Re: [Wicket-user] (conceptual) bug in getModelObject()?

2006-05-10 Thread Ittay Dror

i think the compound concept needs to be generalized.

the ICompoundModel is really IAutomaticallyInheritedModel. whether it is 
compound (a model simulating holding other models) is not important i think.



Matej Knopp wrote:
On the other side, you still have component parameter in 
IModel#getModelObject, which makes only sense when the model is 
compound, so maybe getRootObject() in ICompoundModel wouldn't improve 
things anyway.


-Matej

Matej Knopp wrote:
Hmm. maybe having getRootObjecT() in ICompoundModel would make things 
little easier to understand, wonder what core developers would think.


anyway, the model can't decide, whether to return null or not. it 
depends on the component. but the component would know whether to call 
getObject(this) or getRootObject(), according to FLAG_HAS_ROOT_MODEL.


-Matej

Ittay Dror wrote:
then i think this should be more explicit. e.g., add to 
ICompoundModel a getRootObject(), and i think that if that returns 
null, then return getObject(this)


Matej Knopp wrote:

Ittay Dror wrote:

public final Object getModelObject()
{
final IModel model = getModel();
if (model != null)
{
// If this component has the root model for a compound 
model

if (getFlag(FLAG_HAS_ROOT_MODEL))
{
// we need to return the root model and not a 
property of the

// model
return getRootModel(model).getObject(null);
}

// Get model value for this component
return model.getObject(this);
}
else
{
return null;
}
}



note the statement: getRootModel(model).getObject(null);

why use null?


I believe it's because of compound models. e.g. when you have 
compound property model, getObject(Component) returns you the 
property of the model object which name is sme as component id.

getObject(null) returns you the whole model object.

If you have a form for instance and set it a compoundpropertymodel, 
the modelObject of the form is the object you put to the model.


but the model objects of components placed into the form are 
actually properties of the object you set to the model. (as the 
components will inherit the model from the form)


-Matej


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--
===
Ittay Dror 
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R&D, Qlusters Inc.

[EMAIL PROTECTED]
+972-3-6081994 Fax: +972-3-6081841

http://www.openQRM.org
- Keeps your Data-Center Up and Running


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Re: [Wicket-user] (conceptual) bug in getModelObject()?

2006-05-10 Thread Johan Compagner
It is not simulation holding outer models.It is the model for every child that doesn't have a model so yes it inherits its.But that is just the name. And i can't really discuss that what the real meaning is of comound and if it is the 'good' word for that or not.
So i don't know what you mean with "generalized" because you just say it should be renamed? But from the perspective of the componentyou set it the model on i find a IAutomaticallyInheritedModel very strange. If it is inherited why do i need to set a inherited model on something?
ICompoundModel could have a getRootObject() that would be the samething as getObject(null)But remember that getObject(null) is not really only for Compounds it is also for the normal PropertyModels.They also should just return the complete object.
A normal none property model also just returns the complete object on null (the difference that it just completely don't look what the component is)It is just a contract..johan
On 5/10/06, Ittay Dror <[EMAIL PROTECTED]> wrote:
i think the compound concept needs to be generalized.the ICompoundModel is really IAutomaticallyInheritedModel. whether it is compound (a model simulating holding other models) is not important i think.
Matej Knopp wrote:> On the other side, you still have component parameter in> IModel#getModelObject, which makes only sense when the model is> compound, so maybe getRootObject() in ICompoundModel wouldn't improve
> things anyway.>> -Matej>> Matej Knopp wrote:>> Hmm. maybe having getRootObjecT() in ICompoundModel would make things>> little easier to understand, wonder what core developers would think.
 anyway, the model can't decide, whether to return null or not. it>> depends on the component. but the component would know whether to call>> getObject(this) or getRootObject(), according to FLAG_HAS_ROOT_MODEL.
 -Matej Ittay Dror wrote:>>> then i think this should be more explicit. e.g., add to>>> ICompoundModel a getRootObject(), and i think that if that returns
>>> null, then return getObject(this)>> Matej Knopp wrote: Ittay Dror wrote:> public final Object getModelObject()> {
> final IModel model = getModel();> if (model != null)> {> // If this component has the root model for a compound
> model> if (getFlag(FLAG_HAS_ROOT_MODEL))> {> // we need to return the root model and not a
> property of the> // model> return getRootModel(model).getObject(null);> }>
> // Get model value for this component> return model.getObject(this);> }> else> {
> return null;> }> } note the statement: getRootModel(model).getObject(null);
>> why use null? I believe it's because of compound models. e.g. when you have compound property model, getObject(Component) returns you the
 property of the model object which name is sme as component id. getObject(null) returns you the whole model object. If you have a form for instance and set it a compoundpropertymodel,
 the modelObject of the form is the object you put to the model. but the model objects of components placed into the form are actually properties of the object you set to the model. (as the
 components will inherit the model from the form) -Matej ---
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 Wicket-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/wicket-user
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>> Get stuff done quickly with pre-integrated technology to make your job>> easier>> Download IBM WebSphere Application Server v.1.0.1 based on Apache>> Geronimo>> 
http://sel.as-us.falkag.net/sel?cmd=lnk&kid=120709&bid=263057&dat=121642>> ___>> Wicket-user mailing list>> 
Wicket-user@lists.sourceforge.net>> https://lists.sourceforge.net/lists/listinfo/wicket-user>> ---
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Re: [Wicket-user] (conceptual) bug in getModelObject()?

