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John Toews wrote:
Zope 2.8.0, Python 2.3.5
I'm having a heck of a time figuring out how to zip up some files in my zope
instance and return them to the user. I can sucessfully create a zip file on
the local file system, but if I try to pass it back to the user it is
corrupted. Of course I'd rather not create this tmp3.zip file, so if there's
a way around that (which I'm sure there is!) please do let me know.
filename = 'test.zip'
response = self.REQUEST.RESPONSE
response.setHeader('Content-Type','application/zip')
response.setHeader('Content-Disposition','attachment; filename=%s'
% filename)
# tried zf = zipfile.ZipFile( response, 'w' ) but get error, ZHTTP
object doesn't have tell method
zf = zipfile.ZipFile( '/tmp3.zip', 'w' )
zf.writestr( 'testfilename', str( self._getOb( testfileid ) ) )
zf.close()
f = open('/tmp3.zip')
return f.read()
Any thoughts on what fairly obvious thing I'm doing wrong? Thanks!
A couple of thoughts:
- Be sure you open the file in binary mode ('wb' rather than 'w');
this won't help unless you are running Zope on Windows, however,
because Windows is the only platform where the C runtime will mangle
the line endings for files it thinks are text, rather than
binary.
- You could use a StringIO instance, rather than a tempfile; YMMV.
Tres.
- --
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Tres Seaver +1 202-558-7113 [EMAIL PROTECTED]
Palladion Software Excellence by Designhttp://palladion.com
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