Thanks a lot folks. My mistake...I should have looked at "-p"'s significance before posting it. Thanks again, ArijitDZ-Jay <[EMAIL PROTECTED]> wrote: Arijit Das wrote:> I am just wondering why is this giving a strange result. Any clues...?> This is from the Perl In A Nutshell book:---
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Arijit
Das
Sent: 25 January 2006 11:47
To: activeperl@listserv.activestate.com;
perl-unix-users@listserv.activestate.com
Subject: Strange behaviour in Perl
> I am just wondering why is this giving a strange result. Any cl
Arijit Das wrote:
> I am just wondering why is this giving a strange result. Any clues...?
>
> $ echo 4.56 | perl -p -e 'my $var1 = ; $var2 = $var1 * 100; print
$var2;'
> 04.56
> $
>
> I am expecting 456 in the ouput instead of 4.56
>
> Am I missing anything...?
The '-p' option is causing the
Arijit Das wrote:
> I am just wondering why is this giving a strange result. Any clues...?
>
> bash-2.01$ echo 4.56 | perl -p -e 'my $var1 = ; $var2 =
$var1 * 100; print $var2;'
> 04.56
> bash-2.01$
>
> I am expecting 456 in the ouput instead of 4.56
>
> Am I missing anything...?
>
Remov
Arijit Das wrote:
I am just wondering why is this giving a strange result. Any clues...?
This is from the Perl In A Nutshell book:
--
-p: Causes Perl to assume the following loop around your script, which
makes it iterate over filename arguments:
LINE:
while (<>) {
.
I think the –p is the one causing
the problem
Tried
echo 4.56 | perl -e 'my $var1 =
* 100; print $var1;'
and the result is 456
bash-2.01$ echo 4.56 | perl -p -e 'my $var1 = ; $var2 =
$var1 * 100; print $var2;'
04.56
I only remove th
Arijit Das wrote:
I am just wondering why is this giving a strange result. Any clues...?
bash-2.01$ echo 4.56 | perl -p -e 'my $var1 = ; $var2 = $var1 * 100; print $var2;'
04.56
bash-2.01$
I am expecting 456 in the ouput instead of 4.56
Am I missing anything...?
Thanks,
Arijit
f Of Arijit Das
Sent: Wednesday, January 25, 2006
5:47 AM
To:
activeperl@listserv.activestate.com; perl-unix-users@listserv.activestate.com
Subject: Strange behaviour in Perl
I am just wondering why is this giving a strange result. Any clues...?
bash-2.01$ echo 4.56 | perl -p -e
I am just wondering why is this giving a strange result. Any clues...? bash-2.01$ echo 4.56 | perl -p -e 'my $var1 = ; $var2 = $var1 * 100; print $var2;'04.56bash-2.01$ I am expecting 456 in the ouput instead of 4.56 Am I missing anything...? Thanks,Arijit
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