know if you picked this up, but you don't seem to have row.id as
part of the sqlfrom url.
Perhaps try:
links = [lambda row: A('Details',_href=URL('default','equipment',
args=[row.id, row.slug]))]
On Tuesday, August 28, 2012 10:28:39 AM UTC+12, SeamusSeamus wrote:
Okay, but do I leave everything else alone? All I want to do is make it
www.mysite.com/equipment/id/title
currently, title is set up as slug in the DB. What am I doing wrong.
In my view:
equipment_id = request.args(0)
equipment_slug = request.args(1)
query = (db.equipment.id == item_id) (db.equipment.slug ==
item_slug)
item = db(query).select().first()
try:
equipment = db.equipment[int(request.args(0))]
except:
equipment = db.equipment(request.args(0)) or
db(db.equipment.slug == request.args(0)).select().first()
and then my link in sqlform:
links = [lambda row: A('Details',_href=URL('default','equipment',
args=[row.slug]))]
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
On 27 Aug 2012, at 4:56 PM, SeamusSeamus morrisjamespatr...@gmail.com wrote:
nevermind I fixed it. Not sure why, but if it was named 'equipment' the
controller showed up...any other name it doesnt. I just renamed
Because you also have an application named 'equipment', so some URLs are
ambiguous.
On Monday, August 27, 2012 5:05:44 PM UTC-6, SeamusSeamus wrote:
ah, yes, all is well now...however, this is strange.
Now, when I click the link on the table to take me to the 'equipment.html'
page (I renamed it from details.html), it shows the controller in the URL:
www.mysite.com/default/equipment/id/title
how do I make it so the 'default' does not show up? It didnt show up before
it looked like this:
links = [lambda row: A('Details',_href=URL('default', 'details',
args=[row.id, row.slug]))]
I changed to
links = [lambda row: A('Details',_href=URL('default', 'equipment',
args=[row.id, row.slug]))]
I also changed the controller from def default to def equipment, and also
changed default.html to equipment.html in views...
now it shows the controller in the URL...
my routes looks like this
routers = dict(
BASE = dict(default_application='equipment',
default_controller = 'default',),
)
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
I would like to make it part of the URLbut am unsure how to do it...any
tutorials or a quick way?
On Saturday, August 25, 2012 6:59:29 PM UTC-6, Anthony wrote:
Oh, yeah, I guess you probably can't use the id in a compute because there
is no id until the record has been inserted. You could instead make the id
part of the URL (like Stack Overflow), or maybe make it a virtual field, or
generate your own unique id (separate from the record id).
Anthony
On Saturday, August 25, 2012 8:34:22 PM UTC-4, SeamusSeamus wrote:
Thanks for the info Anthony...
When I do this:
Field('slug', compute=lambda row: IS_SLUG()(row.title + - + str(
row.id))[0])
I get none as a slug...
On Saturday, August 25, 2012 5:53:49 PM UTC-6, Anthony wrote:
Sure, something like that seems fine. Look at what SO does -- for
example:
http://stackoverflow.com/questions/12050934/web2py-build-forms-in-controller-or-view.
I think they use the number as the unique record identifier, but also
include a slug (which doesn't necessarily have to be unique).
Anthony
On Saturday, August 25, 2012 7:16:50 PM UTC-4, SeamusSeamus wrote:
This runs into a problem where if I have two items of the same 'title',
the user will only be linked to the first one that was created. Can I make
it so the slug is a field that I designate? Or make it so the slug adds a
incrementing number such as:
Field('slug', compute=lambda row: IS_SLUG()(row.title *+ row.id*
)[0])
I know thats not how you do it, but do you get what I mean? Is there a
better way?
On Thursday, August 23, 2012 1:18:16 AM UTC-6, Anthony wrote:
links = [lambda ro
w: A('Details',_href=URL('default','show', args=[row.slug]))]
fields = [db.equipment.category, db.equipment.title,
db.equipment.price]
You have not included slug in your list of fields, so I believe it
will not be included in the data query. Instead of specifying the list of
fields, you can set the readable attribute to False for fields you don't
want displayed (including slug). In that case, all fields will be
included in the query (including slug), but only the fields you want to
show will be visible in the grid.
Anthony
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
def show():
item_id = request.args(0)
item_slug = request.args(1)
query = (db.items.id == item_id) (db.items.slug == item_slug)
item = db(query).select().first()
return dict(item=item)
http://myapp/items/show/1/awesome-product
http://myapp/items/show/2/awesome-product
On Sun, Aug 26, 2012 at 4:01 AM, SeamusSeamus
morrisjamespatr...@gmail.comwrote:
I would like to make it part of the URLbut am unsure how to do
it...any tutorials or a quick way?
