[algogeeks] Re: Algorithmic time

2006-06-01 Thread chiat
I don't know if I'm on the right track, perhaps someone can give me some pointers. Thanks. 1b) Since algorithm A is of O(2n^3), and it can solve a problem of size n = 20 in one hr, then by substituting n = 20 into the equation, we have that A performs 2 * (20 ^ 3) = 16000 operations in 1 hr. t

[algogeeks] Algorithmic time

2006-06-01 Thread chiat
Hi guys, I'm preparing for my exams and have been stuck at this problem for a while now, i know my maths is really poor, would really appreciate some pointers. if algorithm A is of O(2n^3) and algorithm B is of O(2^n + n^2) and if A is guaranteed to solve a problem of size n = 20 in 1 hr, then w

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[algogeeks] Re: Friend-machines-assisted approach to downloading via BitTorrent

2006-06-01 Thread Booted Cat
The only supervision is to let my friends timely report which pieces they have downloaded, so I will know when they can quit the swarm and serve just me. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Algorithm Ge

[algogeeks] Re: Friend-machines-assisted approach to downloading via BitTorrent

2006-06-01 Thread Booted Cat
I haven't seen the real world performance of this idea. I may contact some interested programmers and do some experiments. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this gro

[algogeeks] Re: Friend-machines-assisted approach to downloading via BitTorrent

2006-06-01 Thread ashish
I think this is a good idea, esp if lot of people are ready to co-operate. Though you might need to change or write a new client to include the co-operation bit. Does any client today allow you to download a specified portion of a file instead of the entire file ? Do you plan to modify/write suc

[algogeeks] Re: Friend-machines-assisted approach to downloading via BitTorrent

2006-06-01 Thread adak
Let's say it works - and it's faster, also. But now the data you want is spread out still across a few different machines. You'd still have to: 1) download each friend's part of the total download, and 2) then re-assemble the download back together again. Also, I don't view the co-ordinated d