2006-05-10 Thread Matej Knopp
On the other side, you still have component parameter in 
IModel#getModelObject, which makes only sense when the model is 
compound, so maybe getRootObject() in ICompoundModel wouldn't improve 
things anyway.


-Matej

Matej Knopp wrote:
Hmm. maybe having getRootObjecT() in ICompoundModel would make things 
little easier to understand, wonder what core developers would think.


anyway, the model can't decide, whether to return null or not. it 
depends on the component. but the component would know whether to call 
getObject(this) or getRootObject(), according to FLAG_HAS_ROOT_MODEL.


-Matej

Ittay Dror wrote:
then i think this should be more explicit. e.g., add to ICompoundModel 
a getRootObject(), and i think that if that returns null, then return 
getObject(this)


Matej Knopp wrote:

Ittay Dror wrote:

public final Object getModelObject()
{
final IModel model = getModel();
if (model != null)
{
// If this component has the root model for a compound 
model

if (getFlag(FLAG_HAS_ROOT_MODEL))
{
// we need to return the root model and not a 
property of the

// model
return getRootModel(model).getObject(null);
}

// Get model value for this component
return model.getObject(this);
}
else
{
return null;
}
}



note the statement: getRootModel(model).getObject(null);

why use null?


I believe it's because of compound models. e.g. when you have 
compound property model, getObject(Component) returns you the 
property of the model object which name is sme as component id.

getObject(null) returns you the whole model object.

If you have a form for instance and set it a compoundpropertymodel, 
the modelObject of the form is the object you put to the model.


but the model objects of components placed into the form are actually 
properties of the object you set to the model. (as the components 
will inherit the model from the form)


-Matej


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Re: [Wicket-user] (conceptual) bug in getModelObject()?

2006-05-10 Thread Matej Knopp
Hmm. maybe having getRootObjecT() in ICompoundModel would make things 
little easier to understand, wonder what core developers would think.


anyway, the model can't decide, whether to return null or not. it 
depends on the component. but the component would know whether to call 
getObject(this) or getRootObject(), according to FLAG_HAS_ROOT_MODEL.


-Matej

Ittay Dror wrote:
then i think this should be more explicit. e.g., add to ICompoundModel a 
getRootObject(), and i think that if that returns null, then return 
getObject(this)


Matej Knopp wrote:

Ittay Dror wrote:

public final Object getModelObject()
{
final IModel model = getModel();
if (model != null)
{
// If this component has the root model for a compound model
if (getFlag(FLAG_HAS_ROOT_MODEL))
{
// we need to return the root model and not a 
property of the

// model
return getRootModel(model).getObject(null);
}

// Get model value for this component
return model.getObject(this);
}
else
{
return null;
}
}



note the statement: getRootModel(model).getObject(null);

why use null?


I believe it's because of compound models. e.g. when you have compound 
property model, getObject(Component) returns you the property of the 
model object which name is sme as component id.

getObject(null) returns you the whole model object.

