Re: [web2py] Re: How to make smartgrid redirect to edit after creating new record?
Untested, and modified sample: *Model:* db.define_table('purchase_order', Field('po_number', 'string', label=T('PO Number'), unique= True), Field('status', 'string', default='Processed', requires= IS_IN_SET(['Processed', 'Cancelled', 'On Hold', 'Shipped']), label=T('Status')), format='%(po_number)s', ) *Controller:* def po_onupdate(form): # send an email, but only first time (when status changes to 'Shipped', additional record updates will not trigger an email) if ((form.vars.status == 'Shipped') (form.record.status != 'Shipped' )): mail.send(to=['some...@somewhere.com',], subject='Order %s shipped. Date: %s' % (form.record.po_number, request.now), message=Long message) session.flash = ('Updated a %s' % (tbl_name)) + ' ' + (form.vars.po_number if tbl_name == 'purchase_order' else '') return def purchase_order(): grid=SQLFORM.smartgrid(db.purchase_order, details=True, links_in_grid= True, paginate=20, sortable=True, onupdate = po_onupdate, editable = True, formstyle='bootstrap', user_signature=True, ) return dict(grid=grid) On Sunday, September 15, 2013 12:29:04 AM UTC-4, Alex Glaros wrote: Adi, you had a tiny working example above *this works: grid=SQLFORM.smartgrid(.* is the data model available for that? I'm looking for any small self-contained working example of smartgrid redirecting to edit thanks, Alex On Saturday, September 14, 2013 5:38:58 PM UTC-7, Adi wrote: Alex, Can you please clarify what model do you need? I can post the sample code but not sure what exactly do you need. On Fri, Sep 13, 2013 at 8:13 PM, Alex Glaros alexg...@gmail.com wrote: Adi, can you post the model for this? thanks, Alex Glaros On Friday, December 23, 2011 9:44:17 AM UTC-8, Adi wrote: this works: grid=SQLFORM.smartgrid(db.**purchase_order, details=False, links_in_grid=True, maxtextlengths={'purchase_** order.po_number':15,}, maxtextlength=30, paginate=20, sortable=True, orderby=dict(purchase_order=[~** db.purchase_order.modified_on]**, ), oncreate = dict(purchase_order=[po_** oncreation]), csv=False, ui='jquery-ui', links=dict(purchase_order=[**lambda row: A('Duplicate', _class='button', _href=URL('duplicate_purchase_**order',args=[row.id])), lambda row: A('Print', _class='button', _href=URL('print_all',args=[ro**w.id http://row.id]))]), user_signature=False, onupdate=auth.archive, ) def po_oncreation(form1): auth.archive last_id = form1.vars.id row = db(db.purchase_order.id==last_**id).select().first() str_po_number = row.po_number + str(row.id) row.po_number = str_po_number row.update_record() #response.flash = 'Added a Purchase Order' session.flash = 'Added a Purchase Order' return -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+un...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [web2py] Re: How to make smartgrid redirect to edit after creating new record?
Thanks Adi, Alex On Sunday, September 15, 2013 5:33:36 AM UTC-7, Adi wrote: Untested, and modified sample: *Model:* db.define_table('purchase_order', Field('po_number', 'string', label=T('PO Number'), unique= True), Field('status', 'string', default='Processed', requires= IS_IN_SET(['Processed', 'Cancelled', 'On Hold', 'Shipped']), label=T('Status')), format='%(po_number)s', ) *Controller:* def po_onupdate(form): # send an email, but only first time (when status changes to 'Shipped', additional record updates will not trigger an email) if ((form.vars.status == 'Shipped') (form.record.status != 'Shipped' )): mail.send(to=['some...@somewhere.com',], subject='Order %s shipped. Date: %s' % (form.record.po_number, request.now), message=Long message) session.flash = ('Updated a %s' % (tbl_name)) + ' ' + (form.vars.po_number if tbl_name == 'purchase_order' else '') return def purchase_order(): grid=SQLFORM.smartgrid(db.purchase_order, details=True, links_in_grid= True, paginate=20, sortable=True, onupdate = po_onupdate, editable = True, formstyle='bootstrap', user_signature=True, ) return dict(grid=grid) On Sunday, September 15, 2013 12:29:04 AM UTC-4, Alex Glaros wrote: Adi, you had a tiny working example above *this works: grid=SQLFORM.smartgrid(.* is the data model available for that? I'm looking for any small self-contained working example of smartgrid redirecting to edit thanks, Alex On Saturday, September 14, 2013 5:38:58 PM UTC-7, Adi wrote: Alex, Can you please clarify what model do you need? I can post the sample code but not sure what exactly do you need. On Fri, Sep 13, 2013 at 8:13 PM, Alex Glaros alexg...