On Saturday, August 25, 2012 6:59:29 PM UTC-6, Anthony wrote:
Oh, yeah, I guess you probably can't use the id in a compute because
there is no id until the record has been inserted. You could instead make
the id part of the URL (like Stack Overflow), or maybe make it a virtual
field, or generate your own unique id (separate from the record id).
Anthony
On Saturday, August 25, 2012 8:34:22 PM UTC-4, SeamusSeamus wrote:
Thanks for the info Anthony...
When I do this:
Field('slug', compute=lambda row: IS_SLUG()(row.title + - + str(
row.id))[0])
I get none as a slug...
On Saturday, August 25, 2012 5:53:49 PM UTC-6, Anthony wrote:
Sure, something like that seems fine. Look at what SO does -- for
example: http://stackoverflow.**com/questions/12050934/web2py-**
build-forms-in-controller-or-**viewhttp://stackoverflow.com/questions/12050934/web2py-build-forms-in-controller-or-view.
I think they use the number as the unique record identifier, but also
include a slug (which doesn't necessarily have to be unique).
Anthony
On Saturday, August 25, 2012 7:16:50 PM UTC-4, SeamusSeamus wrote:
This runs into a problem where if I have two items of the same
'title', the user will only be linked to the first one that was created.
Can I make it so the slug is a field that I designate? Or make it so the
slug adds a incrementing number such as:
Field('slug', compute=lambda row: IS_SLUG()(row.title *+ row.id*
)[0])
I know thats not how you do it, but do you get what I mean? Is there
a better way?
On Thursday, August 23, 2012 1:18:16 AM UTC-6, Anthony wrote:
links = [lambda ro
w: A('Details',_href=URL('**default','show', args=[row.slug]))]
fields = [db.equipment.category, db.equipment.title,
db.equipment.price]
You have not included slug in your list of fields, so I believe it
will not be included in the data query. Instead of specifying the list of
fields, you can set the readable attribute to False for fields you don't
want displayed (including slug). In that case, all fields will be
included in the query (including slug), but only the fields you want to
show will be visible in the grid.
Anthony
--
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
This runs into a problem where if I have two items of the same 'title', the
user will only be linked to the first one that was created. Can I make it
so the slug is a field that I designate? Or make it so the slug adds a
incrementing number such as:
Field('slug', compute=lambda row: IS_SLUG()(row.title *+ row.id*)[0])
I know thats not how you do it, but do you get what I mean? Is there a
better way?
On Thursday, August 23, 2012 1:18:16 AM UTC-6, Anthony wrote:
links = [lambda ro
w: A('Details',_href=URL('default','show', args=[row.slug]))]
fields = [db.equipment.category, db.equipment.title,
db.equipment.price]
You have not included slug in your list of fields, so I believe it will
not be included in the data query. Instead of specifying the list of
fields, you can set the readable attribute to False for fields you don't
want displayed (including slug). In that case, all fields will be
included in the query (including slug), but only the fields you want to
show will be visible in the grid.
Anthony
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
Sure, something like that seems fine. Look at what SO does -- for example:
http://stackoverflow.com/questions/12050934/web2py-build-forms-in-controller-or-view.
I think they use the number as the unique record identifier, but also
include a slug (which doesn't necessarily have to be unique).
Anthony
On Saturday, August 25, 2012 7:16:50 PM UTC-4, SeamusSeamus wrote:
This runs into a problem where if I have two items of the same 'title',
the user will only be linked to the first one that was created. Can I make
it so the slug is a field that I designate? Or make it so the slug adds a
incrementing number such as:
Field('slug', compute=lambda row: IS_SLUG()(row.title *+ row.id*)[0])
I know thats not how you do it, but do you get what I mean? Is there a
better way?
On Thursday, August 23, 2012 1:18:16 AM UTC-6, Anthony wrote:
links = [lambda ro
w: A('Details',_href=URL('default','show', args=[row.slug]))]
fields = [db.equipment.category, db.equipment.title,
db.equipment.price]
You have not included slug in your list of fields, so I believe it will
not be included in the data query. Instead of specifying the list of
fields, you can set the readable attribute to False for fields you don't
want displayed (including slug). In that case, all fields will be
included in the query (including slug), but only the fields you want to
show will be visible in the grid.
Anthony
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
Thanks for the info Anthony...
When I do this:
Field('slug', compute=lambda row: IS_SLUG()(row.title + - +
str(row.id))[0])
I get none as a slug...
