@Wladimir, Nice articles.
Thanks.
Best Regards,
Rahul.
On Tue, Feb 14, 2012 at 5:05 AM, Wladimir Tavares wladimir...@gmail.comwrote:
Hi Guys,
I transfer some text for this blog.
http://marathoncode.blogspot.com
Some good posts:
algogeeks@googlegroups.com wrote:
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HI , consider that each value could be the root. Recursively find the
size of the left and right subtrees. thats it .
lets try for n=2 e.g. 1,2 there ways to select the root wither 1 or 2 , if
u choose one , size of left subtree will be 0 size of right subtree will
be 1 so
, similarly
in 1 2 3 4 5 6...o/p ll b 5
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For a binary search tree the solution is called the Catalan Numbers.
The formula is (2n)!/(n!(n+1)!)
The first few terms are:
1, 1, 2, 5, 14, 42, 132, 429, 1430, 4862, 16796, 58786, 208012,
742900, 2674440, 9694845, 35357670, 129644790, 477638700, 1767263190,
6564120420, 24466267020, 91482563640,
Given an array of size N having numbers in the range 0 to k where
k=N, preprocess the array inplace and in linear time in such a way
that after preprocessing you should be able to return count of the
input element in O(1).
Please give some idea !!
Thanks..
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if n is less than 10^6 hasing works fine ..and we count in O(1) time only
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@kartik : question says inplace . so using hashing would be violation...
i dont think so it can be done if array is unsorted and with given
restriction
On Wed, Feb 15, 2012 at 10:05 AM, Kartik Sachan kartik.sac...@gmail.comwrote:
if n is less than 10^6 hasing works fine ..and we count in
That means,,,we have to sort the array first in O(n).
Is there any way to sort the array inplace in O(n) ?
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Array 'A' contains N elements st A[i] =k N
Now,
Iterate over the array.
Let k=A[i]
If A[i] N
then k=A[i] mod N
go to A[k] and write A[k] = A[k] + N
So, lets take a sample array of size 5: 1,2,1,0,4
i=0: k=A[i]=1; A[i] 5; A[1] = A[1] + 5 = A[1] = 7 = A = 1,7,1,0,4
i=1: k=A[i]=7; A[i] 5;
@amit : it is valid for comparison based model..
On Wed, Feb 15, 2012 at 12:05 PM, amrit harry dabbcomput...@gmail.comwrote:
@tushar
lower bound for sorting an array is nlogn.
http://www.bowdoin.edu/~ltoma/teaching/cs231/fall11/Lectures/6-moresorting/sortLB.pdf
On Wed, Feb 15, 2012 at
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