Re: [Wien] Hubbard U and mBJ

2015-05-02 Thread tran

Hi,

these are papers on mBJ+U:
http://dx.doi.org/10.1063/1.4798706
http://dx.doi.org/10.1063/1.4828864

Very often, the procedure is to adjust U until the
desired results are obtained.

F. Tran

On Fri, 1 May 2015, delamora wrote:



Sorry for this question, it has been answered before;

- (2/22/2012)

So most likely mBJ + U gives the better solution, but probably the U  should be 
smaller than in LDA+U, because mBJ already shifts the  f-states a bit.



but I am still confused, in GW and DMFT calculations the Hubbard U is still a 
parameter, so; 

Does the mBJ needs a not precisely  known parameter?

Saludos

Pablo


 

Dear P Blaha and F Tran,

I would like to ask if with the

modified Becke Johnson potential

one should use the Hubbard U?


    Saludos


Pablo



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[Wien] Symmetry related

2015-05-02 Thread Lawal Mohammed
Dear Developers and Users
 Please what is wrong in having P1 symmetry? I got P1 when I initialized 
supercell calculations. In the mail archive P1 is regarded as less efficient. 
How can I improve the symmetry at the same time maintaining same structure? 
Could somebody elaborate please.


With kind regards
Lawal Mohammed___
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Re: [Wien] Symmetry related

2015-05-02 Thread Víctor Luaña Cabal
On Sat, May 02, 2015 at 08:25:25AM +, Lawal Mohammed wrote:
> Dear Developers and Users
>  Please what is wrong in having P1 symmetry? I got P1 when I
> initialized supercell calculations. In the mail archive P1 is regarded
> as less efficient. How can I improve the symmetry at the same time
> maintaining same structure? Could somebody elaborate please.

Lawal,

1) Nothing is wrong. P1 eans that there is no rotational symmetry
   available in your crystal. Rotattion, reflection, inversion, etc.

2) Unfortunately symmetry elements (other than traslation) are used
   by the codes to refuce the computationl cost so it may represent
   bad news. Traslation is also used, but that is implicit, as
   you are using solid state codes designed for crystals.

3) This computer experiment may help you to understand: Take a simple
   compund and reduce the symetry progressively. You will see how the
   computer time required for the calculation increases. The less
   symmetry operations available the higher the cpu involved.
   Bad news if your disponibility of computer resources is limited.

Best regards,
 Dr. Víctor Luaña
--
 .  ."Research is to see what everybody else has seen, and to
/ `' \   think what nobody else has thought"-- Albert Szent-Gyorgi
   /(o)(o)\  
  /`. \/ .'\  "Lo mediocre es peor que lo bueno, pero también es peor
 /   '`'`   \ que lo malo, porque la mediocridad no es un grado, es una
 |  \'`'`/  | actitud" -- Jorge Wasenberg, 2015
 |  |'`'`|  | (Mediocre is worse than good, but it is also worse than
  \/`'`'`'\/  bad, because mediocrity is not a grade, it is an attitude)
===(((==)))==+=
! Dr.Víctor Luaña, in silico chemist & prof. ! 
! Departamento de Química Física y Analítica ! 
! Universidad de Oviedo, 33006-Oviedo, Spain ! 
! e-mail:   vic...@fluor.quimica.uniovi.es   ! 
! phone: +34-985-103491  fax: +34-985-103125 ! 
++
 GroupPage : http://azufre.quimica.uniovi.es/
 (being reworked)
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Re: [Wien] Symmetry related

2015-05-02 Thread Lawal Mohammed
Dear Dr. Víctor Luaña,
Thanks so much for the explanation.
Kind regards 
Lawal Mohammed 


 On Saturday, May 2, 2015 5:10 PM, Víctor Luaña Cabal 
 wrote:
   

 On Sat, May 02, 2015 at 08:25:25AM +, Lawal Mohammed wrote:
> Dear Developers and Users
>  Please what is wrong in having P1 symmetry? I got P1 when I
> initialized supercell calculations. In the mail archive P1 is regarded
> as less efficient. How can I improve the symmetry at the same time
> maintaining same structure? Could somebody elaborate please.

Lawal,

1) Nothing is wrong. P1 eans that there is no rotational symmetry
  available in your crystal. Rotattion, reflection, inversion, etc.

2) Unfortunately symmetry elements (other than traslation) are used
  by the codes to refuce the computationl cost so it may represent
  bad news. Traslation is also used, but that is implicit, as
  you are using solid state codes designed for crystals.

3) This computer experiment may help you to understand: Take a simple
  compund and reduce the symetry progressively. You will see how the
  computer time required for the calculation increases. The less
  symmetry operations available the higher the cpu involved.
  Bad news if your disponibility of computer resources is limited.

Best regards,
            Dr. Víctor Luaña
--
    .  .    "Research is to see what everybody else has seen, and to
    / `' \  think what nobody else has thought"-- Albert Szent-Gyorgi
  /(o)(o)\  
  /`. \/ .'\  "Lo mediocre es peor que lo bueno, pero también es peor
 /  '`'`  \ que lo malo, porque la mediocridad no es un grado, es una
 |  \'`'`/  | actitud" -- Jorge Wasenberg, 2015
 |  |'`'`|  | (Mediocre is worse than good, but it is also worse than
  \/`'`'`'\/  bad, because mediocrity is not a grade, it is an attitude)
===(((==)))==+=
! Dr.Víctor Luaña, in silico chemist & prof. ! 
! Departamento de Química Física y Analítica ! 
! Universidad de Oviedo, 33006-Oviedo, Spain ! 
! e-mail:  vic...@fluor.quimica.uniovi.es  ! 
! phone: +34-985-103491  fax: +34-985-103125 ! 
++
 GroupPage : http://azufre.quimica.uniovi.es/
            (being reworked)
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Re: [Wien] Hubbard U and mBJ

2015-05-02 Thread delamora
Professor Tran,
Thank you very much.

Pablo de la Mora

De: wien-boun...@zeus.theochem.tuwien.ac.at 
 en nombre de 
t...@theochem.tuwien.ac.at 
Enviado: sábado, 2 de mayo de 2015 02:28 a. m.
Para: A Mailing list for WIEN2k users
Asunto: Re: [Wien] Hubbard U and mBJ

Hi,

these are papers on mBJ+U:
http://dx.doi.org/10.1063/1.4798706
http://dx.doi.org/10.1063/1.4828864

Very often, the procedure is to adjust U until the
desired results are obtained.

F. Tran

On Fri, 1 May 2015, delamora wrote:

>
> Sorry for this question, it has been answered before;
>
> - (2/22/2012)
>
> So most likely mBJ + U gives the better solution, but probably the U  should 
> be smaller than in LDA+U, because mBJ already shifts the  f-states a bit.
>
> 
>
> but I am still confused, in GW and DMFT calculations the Hubbard U is still a 
> parameter, so;
>
> Does the mBJ needs a not precisely  known parameter?
>
> Saludos
>
> Pablo
>
> 
>
>
> Dear P Blaha and F Tran,
>
> I would like to ask if with the
>
> modified Becke Johnson potential
>
> one should use the Hubbard U?
>
>
> Saludos
>
>
> Pablo
>
>
>
>
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