On Saturday, August 25, 2012 5:53:49 PM UTC-6, Anthony wrote:
Sure, something like that seems fine. Look at what SO does -- for example:
http://stackoverflow.com/questions/12050934/web2py-build-forms-in-controller-or-view.
I think they use the number as the unique record identifier, but also
include a slug (which doesn't necessarily have to be unique).
Anthony
On Saturday, August 25, 2012 7:16:50 PM UTC-4, SeamusSeamus wrote:
This runs into a problem where if I have two items of the same 'title',
the user will only be linked to the first one that was created. Can I make
it so the slug is a field that I designate? Or make it so the slug adds a
incrementing number such as:
Field('slug', compute=lambda row: IS_SLUG()(row.title *+ row.id*)[0])
I know thats not how you do it, but do you get what I mean? Is there a
better way?
On Thursday, August 23, 2012 1:18:16 AM UTC-6, Anthony wrote:
links = [lambda ro
w: A('Details',_href=URL('default','show', args=[row.slug]))]
fields = [db.equipment.category, db.equipment.title,
db.equipment.price]
You have not included slug in your list of fields, so I believe it
will not be included in the data query. Instead of specifying the list of
fields, you can set the readable attribute to False for fields you don't
want displayed (including slug). In that case, all fields will be
included in the query (including slug), but only the fields you want to
show will be visible in the grid.
Anthony
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
Oh, yeah, I guess you probably can't use the id in a compute because there
is no id until the record has been inserted. You could instead make the id
part of the URL (like Stack Overflow), or maybe make it a virtual field, or
generate your own unique id (separate from the record id).
Anthony
On Saturday, August 25, 2012 8:34:22 PM UTC-4, SeamusSeamus wrote:
Thanks for the info Anthony...
When I do this:
Field('slug', compute=lambda row: IS_SLUG()(row.title + - + str(
row.id))[0])
I get none as a slug...
On Saturday, August 25, 2012 5:53:49 PM UTC-6, Anthony wrote:
Sure, something like that seems fine. Look at what SO does -- for
example:
http://stackoverflow.com/questions/12050934/web2py-build-forms-in-controller-or-view.
I think they use the number as the unique record identifier, but also
include a slug (which doesn't necessarily have to be unique).
Anthony
On Saturday, August 25, 2012 7:16:50 PM UTC-4, SeamusSeamus wrote:
This runs into a problem where if I have two items of the same 'title',
the user will only be linked to the first one that was created. Can I make
it so the slug is a field that I designate? Or make it so the slug adds a
incrementing number such as:
Field('slug', compute=lambda row: IS_SLUG()(row.title *+ row.id*
)[0])
I know thats not how you do it, but do you get what I mean? Is there a
better way?
On Thursday, August 23, 2012 1:18:16 AM UTC-6, Anthony wrote:
links = [lambda ro
w: A('Details',_href=URL('default','show', args=[row.slug]))]
fields = [db.equipment.category, db.equipment.title,
db.equipment.price]
You have not included slug in your list of fields, so I believe it
will not be included in the data query. Instead of specifying the list of
fields, you can set the readable attribute to False for fields you don't
want displayed (including slug). In that case, all fields will be
included in the query (including slug), but only the fields you want to
show will be visible in the grid.
Anthony
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
Your are right, I need to change the links to default. This is what I have
done so far, sorry for confusion:
in controller:
def index():
links = [lambda row: A('Details',_href=URL('default','show',
args=[row.slug]))]
fields = [db.equipment.category, db.equipment.title, db.equipment.price]
grid = SQLFORM.grid(fields=fields,
links=links,
)
return dict(grid=grid)
def show():
try:
equipment = db.equipment[int(request.args(0))]
except:
equipment = db(db.equipment.slug ==
request.args(0)).select().first()
return equipment
and in models db.py:
db.define_table('equipment',
Field('title'),
...
Field('slug', compute=lambda row: IS_SLUG()(row.title)[0])
On Wednesday, August 22, 2012 11:49:49 PM UTC-6, Anthony wrote:
equipment is the table.
Yes, but in your code, it simply said args=[equipment.slug]. If your db
object has a table named equipment, you would refer to it as
db.equipment, but in any case, that would not be relevant here.
the equipment details page is 'show' or 'details'. In reality, I thought
I could get away with the default 'view' from sqlform.grid, using a
slug...but it appears I cannot, so I have to create a custom 'show' or
'details' page. If I do
links = [lambda row: A('Details',_href=URL('show','show',
args=[row.slug]))]
i get a key error.
What is the key error? Is your grid selecting from the equipment table
(with the slug field)?
