Re: [Wien] X-FORCE for atom 1 is not zero as required by symmetry

2014-04-24 Thread foyevtsova
Dear Peter,

with your recipe the problem is indeed fixed.

It turns out after all that my in2 was wrong as a result of producing and
running a series of struct files with varying degree of BiO6-octahedra
tilting. I performed initialization for a structure with no tilting and
then ran scf for a sequence of structures with increasing tilting without
reinitializing (with same in2). Now I see that initialization gives
different in2 in the case of tilting and no tilting, probably because of
the lower symmetry in the former case, even though nominally the space
group of the unit cell stays the same. I've got the original structure
from a colleague and so do not know about the origin of the rot matrices.

Thank you for your help and time.

Best,
Kateryna


 1) I am using version 13.1. Still, min_lapw has changed the space group
 number from 14 to 4, which I only noticed after Gerhard had pointed this
 out. The regular scf cycle was done with the correct space group in
 .struct and produced X-FORCE for atom 1 is not zero as required by
 symmetry.

 The spacegroup-label in the struct file is NOT used at all, except in the
 structgenerator of w2web.
 In other words, you can put there anything and as long as you do not load
 such a struct file into structgen@w2web and press SAVE/ACCEPT CHANGES,
 there
 is no effect-

 Nevertheless, I'll modify the structgenerator, such that it writes a blank
 in between #of atoms and SG number, as this is very confusing.

 3) If possible, I'd like to keep this space group or, at least, the unit
 cell dimensions for further analysis.

 So, can I conclude that it is not possible to optimize the position of
 the
 first atom using this space group/unit cell dimensions because of not
 accepting the space group suggested by sgroup? Perhaps, I should try
 reducing the symmetry to P1...

 It should be possible. I did not check it very carefully, but to my
 understanding
 you do NOT need to follow the suggestion of sgroup and can keep the unit
 cell as
 desired. (I still do not know who wrote these local rotation matrices into
 case.struct ???)

 Please transfer the struct file to a new directory.

 Put the number of symmetry operations to ZERO in case.struct
 (use an editor, not structgen to avoid any problems with the SG-label).

 Then reinitialize again and run mini again.


 --
 -
 Peter Blaha
 Inst. Materials Chemistry, TU Vienna
 Getreidemarkt 9, A-1060 Vienna, Austria
 Tel: +43-1-5880115671
 Fax: +43-1-5880115698
 email: pbl...@theochem.tuwien.ac.at
 -
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 Wien mailing list
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Re: [Wien] X-FORCE for atom 1 is not zero as required by symmetry

2014-04-23 Thread Peter Blaha

You did not use the default initialization in wien2k, but probably a
funny mixture of hand-made inputs, which are probably not consistent.

i) sgroup would suggest a different cell with a large monoclinic angle.
   However, it seems as it is possible to neglect this suggestion.

ii) symmetry produces a struct file WITHOUT your local rotation matrices.
Where did you get those ? But again, since symmetry is so low, you
can select any rot.loc. and this should not be the problem.

But symmetry also produces case.in2  and clearly the first atom HAS forces.
(LM list with l=1). So most likely case.in2 is wrong.

Please, put the number of symmetry operations to ZERO in case.struct
and make a valid initialization in a new directory.

Am 23.04.2014 01:43, schrieb foyevts...@th.physik.uni-frankfurt.de:

Hi,

I want to calculate forces and eventually optimize internal parameters for
SrBiO3 with a unit cell of the 4_P21/n space group. Below I copy the
struct file:

