David Nicol wrote:
> On 12/10/05, $Bill Luebkert <[EMAIL PROTECTED]> wrote:
>
>>The fact that you can modify the vrbl passed to a sub from in the sub without
>>using a reference still doesn't mean that it's passed by reference.
>
> No. You are mistaken. That is exactly what passing by reference
On 12/10/05, $Bill Luebkert <[EMAIL PROTECTED]> wrote:
> Chaddaï Fouché wrote:
>
> > $Bill Luebkert wrote:
> >
> >
> >>Perl normally passes by value .
> >>
> >
> > That is unaccurate : Perl always passes by reference (or rather by
> > alias), but we do the copy ourselves when we handle the argument
On Dec 11, 2005, at 09:06, $Bill Luebkert wrote:
DZ-Jay wrote:
Pretty ingenious, albeit a bit of cheating, uh? :)
but if all else fails, I'll probably go with that, thanks!
I still wonder if there is a single regexp that could do what I want,
and if so, I'd like to learn about it. I'm just
$Bill Luebkert wrote:
The fact that you can modify the vrbl passed to a sub from in the sub without
using a reference still doesn't mean that it's passed by reference. This is
a special case that aliasing provides. This could be partially an exercise
in semantics though.
This aliasing provi
DZ-Jay wrote:
> Pretty ingenious, albeit a bit of cheating, uh? :)
> but if all else fails, I'll probably go with that, thanks!
>
> I still wonder if there is a single regexp that could do what I want,
> and if so, I'd like to learn about it. I'm just not very familiar with
> backtracking and
On Dec 10, 2005, at 22:54, $Bill Luebkert wrote:
$_ = q{"LastName, First Name" , "Name" , ;
FirstName LastName, address; "First \"nick\" Last" address};
s/\\"/\003/g; # handle embedded \"
s/"([^"]+)"/\001$1\002/g;# handle open/close