If you have a form for instance and set it a compoundpropertymodel, 
the modelObject of the form is the object you put to the model.


but the model objects of components placed into the form are actually 
properties of the object you set to the model. (as the components will 
inherit the model from the form)


-Matej


---
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Re: [Wicket-user] (conceptual) bug in getModelObject()?

2006-05-10 Thread Ittay Dror

then i think this should be more explicit. e.g., add to ICompoundModel a 
getRootObject(), and i think that if that returns null, then return 
getObject(this)

Matej Knopp wrote:

Ittay Dror wrote:

public final Object getModelObject()
{
final IModel model = getModel();
if (model != null)
{
// If this component has the root model for a compound model
if (getFlag(FLAG_HAS_ROOT_MODEL))
{
// we need to return the root model and not a property 
of the

// model
return getRootModel(model).getObject(null);
}

// Get model value for this component
return model.getObject(this);
}
else
{
return null;
}
}



note the statement: getRootModel(model).getObject(null);

why use null?


I believe it's because of compound models. e.g. when you have compound 
property model, getObject(Component) returns you the property of the 
model object which name is sme as component id.

getObject(null) returns you the whole model object.

If you have a form for instance and set it a compoundpropertymodel, the 
modelObject of the form is the object you put to the model.


but the model objects of components placed into the form are actually 
properties of the object you set to the model. (as the components will 
inherit the model from the form)


-Matej


---
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--
===
Ittay Dror 
Chief architect, openQRM TL, 
R&D, Qlusters Inc.

[EMAIL PROTECTED]
+972-3-6081994 Fax: +972-3-6081841

http://www.openQRM.org
- Keeps your Data-Center Up and Running


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Re: [Wicket-user] (conceptual) bug in getModelObject()?

2006-05-10 Thread Ittay Dror

same in setModelObject

Ittay Dror wrote:

public final Object getModelObject()
{
final IModel model = getModel();
if (model != null)
{
// If this component has the root model for a compound model
if (getFlag(FLAG_HAS_ROOT_MODEL))
{
// we need to return the root model and not a property 
of the

// model
return getRootModel(model).getObject(null);
}

// Get model value for this component
return model.getObject(this);
}
else
{
return null;
}
}



note the statement: getRootModel(model).getObject(null);

why use null?



--
===
Ittay Dror 
Chief architect, openQRM TL, 
R&D, Qlusters Inc.

[EMAIL PROTECTED]
+972-3-6081994 Fax: +972-3-6081841

http://www.openQRM.org
- Keeps your Data-Center Up and Running


---
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Re: [Wicket-user] (conceptual) bug in getModelObject()?

2006-05-10 Thread Matej Knopp

Ittay Dror wrote:

public final Object getModelObject()
{
final IModel model = getModel();
if (model != null)
{
// If this component has the root model for a compound model
if (getFlag(FLAG_HAS_ROOT_MODEL))
{
// we need to return the root model and not a property 
of the

// model
return getRootModel(model).getObject(null);
}

// Get model value for this component
return model.getObject(this);
}
else
{
return null;
}
}



note the statement: getRootModel(model).getObject(null);

why use null?


I believe it's because of compound models. e.g. when you have compound 
property model, getObject(Component) returns you the property of the 
model object which name is sme as component id.

getObject(null) returns you the whole model object.

If you have a form for instance and set it a compoundpropertymodel, the 
modelObject of the form is the object you put to the model.


but the model objects of components placed into the form are actually 
properties of the object you set to the model. (as the components will 
inherit the model from the form)


-Matej


---
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[Wicket-user] (conceptual) bug in getModelObject()?

2006-05-10 Thread Ittay Dror

public final Object getModelObject()
{
final IModel model = getModel();
if (model != null)
{
// If this component has the root model for a compound 
model
if (getFlag(FLAG_HAS_ROOT_MODEL))
{
// we need to return the root model and not a 
property of the
// model
return getRootModel(model).getObject(null);
}

// Get model value for this component
return model.getObject(this);
}
else
{
return null;
}
}



note the statement: getRootModel(model).getObject(null);

why use null? 


--
===
Ittay Dror 
Chief architect, openQRM TL, 
R&D, Qlusters Inc.

[EMAIL PROTECTED]
+972-3-6081994 Fax: +972-3-6081841

http://www.openQRM.org
- Keeps your Data-Center Up and Running


---
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