Questions about Deduplication

[Farrukh Ijaz]

Hi Guys,

In Wonder's documentation there is a method called setDeduplicationEnabled() 
for ERXKeyFilter. I've the latest code from trunk but couldn't find this 
method. Can someone help me locate that? or is there any alternative way to 
implement the similar behaviour?

The problem I'm facing is here:

I've following entities, Horse, HorseDetail, HorseType, HorseColor.

Following are the relationships.

Horse -> toMany -> HorseDetail
Horse -> toOne -> Horse (Sir)
Horse -> toOne -> Horse (Dam)
Horse -> toOne -> HorseType
Horse -> toOne -> HorseColor

There are many horses in the database and I fetch record based on HorseDetail 
because it contains the horseName. E.g. I fetch all the instances of 
HorseDetail where the horseName contains letter "a".

It works fine when I set the rule for entity = "HorseDetail", task = "GET":

displayPropertyKeys =
(
  "horseName", 
  "horseBio", 
  "toLanguage", 
  "toHorseProfile.toHorseType.typeName", 
  "toHorseProfile.toHorseColor.colorName"
)

For all the horses the filter works fine. But when I modify the above rule as 
following:

displayPropertyKeys =
(
  "horseName", 
  "horseBio", 
  "toLanguage", 
  "toHorse.toHorseType.typeName", 
  "toHorse.toHorseColor.colorName",
  "toHorse.toSirHorse.toHorseDetails.horseName",
  "toHorse.toDamHorse.toHorseDetails.horseName"
)

This also works fine but for only those horses which have toSirHorse and 
toDamHorse set. If any of them is missing, the returned data for those horses 
only contain the "horseName".

Here is the method that I use for creating the ERXKeyFilter for HorseDetail. 
Basically the inferFilterKeysForEntity checks the d2w rules for the entity 
where the task is "GET" and gets the "displayPropertyKeys".

public ERXKeyFilter showFilter(String entityName) {
        NSArray<String> keys = inferFilterKeysForEntity(entityName);
        ERXKeyFilter filter = null;
        if (keys != null && !keys.isEmpty()) {
                filter = ERXKeyFilter.filterWithNone();
                for (String key : keys) {
                        filter.include(new ERXKey<String>(key));
                }
        } else {
                filter = 
ERXKeyFilter.filterWithAttributesAndToOneRelationships();
        }
        return filter;
}

Here is the action defined in the custom rest controller for the horses method:

public WOActionResults searchAction() throws Throwable {
        NSArray<EOQualifier> quals = new NSMutableArray<EOQualifier>();

        String name = request().stringFormValueForKey("name");
        if (name != null) {
                quals.add(HorseDetail.TO_LANGUAGE.eq(language()));
                quals.add(HorseDetail.PROFILE_NAME.ilike(name));
        }

        EOFetchSpecification fs = new EOFetchSpecification(
                HorseDetail.ENTITY_NAME, new ERXAndQualifier(quals),
                null);

        NSArray<HorseDetail> elements = editingContext()
                .objectsWithFetchSpecification(fs);

        HorseColor horseColor = horseColor();
        if (horseColor != null) {
                elements = HorseDetail.TO_HORSE
                .append(Horse.TO_HORSE_COLOR).eq(horseColor)
                .filtered(elements);
        }

        HorseType type = type();
        if (type != null) {
                elements = HorseDetail.TO_HORSE
                .append(Horse.TO_HORSE_TYPE).eq(type)
                .filtered(elements);
        }

        return response(elements, showFilter(HorseDetail.ENTITY_NAME));
}

I guess modifying the value of deduplication can give me the intended results. 
or is there any other solution to this problem?

Here is the link:

http://webobjects.mdimension.com/hudson/job/Wonder/javadoc/er/extensions/eof/ERXKeyFilter.html#setDeduplicationEnabled(boolean)

Thanks,

Farrukh
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