str
P6 4_P21/n
  RELA
  11.160207 11.599001 16.096181 90.00 90.00 90.00
ATOM  -1: X=0. Y=0. Z=0.2500
   MULT= 4  ISPLIT= 2
   -1: X=0. Y=0. Z=0.7500
   -1: X=0.5000 Y=0.5000 Z=0.2500
   -1: X=0.5000 Y=0.5000 Z=0.7500
Sr NPT=  781  R0=0.1000 RMT=2.3500   Z:  38.0
  1.000 0.000 0.000
  0.000 1.000 0.000
  0.000 0.000 1.000
ATOM  -2: X=0.5000 Y=0. Z=0.
   MULT= 2  ISPLIT= 8
   -2: X=0. Y=0.5000 Z=0.5000
Bi NPT=  781  R0=0.0500 RMT=2.0500   Z:  83.0
  0.7071068 0.7071068 0.000
 -0.7071068 0.7071068 0.000
  0.000 0.000 1.000
ATOM  -3: X=0.5000 Y=0. Z=0.5000
   MULT= 2  ISPLIT= 8
   -3: X=0. Y=0.5000 Z=0.
Bi NPT=  781  R0=0.0500 RMT=2.0500   Z:  83.0
  0.7071068 0.7071068 0.000
 -0.7071068 0.7071068 0.000
  0.000 0.000 1.000
ATOM  -4: X=0.09988080 Y=0.48071300 Z=0.23264600
   MULT= 4  ISPLIT= 8
   -4: X=0.90011920 Y=0.51928700 Z=0.76735400
   -4: X=0.40011920 Y=0.98071300 Z=0.26735400
   -4: X=0.59988080 Y=0.01928700 Z=0.73264600
O  NPT=  781  R0=0.0001 RMT=1.7000   Z:   8.0
  0.7071068 0.7071068 0.000
 -0.7071068 0.7071068 0.000
  0.000 0.000 1.000
ATOM  -5: X=0.71614580 Y=0.31476100 Z=0.05060980
   MULT= 4  ISPLIT= 8
   -5: X=0.28385420 Y=0.68523900 Z=0.94939020
   -5: X=0.78385420 Y=0.81476100 Z=0.44939020
   -5: X=0.21614580 Y=0.18523900 Z=0.55060980
O  NPT=  781  R0=0.0001 RMT=1.7000   Z:   8.0
  0.000-0.7071068 0.7071068
  0.000 0.7071068 0.7071068
 -1.000 0.000 0.000
ATOM  -6: X=0.18004640 Y=0.21865880 Z=0.95072900
   MULT= 4  ISPLIT= 8
   -6: X=0.81995360 Y=0.78134120 Z=0.04927100
   -6: X=0.31995360 Y=0.71865880 Z=0.54927100
   -6: X=0.68004640 Y=0.28134120 Z=0.45072900
O  NPT=  781  R0=0.0001 RMT=1.7000   Z:   8.0
  0.000 0.7071068-0.7071068
  0.000 0.7071068 0.7071068
  1.000 0.000 0.000
4  NUMBER OF SYMMETRY OPERATIONS
-1 0 0 0.
  0-1 0 0.
  0 0-1 0.
1
  1 0 0 0.
  0 1 0 0.
  0 0 1 0.
2
-1 0 0 0.5000
  0 1 0 0.5000
  0 0-1 0.5000
3
  1 0 0 0.5000
  0-1 0 0.5000
  0 0 1 0.5000
4

After 'run_lapw -f 1' I get the following information in the .scf:

:WARN  : X-FORCE for atom   1 is not zero as required by symmetry:   28.2338
:WARN  : Y-FORCE for atom   1 is not zero as required by symmetry: -113.3722
:WARN  : Z-FORCE for atom   1 is not zero as required by symmetry:   11.9520
:WARN  : X-FORCE for atom   4 is not zero as required by symmetry:  -35.0616
:WARN  : Y-FORCE for atom   4 is not zero as required by symmetry:   -7.5757
:WARN  : X-FORCE for atom   5 is not zero as required by symmetry:   30.2203
:WARN  : Y-FORCE for atom   5 is not zero as required by symmetry:  -25.6543
:WARN  : X-FORCE for atom   6 is not zero as required by symmetry:   30.6085
:WARN  : Y-FORCE for atom   6 is not zero as required by symmetry:   34.8658

:ENE  : *WARNING** TOTAL ENERGY IN Ry =  -199762.69661481

TOTAL FORCE IN mRy/a.u. = |F| Fx Fy Fz
with/without FOR in case.in2
:FOR001:   1.ATOM 117.444686   0.00   0.00
0.00 total forces
:FOR002:   

Re: [Wien] X-FORCE for atom 1 is not zero as required by symmetry

2014-04-23 Thread Fecher, Gerhard
Possible reasons: bug in some older version and/or a mistake made in one of the 
input files caused by a handbook not read error.

Note: only the Bi atoms (atoms 2 and 3, but not 1, 4, 5, 6) are in positions 
without free parameters 
where the forces have to be zero by symmetry. 
Seems that in your calculation the struct file is completely wrong interpreted 
somewhere.

I used the structure file with Wien2k Version 11.1 and 13.1 and min_lapw as 
well as MSR1a (13.1 only)
no problems or warnings appeared.
However, the struct file seems to be created by a min_lapw version older then 
13.1 (see remark on 11.1 below)
in line 2 of your struct the space group is 4_P21/n and has the wrong space 
group number it should be 14 !  (bug in older versions up to ??)  

