[Wien] WARN : bad integral in ELNES

2014-01-16 Thread Salman Zarrini

=
Dear Wien2k user,

In the ELNES calculation of B-K edge for Ni3B by TELNES3, warnings  
followed by  "bad integral" phrases like below show up in the  
"case.outputelnes" in radial integration, while the other edge's ELNES  
calculation can be smoothly calculated. I would be appreciated if  
anybody let me know where such warnings are usually originated from  
and how I can get rid of them.



:WARN : bad integral  E=  La=   l=   i=  0Typ=   I=  0.30E-01err =  
 0.30E-03 or   1% q=  0.36E+00
:WARN : bad integral  E=  La=   l=   i=  0Typ=   I=  0.18E-02err =  
 0.35E-04 or   2% q=  0.36E+00
:WARN : bad integral  E=  La=   l=   i=  0Typ=   I= -0.76E-02err =  
 0.14E-03 or   2% q=  0.36E+00


Sincerely yours,
Salman Zarrini
E-mail: salman.zarr...@tu-darmstadt.de
=

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Re: [Wien] Trouble executing lapw1 (Cannot find libfftw.so.3)

2014-01-16 Thread Laurence Marks
By default openmpi does not export $LD_LIBRARY_PATH, so you need in
parallel options something like

setenv WIEN_MPIRUN "mpirun -x LD_LIBRARY_PATH -x PATH -np _NP_
-machinefile _HOSTS_ _EXEC_"


(See SRC_mpiutil which has some other examples)

On Wed, Jan 15, 2014 at 4:23 PM, Joshua Davis
 wrote:
> Dear Wien Users
>
> I have Compiled Wien2K 13.1 on our institutions High Performance Computer
> Cluster.
> It was complied with ifort13.01,mkl10.3,FFTW3.3.3, and OpenMPI1.4.4.  It all
> compiled perfectly with no errors.  However, when I go execute the program I
> get the error:
>
> lapw1: error while loading shared libraries: libfftw3.so.3: cannot open
> shared object file: No such file or directory
>
> my $LD_LIBRARY_PATH is:
>
> /opt/software/fftw/3.3.3--Intel-13.0.1.117--OpenMPI-1.4.4/lib:/opt/software/R/2.15.1--Intel-12.0.0.084/lib64/R/lib:/opt/software/boost/1.52.0--Intel-13.0.1.117--OpenMPI-1.4.4/lib:/opt/software/ClusterStudio/2013.1/composer_xe_2013.1.117
>
> Where the library should be is located int the first pathway listed.  I am
> very confused as to why this I am getting this error when I feel the library
> path is clearly stated.
>
> For other information, the HPCC that is being used is made up of different
> machines with differing memory and cpus, however they are all linked by high
> speed infiniband.
>
> Thank you for your help
>
> 
> Joshua D. Davis
> davis.d.j...@gmail.com
> Cell: (734)945-6031
>
> Graduate Assistant
> Department of Chemistry
> Michigan State University
>
> 578 S. Shaw Lane, room 432
>
> East Lansing, MI 48824
> -



-- 
Professor Laurence Marks
Department of Materials Science and Engineering
Northwestern University
www.numis.northwestern.edu 1-847-491-3996
"Research is to see what everybody else has seen, and to think what
nobody else has thought"
Albert Szent-Gyorgi
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[Wien] force output problem

2014-01-16 Thread Hua Peng
Dear Wien2k users,
I have questions about the Wien2K force output.
After I run run_lapw -fc 0.01 -p &, the calculation converged, which
means the force in the system should small than 0.01mRy/a.u..
But in end of  the scf file, the last interaction gives,

   TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
Fz with/without FOR in case.in2
:FOR001:   1.ATOM   0.00   0.00   0.00
0.00 total forces
:FOR002:   2.ATOM   0.00   0.00   0.00
0.00 total forces
:FOR003:   3.ATOM   6.48   0.00   0.00
-6.48 total forces

   TOTAL FORCE WITH RESPECT TO THE GLOBAL COORDINATE SYSTEM:
:FGL001:   1.ATOM 0.0 0.0
0.0 total forces
:FGL002:   2.ATOM 0.0 0.0
0.0 total forces
:FGL003:   3.ATOM-6.48000 0.0
0.0 total forces
:FSUM  : Sum of forces Fx,Fy,Fz0.00.0
  0.0

Besides, in the previous two  interaction, the force is 1.905.

 TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
Fz with/without FOR in case.in2
:FOR001:   1.ATOM  0.000  0.000  0.000
 0.000 partial forces
:FOR002:   2.ATOM  0.000  0.000  0.000
 0.000 partial forces
:FOR003:   3.ATOM  1.905  0.000  0.000
 1.905 partial forces

Is the TOTAL force in the last interaction the sum of force in the
cell? The equivalent atom for ATOM3 is 4.
Best,
Hua Peng
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Re: [Wien] force output problem

2014-01-16 Thread Oleg Rubel
It would be helpful to give a hint of the structure you attempt to
calculate (better enclose the structure file).

Oleg
On Jan 16, 2014 8:49 PM, "Hua Peng"  wrote:

> Dear Wien2k users,
> I have questions about the Wien2K force output.
> After I run run_lapw -fc 0.01 -p &, the calculation converged, which
> means the force in the system should small than 0.01mRy/a.u..
> But in end of  the scf file, the last interaction gives,
>
>TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
> Fz with/without FOR in case.in2
> :FOR001:   1.ATOM   0.00   0.00   0.00
> 0.00 total forces
> :FOR002:   2.ATOM   0.00   0.00   0.00
> 0.00 total forces
> :FOR003:   3.ATOM   6.48   0.00   0.00
> -6.48 total forces
>
>TOTAL FORCE WITH RESPECT TO THE GLOBAL COORDINATE SYSTEM:
> :FGL001:   1.ATOM 0.0 0.0
> 0.0 total forces
> :FGL002:   2.ATOM 0.0 0.0
> 0.0 total forces
> :FGL003:   3.ATOM-6.48000 0.0
> 0.0 total forces
> :FSUM  : Sum of forces Fx,Fy,Fz0.00.0
>   0.0
>
> Besides, in the previous two  interaction, the force is 1.905.
>
>  TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
> Fz with/without FOR in case.in2
> :FOR001:   1.ATOM  0.000  0.000  0.000
>  0.000 partial forces
> :FOR002:   2.ATOM  0.000  0.000  0.000
>  0.000 partial forces
> :FOR003:   3.ATOM  1.905  0.000  0.000
>  1.905 partial forces
>
> Is the TOTAL force in the last interaction the sum of force in the
> cell? The equivalent atom for ATOM3 is 4.
> Best,
> Hua Peng
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Re: [Wien] force output problem

2014-01-16 Thread Laurence Marks
Total Forces have the Pulay corrections included.

Partial Forces do not, are not the correct ones to use and are different.

There is nothing wrong. Note that run_lapw only converges the electron
density with MSR1, you need to use MSR1a to minimize the forces.

__
Laurence Marks
Dept Mat Sci & Eng
Northwestern University
www.numis.northwestern.edu
847 491 3996
On Jan 16, 2014 7:49 PM, "Hua Peng"  wrote:

> Dear Wien2k users,
> I have questions about the Wien2K force output.
> After I run run_lapw -fc 0.01 -p &, the calculation converged, which
> means the force in the system should small than 0.01mRy/a.u..
> But in end of  the scf file, the last interaction gives,
>
>TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
> Fz with/without FOR in case.in2
> :FOR001:   1.ATOM   0.00   0.00   0.00
> 0.00 total forces
> :FOR002:   2.ATOM   0.00   0.00   0.00
> 0.00 total forces
> :FOR003:   3.ATOM   6.48   0.00   0.00
> -6.48 total forces
>
>TOTAL FORCE WITH RESPECT TO THE GLOBAL COORDINATE SYSTEM:
> :FGL001:   1.ATOM 0.0 0.0
> 0.0 total forces
> :FGL002:   2.ATOM 0.0 0.0
> 0.0 total forces
> :FGL003:   3.ATOM-6.48000 0.0
> 0.0 total forces
> :FSUM  : Sum of forces Fx,Fy,Fz0.00.0
>   0.0
>
> Besides, in the previous two  interaction, the force is 1.905.
>
>  TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
> Fz with/without FOR in case.in2
> :FOR001:   1.ATOM  0.000  0.000  0.000
>  0.000 partial forces
> :FOR002:   2.ATOM  0.000  0.000  0.000
>  0.000 partial forces
> :FOR003:   3.ATOM  1.905  0.000  0.000
>  1.905 partial forces
>
> Is the TOTAL force in the last interaction the sum of force in the
> cell? The equivalent atom for ATOM3 is 4.
> Best,
> Hua Peng
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Re: [Wien] force output problem

2014-01-16 Thread Hua Peng
Thank you Laurence for your suggestion. I will have a try.
Best,
Hua

2014/1/16 Laurence Marks :
> Total Forces have the Pulay corrections included.
>
> Partial Forces do not, are not the correct ones to use and are different.
>
> There is nothing wrong. Note that run_lapw only converges the electron
> density with MSR1, you need to use MSR1a to minimize the forces.
>
> __
> Laurence Marks
> Dept Mat Sci & Eng
> Northwestern University
> www.numis.northwestern.edu
> 847 491 3996
>
> On Jan 16, 2014 7:49 PM, "Hua Peng"  wrote:
>>
>> Dear Wien2k users,
>> I have questions about the Wien2K force output.
>> After I run run_lapw -fc 0.01 -p &, the calculation converged, which
>> means the force in the system should small than 0.01mRy/a.u..
>> But in end of  the scf file, the last interaction gives,
>>
>>TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
>> Fz with/without FOR in case.in2
>> :FOR001:   1.ATOM   0.00   0.00   0.00
>> 0.00 total forces
>> :FOR002:   2.ATOM   0.00   0.00   0.00
>> 0.00 total forces
>> :FOR003:   3.ATOM   6.48   0.00   0.00
>> -6.48 total forces
>>
>>TOTAL FORCE WITH RESPECT TO THE GLOBAL COORDINATE SYSTEM:
>> :FGL001:   1.ATOM 0.0 0.0
>> 0.0 total forces
>> :FGL002:   2.ATOM 0.0 0.0
>> 0.0 total forces
>> :FGL003:   3.ATOM-6.48000 0.0
>> 0.0 total forces
>> :FSUM  : Sum of forces Fx,Fy,Fz0.00.0
>>   0.0
>>
>> Besides, in the previous two  interaction, the force is 1.905.
>>
>>  TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
>> Fz with/without FOR in case.in2
>> :FOR001:   1.ATOM  0.000  0.000  0.000
>>  0.000 partial forces
>> :FOR002:   2.ATOM  0.000  0.000  0.000
>>  0.000 partial forces
>> :FOR003:   3.ATOM  1.905  0.000  0.000
>>  1.905 partial forces
>>
>> Is the TOTAL force in the last interaction the sum of force in the
>> cell? The equivalent atom for ATOM3 is 4.
>> Best,
>> Hua Peng
>> ___
>> Wien mailing list
>> Wien@zeus.theochem.tuwien.ac.at
>> http://zeus.theochem.tuwien.ac.at/mailman/listinfo/wien
>> SEARCH the MAILING-LIST at:
>> http://www.mail-archive.com/wien@zeus.theochem.tuwien.ac.at/index.html
>
>
> ___
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