[Wien] force output problem

2014-01-16 Thread Hua Peng
Dear Wien2k users,
I have questions about the Wien2K force output.
After I run run_lapw -fc 0.01 -p , the calculation converged, which
means the force in the system should small than 0.01mRy/a.u..
But in end of  the scf file, the last interaction gives,

   TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
Fz with/without FOR in case.in2
:FOR001:   1.ATOM   0.00   0.00   0.00
0.00 total forces
:FOR002:   2.ATOM   0.00   0.00   0.00
0.00 total forces
:FOR003:   3.ATOM   6.48   0.00   0.00
-6.48 total forces

   TOTAL FORCE WITH RESPECT TO THE GLOBAL COORDINATE SYSTEM:
:FGL001:   1.ATOM 0.0 0.0
0.0 total forces
:FGL002:   2.ATOM 0.0 0.0
0.0 total forces
:FGL003:   3.ATOM-6.48000 0.0
0.0 total forces
:FSUM  : Sum of forces Fx,Fy,Fz0.00.0
  0.0

Besides, in the previous two  interaction, the force is 1.905.

 TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
Fz with/without FOR in case.in2
:FOR001:   1.ATOM  0.000  0.000  0.000
 0.000 partial forces
:FOR002:   2.ATOM  0.000  0.000  0.000
 0.000 partial forces
:FOR003:   3.ATOM  1.905  0.000  0.000
 1.905 partial forces

Is the TOTAL force in the last interaction the sum of force in the
cell? The equivalent atom for ATOM3 is 4.
Best,
Hua Peng
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Re: [Wien] force output problem

2014-01-16 Thread Oleg Rubel
It would be helpful to give a hint of the structure you attempt to
calculate (better enclose the structure file).

Oleg
On Jan 16, 2014 8:49 PM, Hua Peng penghu...@gmail.com wrote:

 Dear Wien2k users,
 I have questions about the Wien2K force output.
 After I run run_lapw -fc 0.01 -p , the calculation converged, which
 means the force in the system should small than 0.01mRy/a.u..
 But in end of  the scf file, the last interaction gives,

TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
 Fz with/without FOR in case.in2
 :FOR001:   1.ATOM   0.00   0.00   0.00
 0.00 total forces
 :FOR002:   2.ATOM   0.00   0.00   0.00
 0.00 total forces
 :FOR003:   3.ATOM   6.48   0.00   0.00
 -6.48 total forces

TOTAL FORCE WITH RESPECT TO THE GLOBAL COORDINATE SYSTEM:
 :FGL001:   1.ATOM 0.0 0.0
 0.0 total forces
 :FGL002:   2.ATOM 0.0 0.0
 0.0 total forces
 :FGL003:   3.ATOM-6.48000 0.0
 0.0 total forces
 :FSUM  : Sum of forces Fx,Fy,Fz0.00.0
   0.0

 Besides, in the previous two  interaction, the force is 1.905.

  TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
 Fz with/without FOR in case.in2
 :FOR001:   1.ATOM  0.000  0.000  0.000
  0.000 partial forces
 :FOR002:   2.ATOM  0.000  0.000  0.000
  0.000 partial forces
 :FOR003:   3.ATOM  1.905  0.000  0.000
  1.905 partial forces

 Is the TOTAL force in the last interaction the sum of force in the
 cell? The equivalent atom for ATOM3 is 4.
 Best,
 Hua Peng
 ___
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 http://zeus.theochem.tuwien.ac.at/mailman/listinfo/wien
 SEARCH the MAILING-LIST at:
 http://www.mail-archive.com/wien@zeus.theochem.tuwien.ac.at/index.html

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Re: [Wien] force output problem

2014-01-16 Thread Laurence Marks
Total Forces have the Pulay corrections included.

Partial Forces do not, are not the correct ones to use and are different.

There is nothing wrong. Note that run_lapw only converges the electron
density with MSR1, you need to use MSR1a to minimize the forces.