I used batch initialisation (energy separation -8.5 and rkmax = 5.0, kpoints 
10, the latter 2 just to be fast)
and ignored the warning that the space group may be P21/c instead of P21/n 
(Note: if accepting the change of sgroup it was also running without problems 
in 13.1 with MSR1a).
I also guess it might be better to use smaller spheres (use the struct 
generator to do that)

Remark on changes made by some subroutines in the first 3 lines of the 
structure files 
The original header is (first 3 lines of case.struct)
Title  
P   LATTICE,NONEQUIV.ATOMS:  614_P21/n 
MODE OF CALC=RELA unit=ang

in 11.1 min_lapw changes the 2nd lin to 
   
P6 4_P21/n
that is interpreted by the structure generator as
P   LATTICE,NONEQUIV.ATOMS:  64_P21
what is a different space group


in 13.1 min_lapw changes the first 4 lines to
Title   
P614_P21/n
 RELA
 11.160207 11.599001 16.096181 90.00 90.00 90.00

and MSR1a the second line to
P6 14 P21/n
interesting to note in case.struct_sgroup there is a space between 
the number of atoms and the number of the space group
P   LATTICE,NONEQUIV.ATOMS:  6 14 P21/n
this line is read correctly by the structure generator

would be favourable if it was always like that, because two atoms in spgr 
twentyfive result in 225
and similar, this confuses always when having a quick look.
I also wonder wether 2220 may be interpreted as 2 atoms in I-43d or as 22 atoms 
in C2221 (I did not check it) ?

Actually I do not really know why any sub-programm with exception of sgroup 
(only needs a change of the 2nd line of the first 3
but why does it change  unit=ang to unit=bohr, this is not a symmetry operation 
;-)
should change the header of the struct files ? Seems to be historically based.

Ciao
Gerhard

DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
I think the problem, to be quite honest with you,
is that you have never actually known what the question is.


Dr. Gerhard H. Fecher
Institut of Inorganic and Analytical Chemistry
Johannes Gutenberg - University
55099 Mainz

Von: wien-boun...@zeus.theochem.tuwien.ac.at 
[wien-boun...@zeus.theochem.tuwien.ac.at]quot; im Auftrag von 
quot;foyevts...@th.physik.uni-frankfurt.de 
[foyevts...@th.physik.uni-frankfurt.de]
Gesendet: Mittwoch, 23. April 2014 01:43
An: wien@zeus.theochem.tuwien.ac.at
Betreff: [Wien] X-FORCE for atom   1 is not zero as required by symmetry

Hi,

I want to calculate forces and eventually optimize internal parameters for
SrBiO3 with a unit cell of the 4_P21/n space group. Below I copy the
struct file:

str
P6 4_P21/n
 RELA
 11.160207 11.599001 16.096181 90.00 90.00 90.00
ATOM  -1: X=0. Y=0. Z=0.2500
  MULT= 4  ISPLIT= 2
  -1: X=0. Y=0. Z=0.7500
  -1: X=0.5000 Y=0.5000 Z=0.2500
  -1: X=0.5000 Y=0.5000 Z=0.7500
Sr NPT=  781  R0=0.1000 RMT=2.3500   Z:  38.0
 1.000 0.000 0.000
 0.000 1.000 0.000
 0.000 0.000 1.000
ATOM  -2: X=0.5000 Y=0. Z=0.
  MULT= 2  ISPLIT= 8
  -2: X=0. Y=0.5000 Z=0.5000
Bi NPT=  781  R0=0.0500 RMT=2.0500   Z:  83.0
 0.7071068 0.7071068 0.000
-0.7071068 0.7071068 0.000
 0.000 0.000 1.000
ATOM  -3: X=0.5000 Y=0. Z=0.5000
  MULT= 2  ISPLIT= 8
  -3: X=0. Y=0.5000 Z=0.
Bi NPT=  781  R0=0.0500 RMT=2.0500   Z:  83.0
 0.7071068 0.7071068 0.000
-0.7071068 0.7071068 0.000
 

Re: [Wien] X-FORCE for atom 1 is not zero as required by symmetry

2014-04-23 Thread Fecher, Gerhard
but still the line
P6 4_P21/n
is wrong
either 14_P21/n (sgroup - 14 P21/c) or 4_P21, these two things are not the 
same !


Ciao
Gerhard

DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
I think the problem, to be quite honest with you,
is that you have never actually known what the question is.