Why is the URL now URL('show', 'show')? Is the controller named show.py,
with a function called show()? In the URL() function, the first argument
should be the controller and the second the function.
Anthony
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
links = [lambda ro
w: A('Details',_href=URL('default','show', args=[row.slug]))]
fields = [db.equipment.category, db.equipment.title,
db.equipment.price]
You have not include slug in your list of fields, so I believe it will
not be included in the data query. Instead of specifying the list of
fields, you can set the readable attribute to False for fields you don't
want displayed (including slug). In that case, all fields will be
included in the query (including slug), but only the fields you want to
show will be visible in the grid.
Anthony
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
Thanks, that worked. I just added db.equipment.slug to the fields
On Thursday, August 23, 2012 1:18:16 AM UTC-6, Anthony wrote:
links = [lambda ro
w: A('Details',_href=URL('default','show', args=[row.slug]))]
fields = [db.equipment.category, db.equipment.title,
db.equipment.price]
You have not included slug in your list of fields, so I believe it will
not be included in the data query. Instead of specifying the list of
fields, you can set the readable attribute to False for fields you don't
want displayed (including slug). In that case, all fields will be
included in the query (including slug), but only the fields you want to
show will be visible in the grid.
Anthony
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
In my SQLForm.grid I added this
links = [lambda row: A('Details',_href=URL('default','show',
args=[equipment.slug]))]
grid = SQLFORM.grid(query=query, links=links)
I also added the is_slug into the model...but get this error..
links = [lambda row: A('Details',_href=URL('equipment','show',
args=equipment.slug))]
AttributeError: 'function' object has no attribute 'slug'
On Tuesday, August 21, 2012 3:49:55 PM UTC-6, rochacbruno wrote:
You want to create a slug?
web2py comes with IS_SLUG validator which helps with this.
db.define_table(product,
Field(title, unique=True),
...
...
Field(slug, compute=lambda row: IS_SLUG()(row.title)[0]
)
So now you can use slug field to build your urls.
URL(product, show, args=product.slug)
in product/show/product-name
def show():
try:
product = db.product[int(request.args(0))]
except:
product = db(db.product.slug == request.args(0)).select().first()
return product
On Tue, Aug 21, 2012 at 6:18 PM, SeamusSeamus
morrisjam...@gmail.comjavascript:
wrote:
I didnt mean to do {{ }}, but I mean domain.com/product/productname
(Product name being the name of the variable in the field from the model)
On Tuesday, August 21, 2012 2:43:35 PM UTC-6, Anthony wrote:
What is {{fieldname title}}? How do you get that value?
On Tuesday, August 21, 2012 4:31:54 PM UTC-4, SeamusSeamus wrote:
Thanks, what about URLs so it is
www.domain.com/product/{{**fieldnamehttp://www.domain.com/product/%7B%7Bfieldnametitle}}
On Tuesday, August 21, 2012 10:56:49 AM UTC-6, Anthony wrote:
You can set response.title and response.meta in the controller or
function to make it specific to particular controllers or functions (or
you
can set them conditionally in a model file). If you need to use a
database
value, just do a query to get the value (your probably want to cache it
to
improve performance).
Anthony
On Tuesday, August 21, 2012 12:49:00 PM UTC-4, SeamusSeamus wrote:
1. What is the easiest way to make it so each page has it's own
title? Currently it is set by layout.html, but what if I want its own
page
to have an independent title?
2. How can I make it so the title of the page is the name of a
field in a model? I am using SQLForm now, and have /product/1 and would
like to have /product/purple-desk
3. How can I make it so the meta description on each page has its own
? For example, the description is the data in the field 'product
description' used in the model.
Thanks.
--
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
What is equipment?
On Thursday, August 23, 2012 12:53:10 AM UTC-4, SeamusSeamus wrote:
In my SQLForm.grid I added this
links = [lambda row: A('Details',_href=URL('default','show',
args=[equipment.slug]))]
grid = SQLFORM.grid(query=query, links=links)
I also added the is_slug into the model...but get this error..
links = [lambda row: A('Details',_href=URL('equipment','show',
args=equipment.slug))]
AttributeError: 'function' object has no attribute 'slug'
On Tuesday, August 21, 2012 3:49:55 PM UTC-6, rochacbruno wrote:
You want to create a slug?
web2py comes with IS_SLUG validator which helps with this.
db.define_table(product,
Field(title, unique=True),
...
...
Field(slug, compute=lambda row: IS_SLUG()(row.title)[0]
)
So now you can use slug field to build your urls.
