Re: [web2py] Web2Py and Ajax
Thanks for your quick response. Op vrijdag 21 december 2012 06:14:25 UTC+1 schreef rochacbruno het volgende: if not request.ajax: response.menu = _menu() On Thu, Dec 20, 2012 at 1:52 PM, Martijn Hermans martijn...@gmail.comjavascript: wrote: When I handle a request in Web2Py it builds a menu in models/menu.py. This behaviour is exactly what I want for a normal request, but I want to skip this, when I make an ajax-call. Is this possible? thx, Martijn -- --
[web2py] Web2Py and Ajax
I've just started using web2py and have a question about ajax calls. In my project a menu is defined (and build) in models/meny.py). The menu is added to the response like this : response.menu = _menu() In this way I can access the menu in my layout and that is exacly what I want, except... when I am doing a ajax call. Is there a way to skip building my menu when I'm using a ajax call? --
[web2py] Web2Py and Ajax
When I handle a request in Web2Py it builds a menu in models/menu.py. This behaviour is exactly what I want for a normal request, but I want to skip this, when I make an ajax-call. Is this possible? thx, Martijn --
Re: [web2py] Web2Py and Ajax
if not request.ajax: response.menu = _menu() On Thu, Dec 20, 2012 at 1:52 PM, Martijn Hermans martijn.herm...@gmail.comwrote: When I handle a request in Web2Py it builds a menu in models/menu.py. This behaviour is exactly what I want for a normal request, but I want to skip this, when I make an ajax-call. Is this possible? thx, Martijn -- --
[web2py] Web2Py : JQuery .ajax data sent not present in request.vars
Trying to make a simple ajax call from the view back to the controller. It is working, however the data I'm sending isn't coming in the request.vars if I sent the contentType=application/json. I know there is an internal ajax function, but I have my own library with these functions I'd like to use. Here is the code : http://pastie.textmate.org/4670338 Pretty sure I'm doing something silly here. Thanks. --
Re: [web2py] Web2Py : JQuery .ajax data sent not present in request.vars
Your URL should have the vars url: /test01/default/getContent?sourcetitle=xxx If you do not pass the vars on url you can't get them at the called controller --
Re: [web2py] Web2Py : JQuery .ajax data sent not present in request.vars
Thanks Bruno !
That worked, but now when I get the response back as JSON, JQuery throws an
error saying the JSON isn't valid. The JSON seems valid to me also passes
JSONLint test :
{readyState:4,responseText:FIFA support India for U-17 and 2022 World
Cup - Times,status:200,statusText:OK}
On Wednesday, 5 September 2012 17:40:42 UTC-4, rochacbruno wrote:
Your URL should have the vars
url: /test01/default/getContent?sourcetitle=xxx
If you do not pass the vars on url you can't get them at the called
controller
--
Re: [web2py] Web2Py : JQuery .ajax data sent not present in request.vars
or you call it with .json extension and use the generic json view
url: /test01/default/getContent*.json*?sourceTitle=x
or you do this on the return
import json
def getContent():
titleArg = str(request.vars.sourceTitle)
print --
print --
print request.vars # Starts working if contentType in ajax request
above is commented
print Getting news content for : + titleArg
print --
print --
#rows=db(db.NewsMaster).select(db.NewsMaster.ALL)
myobj = [dict(value=x),dict(value=x), dict(value=x)]
return json.dumps(myobj)
On Wed, Sep 5, 2012 at 6:51 PM, Nik nikhil.kodil...@gmail.com wrote:
Thanks Bruno !
That worked, but now when I get the response back as JSON, JQuery throws
an error saying the JSON isn't valid. The JSON seems valid to me also
passes JSONLint test :
{readyState:4,responseText:FIFA support India for U-17 and 2022 World
Cup - Times,status:200,statusText:OK}
On Wednesday, 5 September 2012 17:40:42 UTC-4, rochacbruno wrote:
Your URL should have the vars
url: /test01/default/getContent?**sourcetitle=xxx
If you do not pass the vars on url you can't get them at the called
controller
--
--
Re: [web2py] Web2Py : JQuery .ajax data sent not present in request.vars
That worked too ! You rock :)
On Wednesday, 5 September 2012 17:58:16 UTC-4, rochacbruno wrote:
or you call it with .json extension and use the generic json view
url: /test01/default/getContent*.json*?sourceTitle=x
or you do this on the return
import json
def getContent():
titleArg = str(request.vars.sourceTitle)
print --
print --
print request.vars # Starts working if contentType in ajax request
above is commented
print Getting news content for : + titleArg
print --
print --
#rows=db(db.NewsMaster).select(db.NewsMaster.ALL)
myobj = [dict(value=x),dict(value=x), dict(value=x)]
return json.dumps(myobj)
On Wed, Sep 5, 2012 at 6:51 PM, Nik nikhil@gmail.com javascript:wrote:
Thanks Bruno !
That worked, but now when I get the response back as JSON, JQuery throws
an error saying the JSON isn't valid. The JSON seems valid to me also
passes JSONLint test :
{readyState:4,responseText:FIFA support India for U-17 and 2022
World Cup - Times,status:200,statusText:OK}
On Wednesday, 5 September 2012 17:40:42 UTC-4, rochacbruno wrote:
Your URL should have the vars
url: /test01/default/getContent?**sourcetitle=xxx
If you do not pass the vars on url you can't get them at the called
controller
--
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[web2py] web2py and ajax
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