Dr. Gerhard H. Fecher
Institut of Inorganic and Analytical Chemistry
Johannes Gutenberg - University
55099 Mainz

Von: wien-boun...@zeus.theochem.tuwien.ac.at 
[wien-boun...@zeus.theochem.tuwien.ac.at]quot; im Auftrag von quot;Peter 
Blaha [pbl...@theochem.tuwien.ac.at]
Gesendet: Mittwoch, 23. April 2014 08:03
An: A Mailing list for WIEN2k users
Betreff: Re: [Wien] X-FORCE for atom 1 is not zero as required by symmetry

You did not use the default initialization in wien2k, but probably a
funny mixture of hand-made inputs, which are probably not consistent.

i) sgroup would suggest a different cell with a large monoclinic angle.
However, it seems as it is possible to neglect this suggestion.

ii) symmetry produces a struct file WITHOUT your local rotation matrices.
 Where did you get those ? But again, since symmetry is so low, you
 can select any rot.loc. and this should not be the problem.

 But symmetry also produces case.in2  and clearly the first atom HAS forces.
 (LM list with l=1). So most likely case.in2 is wrong.

Please, put the number of symmetry operations to ZERO in case.struct
and make a valid initialization in a new directory.

Am 23.04.2014 01:43, schrieb foyevts...@th.physik.uni-frankfurt.de:
 Hi,

 I want to calculate forces and eventually optimize internal parameters for
 SrBiO3 with a unit cell of the 4_P21/n space group. Below I copy the
 struct file:

 str
 P6 4_P21/n
   RELA
   11.160207 11.599001 16.096181 90.00 90.00 90.00
 ATOM  -1: X=0. Y=0. Z=0.2500
MULT= 4  ISPLIT= 2
-1: X=0. Y=0. Z=0.7500
-1: X=0.5000 Y=0.5000 Z=0.2500
-1: X=0.5000 Y=0.5000 Z=0.7500
 Sr NPT=  781  R0=0.1000 RMT=2.3500   Z:  38.0
   1.000 0.000 0.000
   0.000 1.000 0.000
   0.000 0.000 1.000
 ATOM  -2: X=0.5000 Y=0. Z=0.
MULT= 2  ISPLIT= 8
-2: X=0. Y=0.5000 Z=0.5000
 Bi NPT=  781  R0=0.0500 RMT=2.0500   Z:  83.0
   0.7071068 0.7071068 0.000
  -0.7071068 0.7071068 0.000
   0.000 0.000 1.000
 ATOM  -3: X=0.5000 Y=0. Z=0.5000
MULT= 2  ISPLIT= 8
-3: X=0. Y=0.5000 Z=0.
 Bi NPT=  781  R0=0.0500 RMT=2.0500   Z:  83.0
   0.7071068 0.7071068 0.000
  -0.7071068 0.7071068 0.000
   0.000 0.000 1.000
 ATOM  -4: X=0.09988080 Y=0.48071300 Z=0.23264600
MULT= 4  ISPLIT= 8
-4: X=0.90011920 Y=0.51928700 Z=0.76735400
-4: X=0.40011920 Y=0.98071300 Z=0.26735400
-4: X=0.59988080 Y=0.01928700 Z=0.73264600
 O  NPT=  781  R0=0.0001 RMT=1.7000   Z:   8.0
   0.7071068 0.7071068 0.000
  -0.7071068 0.7071068 0.000
   0.000 0.000 1.000
 ATOM  -5: X=0.71614580 Y=0.31476100 Z=0.05060980
MULT= 4  ISPLIT= 8
-5: X=0.28385420 Y=0.68523900 Z=0.94939020
-5: X=0.78385420 Y=0.81476100 Z=0.44939020
-5: X=0.21614580 Y=0.18523900 Z=0.55060980
 O  NPT=  781  R0=0.0001 RMT=1.7000   Z:   8.0
   0.000-0.7071068 0.7071068
   0.000 0.7071068 0.7071068
  -1.000 0.000 0.000
 ATOM  -6: X=0.18004640 Y=0.21865880 Z=0.95072900
MULT= 4  ISPLIT= 8
-6: X=0.81995360 Y=0.78134120 Z=0.04927100
-6: X=0.31995360 Y=0.71865880 Z=0.54927100
-6: X=0.68004640 Y=0.28134120 Z=0.45072900
 O  NPT=  781  R0=0.0001 RMT=1.7000   Z:   8.0
   0.000 0.7071068-0.7071068
   0.000 0.7071068 0.7071068
   1.000 0.000 0.000
 4  NUMBER OF SYMMETRY OPERATIONS
 -1 0 0 0.
   0-1 0 0.
   0 0-1 0.
 1
   1 0 0 0.
   0 1 0 0.
   0 0 1 0.
 2
 -1 0 0 0.5000
   0 1 0 0.5000
   0 0-1 0.5000
 3
   1 0 0 0.5000
   0-1 0 0.5000
   0 0 1 0.5000
 4

 After 'run_lapw -f 1' I get the following information in the .scf:

 :WARN  : X-FORCE for atom   1 is not zero 

Re: [Wien] X-FORCE for atom 1 is not zero as required by symmetry

2014-04-23 Thread foyevtsova
Dear Laurence, Peter and Gerhard,

thanks for your comments. Some answers:

1) I am using version 13.1. Still, min_lapw has changed the space group
number from 14 to 4, which I only noticed after Gerhard had pointed this
out. The regular scf cycle was done with the correct space group in
.struct and produced X-FORCE for atom 1 is not zero as required by
symmetry.