URL(product, show, args=product.slug)
in product/show/product-name
def show():
try:
product = db.product[int(request.args(0))]
except:
product = db(db.product.slug == request.args(0)).select().first()
return product
On Tue, Aug 21, 2012 at 6:18 PM, SeamusSeamus morrisjam...@gmail.comwrote:
I didnt mean to do {{ }}, but I mean domain.com/product/productname
(Product name being the name of the variable in the field from the model)
On Tuesday, August 21, 2012 2:43:35 PM UTC-6, Anthony wrote:
What is {{fieldname title}}? How do you get that value?
On Tuesday, August 21, 2012 4:31:54 PM UTC-4, SeamusSeamus wrote:
Thanks, what about URLs so it is
www.domain.com/product/{{**fieldnamehttp://www.domain.com/product/%7B%7Bfieldnametitle}}
On Tuesday, August 21, 2012 10:56:49 AM UTC-6, Anthony wrote:
You can set response.title and response.meta in the controller or
function to make it specific to particular controllers or functions (or
you
can set them conditionally in a model file). If you need to use a
database
value, just do a query to get the value (your probably want to cache it
to
improve performance).
Anthony
On Tuesday, August 21, 2012 12:49:00 PM UTC-4, SeamusSeamus wrote:
1. What is the easiest way to make it so each page has it's own
title? Currently it is set by layout.html, but what if I want its own
page
to have an independent title?
2. How can I make it so the title of the page is the name of a
field in a model? I am using SQLForm now, and have /product/1 and would
like to have /product/purple-desk
3. How can I make it so the meta description on each page has its
own ? For example, the description is the data in the field 'product
description' used in the model.
Thanks.
--
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
sorry, replace products with equipment. My bad. I renamed it since and am
using equipment instead of 'products'. I have it set up now and it is
taking me to the view, but I cannot get the sqlform.grid to show anything
except row.id.
On Wednesday, August 22, 2012 11:01:36 PM UTC-6, Anthony wrote:
What is equipment?
On Thursday, August 23, 2012 12:53:10 AM UTC-4, SeamusSeamus wrote:
In my SQLForm.grid I added this
links = [lambda row: A('Details',_href=URL('default','show',
args=[equipment.slug]))]
grid = SQLFORM.grid(query=query, links=links)
I also added the is_slug into the model...but get this error..
links = [lambda row: A('Details',_href=URL('equipment','show',
args=equipment.slug))]
AttributeError: 'function' object has no attribute 'slug'
On Tuesday, August 21, 2012 3:49:55 PM UTC-6, rochacbruno wrote:
You want to create a slug?
web2py comes with IS_SLUG validator which helps with this.
db.define_table(product,
Field(title, unique=True),
...
...
Field(slug, compute=lambda row: IS_SLUG()(row.title)[0]
)
So now you can use slug field to build your urls.
URL(product, show, args=product.slug)
in product/show/product-name
def show():
try:
product = db.product[int(request.args(0))]
except:
product = db(db.product.slug == request.args(0)).select().first()
return product
On Tue, Aug 21, 2012 at 6:18 PM, SeamusSeamus morrisjam...@gmail.comwrote:
I didnt mean to do {{ }}, but I mean domain.com/product/productname
(Product name being the name of the variable in the field from the model)
On Tuesday, August 21, 2012 2:43:35 PM UTC-6, Anthony wrote:
What is {{fieldname title}}? How do you get that value?
On Tuesday, August 21, 2012 4:31:54 PM UTC-4, SeamusSeamus wrote:
Thanks, what about URLs so it is
www.domain.com/product/{{**fieldnamehttp://www.domain.com/product/%7B%7Bfieldnametitle}}
On Tuesday, August 21, 2012 10:56:49 AM UTC-6, Anthony wrote:
You can set response.title and response.meta in the controller or
function to make it specific to particular controllers or functions (or
you
can set them conditionally in a model file). If you need to use a
database
value, just do a query to get the value (your probably want to cache it
to
improve performance).
Anthony
On Tuesday, August 21, 2012 12:49:00 PM UTC-4, SeamusSeamus wrote:
1. What is the easiest way to make it so each page has it's own
title? Currently it is set by layout.html, but what if I want its own
page
to have an independent title?
2. How can I make it so the title of the page is the name of a
field in a model? I am using SQLForm now, and have /product/1 and
would
like to have /product/purple-desk
3. How can I make it so the meta description on each page has its
own ? For example, the description is the data in the field 'product
description' used in the model.
Thanks.
--
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
The only argument to your lambda is row, so I assume you want row.slug.
Because equipment is not an argument of the lambda, it will look for it
in the outer scope. It looks like you must have a function named
equipment, which is what is being referenced in the lambda.