@gmail.com wrote: Adi, can you post the model for this? thanks, Alex Glaros On Friday, December 23, 2011 9:44:17 AM UTC-8, Adi wrote: this works: grid=SQLFORM.smartgrid(db.**purchase_order, details=False, links_in_grid=True, maxtextlengths={'purchase_** order.po_number':15,}, maxtextlength=30, paginate=20, sortable=True, orderby=dict(purchase_order=[~** db.purchase_order.modified_on]**, ), oncreate = dict(purchase_order=[po_** oncreation]), csv=False, ui='jquery-ui', links=dict(purchase_order=[**lambda row: A('Duplicate', _class='button', _href=URL('duplicate_purchase_**order',args=[row.id])), lambda row: A('Print', _class='button', _href=URL('print_all',args=[ro**w.id http://row.id]))]), user_signature=False, onupdate=auth.archive, ) def po_oncreation(form1): auth.archive last_id = form1.vars.id row = db(db.purchase_order.id==last_**id).select().first() str_po_number = row.po_number + str(row.id) row.po_number = str_po_number row.update_record() #response.flash = 'Added a Purchase Order' session.flash = 'Added a Purchase Order' return -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+un...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [web2py] Re: How to make smartgrid redirect to edit after creating new record?
Alex, Can you please clarify what model do you need? I can post the sample code but not sure what exactly do you need. On Fri, Sep 13, 2013 at 8:13 PM, Alex Glaros alexgla...@gmail.com wrote: Adi, can you post the model for this? thanks, Alex Glaros On Friday, December 23, 2011 9:44:17 AM UTC-8, Adi wrote: this works: grid=SQLFORM.smartgrid(db.**purchase_order, details=False, links_in_grid=True, maxtextlengths={'purchase_** order.po_number':15,}, maxtextlength=30, paginate=20, sortable=True, orderby=dict(purchase_order=[~** db.purchase_order.modified_on]**, ), oncreate = dict(purchase_order=[po_** oncreation]), csv=False, ui='jquery-ui', links=dict(purchase_order=[**lambda row: A('Duplicate', _class='button', _href=URL('duplicate_purchase_**order',args=[row.id])), lambda row: A('Print', _class='button', _href=URL('print_all',args=[ ro**w.id http://row.id]))]), user_signature=False, onupdate=auth.archive, ) def po_oncreation(form1): auth.archive last_id = form1.vars.id row = db(db.purchase_order.id==last_**id).select().first() str_po_number = row.po_number + str(row.id) row.po_number = str_po_number row.update_record() #response.flash = 'Added a Purchase Order' session.flash = 'Added a Purchase Order' return -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [web2py] Re: How to make smartgrid redirect to edit after creating new record?
Adi, you had a tiny working example above *this works: grid=SQLFORM.smartgrid(.* is the data model available for that? I'm looking for any small self-contained working example of smartgrid redirecting to edit thanks, Alex On Saturday, September 14, 2013 5:38:58 PM UTC-7, Adi wrote: Alex, Can you please clarify what model do you need? I can post the sample code but not sure what exactly do you need. On Fri, Sep 13, 2013 at 8:13 PM, Alex Glaros alexg...@gmail.comjavascript: wrote: Adi, can you post the model for this? thanks, Alex Glaros On Friday, December 23, 2011 9:44:17 AM UTC-8, Adi wrote: this works: grid=SQLFORM.smartgrid(db.**purchase_order, details=False, links_in_grid=True, maxtextlengths={'purchase_** order.po_number':15,}, maxtextlength=30, paginate=20, sortable=True, orderby=dict(purchase_order=[~** db.purchase_order.modified_on]**, ), oncreate = dict(purchase_order=[po_** oncreation]), csv=False, ui='jquery-ui', links=dict(purchase_order=[**lambda row: A('Duplicate', _class='button', _href=URL('duplicate_purchase_**order',args=[row.id])), lambda row: A('Print', _class='button', _href=URL('print_all',args=[ ro**w.id http://row.id]))]), user_signature=False, onupdate=auth.archive, ) def po_oncreation(form1): auth.archive last_id = form1.vars.id row = db(db.purchase_order.id==last_**id).select().first() str_po_number = row.po_number + str(row.id) row.po_number = str_po_number row.update_record() #response.flash = 'Added a Purchase Order' session.flash = 'Added a Purchase Order' return -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+un...@googlegroups.com javascript:. For more options, visit https://groups.google.com/groups/opt_out. -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.