2) I've never touched .in2.

3) If possible, I'd like to keep this space group or, at least, the unit
cell dimensions for further analysis.

So, can I conclude that it is not possible to optimize the position of the
first atom using this space group/unit cell dimensions because of not
accepting the space group suggested by sgroup? Perhaps, I should try
reducing the symmetry to P1...

Bests,
Kateryna

 Possible reasons: bug in some older version and/or a mistake made in one
 of the input files caused by a handbook not read error.

 Note: only the Bi atoms (atoms 2 and 3, but not 1, 4, 5, 6) are in
 positions without free parameters
 where the forces have to be zero by symmetry.
 Seems that in your calculation the struct file is completely wrong
 interpreted somewhere.

 I used the structure file with Wien2k Version 11.1 and 13.1 and min_lapw
 as well as MSR1a (13.1 only)
 no problems or warnings appeared.
 However, the struct file seems to be created by a min_lapw version older
 then 13.1 (see remark on 11.1 below)
 in line 2 of your struct the space group is 4_P21/n and has the wrong
 space group number it should be 14 !  (bug in older versions up to ??)

 I used batch initialisation (energy separation -8.5 and rkmax = 5.0,
 kpoints 10, the latter 2 just to be fast)
 and ignored the warning that the space group may be P21/c instead of P21/n
 (Note: if accepting the change of sgroup it was also running without
 problems in 13.1 with MSR1a).
 I also guess it might be better to use smaller spheres (use the struct
 generator to do that)

 Remark on changes made by some subroutines in the first 3 lines of the
 structure files
 The original header is (first 3 lines of case.struct)
 Title
 P   LATTICE,NONEQUIV.ATOMS:  614_P21/n
 MODE OF CALC=RELA unit=ang

 in 11.1 min_lapw changes the 2nd lin to
 P6 4_P21/n
 that is interpreted by the structure generator as
 P   LATTICE,NONEQUIV.ATOMS:  64_P21
 what is a different space group


 in 13.1 min_lapw changes the first 4 lines to
 Title
 P614_P21/n
  RELA
  11.160207 11.599001 16.096181 90.00 90.00 90.00

 and MSR1a the second line to
 P6 14 P21/n
 interesting to note in case.struct_sgroup there is a space between
 the number of atoms and the number of the space group
 P   LATTICE,NONEQUIV.ATOMS:  6 14 P21/n
 this line is read correctly by the structure generator

 would be favourable if it was always like that, because two atoms in spgr
 twentyfive result in 225
 and similar, this confuses always when having a quick look.
 I also wonder wether 2220 may be interpreted as 2 atoms in I-43d or as 22
 atoms in C2221 (I did not check it) ?

 Actually I do not really know why any sub-programm with exception of
 sgroup (only needs a change of the 2nd line of the first 3
 but why does it change  unit=ang to unit=bohr, this is not a symmetry
 operation ;-)
 should change the header of the struct files ? Seems to be historically
 based.

 Ciao
 Gerhard

 DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
 I think the problem, to be quite honest with you,
 is that you have never actually known what the question is.

 
 Dr. Gerhard H. Fecher
 Institut of Inorganic and Analytical Chemistry
 Johannes Gutenberg - University
 55099 Mainz
 
 Von: wien-boun...@zeus.theochem.tuwien.ac.at
 [wien-boun...@zeus.theochem.tuwien.ac.at] im Auftrag von
 foyevts...@th.physik.uni-frankfurt.de
 [foyevts...@th.physik.uni-frankfurt.de]
 Gesendet: Mittwoch, 23. April 2014 01:43
 An: wien@zeus.theochem.tuwien.ac.at
 Betreff: [Wien] X-FORCE for atom   1 is not zero as required by symmetry