Anthony
On Thursday, August 23, 2012 1:05:45 AM UTC-4, SeamusSeamus wrote:
sorry, replace products with equipment. My bad. I renamed it since and am
using equipment instead of 'products'. I have it set up now and it is
taking me to the view, but I cannot get the sqlform.grid to show anything
except row.id.
On Wednesday, August 22, 2012 11:01:36 PM UTC-6, Anthony wrote:
What is equipment?
On Thursday, August 23, 2012 12:53:10 AM UTC-4, SeamusSeamus wrote:
In my SQLForm.grid I added this
links = [lambda row: A('Details',_href=URL('default','show',
args=[equipment.slug]))]
grid = SQLFORM.grid(query=query, links=links)
I also added the is_slug into the model...but get this error..
links = [lambda row: A('Details',_href=URL('equipment','show',
args=equipment.slug))]
AttributeError: 'function' object has no attribute 'slug'
On Tuesday, August 21, 2012 3:49:55 PM UTC-6, rochacbruno wrote:
You want to create a slug?
web2py comes with IS_SLUG validator which helps with this.
db.define_table(product,
Field(title, unique=True),
...
...
Field(slug, compute=lambda row: IS_SLUG()(row.title)[0]
)
So now you can use slug field to build your urls.
URL(product, show, args=product.slug)
in product/show/product-name
def show():
try:
product = db.product[int(request.args(0))]
except:
product = db(db.product.slug ==
request.args(0)).select().first()
return product
On Tue, Aug 21, 2012 at 6:18 PM, SeamusSeamus
morrisjam...@gmail.comwrote:
I didnt mean to do {{ }}, but I mean domain.com/product/productname
(Product name being the name of the variable in the field from the model)
On Tuesday, August 21, 2012 2:43:35 PM UTC-6, Anthony wrote:
What is {{fieldname title}}? How do you get that value?
On Tuesday, August 21, 2012 4:31:54 PM UTC-4, SeamusSeamus wrote:
Thanks, what about URLs so it is www.domain.com/product/{{**
fieldname http://www.domain.com/product/%7B%7Bfieldname title}}
On Tuesday, August 21, 2012 10:56:49 AM UTC-6, Anthony wrote:
You can set response.title and response.meta in the controller or
function to make it specific to particular controllers or functions
(or you
can set them conditionally in a model file). If you need to use a
database
value, just do a query to get the value (your probably want to cache
it to
improve performance).
Anthony
On Tuesday, August 21, 2012 12:49:00 PM UTC-4, SeamusSeamus wrote:
1. What is the easiest way to make it so each page has it's own
title? Currently it is set by layout.html, but what if I want its own
page
to have an independent title?
2. How can I make it so the title of the page is the name of a
field in a model? I am using SQLForm now, and have /product/1 and
would
like to have /product/purple-desk
3. How can I make it so the meta description on each page has its
own ? For example, the description is the data in the field 'product
description' used in the model.
Thanks.
--
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
equipment is the table.
the equipment details page is 'show' or 'details'. In reality, I thought I
could get away with the default 'view' from sqlform.grid, using a
slug...but it appears I cannot, so I have to create a custom 'show' or
'details' page. If I do
links = [lambda row: A('Details',_href=URL('show','show',
args=[row.slug]))]
i get a key error.
show and show being the html page and the controller...
My apologize in advanced if I am making this more confusing than it needs
to be. The help truly is greatly appreciated. I am essentially moving my
whole entire online business on to web2py from an old modified shopping
cart...so far I have the minimal but it way better and more simple using
web2py
On Wednesday, August 22, 2012 11:25:24 PM UTC-6, Anthony wrote:
The only argument to your lambda is row, so I assume you want row.slug.
Because equipment is not an argument of the lambda, it will look for it
in the outer scope. It looks like you must have a function named
equipment, which is what is being referenced in the lambda.
Anthony
On Thursday, August 23, 2012 1:05:45 AM UTC-4, SeamusSeamus wrote:
sorry, replace products with equipment. My bad. I renamed it since and am
using equipment instead of 'products'. I have it set up now and it is
taking me to the view, but I cannot get the sqlform.grid to show anything
except row.id.
On Wednesday, August 22, 2012 11:01:36 PM UTC-6, Anthony wrote:
What is equipment?
On Thursday, August 23, 2012 12:53:10 AM UTC-4, SeamusSeamus wrote:
In my SQLForm.grid I added this
links = [lambda row: A('Details',_href=URL('default','show',
args=[equipment.slug]))]
grid = SQLFORM.grid(query=query, links=links)
I also added the is_slug into the model...but get this error..
links = [lambda row: A('Details',_href=URL('equipment','show',
args=equipment.slug))]
AttributeError: 'function' object has no attribute 'slug'
On Tuesday, August 21, 2012 3:49:55 PM UTC-6, rochacbruno wrote:
You want to create a slug?
web2py comes with IS_SLUG validator which helps with this.
db.define_table(product,
Field(title, unique=True),
...