__
Laurence Marks
Dept Mat Sci  Eng
Northwestern University
www.numis.northwestern.edu
847 491 3996
On Jan 16, 2014 7:49 PM, Hua Peng penghu...@gmail.com wrote:

 Dear Wien2k users,
 I have questions about the Wien2K force output.
 After I run run_lapw -fc 0.01 -p , the calculation converged, which
 means the force in the system should small than 0.01mRy/a.u..
 But in end of  the scf file, the last interaction gives,

TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
 Fz with/without FOR in case.in2
 :FOR001:   1.ATOM   0.00   0.00   0.00
 0.00 total forces
 :FOR002:   2.ATOM   0.00   0.00   0.00
 0.00 total forces
 :FOR003:   3.ATOM   6.48   0.00   0.00
 -6.48 total forces

TOTAL FORCE WITH RESPECT TO THE GLOBAL COORDINATE SYSTEM:
 :FGL001:   1.ATOM 0.0 0.0
 0.0 total forces
 :FGL002:   2.ATOM 0.0 0.0
 0.0 total forces
 :FGL003:   3.ATOM-6.48000 0.0
 0.0 total forces
 :FSUM  : Sum of forces Fx,Fy,Fz0.00.0
   0.0

 Besides, in the previous two  interaction, the force is 1.905.

  TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
 Fz with/without FOR in case.in2
 :FOR001:   1.ATOM  0.000  0.000  0.000
  0.000 partial forces
 :FOR002:   2.ATOM  0.000  0.000  0.000
  0.000 partial forces
 :FOR003:   3.ATOM  1.905  0.000  0.000
  1.905 partial forces

 Is the TOTAL force in the last interaction the sum of force in the
 cell? The equivalent atom for ATOM3 is 4.
 Best,
 Hua Peng
 ___
 Wien mailing list
 Wien@zeus.theochem.tuwien.ac.at
 http://zeus.theochem.tuwien.ac.at/mailman/listinfo/wien
 SEARCH the MAILING-LIST at:
 http://www.mail-archive.com/wien@zeus.theochem.tuwien.ac.at/index.html

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Re: [Wien] force output problem

2014-01-16 Thread Hua Peng
Thank you Laurence for your suggestion. I will have a try.
Best,
Hua

2014/1/16 Laurence Marks l-ma...@northwestern.edu:
 Total Forces have the Pulay corrections included.

 Partial Forces do not, are not the correct ones to use and are different.

 There is nothing wrong. Note that run_lapw only converges the electron
 density with MSR1, you need to use MSR1a to minimize the forces.

 __
 Laurence Marks
 Dept Mat Sci  Eng
 Northwestern University
 www.numis.northwestern.edu
 847 491 3996

 On Jan 16, 2014 7:49 PM, Hua Peng penghu...@gmail.com wrote:

 Dear Wien2k users,
 I have questions about the Wien2K force output.
 After I run run_lapw -fc 0.01 -p , the calculation converged, which
 means the force in the system should small than 0.01mRy/a.u..
 But in end of  the scf file, the last interaction gives,

TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
 Fz with/without FOR in case.in2
 :FOR001:   1.ATOM   0.00   0.00   0.00
 0.00 total forces
 :FOR002:   2.ATOM   0.00   0.00   0.00
 0.00 total forces
 :FOR003:   3.ATOM   6.48   0.00   0.00
 -6.48 total forces

TOTAL FORCE WITH RESPECT TO THE GLOBAL COORDINATE SYSTEM:
 :FGL001:   1.ATOM 0.0 0.0
 0.0 total forces
 :FGL002:   2.ATOM 0.0 0.0
 0.0 total forces
 :FGL003:   3.ATOM-6.48000 0.0
 0.0 total forces
 :FSUM  : Sum of forces Fx,Fy,Fz0.00.0
   0.0

 Besides, in the previous two  interaction, the force is 1.905.

  TOTAL FORCE IN mRy/a.u. = |F| Fx Fy
 Fz with/without FOR in case.in2
 :FOR001:   1.ATOM  0.000  0.000  0.000
  0.000 partial forces
 :FOR002:   2.ATOM  0.000  0.000  0.000
  0.000 partial forces
 :FOR003:   3.ATOM  1.905  0.000  0.000
  1.905 partial forces

 Is the TOTAL force in the last interaction the sum of force in the
 cell? The equivalent atom for ATOM3 is 4.
 Best,
 Hua Peng
 ___
 Wien mailing list
 Wien@zeus.theochem.tuwien.ac.at
 http://zeus.theochem.tuwien.ac.at/mailman/listinfo/wien
 SEARCH the MAILING-LIST at:
 http://www.mail-archive.com/wien@zeus.theochem.tuwien.ac.at/index.html


 ___
 Wien mailing list
 Wien@zeus.theochem.tuwien.ac.at
 http://zeus.theochem.tuwien.ac.at/mailman/listinfo/wien
 SEARCH the MAILING-LIST at:
 http://www.mail-archive.com/wien@zeus.theochem.tuwien.ac.at/index.html

___
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http://zeus.theochem.tuwien.ac.at/mailman/listinfo/wien
SEARCH the MAILING-LIST at:  
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