 Hi,

 I want to calculate forces and eventually optimize internal parameters for
 SrBiO3 with a unit cell of the 4_P21/n space group. Below I copy the
 struct file:

 str
 P6 4_P21/n
  RELA
  11.160207 11.599001 16.096181 90.00 90.00 90.00
 ATOM  -1: X=0. Y=0. Z=0.2500
   MULT= 4  ISPLIT= 2
   -1: X=0. Y=0. Z=0.7500
   -1: X=0.5000 Y=0.5000 Z=0.2500
   -1: X=0.5000 Y=0.5000 Z=0.7500
 Sr NPT=  781  R0=0.1000 RMT=2.3500   Z:  38.0
  1.000 0.000 0.000
  0.000 1.000 0.000
  0.000 0.000 1.000
 ATOM  -2: X=0.5000 Y=0. Z=0.
   MULT= 2  ISPLIT= 8
   -2: X=0. Y=0.5000 

Re: [Wien] X-FORCE for atom 1 is not zero as required by symmetry

2014-04-23 Thread Peter Blaha

1) I am using version 13.1. Still, min_lapw has changed the space group
number from 14 to 4, which I only noticed after Gerhard had pointed this
out. The regular scf cycle was done with the correct space group in
.struct and produced X-FORCE for atom 1 is not zero as required by
symmetry.


The spacegroup-label in the struct file is NOT used at all, except in the
structgenerator of w2web.
In other words, you can put there anything and as long as you do not load
such a struct file into structgen@w2web and press SAVE/ACCEPT CHANGES, there
is no effect-

Nevertheless, I'll modify the structgenerator, such that it writes a blank
in between #of atoms and SG number, as this is very confusing.


3) If possible, I'd like to keep this space group or, at least, the unit
cell dimensions for further analysis.

So, can I conclude that it is not possible to optimize the position of the
first atom using this space group/unit cell dimensions because of not
accepting the space group suggested by sgroup? Perhaps, I should try
reducing the symmetry to P1...


It should be possible. I did not check it very carefully, but to my 
understanding
you do NOT need to follow the suggestion of sgroup and can keep the unit cell as
desired. (I still do not know who wrote these local rotation matrices into 
case.struct ???)

Please transfer the struct file to a new directory.

Put the number of symmetry operations to ZERO in case.struct
(use an editor, not structgen to avoid any problems with the SG-label).

Then reinitialize again and run mini again.


--
-
Peter Blaha
Inst. Materials Chemistry, TU Vienna
Getreidemarkt 9, A-1060 Vienna, Austria
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[Wien] X-FORCE for atom 1 is not zero as required by symmetry

2014-04-22 Thread foyevtsova
Hi,

I want to calculate forces and eventually optimize internal parameters for
SrBiO3 with a unit cell of the 4_P21/n space group. Below I copy the
struct file:

str
P6 4_P21/n
 RELA
 11.160207 11.599001 16.096181 90.00 90.00 90.00
ATOM  -1: X=0. Y=0. Z=0.2500
  MULT= 4  ISPLIT= 2
  -1: X=0. Y=0. Z=0.7500
  -1: X=0.5000 Y=0.5000 Z=0.2500
  -1: X=0.5000 Y=0.5000 Z=0.7500
Sr NPT=  781  R0=0.1000 RMT=2.3500   Z:  38.0
 1.000 0.000 0.000
 0.000 1.000 0.000
 0.000 0.000 1.000
ATOM  -2: X=0.5000 Y=0. Z=0.
  MULT= 2  ISPLIT= 8
  -2: X=0. Y=0.5000 Z=0.5000
Bi NPT=  781  R0=0.0500 RMT=2.0500   Z:  83.0
 0.7071068 0.7071068 0.000
-0.7071068 0.7071068 0.000
 0.000 0.000 1.000
ATOM  -3: X=0.5000 Y=0. Z=0.5000
  MULT= 2  ISPLIT= 8
  -3: X=0. Y=0.5000 Z=0.
Bi NPT=  781  R0=0.0500 RMT=2.0500   Z:  83.0
 0.7071068 0.7071068 0.000
-0.7071068 0.7071068 0.000
 0.000 0.000 1.000
ATOM  -4: X=0.09988080 Y=0.48071300 Z=0.23264600
  MULT= 4  ISPLIT= 8
  -4: X=0.90011920 Y=0.51928700 Z=0.76735400
  -4: X=0.40011920 Y=0.98071300 Z=0.26735400
  -4: X=0.59988080 Y=0.01928700 Z=0.73264600
O  NPT=  781  R0=0.0001 RMT=1.7000   Z:   8.0
 0.7071068 0.7071068 0.000
-0.7071068 0.7071068 0.000
 0.000 0.000 1.000
ATOM  -5: X=0.71614580 Y=0.31476100 Z=0.05060980
  MULT= 4  ISPLIT= 8
  -5: X=0.28385420 Y=0.68523900 Z=0.94939020
  -5: X=0.78385420 Y=0.81476100 Z=0.44939020
  -5: X=0.21614580 Y=0.18523900 Z=0.55060980
O  NPT=  781  R0=0.0001 RMT=1.7000   Z:   8.0
 0.000-0.7071068 0.7071068
 0.000 0.7071068 0.7071068
-1.000 0.000 0.000
ATOM  -6: X=0.18004640 Y=0.21865880 Z=0.95072900
  MULT= 4  ISPLIT= 8
  -6: X=0.81995360 Y=0.78134120 Z=0.04927100
  -6: X=0.31995360 Y=0.71865880 Z=0.54927100
  -6: X=0.68004640 Y=0.28134120 Z=0.45072900
O  NPT=  781  R0=0.0001 RMT=1.7000   Z:   8.0
 0.000 0.7071068-0.7071068
 0.000 0.7071068 0.7071068
 1.000 0.000 0.000
   4  NUMBER OF SYMMETRY OPERATIONS
-1 0 0 0.
 0-1 0 0.
 0 0-1 0.
   1
 1 0 0 0.
 0 1 0 0.
 0 0 1 0.
   2
-1 0 0 0.5000
 0 1 0 0.5000
 0 0-1 0.5000
   3
 1 0 0 0.5000
 0-1 0 0.5000
 0 0 1 0.5000
   4