...
Field(slug, compute=lambda row: IS_SLUG()(row.title)[0]
)
So now you can use slug field to build your urls.
URL(product, show, args=product.slug)
in product/show/product-name
def show():
try:
product = db.product[int(request.args(0))]
except:
product = db(db.product.slug ==
request.args(0)).select().first()
return product
On Tue, Aug 21, 2012 at 6:18 PM, SeamusSeamus
morrisjam...@gmail.comwrote:
I didnt mean to do {{ }}, but I mean domain.com/product/productname
(Product name being the name of the variable in the field from the model)
On Tuesday, August 21, 2012 2:43:35 PM UTC-6, Anthony wrote:
What is {{fieldname title}}? How do you get that value?
On Tuesday, August 21, 2012 4:31:54 PM UTC-4, SeamusSeamus wrote:
Thanks, what about URLs so it is www.domain.com/product/{{**
fieldname http://www.domain.com/product/%7B%7Bfieldname title}}
On Tuesday, August 21, 2012 10:56:49 AM UTC-6, Anthony wrote:
You can set response.title and response.meta in the controller or
function to make it specific to particular controllers or functions
(or you
can set them conditionally in a model file). If you need to use a
database
value, just do a query to get the value (your probably want to cache
it to
improve performance).
Anthony
On Tuesday, August 21, 2012 12:49:00 PM UTC-4, SeamusSeamus wrote:
1. What is the easiest way to make it so each page has it's own
title? Currently it is set by layout.html, but what if I want its
own page
to have an independent title?
2. How can I make it so the title of the page is the name of
a field in a model? I am using SQLForm now, and have /product/1 and
would
like to have /product/purple-desk
3. How can I make it so the meta description on each page has its
own ? For example, the description is the data in the field 'product
description' used in the model.
Thanks.
--
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
equipment is the table.
Yes, but in your code, it simply said args=[equipment.slug]. If your db
object has a table named equipment, you would refer to it as
db.equipment, but in any case, that would not be relevant here.
the equipment details page is 'show' or 'details'. In reality, I thought I
could get away with the default 'view' from sqlform.grid, using a
slug...but it appears I cannot, so I have to create a custom 'show' or
'details' page. If I do
links = [lambda row: A('Details',_href=URL('show','show',
args=[row.slug]))]
i get a key error.
What is the key error? Is your grid selecting from the equipment table
(with the slug field)?
Why is the URL now URL('show', 'show')? Is the controller named show.py,
with a function called show()? In the URL() function, the first argument
should be the controller and the second the function.
Anthony
--
[web2py] Re: SEO Friendly URLs and Page Titles
You can set response.title and response.meta in the controller or function to make it specific to particular controllers or functions (or you can set them conditionally in a model file). If you need to use a database value, just do a query to get the value (your probably want to cache it to improve performance). Anthony On Tuesday, August 21, 2012 12:49:00 PM UTC-4, SeamusSeamus wrote: 1. What is the easiest way to make it so each page has it's own title? Currently it is set by layout.html, but what if I want its own page to have an independent title? 2. How can I make it so the title of the page is the name of a field in a model? I am using SQLForm now, and have /product/1 and would like to have /product/purple-desk 3. How can I make it so the meta description on each page has its own ? For example, the description is the data in the field 'product description' used in the model. Thanks. --
[web2py] Re: SEO Friendly URLs and Page Titles
Thanks, what about URLs so it is www.domain.com/product/{{fieldname title}}
On Tuesday, August 21, 2012 10:56:49 AM UTC-6, Anthony wrote:
You can set response.title and response.meta in the controller or function
to make it specific to particular controllers or functions (or you can set
them conditionally in a model file). If you need to use a database value,
just do a query to get the value (your probably want to cache it to improve
performance).
Anthony
On Tuesday, August 21, 2012 12:49:00 PM UTC-4, SeamusSeamus wrote:
1. What is the easiest way to make it so each page has it's own title?
Currently it is set by layout.html, but what if I want its own page to have
an independent title?
2. How can I make it so the title of the page is the name of a field
in a model? I am using SQLForm now, and have /product/1 and would like to
have /product/purple-desk
3. How can I make it so the meta description on each page has its own ?
For example, the description is the data in the field 'product description'
used in the model.
Thanks.
