Re: [web2py] xml.etree

2011-09-19 Thread Michele Comitini 
There is nothing wrong with your code. Maybe it is better to use
find() to get the geo tag.
If you have an XSD schema you can use generateDS
http://www.rexx.com/~dkuhlman/generateDS.html
to have a python parser.

But if you can use the JSON API... much simpler.

mic


2011/9/19 Chris Rowson christopherrow...@gmail.com:
 Anybody using xml.etree?

 I asked this question over at the Python tutors group but it seems
 that few people there had experience of it.

 I'm trying to access a UK postcode API at www.uk-postcodes.com to take
 a UK postcode and return the lat/lng of the postcode. This is what the
 XML looks like: http://www.uk-postcodes.com/postcode/HU11AA.xml

 The function below returns a dict with the xml tag as a key and the
 text as a value. Is this a correct way to use xml.etree? Is there a
 better way of doing this?

 Thanks in advance!

 Chris


 def ukpostcodesapi(postcode):
       import urllib
       import xml.etree.ElementTree as etree

       baseURL='http://www.uk-postcodes.com/'
       geocodeRequest='postcode/'+postcode+'.xml'

       #grab the xml
       tree=etree.parse(urllib.urlopen(baseURL+geocodeRequest))
       root=tree.getroot()
       results={}
       for child in root[1]: #here's the geo tag
               results.update({child.tag:child.text}) #build a dict
 containing the geocode data
       return results

 #example usage (testing the function)
 results = ukpostcodesapi('hu11aa')
 print results['lat']+' '+results['lng']

Re: [web2py] xml.etree

2011-09-19 Thread Chris Rowson 
Thank you Michele,

Chris

On Mon, Sep 19, 2011 at 2:00 PM, Michele Comitini
michele.comit...@gmail.com wrote:
 There is nothing wrong with your code. Maybe it is better to use
 find() to get the geo tag.
 If you have an XSD schema you can use generateDS
 http://www.rexx.com/~dkuhlman/generateDS.html
 to have a python parser.

 But if you can use the JSON API... much simpler.

 mic


 2011/9/19 Chris Rowson christopherrow...@gmail.com:
 Anybody using xml.etree?

 I asked this question over at the Python tutors group but it seems
 that few people there had experience of it.

 I'm trying to access a UK postcode API at www.uk-postcodes.com to take
 a UK postcode and return the lat/lng of the postcode. This is what the
 XML looks like: http://www.uk-postcodes.com/postcode/HU11AA.xml

 The function below returns a dict with the xml tag as a key and the
 text as a value. Is this a correct way to use xml.etree? Is there a
 better way of doing this?

 Thanks in advance!

 Chris


 def ukpostcodesapi(postcode):
       import urllib
       import xml.etree.ElementTree as etree

       baseURL='http://www.uk-postcodes.com/'
       geocodeRequest='postcode/'+postcode+'.xml'

       #grab the xml
       tree=etree.parse(urllib.urlopen(baseURL+geocodeRequest))
       root=tree.getroot()
       results={}
       for child in root[1]: #here's the geo tag
               results.update({child.tag:child.text}) #build a dict
 containing the geocode data
       return results

 #example usage (testing the function)
 results = ukpostcodesapi('hu11aa')
 print results['lat']+' '+results['lng']

Re: [web2py] xml.etree

2011-09-19 Thread Bruno Rocha 
I use xml minidom and it is easier.

http://zerp.ly/rochacbruno
Em 19/09/2011 11:40, Chris Rowson christopherrow...@gmail.com escreveu:
 Thank you Michele,

 Chris

 On Mon, Sep 19, 2011 at 2:00 PM, Michele Comitini
 michele.comit...@gmail.com wrote:
 There is nothing wrong with your code. Maybe it is better to use
 find() to get the geo tag.
 If you have an XSD schema you can use generateDS
 http://www.rexx.com/~dkuhlman/generateDS.html
 to have a python parser.

 But if you can use the JSON API... much simpler.

 mic


 2011/9/19 Chris Rowson christopherrow...@gmail.com:
 Anybody using xml.etree?

 I asked this question over at the Python tutors group but it seems
 that few people there had experience of it.