After 'run_lapw -f 1' I get the following information in the .scf:

:WARN  : X-FORCE for atom   1 is not zero as required by symmetry:   28.2338
:WARN  : Y-FORCE for atom   1 is not zero as required by symmetry: -113.3722
:WARN  : Z-FORCE for atom   1 is not zero as required by symmetry:   11.9520
:WARN  : X-FORCE for atom   4 is not zero as required by symmetry:  -35.0616
:WARN  : Y-FORCE for atom   4 is not zero as required by symmetry:   -7.5757
:WARN  : X-FORCE for atom   5 is not zero as required by symmetry:   30.2203
:WARN  : Y-FORCE for atom   5 is not zero as required by symmetry:  -25.6543
:WARN  : X-FORCE for atom   6 is not zero as required by symmetry:   30.6085
:WARN  : Y-FORCE for atom   6 is not zero as required by symmetry:   34.8658

:ENE  : *WARNING** TOTAL ENERGY IN Ry =  -199762.69661481

   TOTAL FORCE IN mRy/a.u. = |F| Fx Fy Fz 
   with/without FOR in case.in2
:FOR001:   1.ATOM 117.444686   0.00   0.00  
0.00 total forces
:FOR002:   2.ATOM   0.00   0.00   0.00  
0.00 total forces
:FOR003:   3.ATOM   0.00   0.00   0.00  
0.00 total forces
:FOR004:   4.ATOM  54.932586   0.00   0.00 
41.603856 total forces
:FOR005:   5.ATOM  58.546663   0.00   0.00
-43.084779 total forces
:FOR006:   6.ATOM  61.573155   0.00   0.00
-40.481491 total forces
   TOTAL FORCE WITH RESPECT TO GLOBAL CARTESIAN COORDINATES:
:FCA001:   1.ATOM  0.00   0.00  
0.00 total forces
:FCA002:   2.ATOM  0.00   0.00  
0.00 total forces
:FCA003:   3.ATOM  0.00   0.00  
0.00 total forces
:FCA004:   4.ATOM  0.00   0.00 
41.603856 total 

Re: [Wien] X-FORCE for atom 1 is not zero as required by symmetry

2014-04-22 Thread Laurence Marks
Many things:

1. It appears that you did not adopt Wien2k's recommendation about
reducing to the primitive cell -- why not?
2. Your RMT's look strange. You probably need to reduce the O a bit
and increase the Bi.
3. Did you use the default case.in2? In a quick check this seems to
have forces for the first atom.
4. Are you using a new or old version?

On Tue, Apr 22, 2014 at 6:43 PM, foyevts...@th.physik.uni-frankfurt.de
foyevts...@th.physik.uni-frankfurt.de wrote:
 Hi,

