On 16 juil, 18:19, Miroslav Balaz wrote:
> I think that there is logical error, in the proof what do you think about
> it?
> f(A)=B iff A and B have the same labelig, but what if there are 3 vertices
> with the same labeling? say A,B,C
> then F(A)=B and F(A)=C
>
> you forget to quantify the f.
I believe that everything is clear: if I should seek the existence of
the isomorphism between two graphs G and H, I should generate the
label of each vertex of G and each vertex of H. ..
On 16 juil, 18:26, Miroslav Balaz wrote:
> And also you should answer the main question , how will you find t
example of a triangle:
A - B
A - C
B - C
here the three vertices A, B and C have the same labeling.
On 16 juil, 18:19, Miroslav Balaz wrote:
> I think that there is logical error, in the proof what do you think about
> it?
> f(A)=B iff A and B have the same labelig, but what if there are 3 verti
example of a triangle:
A - B
A - C
B - C
here the three vertices A, B and C have the same labeling.
On 16 juil, 18:19, Miroslav Balaz wrote:
> I think that there is logical error, in the proof what do you think about
> it?
> f(A)=B iff A and B have the same labelig, but what if there are 3 verti
example of a triangle:
A-B
A-C
A-B
here it is clear that the vertex A, B and C have identical labeling.
On 16 juil, 18:19, Miroslav Balaz wrote:
> I think that there is logical error, in the proof what do you think about
> it?
> f(A)=B iff A and B have the same labelig, but what if there are 3