 I'm trying to access a UK postcode API at www.uk-postcodes.com to take
 a UK postcode and return the lat/lng of the postcode. This is what the
 XML looks like: http://www.uk-postcodes.com/postcode/HU11AA.xml

 The function below returns a dict with the xml tag as a key and the
 text as a value. Is this a correct way to use xml.etree? Is there a
 better way of doing this?

 Thanks in advance!

 Chris


 def ukpostcodesapi(postcode):
   import urllib
   import xml.etree.ElementTree as etree

   baseURL='http://www.uk-postcodes.com/'
   geocodeRequest='postcode/'+postcode+'.xml'

   #grab the xml
   tree=etree.parse(urllib.urlopen(baseURL+geocodeRequest))
   root=tree.getroot()
   results={}
   for child in root[1]: #here's the geo tag
   results.update({child.tag:child.text}) #build a dict
 containing the geocode data
   return results

 #example usage (testing the function)
 results = ukpostcodesapi('hu11aa')
 print results['lat']+' '+results['lng']

Re: [web2py] xml.etree

2011-09-19 Thread Chris Rowson 
I did look at that Bruno, but some of the articles I read suggested that it
is not very memory efficient?

Chris
On Sep 19, 2011 3:44 PM, Bruno Rocha rochacbr...@gmail.com wrote:
 I use xml minidom and it is easier.

 http://zerp.ly/rochacbruno
 Em 19/09/2011 11:40, Chris Rowson christopherrow...@gmail.com
escreveu:
 Thank you Michele,

 Chris

 On Mon, Sep 19, 2011 at 2:00 PM, Michele Comitini
 michele.comit...@gmail.com wrote:
 There is nothing wrong with your code. Maybe it is better to use
 find() to get the geo tag.
 If you have an XSD schema you can use generateDS
 http://www.rexx.com/~dkuhlman/generateDS.html
 to have a python parser.

 But if you can use the JSON API... much simpler.

 mic


 2011/9/19 Chris Rowson christopherrow...@gmail.com:
 Anybody using xml.etree?

 I asked this question over at the Python tutors group but it seems
 that few people there had experience of it.

 I'm trying to access a UK postcode API at www.uk-postcodes.com to take
 a UK postcode and return the lat/lng of the postcode. This is what the
 XML looks like: http://www.uk-postcodes.com/postcode/HU11AA.xml

 The function below returns a dict with the xml tag as a key and the
 text as a value. Is this a correct way to use xml.etree? Is there a
 better way of doing this?

 Thanks in advance!

 Chris


 def ukpostcodesapi(postcode):
 import urllib
 import xml.etree.ElementTree as etree

 baseURL='http://www.uk-postcodes.com/'
 geocodeRequest='postcode/'+postcode+'.xml'

 #grab the xml
 tree=etree.parse(urllib.urlopen(baseURL+geocodeRequest))
 root=tree.getroot()
 results={}
 for child in root[1]: #here's the geo tag
 results.update({child.tag:child.text}) #build a dict
 containing the geocode data
 return results

 #example usage (testing the function)
 results = ukpostcodesapi('hu11aa')
 print results['lat']+' '+results['lng']

Re: [web2py] xml.etree

2011-09-19 Thread Bruno Rocha 
I dont know your needs but, you can pass any XML to web2py TAG[''] helper so
then you can use Server side DOM to inspect

http://web2py.com/book/default/chapter/05#Server-side-DOM-and-Parsing

Re: [web2py] xml.etree

2011-09-19 Thread Phyo Arkar 
I like lxml more , and check pyquery! jQuery of python at server side.

On 9/20/11, Bruno Rocha rochacbr...@gmail.com wrote:
 I dont know your needs but, you can pass any XML to web2py TAG[''] helper so
 then you can use Server side DOM to inspect

 http://web2py.com/book/default/chapter/05#Server-side-DOM-and-Parsing

Re: [web2py] xml.etree

2011-09-19 Thread Chris Rowson 
Thanks all!

Chris

On Mon, Sep 19, 2011 at 6:49 PM, Phyo Arkar phyo.arkarl...@gmail.com wrote:
 I like lxml more , and check pyquery! jQuery of python at server side.

 On 9/20/11, Bruno Rocha rochacbr...@gmail.com wrote:
 I dont know your needs but, you can pass any XML to web2py TAG[''] helper so
 then you can use Server side DOM to inspect

 http://web2py.com/book/default/chapter/05#Server-side-DOM-and-Parsing