 I want to calculate forces and eventually optimize internal parameters for
 SrBiO3 with a unit cell of the 4_P21/n space group. Below I copy the
 struct file:

 str
 P6 4_P21/n
  RELA
  11.160207 11.599001 16.096181 90.00 90.00 90.00
 ATOM  -1: X=0. Y=0. Z=0.2500
   MULT= 4  ISPLIT= 2
   -1: X=0. Y=0. Z=0.7500
   -1: X=0.5000 Y=0.5000 Z=0.2500
   -1: X=0.5000 Y=0.5000 Z=0.7500
 Sr NPT=  781  R0=0.1000 RMT=2.3500   Z:  38.0
  1.000 0.000 0.000
  0.000 1.000 0.000
  0.000 0.000 1.000
 ATOM  -2: X=0.5000 Y=0. Z=0.
   MULT= 2  ISPLIT= 8
   -2: X=0. Y=0.5000 Z=0.5000
 Bi NPT=  781  R0=0.0500 RMT=2.0500   Z:  83.0
  0.7071068 0.7071068 0.000
 -0.7071068 0.7071068 0.000
  0.000 0.000 1.000
 ATOM  -3: X=0.5000 Y=0. Z=0.5000
   MULT= 2  ISPLIT= 8
   -3: X=0. Y=0.5000 Z=0.
 Bi NPT=  781  R0=0.0500 RMT=2.0500   Z:  83.0
  0.7071068 0.7071068 0.000
 -0.7071068 0.7071068 0.000
  0.000 0.000 1.000
 ATOM  -4: X=0.09988080 Y=0.48071300 Z=0.23264600
   MULT= 4  ISPLIT= 8
   -4: X=0.90011920 Y=0.51928700 Z=0.76735400
   -4: X=0.40011920 Y=0.98071300 Z=0.26735400
   -4: X=0.59988080 Y=0.01928700 Z=0.73264600
 O  NPT=  781  R0=0.0001 RMT=1.7000   Z:   8.0
  0.7071068 0.7071068 0.000
 -0.7071068 0.7071068 0.000
  0.000 0.000 1.000
 ATOM  -5: X=0.71614580 Y=0.31476100 Z=0.05060980
   MULT= 4  ISPLIT= 8
   -5: X=0.28385420 Y=0.68523900 Z=0.94939020
   -5: X=0.78385420 Y=0.81476100 Z=0.44939020
   -5: X=0.21614580 Y=0.18523900 Z=0.55060980
 O  NPT=  781  R0=0.0001 RMT=1.7000   Z:   8.0
  0.000-0.7071068 0.7071068
  0.000 0.7071068 0.7071068
 -1.000 0.000 0.000
 ATOM  -6: X=0.18004640 Y=0.21865880 Z=0.95072900
   MULT= 4  ISPLIT= 8
   -6: X=0.81995360 Y=0.78134120 Z=0.04927100
   -6: X=0.31995360 Y=0.71865880 Z=0.54927100
   -6: X=0.68004640 Y=0.28134120 Z=0.45072900
 O  NPT=  781  R0=0.0001 RMT=1.7000   Z:   8.0
  0.000 0.7071068-0.7071068
  0.000 0.7071068 0.7071068
  1.000 0.000 0.000
4  NUMBER OF SYMMETRY OPERATIONS
 -1 0 0 0.
  0-1 0 0.
  0 0-1 0.
1
  1 0 0 0.
  0 1 0 0.
  0 0 1 0.
2
 -1 0 0 0.5000
  0 1 0 0.5000
  0 0-1 0.5000
3
  1 0 0 0.5000
  0-1 0 0.5000
  0 0 1 0.5000
4

 After 'run_lapw -f 1' I get the following information in the .scf:

 :WARN  : X-FORCE for atom   1 is not zero as required by symmetry:   28.2338
 :WARN  : Y-FORCE for atom   1 is not zero as required by symmetry: -113.3722
 :WARN  : Z-FORCE for atom   1 is not zero as required by symmetry:   11.9520
 :WARN  : X-FORCE for atom   4 is not zero as required by symmetry:  -35.0616
 :WARN  : Y-FORCE for atom   4 is not zero as required by symmetry:   -7.5757
 :WARN  : X-FORCE for atom   5 is not zero as required by symmetry:   30.2203
 :WARN  : Y-FORCE for atom   5 is not zero as required by symmetry:  -25.6543
 :WARN  : X-FORCE for atom   6 is not zero as required by symmetry:   30.6085
 :WARN  : Y-FORCE for atom   6 is not zero as required by symmetry:   34.8658

 :ENE  : *WARNING** TOTAL ENERGY IN Ry =  -199762.69661481

TOTAL FORCE IN mRy/a.u. = |F| Fx Fy Fz
with/without FOR in case.in2
 :FOR001:   1.ATOM 117.444686   0.00   0.00
 0.00 total forces
 :FOR002:   2.ATOM   0.00   0.00   0.00
 0.00 total forces
 :FOR003:   3.ATOM   0.00   0.00   0.00
 0.00 total forces
 :FOR004:   4.ATOM  54.932586   0.00   0.00
 41.603856 total forces
 :FOR005:   5.ATOM  58.546663   0.00   0.00