--
[web2py] Re: SEO Friendly URLs and Page Titles
What is {{fieldname title}}? How do you get that value?
On Tuesday, August 21, 2012 4:31:54 PM UTC-4, SeamusSeamus wrote:
Thanks, what about URLs so it is
www.domain.com/product/{{fieldnamehttp://www.domain.com/product/%7B%7Bfieldnametitle}}
On Tuesday, August 21, 2012 10:56:49 AM UTC-6, Anthony wrote:
You can set response.title and response.meta in the controller or
function to make it specific to particular controllers or functions (or you
can set them conditionally in a model file). If you need to use a database
value, just do a query to get the value (your probably want to cache it to
improve performance).
Anthony
On Tuesday, August 21, 2012 12:49:00 PM UTC-4, SeamusSeamus wrote:
1. What is the easiest way to make it so each page has it's own title?
Currently it is set by layout.html, but what if I want its own page to have
an independent title?
2. How can I make it so the title of the page is the name of a field
in a model? I am using SQLForm now, and have /product/1 and would like to
have /product/purple-desk
3. How can I make it so the meta description on each page has its own ?
For example, the description is the data in the field 'product description'
used in the model.
Thanks.
--
[web2py] Re: SEO Friendly URLs and Page Titles
I didnt mean to do {{ }}, but I mean domain.com/product/productname
(Product name being the name of the variable in the field from the model)
On Tuesday, August 21, 2012 2:43:35 PM UTC-6, Anthony wrote:
What is {{fieldname title}}? How do you get that value?
On Tuesday, August 21, 2012 4:31:54 PM UTC-4, SeamusSeamus wrote:
Thanks, what about URLs so it is
www.domain.com/product/{{fieldnamehttp://www.domain.com/product/%7B%7Bfieldnametitle}}
On Tuesday, August 21, 2012 10:56:49 AM UTC-6, Anthony wrote:
You can set response.title and response.meta in the controller or
function to make it specific to particular controllers or functions (or you
can set them conditionally in a model file). If you need to use a database
value, just do a query to get the value (your probably want to cache it to
improve performance).
Anthony
On Tuesday, August 21, 2012 12:49:00 PM UTC-4, SeamusSeamus wrote:
1. What is the easiest way to make it so each page has it's own title?
Currently it is set by layout.html, but what if I want its own page to
have
an independent title?
2. How can I make it so the title of the page is the name of a
field in a model? I am using SQLForm now, and have /product/1 and would
like to have /product/purple-desk
3. How can I make it so the meta description on each page has its own ?
For example, the description is the data in the field 'product
description'
used in the model.
Thanks.
--
Re: [web2py] Re: SEO Friendly URLs and Page Titles
You want to create a slug?
web2py comes with IS_SLUG validator which helps with this.
db.define_table(product,
Field(title, unique=True),
...
...
Field(slug, compute=lambda row: IS_SLUG()(row.title)[0]
)
So now you can use slug field to build your urls.
URL(product, show, args=product.slug)
in product/show/product-name
def show():
try:
product = db.product[int(request.args(0))]
except:
product = db(db.product.slug == request.args(0)).select().first()
return product
On Tue, Aug 21, 2012 at 6:18 PM, SeamusSeamus
morrisjamespatr...@gmail.comwrote:
I didnt mean to do {{ }}, but I mean domain.com/product/productname
(Product name being the name of the variable in the field from the model)
On Tuesday, August 21, 2012 2:43:35 PM UTC-6, Anthony wrote:
What is {{fieldname title}}? How do you get that value?
On Tuesday, August 21, 2012 4:31:54 PM UTC-4, SeamusSeamus wrote:
Thanks, what about URLs so it is
www.domain.com/product/{{**fieldnamehttp://www.domain.com/product/%7B%7Bfieldnametitle}}
On Tuesday, August 21, 2012 10:56:49 AM UTC-6, Anthony wrote:
You can set response.title and response.meta in the controller or
function to make it specific to particular controllers or functions (or you
can set them conditionally in a model file). If you need to use a database
value, just do a query to get the value (your probably want to cache it to
improve performance).
Anthony
On Tuesday, August 21, 2012 12:49:00 PM UTC-4, SeamusSeamus wrote:
1. What is the easiest way to make it so each page has it's own title?
Currently it is set by layout.html, but what if I want its own page to
have
an independent title?
2. How can I make it so the title of the page is the name of a
field in a model? I am using SQLForm now, and have /product/1 and would
like to have /product/purple-desk
3. How can I make it so the meta description on each page has its own
? For example, the description is the data in the field 'product
description' used in the model.
Thanks.
--
--
